How to upload my video to other channels in youtube API - python

The question should be how to upload users video to their youtube channel?
for that i am using youtube api V3 and quick search from google i found below code
client_secrets.json
{
"web": {
"client_id": "[[INSERT CLIENT ID HERE]]",
"client_secret": "[[INSERT CLIENT SECRET HERE]]",
"redirect_uris": [],
"auth_uri": "https://accounts.google.com/o/oauth2/auth",
"token_uri": "https://accounts.google.com/o/oauth2/token"
}
}
from the terminal
python upload_video.py --file="/tmp/test_video_file.flv"
--title="Summer vacation in California"
--description="Had a great time surfing in Santa Cruz"
--keywords="surfing,Santa Cruz"
--category="22"
--privacyStatus="private"
How to upload my video to other channels in youtube API
The complete working sample for the upload_video.py script is listed below:
#!/usr/bin/python
import httplib
import httplib2
import os
import random
import sys
import time
from apiclient.discovery import build
from apiclient.errors import HttpError
from apiclient.http import MediaFileUpload
from oauth2client.file import Storage
from oauth2client.client import flow_from_clientsecrets
from oauth2client.tools import run
from optparse import OptionParser
# Explicitly tell the underlying HTTP transport library not to retry, since
# we are handling retry logic ourselves.
httplib2.RETRIES = 1
# Maximum number of times to retry before giving up.
MAX_RETRIES = 10
# Always retry when these exceptions are raised.
RETRIABLE_EXCEPTIONS = (httplib2.HttpLib2Error, IOError, httplib.NotConnected,
httplib.IncompleteRead, httplib.ImproperConnectionState,
httplib.CannotSendRequest, httplib.CannotSendHeader,
httplib.ResponseNotReady, httplib.BadStatusLine)
# Always retry when an apiclient.errors.HttpError with one of these status
# codes is raised.
RETRIABLE_STATUS_CODES = [500, 502, 503, 504]
# CLIENT_SECRETS_FILE, name of a file containing the OAuth 2.0 information for
# this application, including client_id and client_secret. You can acquire an
# ID/secret pair from the API Access tab on the Google APIs Console
# http://code.google.com/apis/console#access
# For more information about using OAuth2 to access Google APIs, please visit:
# https://developers.google.com/accounts/docs/OAuth2
# For more information about the client_secrets.json file format, please visit:
# https://developers.google.com/api-client-library/python/guide/aaa_client_secrets
# Please ensure that you have enabled the YouTube Data API for your project.
CLIENT_SECRETS_FILE = "client_secrets.json"
# A limited OAuth 2 access scope that allows for uploading files, but not other
# types of account access.
YOUTUBE_UPLOAD_SCOPE = "https://www.googleapis.com/auth/youtube.upload"
YOUTUBE_API_SERVICE_NAME = "youtube"
YOUTUBE_API_VERSION = "v3"
# Helpful message to display if the CLIENT_SECRETS_FILE is missing.
MISSING_CLIENT_SECRETS_MESSAGE = """
WARNING: Please configure OAuth 2.0
To make this sample run you will need to populate the client_secrets.json file
found at:
%s
with information from the APIs Console
https://code.google.com/apis/console#access
For more information about the client_secrets.json file format, please visit:
https://developers.google.com/api-client-library/python/guide/aaa_client_secrets
""" % os.path.abspath(os.path.join(os.path.dirname(__file__),
CLIENT_SECRETS_FILE))
def get_authenticated_service():
flow = flow_from_clientsecrets(CLIENT_SECRETS_FILE, scope=YOUTUBE_UPLOAD_SCOPE,
message=MISSING_CLIENT_SECRETS_MESSAGE)
storage = Storage("%s-oauth2.json" % sys.argv[0])
credentials = storage.get()
if credentials is None or credentials.invalid:
credentials = run(flow, storage)
return build(YOUTUBE_API_SERVICE_NAME, YOUTUBE_API_VERSION,
http=credentials.authorize(httplib2.Http()))
def initialize_upload(options):
youtube = get_authenticated_service()
tags = None
if options.keywords:
tags = options.keywords.split(",")
insert_request = youtube.videos().insert(
part="snippet,status",
body=dict(
snippet=dict(
title=options.title,
description=options.description,
tags=tags,
categoryId=options.category
),
status=dict(
privacyStatus=options.privacyStatus
)
),
# chunksize=-1 means that the entire file will be uploaded in a single
# HTTP request. (If the upload fails, it will still be retried where it
# left off.) This is usually a best practice, but if you're using Python
# older than 2.6 or if you're running on App Engine, you should set the
# chunksize to something like 1024 * 1024 (1 megabyte).
media_body=MediaFileUpload(options.file, chunksize=-1, resumable=True)
)
resumable_upload(insert_request)
def resumable_upload(insert_request):
response = None
error = None
retry = 0
while response is None:
try:
print "Uploading file..."
status, response = insert_request.next_chunk()
if 'id' in response:
print "'%s' (video id: %s) was successfully uploaded." % (
options.title, response['id'])
else:
exit("The upload failed with an unexpected response: %s" % response)
except HttpError, e:
if e.resp.status in RETRIABLE_STATUS_CODES:
error = "A retriable HTTP error %d occurred:\n%s" % (e.resp.status,
e.content)
else:
raise
except RETRIABLE_EXCEPTIONS, e:
error = "A retriable error occurred: %s" % e
if error is not None:
print error
retry += 1
if retry > MAX_RETRIES:
exit("No longer attempting to retry.")
max_sleep = 2 ** retry
sleep_seconds = random.random() * max_sleep
print "Sleeping %f seconds and then retrying..." % sleep_seconds
time.sleep(sleep_seconds)
if __name__ == '__main__':
parser = OptionParser()
parser.add_option("--file", dest="file", help="Video file to upload")
parser.add_option("--title", dest="title", help="Video title",
default="Test Title")
parser.add_option("--description", dest="description",
help="Video description",
default="Test Description")
parser.add_option("--category", dest="category",
help="Numeric video category. " +
"See https://developers.google.com/youtube/v3/docs/videoCategories/list",
default="22")
parser.add_option("--keywords", dest="keywords",
help="Video keywords, comma separated", default="")
parser.add_option("--privacyStatus", dest="privacyStatus",
help="Video privacy status: public, private or unlisted",
default="public")
(options, args) = parser.parse_args()
if options.file is None or not os.path.exists(options.file):
exit("Please specify a valid file using the --file= parameter.")
else:
initialize_upload(options)
Question 1 :
How to integrate with django view function ?
like when user access localhost:8000/upload page then followed by browse & submit button next google will ask for user credential after successful login video will uploaded to given username youtube channel. For this how to integrate above code to django view funtion
Question 2 :
How to change below command to view
python upload_video.py --file="/tmp/test_video_file.flv"
--title="Summer vacation in California"
--description="Had a great time surfing in Santa Cruz"
--keywords="surfing,Santa Cruz"
--category="22"
--privacyStatus="private"

