I have a model with some default entries in a choices field. I was wondering if it was possible for the admin to add and remove entries to the choices from the admin site. The only other option I see at the moment is to have a separate table for the entries, but the spec specifically says to only use one table and I'm fairly new to Django. The current model code is very basic, and I haven't added any forms to admin.py, only registered my model. Example code:
class Contact(models.Model):
#some other fields here...
...
TYPES = (
('op1','option1'),
('op2','option2'),
('op3','option3')
)
option = models.CharField(
max_length=3,
choices=TYPES,
default='op1'
)
I want the super user to be able to click an add/remove type button on the admin page to open a new box which will allow them to edit the possible types.
Turns out I had to make a new model after all. it's fine, the admin site works as it needs to.
Related
Is it possible to create and delete new charfields or textareas through the Django admin page without harcoding them?
For example, I have a simple model, registered in Django admin page
class DocumentList(models.Model):
title = models.CharField(max_length=200)
def __str__(self):
return self.title
Obviously, it has only one charfield on admin page, something like:
DocumentList: [___________]
How can I add another one and delete her later if needed from Django admin page without actually hardcoding another charfield/textarea in models.py, to make it look like:
DocumentList: [___________]
*****************[___________]
Django models are not meant to be dynamically altered. You have to explicitly add the fields on your model, run migrations to have the fields created in your database backend, and reload your server process (./manage.py runserver does this automatically).
If you want to create a model that can hold an arbitrary amount of text strings instead of just one or a fixed amount, you need to use a many-to-many relation to another model.
You can use a custom form in the admin, either by using the form option of the get_form method. This is the documentation example for how you'd pass a custom form:
from django import forms
from django.contrib import admin
from myapp.models import Person
class PersonForm(forms.ModelForm):
class Meta:
model = Person
exclude = ['name']
class PersonAdmin(admin.ModelAdmin):
exclude = ['age']
form = PersonForm
You can add extra fields, as in any form.
I was wondering why you wanted this. Since you said in a comment it is to submit information to an API, you can also use an action, taking input from the user in an intermediate page.
EDIT: As became apparent in comments, the form needs to be dynamic for the user, and not when it is created. Therefore, the solution is using inlines, which once created and linked to the current model, allow the user to add any number of related forms to the current form.
I am designing a Django 1.8 application in which I have the concept of trials and assessors. I will have six assessors, who will use the Django admin to log in and make assessments.
I want each trial to have two attached assessors. How can I use the Django User model in models.py to ensure that the assessors are Users, and can be managed using the full power of Users?
Right now I have this, in which the assessors are not Users, but are just ordinary models:
class Assessor(models.Model):
name = models.CharField(max_length=200)
class Trial(models.Model):
title = models.CharField(max_length=800)
publication_date = models.DateField()
first_assessor = models.ForeignKey(assessor)
second_assessor = models.ForeignKey(assessor)
I want the assessors to be Users, so that I can manage them in the usual way through the User tables, but I don't know how to make this change.
They probably don't need any custom fields on top of the standard User attributes.
(NB: I don't need full-on permissions management within the admin, it's OK for any assessor to be able to edit the trial.)
UPDATE: Apologies, this is rather hard to explain! I don't care about the Django front-end at all, only the admin. I want a user to be able to log into the admin, see all the trials on which they are a primary assessor, and edit those trials. I'm not sure if it's best to do this with the User model, or not.
Instead of two foreign keys add a manytomany relation from Trail to user. Later, if you want you can add more assessors to a trail.
You can do like:
from django.contrib.auth.models import User
class Trial(models.Model):
title = models.CharField(max_length=800)
publication_date = models.DateField()
assessors = models.ManyToManyField(User,related_name="trials")
You can add assessors to Trial like:
trial = Trial.objects.get(id=give-trial-id)
user = User.objects.get(id=give-assessor-id)
trail.assessors.add(user)
You can get more info about manytomany here
I just saw your UPDATE. Any one who logs in to admin will have access to all objects of all models.
In your case all assessors who login to admin will have access to all trails irrespective of they are assigned to it or not.
If you want Filter django admin by logged in user then refer this question
Im working on page with car ads. But I want to let admin extend the page in the future, let him add from django admin site new category of ads - houses for instance.
I know how to let admin create new ad in existing category,
but how to let admin to create new category with new fields (int, str, Boolean)?
Thanx for anwsers.
Create a Category model:
from django.db import models
class Category(models.Model):
name = models.CharField(max_length=30)
This is the advertisement model
class Adv(models.Model):
your fields here
category = models.ForeignKey()
I have an app for adding Schools see the following images for refrence.
when I click on "Add" against Schools following screen follows
after filling in the necessary details click Save and the School is successfully added!
You should be able to do this with any model you created
Unfortunately I can't share the code the company won't allow but I may be able to help you if you pasted your models.py and the corresponding template. You will also need some javascript to do this. If you are trying to do something like this I may be of help.