No way to do it as you can't get the CLIENT SECRET FILE of a user until he gives you
client_id
client_secret
And here is what google says
Warning: Keep your client secret private. If someone obtains your client secret, they could use it to consume your quota, incur charges against your Google APIs Console project, and request access to user data.

You will almost certainly find it easier using a library like python-social-auth or django-allauth, personally I'd use python-social-auth but as you seem to be just starting out with Django use django-allauth.
https://github.com/pennersr/django-allauth
There is a good tutorial that will take you through it:
http://www.sarahhagstrom.com/2013/09/the-missing-django-allauth-tutorial/
As for turning that script into a view, just call it from inside any django view, you should check to see if the user is logged into Google, if they are then use the access token stored in the database. If not you should redirect them to the Google login url pattern provide by django-allauth.

Save your upload_video.py file into your video app.
In your view.py try following the post of the form:
form_upload = VideoForm(request.POST, request.FILES)
if form_upload.is_valid():
uploaded_video = form_upload.save(commit=True)
# send this file to youtube
credentials = get_authenticated_service(uploaded_video)
initialize_upload(credentials, uploaded_video)
In your videos models.py
file_on_server = models.FileField(max_length=100, null=True, blank=True)
auth_host_name = 'localhost'
noauth_local_webserver = True
auth_host_port = [8080, 8090]
logging_level = 'ERROR'
category = 23
privacyStatus = 'public'
#property
def file(self):
return self.file_on_server.path
Under the Google Developer Console:
Create a Google OAuth Client ID for native application not web application.
Download JSON to your video app.
Once submitted you should get the following message in your console:
Uploading file...
Video id '' was successfully uploaded.

Related

Office 365 IMAP authentication via OAuth2 and python MSAL library

I'm trying to upgrade a legacy mail bot to authenticate via Oauth2 instead of Basic authentication, as it's now deprecated two days from now.
The document states applications can retain their original logic, while swapping out only the authentication bit
Application developers who have built apps that send, read, or
otherwise process email using these protocols will be able to keep the
same protocol, but need to implement secure, Modern authentication
experiences for their users. This functionality is built on top of
Microsoft Identity platform v2.0 and supports access to Microsoft 365
email accounts.
Note I've explicitly chosen the client credentials flow, because the documentation states
This type of grant is commonly used for server-to-server interactions
that must run in the background, without immediate interaction with a
user.
So I've got a python script that retrieves an Access Token using the MSAL python library. Now I'm trying to authenticate with the IMAP server, using that Access Token. There's some existing threads out there showing how to connect to Google, I imagine my case is pretty close to this one, except I'm connecting to a Office 365 IMAP server. Here's my script
import imaplib
import msal
import logging
app = msal.ConfidentialClientApplication(
'client-id',
authority='https://login.microsoftonline.com/tenant-id',
client_credential='secret-key'
)
result = app.acquire_token_for_client(scopes=['https://graph.microsoft.com/.default'])
def generate_auth_string(user, token):
return 'user=%s\1auth=Bearer %s\1\1' % (user, token)
# IMAP time!
mailserver = 'outlook.office365.com'
imapport = 993
M = imaplib.IMAP4_SSL(mailserver,imapport)
M.debug = 4
M.authenticate('XOAUTH2', lambda x: generate_auth_string('user#mydomain.com', result['access_token']))
print(result)
The IMAP authentication is failing and despite setting M.debug = 4, the output isn't very helpful
22:56.53 > b'DBDH1 AUTHENTICATE XOAUTH2'
22:56.53 < b'+ '
22:56.53 write literal size 2048
22:57.84 < b'DBDH1 NO AUTHENTICATE failed.'
22:57.84 NO response: b'AUTHENTICATE failed.'
Traceback (most recent call last):
File "/home/ubuntu/mini-oauth.py", line 21, in <module>
M.authenticate("XOAUTH2", lambda x: generate_auth_string('user#mydomain.com', result['access_token']))
File "/usr/lib/python3.10/imaplib.py", line 444, in authenticate
raise self.error(dat[-1].decode('utf-8', 'replace'))
imaplib.IMAP4.error: AUTHENTICATE failed.
Any idea where I might be going wrong, or how to get more robust information from the IMAP server about why the authentication is failing?
Things I've looked at
Note this answer no longer works as the suggested scopes fail to generate an Access Token.
The client credentials flow seems to mandate the https://graph.microsoft.com/.default grant. I'm not sure if that includes the scope required for the IMAP resource
https://outlook.office.com/IMAP.AccessAsUser.All?
Verified the code lifted from the Google thread produces the SASL XOAUTH2 string correctly, per example on the MS docs
import base64
user = 'test#contoso.onmicrosoft.com'
token = 'EwBAAl3BAAUFFpUAo7J3Ve0bjLBWZWCclRC3EoAA'
xoauth = "user=%s\1auth=Bearer %s\1\1" % (user, token)
xoauth = xoauth.encode('ascii')
xoauth = base64.b64encode(xoauth)
xoauth = xoauth.decode('ascii')
xsanity = 'dXNlcj10ZXN0QGNvbnRvc28ub25taWNyb3NvZnQuY29tAWF1dGg9QmVhcmVyIEV3QkFBbDNCQUFVRkZwVUFvN0ozVmUwYmpMQldaV0NjbFJDM0VvQUEBAQ=='
print(xoauth == xsanity) # prints True
This thread seems to suggest multiple tokens need to be fetched, one for graph, then another for the IMAP connection; could that be what I'm missing?
Try the below steps.
For Client Credentials Flow you need to assign “Application permissions” in the app registration, instead of “Delegated permissions”.
Add permission “Office 365 Exchange Online / IMAP.AccessAsApp” (application).
Grant admin consent to you application
Service Principals and Exchange.
Once a service principal is registered with Exchange Online, administrators can run the Add-Mailbox Permission cmdlet to assign receive permissions to the service principal.
Use scope 'https://outlook.office365.com/.default'.
Now you can generate the SALS authentication string by combining this access token and the mailbox username to authenticate with IMAP4.
#Python code
def get_access_token():
tenantID = 'abc'
authority = 'https://login.microsoftonline.com/' + tenantID
clientID = 'abc'
clientSecret = 'abc'
scope = ['https://outlook.office365.com/.default']
app = ConfidentialClientApplication(clientID,
authority=authority,
client_credential = clientSecret)