I'm trying to mimic the functionality from the Django Admin tool where it allows you to add objects for foreign keys (a little plus icon next to a dropdown). For example, let's say I have the following:
class Author(models.Model):
first_name = models.CharField(max_length=100)
last_name = models.CharField(max_length=100)
class Blog(models.Model):
name = models.CharField(max_length=50)
author = models.ForeignKey('Author')
When I go to add my first Blog using a ModelForm for Blog, it shows a dropdown next to Author. However, I have no Authors in the system so that dropdown is empty. In the admin tool, I believe it puts a little "+" icon next to the dropdown so you can quickly and efficiently add a record to the dropdown by opening up a popup.
That is extremely useful, and so I'd like to mimic it in my own app using ModelForms. Is that also built into Django's ModelForms? If so, how do I use it? I can't seem to find anything in the documentation.
You will need to work with: django.contrib.admin.widgets.RelatedFieldWidgetWrapper
This post certainly will guide you:
Django admin - How can I add the green plus sign for Many-to-many Field in custom admin form
hello i'm new in python and django
I need a view that get current user profile I know I shoud use get_profile from User but I don't know how to use it . i read the django document and It didn't help me.
this is what I found from doc:
from django.contrib.auth.models import User
profile=request.user.get_profile()
Django's documentation says it all, specifically the part Storing additional information about users. First you need to define a model somewhere in your models.py with fields for the additional information of the user:
models.py
from django.contrib.auth.models import User
class UserProfile(models.Model):
# This field is required.
user = models.OneToOneField(User)
# Other fields here
accepted_eula = models.BooleanField()
favorite_animal = models.CharField(max_length=20, default="Dragons.")
Then, you need to indicate that this model (UserProfile) is the user profile by setting AUTH_PROFILE_MODULE inside your settings.py:
settings.py
...
AUTH_PROFILE_MODULE = 'accounts.UserProfile'
...
You need to replace accounts with the name of your app. Finally, you want to create a profile every time a User instance is created by registering a post_save handler, this way every time you create a user Django will create his profile too:
models.py
from django.contrib.auth.models import User
class UserProfile(models.Model):
# This field is required.
user = models.OneToOneField(User)
# Other fields here
accepted_eula = models.BooleanField()
favorite_animal = models.CharField(max_length=20, default="Dragons.")
def create_user_profile(sender, instance, created, **kwargs):
if created:
UserProfile.objects.create(user=instance)
post_save.connect(create_user_profile, sender=User)
Accessing the Profile
To access the current user's profile in your view, just use the User instance provided by the request, and call get_profile on it:
def your_view(request):
profile = request.user.get_profile()
...
# Your code
Basically django User models will provide access only for the fields ( firstname,lastname,email,password,is_staff,is_active,last_login).
However if we want to add any extra fields to this model, say we need to add a new column named dateofbirth for every user, then we need to add a column named DOB into User model. But this is not possible as we aren't able to edit django User models.
To achieve this either
1.We can have a separate new table with email id & DOB column, such that a column in User model is mapped with a column in the new table. But this will create a new db instance for every db request. Say if u want to find the DOB of a customer,
First we need to fetch the value of mapped id of a customer from the
User table.
WIth the above value, get DOB from the new table.
In the second method,
Instead of using django User model, use your own customize model with all the fields needed. However if any updation related to security or some enhancement made to django User model we can't use it directly. We need to do more code changes at our end( wherever we use our customize models.) This will be a bit pain for a developer to identify the code & make changes.
To overcome the above issues, django introduce django profile which is very simple and more flexible. The advantages are
Updation/enhancement to the User model can be applied without modifying the code much
No need of creating new db instance to fetch the extra values.
Since the field has onetoone mapping deletion of data from one table will delete others also.
More secure, since we use django models ( no sql injection)
How to Use this:
In settings.py create a variable AUTH_PROFILE_MODULE = "appname.profiletable"
In models.py, create a new table with the fields needed and make sure that the id in User model is onetoone mapped with new table.
create a signal which inserts a row into the new table whenever a new entry is added into User model.
The value in the new table can be accessed using User object itself.
Say, we created a new table extrauser which has DOB, emailid. To find the DOB of a customer, use
a=User.objects.get(email='x#x.xom')
a.get_profile().DOB will give the dateofbirth value from extrauser table.
Hope the above details make you clear in understanding django profile. Incase of any help further, let me know. I have used django profile in my project.
Old question but I thought anyone seeing it today may benefit from this:
Django 1.5 adds the ability to - easily - extend the User model. This may be preferable as you now only got one object to deal with rather than two! Seems the more modern way.
https://hurricanelabs.com/blog/django-user-models/
You need to specify which class is your "Profile" by setting AUTH_PROFILE_MODULE = 'accounts.UserProfile' (for example)
https://docs.djangoproject.com/en/1.4/topics/auth/