access_token = app.acquire_token_for_client(scopes=scope)
return access_token
def generate_auth_string(user, token):
auth_string = f"user={user}\1auth=Bearer {token}\1\1"
return auth_string
#IMAP AUTHENTICATE
imap = imaplib.IMAP4_SSL(imap_host, 993)
imap.debug = 4
access_token = get_access_token_to_authenticate_imap()
imap.authenticate("XOAUTH2", lambda x:generate_auth_string(
'useremail',
access_token['access_token']))
imap.select('inbox')
The imaplib.IMAP4.error: AUTHENTICATE failed Error occured because one point in the documentation is not that clear.
When setting up the the Service Principal via Powershell you need to enter the App-ID and an Object-ID. Many people will think, it is the Object-ID you see on the overview page of the registered App, but its not!
At this point you need the Object-ID from "Azure Active Directory -> Enterprise Applications --> Your-App --> Object-ID"
New-ServicePrincipal -AppId <APPLICATION_ID> -ServiceId <OBJECT_ID> [-Organization <ORGANIZATION_ID>]
Microsoft says:
The OBJECT_ID is the Object ID from the Overview page of the
Enterprise Application node (Azure Portal) for the application
registration. It is not the Object ID from the Overview of the App
Registrations node. Using the incorrect Object ID will cause an
authentication failure.
Ofcourse you need to take care for the API-permissions and the other stuff, but this was for me the point.
So lets go trough it again, like it is explained on the documentation page.
Authenticate an IMAP, POP or SMTP connection using OAuth
Register the Application in your Tenant
Setup a Client-Key for the application
Setup the API permissions, select the APIs my organization uses tab and search for "Office 365 Exchange Online" -> Application permissions -> Choose IMAP and IMAP.AccessAsApp
Setup the Service Principal and full access for your Application on the mailbox
Check if IMAP is activated for the mailbox
Thats the code I use to test it:
import imaplib
import msal
import pprint
conf = {
"authority": "https://login.microsoftonline.com/XXXXyourtenantIDXXXXX",
"client_id": "XXXXXXXX-XXXX-XXXX-XXXX-XXXXXXXXXXXXX", #AppID
"scope": ['https://outlook.office365.com/.default'],
"secret": "XXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXX", #Key-Value
"secret-id": "XXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXX", #Key-ID
}
def generate_auth_string(user, token):
return f"user={user}\x01auth=Bearer {token}\x01\x01"
if __name__ == "__main__":
app = msal.ConfidentialClientApplication(conf['client_id'], authority=conf['authority'],
client_credential=conf['secret'])
result = app.acquire_token_silent(conf['scope'], account=None)
if not result:
print("No suitable token in cache. Get new one.")
result = app.acquire_token_for_client(scopes=conf['scope'])
if "access_token" in result:
print(result['token_type'])
pprint.pprint(result)
else:
print(result.get("error"))
print(result.get("error_description"))
print(result.get("correlation_id"))
imap = imaplib.IMAP4('outlook.office365.com')
imap.starttls()
imap.authenticate("XOAUTH2", lambda x: generate_auth_string("target_mailbox#example.com", result['access_token']).encode("utf-8"))
After setting up the Service Principal and giving the App full access on the mailbox, wait 15 - 30 minutes for the changes to take effect and test it.
Try with this script:
import json
import msal
import requests
client_id = '***'
client_secret = '***'
tenant_id = '***'
authority = f"https://login.microsoftonline.com/{tenant_id}"
app = msal.ConfidentialClientApplication(
client_id=client_id,
client_credential=client_secret,
authority=authority)
scopes = ["https://graph.microsoft.com/.default"]
result = None
result = app.acquire_token_silent(scopes, account=None)
if not result:
print(
"No suitable token exists in cache. Let's get a new one from Azure Active Directory.")
result = app.acquire_token_for_client(scopes=scopes)
# if "access_token" in result:
# print("Access token is " + result["access_token"])
if "access_token" in result:
userId = "***"
endpoint = f'https://graph.microsoft.com/v1.0/users/{userId}/sendMail'
toUserEmail = "***"
email_msg = {'Message': {'Subject': "Test Sending Email from Python",
'Body': {'ContentType': 'Text', 'Content': "This is a test email."},
'ToRecipients': [{'EmailAddress': {'Address': toUserEmail}}]
},
'SaveToSentItems': 'true'}
r = requests.post(endpoint,
headers={'Authorization': 'Bearer ' + result['access_token']}, json=email_msg)
if r.ok:
print('Sent email successfully')
else:
print(r.json())
else:
print(result.get("error"))
print(result.get("error_description"))
print(result.get("correlation_id"))
Source: https://kontext.tech/article/795/python-send-email-via-microsoft-graph-api

YT Data API throws Error 403 for just one video

I was using the YouTube Data API v3 to put the current view count in my video title just like in this video ( https://www.youtube.com/watch?v=BxV14h0kFs0 ) and it works!
I set it up in pythonanywhere for this video ID: 7vSw7XRivWY, worked like a charm, still running.
Then I tried to do the same thing for another video (ID: fDh-qcbIxtU ) and now it throws
googleapiclient.errors.HttpError: <HttpError 400 when requesting https://www.googleapis.com/youtube/v3/videos?part=snippet&alt=json returned "The request metadata is invalid.">
{
"error": {
"code": 403,
"message": "The request is missing a valid API key.",
"errors": [
{
"message": "The request is missing a valid API key.",
"domain": "global",
"reason": "forbidden"
}
],
"status": "PERMISSION_DENIED"
}
}
this error. I'm using the exact same code I used for the other ID, all I did was changing my variable for the video ID to the other one.
I've no clue why this happens. I retried it multiple times, I tried it with different API scopes, I tried it with another API client key - same result, not working.
In my python code I implemented a method change_title that takes the apiclient and the video ID as parameters then first fetches the view count & snippet part ( which contains the title ), edits the title section of the snippet, and then updates the video accordingly.
As already stated, it works for any other of my videos but not for this one (ID: fDh-qcbIxtU). I'm 100% sure I put in the correct ID and that I didn't change anything else.
Here's the whole file that is being executed:
# -*- coding: utf-8 -*-
# Sample Python code for youtube.channels.list
# See instructions for running these code samples locally:
# https://developers.google.com/explorer-help/guides/code_samples#python
import os
import google_auth_oauthlib.flow
import googleapiclient.discovery
import googleapiclient.errors
import time
scopes = ['https://www.googleapis.com/auth/youtube.force-ssl']
def like_video(youtube, videoID):
youtube.videos().rate(
id=videoID,
rating='like'
).execute()
def change_title(youtube, videoID):
video_list_response_statistics = youtube.videos().list(
id=videoID,
part="statistics"
).execute()
videos_list_statistics = video_list_response_statistics['items'][0]['statistics']
views = videos_list_statistics['viewCount']
print("Views: " + str(views))
snippetPart = youtube.videos().list(
id=videoID,
part="snippet"
).execute()
# Since the request specified a video ID, the response only contains one
# video resource. This code extracts the snippet from that resource.
videos_list_snippet = snippetPart['items'][0]['snippet']
print(videos_list_snippet)
videos_list_snippet['title'] += " [" + str(views) + " Views]"
videos_update_response = youtube.videos().update(
part='snippet',
body=dict(
id=videoID,
snippet=videos_list_snippet
)).execute()
def main():
# Disable OAuthlib's HTTPS verification when running locally.
# *DO NOT* leave this option enabled in production.
os.environ["OAUTHLIB_INSECURE_TRANSPORT"] = "0"
api_service_name = "youtube"
api_version = "v3"
client_secrets_file = "credentials.json"
# Get credentials and create an API client
flow = google_auth_oauthlib.flow.InstalledAppFlow.from_client_secrets_file(
client_secrets_file, scopes)
credentials = flow.run_console()
youtube = googleapiclient.discovery.build(
api_service_name, api_version, credentials=credentials)
i = 1
videoID = "fDh-qcbIxtU"
while True:
print("Update No" + str(i))
response = change_title(youtube, videoID)
print(response)
i += 1
time.sleep(1000)
if __name__ == "__main__":
main()
Thanks for anyone that's taking the time to try & solve my issue.
I was getting this error for my one particular youtube channel, and that was because it was managed by a brand account than its owner account.
It might not be helpful in your case but maybe it can help others facing this issue.
Just authorize with the right account.

YouTube API Python upload_video.py run from script, not command line

I have the youtube script that YouTube supplies installed and working, but I can only figure out how to use it from the command line.
For example to upload a file, I use the command prompt and enter
python upload_video.py --file="temp/british.mp4" --title="Summer vacation in California" --description="Had fun surfing in Santa Cruz" --keywords="surfing,Santa Cruz" --category="22" --privacyStatus="private" which will upload the file using the parameters.
My question is, how would I go about having script start.py, and then run something like the above command prompt command from within start.py, calling upon the parameters and passing them though to video_upload.py? I am trying to call the command three times in a row in the start.py script for three different videos. I am using Python 2.7.
I have figured out how to do it via os.system with
import os
os.system("python video_upload.py --file=\"temp/british.mp4\" --title=\"Summer vacation in California\" --description=\"Had fun surfing in Santa Cruz\" --keywords=\"surfing,Santa Cruz\" --category=\"22\" --privacyStatus=\"private\"")
But this done externally and not done straight in Python as I would like to capture the 'id' that is printed out at the end.
#!/usr/bin/python
import httplib
import httplib2
import os
import random
import sys
import time
from apiclient.discovery import build
from apiclient.errors import HttpError
from apiclient.http import MediaFileUpload
from oauth2client.client import flow_from_clientsecrets
from oauth2client.file import Storage
from oauth2client.tools import argparser, run_flow
# Explicitly tell the underlying HTTP transport library not to retry, since
# we are handling retry logic ourselves.
httplib2.RETRIES = 1
# Maximum number of times to retry before giving up.
MAX_RETRIES = 10
# Always retry when these exceptions are raised.
RETRIABLE_EXCEPTIONS = (httplib2.HttpLib2Error, IOError, httplib.NotConnected,
httplib.IncompleteRead, httplib.ImproperConnectionState,
httplib.CannotSendRequest, httplib.CannotSendHeader,
httplib.ResponseNotReady, httplib.BadStatusLine)
# Always retry when an apiclient.errors.HttpError with one of these status
# codes is raised.
RETRIABLE_STATUS_CODES = [500, 502, 503, 504]
# The CLIENT_SECRETS_FILE variable specifies the name of a file that contains
# the OAuth 2.0 information for this application, including its client_id and
# client_secret. You can acquire an OAuth 2.0 client ID and client secret from
# the Google Developers Console at
# https://console.developers.google.com/.
# Please ensure that you have enabled the YouTube Data API for your project.
# For more information about using OAuth2 to access the YouTube Data API, see:
# https://developers.google.com/youtube/v3/guides/authentication
# For more information about the client_secrets.json file format, see:
# https://developers.google.com/api-client-library/python/guide/aaa_client_secrets
CLIENT_SECRETS_FILE = "client_secrets.json"
# This OAuth 2.0 access scope allows an application to upload files to the
# authenticated user's YouTube channel, but doesn't allow other types of access.
YOUTUBE_UPLOAD_SCOPE = "https://www.googleapis.com/auth/youtube.upload"
YOUTUBE_API_SERVICE_NAME = "youtube"
YOUTUBE_API_VERSION = "v3"
# This variable defines a message to display if the CLIENT_SECRETS_FILE is
# missing.
MISSING_CLIENT_SECRETS_MESSAGE = """
WARNING: Please configure OAuth 2.0
To make this sample run you will need to populate the client_secrets.json file
found at:
%s
with information from the Developers Console
https://console.developers.google.com/
For more information about the client_secrets.json file format, please visit:
https://developers.google.com/api-client-library/python/guide/aaa_client_secrets
""" % os.path.abspath(os.path.join(os.path.dirname(__file__),
CLIENT_SECRETS_FILE))
VALID_PRIVACY_STATUSES = ("public", "private", "unlisted")
def get_authenticated_service(args):
flow = flow_from_clientsecrets(CLIENT_SECRETS_FILE,
scope=YOUTUBE_UPLOAD_SCOPE,
message=MISSING_CLIENT_SECRETS_MESSAGE)
storage = Storage("%s-oauth2.json" % sys.argv[0])
credentials = storage.get()
if credentials is None or credentials.invalid:
credentials = run_flow(flow, storage, args)
return build(YOUTUBE_API_SERVICE_NAME, YOUTUBE_API_VERSION,
http=credentials.authorize(httplib2.Http()))
def initialize_upload(youtube, options):
tags = None
if options.keywords:
tags = options.keywords.split(",")
body=dict(
snippet=dict(
title=options.title,
description=options.description,
tags=tags,
categoryId=options.category
),
status=dict(
privacyStatus=options.privacyStatus
)
)
# Call the API's videos.insert method to create and upload the video.
insert_request = youtube.videos().insert(
part=",".join(body.keys()),
body=body,
# The chunksize parameter specifies the size of each chunk of data, in
# bytes, that will be uploaded at a time. Set a higher value for
# reliable connections as fewer chunks lead to faster uploads. Set a lower
# value for better recovery on less reliable connections.
#
# Setting "chunksize" equal to -1 in the code below means that the entire
# file will be uploaded in a single HTTP request. (If the upload fails,
# it will still be retried where it left off.) This is usually a best
# practice, but if you're using Python older than 2.6 or if you're
# running on App Engine, you should set the chunksize to something like
# 1024 * 1024 (1 megabyte).
media_body=MediaFileUpload(options.file, chunksize=-1, resumable=True)
)
resumable_upload(insert_request)
# This method implements an exponential backoff strategy to resume a
# failed upload.
def resumable_upload(insert_request):
response = None
error = None
retry = 0
while response is None:
try:
print "Uploading file..."
status, response = insert_request.next_chunk()
if 'id' in response:
print "Video id '%s' was successfully uploaded." % response['id']
else:
exit("The upload failed with an unexpected response: %s" % response)
except HttpError, e:
if e.resp.status in RETRIABLE_STATUS_CODES:
error = "A retriable HTTP error %d occurred:\n%s" % (e.resp.status,
e.content)
else:
raise
except RETRIABLE_EXCEPTIONS, e:
error = "A retriable error occurred: %s" % e
if error is not None:
print error
retry += 1
if retry > MAX_RETRIES:
exit("No longer attempting to retry.")
max_sleep = 2 ** retry
sleep_seconds = random.random() * max_sleep
print "Sleeping %f seconds and then retrying..." % sleep_seconds
time.sleep(sleep_seconds)
if __name__ == '__main__':
argparser.add_argument("--file", required=True, help="Video file to upload")
argparser.add_argument("--title", help="Video title", default="Test Title")
argparser.add_argument("--description", help="Video description",
default="Test Description")
argparser.add_argument("--category", default="22",
help="Numeric video category. " +
"See https://developers.google.com/youtube/v3/docs/videoCategories/list")
argparser.add_argument("--keywords", help="Video keywords, comma separated",
default="")
argparser.add_argument("--privacyStatus", choices=VALID_PRIVACY_STATUSES,
default=VALID_PRIVACY_STATUSES[0], help="Video privacy status.")
args = argparser.parse_args()
if not os.path.exists(args.file):
exit("Please specify a valid file using the --file= parameter.")
youtube = get_authenticated_service(args)
try:
initialize_upload(youtube, args)
except HttpError, e:
print "An HTTP error %d occurred:\n%s" % (e.resp.status, e.content)
Have you tried using
your_string = raw_input('Enter your string here: ')
Then you would be able to type your string in the console running your start.py

Youtube API commentThreads.update return 400 error when replying to topLevelComment

Reporting a possible bug on Youtube Api commentThreads.update
Name of API affected: CommentThreads: update
Issue summary: CommentThreads: update When calling this api to update the topLevelComment returned by CommentThreads.list, I got a 400 error. I was using this API in an internal tool to allow me respond to comments. It was working fine for the last months... and in the last days (~2016-11-07) with no changes on any code on my side, the API started to return a 400 error. I have all my internal comment systems halted right now as I could not figure out how to fix this. Every thing I tried and tested brings me to the 400 error and the message below.
"While this can be a transient error, it usually indicates that the requests input is invalid."
Even using the API console, I got the same errror!
My bet? This is a transient error that I hope Google can fix.
Steps to reproduce issue:
Retrieve "heldForReview" threads using CommentThreads.list
Try to update the returned topLevelComment changing ["topLevelComment"]["snippet"]["textOriginal"] = "some text". Optionally, change the "moderationStatus" to "published". The error is the same.
This behaviour can be easily spotted using the Python API samples, specifically the file comment_threads.py from https://github.com/youtube/api-samples/blob/master/python/comment_threads.py
Expected output: The top level comment from Thread should become visible (after setting the moderationStatus to published) and have the "some text" as the first child comment as its answer.
Actual results:
{
"error": {
"errors": [
{
"domain": "youtube.commentThread",
"reason": "processingFailure",
"message": "The API server failed to successfully process the request. While this can be a transient error, it usually indicates that the requests input is invalid. Check the structure of the \u003ccode\u003ecommentThread\u003c/code\u003e resource in the request body to ensure that it is valid.",
"locationType": "other",
"location": "body"
}
],
"code": 400,
"message": "The API server failed to successfully process the request. While this can be a transient error, it usually indicates that the requests input is invalid. Check the structure of the \u003ccode\u003ecommentThread\u003c/code\u003e resource in the request body to ensure that it is valid."
}
}
Notes: I am providing a sample code below.
#!/usr/bin/python
# Usage example:
# python comment_threads.py --channelid='<channel_id>' --videoid='<video_id>' --text='<text>'
import httplib2
import os
import sys
from apiclient.discovery import build_from_document
from apiclient.errors import HttpError
from oauth2client.client import flow_from_clientsecrets
from oauth2client.file import Storage
from oauth2client.tools import argparser, run_flow
# The CLIENT_SECRETS_FILE variable specifies the name of a file that contains
# the OAuth 2.0 information for this application, including its client_id and
# client_secret. You can acquire an OAuth 2.0 client ID and client secret from
# the {{ Google Cloud Console }} at
# {{ https://cloud.google.com/console }}.
# Please ensure that you have enabled the YouTube Data API for your project.
# For more information about using OAuth2 to access the YouTube Data API, see:
# https://developers.google.com/youtube/v3/guides/authentication
# For more information about the client_secrets.json file format, see:
# https://developers.google.com/api-client-library/python/guide/aaa_client_secrets
CLIENT_SECRETS_FILE = "client_secrets.json"
# This OAuth 2.0 access scope allows for full read/write access to the
# authenticated user's account and requires requests to use an SSL connection.
YOUTUBE_READ_WRITE_SSL_SCOPE = "https://www.googleapis.com/auth/youtube.force-ssl"
YOUTUBE_API_SERVICE_NAME = "youtube"
YOUTUBE_API_VERSION = "v3"
# This variable defines a message to display if the CLIENT_SECRETS_FILE is
# missing.
MISSING_CLIENT_SECRETS_MESSAGE = """
WARNING: Please configure OAuth 2.0
To make this sample run you will need to populate the client_secrets.json file
found at:
%s
with information from the APIs Console
https://console.developers.google.com
For more information about the client_secrets.json file format, please visit:
https://developers.google.com/api-client-library/python/guide/aaa_client_secrets
""" % os.path.abspath(os.path.join(os.path.dirname(__file__),CLIENT_SECRETS_FILE))
# Authorize the request and store authorization credentials.
def get_authenticated_service(args):
flow = flow_from_clientsecrets(CLIENT_SECRETS_FILE, scope=YOUTUBE_READ_WRITE_SSL_SCOPE,message=MISSING_CLIENT_SECRETS_MESSAGE)
storage = Storage("%s-oauth2.json" % sys.argv[0])
credentials = storage.get()
if credentials is None or credentials.invalid:
credentials = run_flow(flow, storage, args)
# Trusted testers can download this discovery document from the developers page
# and it should be in the same directory with the code.
with open("youtube-v3-discoverydocument.json", "r") as f:
doc = f.read()
return build_from_document(doc, http=credentials.authorize(httplib2.Http()))
# Call the API's commentThreads.list method to list the existing comments.
def get_comments(youtube, video_id, channel_id):
results = youtube.commentThreads().list(
part="snippet",
videoId=video_id,
channelId=channel_id,
# ONLY FILTER COMMENTS THAT ARE HELD FOR REVIEW
# THOSE COMMENTS ONLY HAVE ONE TOP LEVEL COMMENT
moderationStatus="heldForReview",
textFormat="plainText").execute()
for item in results["items"]:
comment = item["snippet"]["topLevelComment"]
author = comment["snippet"]["authorDisplayName"]
text = comment["snippet"]["textDisplay"]
print "Comment by %s: %s" % (author, text)
return results["items"]
# Call the API's commentThreads.insert method to insert a comment.
def insert_comment(youtube, channel_id, video_id, text):
insert_result = youtube.commentThreads().insert(
part="snippet",
body=dict(
snippet=dict(
channelId=channel_id,
videoId=video_id,
topLevelComment=dict(
snippet=dict(
textOriginal=text
)
)
)
)
).execute()
comment = insert_result["snippet"]["topLevelComment"]
author = comment["snippet"]["authorDisplayName"]
text = comment["snippet"]["textDisplay"]
print "Inserted comment for %s: %s" % (author, text)
# Call the API's commentThreads.update method to update an existing comment.
def update_comment(youtube, comment):
comment["snippet"]["topLevelComment"]["snippet"]["textOriginal"] = 'updated'
update_result = youtube.commentThreads().update(
part="snippet",
body=comment
).execute()
comment = update_result["snippet"]["topLevelComment"]
author = comment["snippet"]["authorDisplayName"]
text = comment["snippet"]["textDisplay"]
print "Updated comment for %s: %s" % (author, text)
if __name__ == "__main__":
# The "channelid" option specifies the YouTube channel ID that uniquely
# identifies the channel for which the comment will be inserted.
argparser.add_argument("--channelid",
help="Required; ID for channel for which the comment will be inserted.")
# The "videoid" option specifies the YouTube video ID that uniquely
# identifies the video for which the comment will be inserted.
argparser.add_argument("--videoid",
help="Required; ID for video for which the comment will be inserted.")
# The "text" option specifies the text that will be used as comment.
argparser.add_argument("--text", help="Required; text that will be used as comment.")
args = argparser.parse_args()
if not args.channelid:
exit("Please specify channelid using the --channelid= parameter.")
if not args.videoid:
exit("Please specify videoid using the --videoid= parameter.")
if not args.text:
exit("Please specify text using the --text= parameter.")
youtube = get_authenticated_service(args)
try:
# All the available methods are used in sequence just for the sake of an example.
# Insert channel comment by omitting videoId
# REMOVED AS IT IS NOT RELEVANT TO THE ERRRO REPORT. insert_comment(youtube, args.channelid, None, args.text)
# Insert video comment
# REMOVED AS IT IS NOT RELEVANT TO THE ERRRO REPORT. insert_comment(youtube, args.channelid, args.videoid, args.text)
video_comments = get_comments(youtube, args.videoid, None)
if video_comments:
update_comment(youtube, video_comments[0])
except HttpError, e:
print "An HTTP error %d occurred:\n%s" % (e.resp.status, e.content)
else:
print "Inserted, listed and updated top-level comments."
Of course, you will need your authorization files inside the same directory.

Python: Upload a photo to photobucket

Can a Python script upload a photo to photo bucket and then retrieve the URL for it? Is so how?
I found a script at this link: http://www.democraticunderground.com/discuss/duboard.php?az=view_all&address=240x677
But I just found that confusing.
many thanks,
Phil
Yes, you can. Photobucket has a well-documented API, and someone wrote a wrapper around it.
Download the it and put it into your Python path, then download httplib2 (you can use easy_install or pip for this one).
Then, you have to request a key for the Photobucket API.
If you did everything right, you can write your script now. The Python wrapper is great, but is not documented at all which makes it very difficult to use it. I spent hours on understanding it (compare the question and response time here). As example, the script even has form/multipart support, but I had to read the code to find out how to use it. I had to prefix the filename with a #.
This library is a great example how you should NOT document your code!
I finally got it working, enjoy the script: (it even has oAuth handling!)
import pbapi
import webbrowser
import cPickle
import os
import re
import sys
from xml.etree import ElementTree
__author__ = "leoluk"
###############################################
## CONFIGURATION ##
###############################################
# File in which the oAuth token will be stored
TOKEN_FILE = "token.txt"
IMAGE_PATH = r"D:\Eigene Dateien\Bilder\SC\foo.png"
IMAGE_RECORD = {
"type": 'image',
"uploadfile": '#'+IMAGE_PATH,
"title": "My title", # <---
"description": "My description", # <---
}
ALBUM_NAME = None # default album if None
API_KEY = "149[..]"
API_SECRET = "528[...]"
###############################################
## SCRIPT ##
###############################################
api = pbapi.PbApi(API_KEY, API_SECRET)
api.pb_request.connection.cache = None
# Test if service online
api.reset().ping().post()
result = api.reset().ping().post().response_string
ET = ElementTree.fromstring(result)
if ET.find('status').text != 'OK':
sys.stderr.write("error: Ping failed \n"+result)
sys.exit(-1)
try:
# If there is already a saved oAuth token, no need for a new one
api.username, api.pb_request.oauth_token = cPickle.load(open(TOKEN_FILE))
except (ValueError, KeyError, IOError, TypeError):
# If error, there's no valid oAuth token
# Getting request token
api.reset().login().request().post().load_token_from_response()
# Requesting user permission (you have to login with your account)
webbrowser.open_new_tab(api.login_url)
raw_input("Press Enter when you finished access permission. ")
#Getting oAuth token
api.reset().login().access().post().load_token_from_response()
# This is needed for getting the right subdomain
infos = api.reset().album(api.username).url().get().response_string
ET = ElementTree.fromstring(infos)
if ET.find('status').text != 'OK':
# Remove the invalid oAuth
os.remove(TOKEN_FILE)
# This happend is user deletes the oAuth permission online
sys.stderr.write("error: Permission deleted. Please re-run.")
sys.exit(-1)
# Fresh values for username and subdomain
api.username = ET.find('content/username').text
api.set_subdomain(ET.find('content/subdomain/api').text)
# Default album name
if not ALBUM_NAME:
ALBUM_NAME = api.username
# Debug :-)
print "User: %s" % api.username
# Save the new, valid oAuth token
cPickle.dump((api.username, api.oauth_token), open(TOKEN_FILE, 'w'))
# Posting the image
result = (api.reset().album(ALBUM_NAME).
upload(IMAGE_RECORD).post().response_string)
ET = ElementTree.fromstring(result)
if ET.find('status').text != 'OK':
sys.stderr.write("error: File upload failed \n"+result)
sys.exit(-1)
# Now, as an example what you could do now, open the image in the browser
webbrowser.open_new_tab(ET.find('content/browseurl').text)
Use the python API by Ron White that was written to do just this

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