Develop Reference

Is commit used on the connect or cursor?

The book named "Practical Programming: 2nd Edition" has conflicting code. This is the start of my code:
import sqlite3
con = sqlite3.connect('stackoverflow.db')
cur = conn.cursor()
To commit, would I use con.commit(), cur.commit() or are there different times to use each? From the book:
con.commit() :
cur.commit() :
Documentation shows con.commit() :

I took unutbu's advice and tried it myself.
Sample code:
import sqlite3
con = sqlite3.connect('db.db')
cur = con.cursor()
data = [('data', 3), ('data2', 69)]
cur.execute('CREATE TABLE Density(Name TEXT, Number INTEGER)')
for i in data:
cur.execute('INSERT INTO Density VALUES (?, ?)', (i[0], i[1]))
cur.commit()
PyCharm Run:
Traceback (most recent call last):
File "/Users/User/Library/Preferences/PyCharmCE2018.1/scratches/scratch_2.py", line 13, in <module>
cur.commit()
AttributeError: 'sqlite3.Cursor' object has no attribute 'commit'
Error in textbook. cur.commit() does not exist.
Thanks unutbu and s3n0

con.commit() and conn.commit() are the same ... they are created object types ... in both cases they are otherwise named ... important is mainly .commit() and not the naming that the programmer has specified
There are object types that use a different name (con and cur - as you asked) to calling the method. You can also use a different name in your code, for example:
db = sqlite3.connect('/tmp/filename.db')
cursor = db.cursor()
cursor.execute("CREATE TABLE ....
.... some DB-API 2.0 commands ....
")
db.commit()
Please check again the webpage https://docs.python.org/3/library/sqlite3.html .
You forgot to copy these two lines from the webpage:
import sqlite3
conn = sqlite3.connect('example.db')
And then continuing the code (just copied it):
c = conn.cursor()
# Create table
c.execute('''CREATE TABLE stocks
(date text, trans text, symbol text, qty real, price real)''')
# Insert a row of data
c.execute("INSERT INTO stocks VALUES ('2006-01-05','BUY','RHAT',100,35.14)")
# Save (commit) the changes
conn.commit()
# We can also close the connection if we are done with it.
# Just be sure any changes have been committed or they will be lost.
conn.close()

I think if you're using a specified cursor to commit changes, in your case, it should be cur.connection.commit().
You can always use connect to commit in the end of your code, whether it's named db, or con or conn.
But when your code gets complicated, you'll have different function to do certain operation to the database, if you only use connection commit, when there is a bug, you gonna have a hard time to find which function failed. So you create specific cursor for specific operation, when that failed, the traceback message will show you which specific cursor when wrong.

To #s3n0 & #DanielYu's point they can be handled two different ways. I had to list these out to better understand the overlap:
Connection Objects
backup
close
commit
create_aggregate
create_collation
create_function
cursor
enable_load_extension
execute
executemany
executescript
in_transaction
interrupt
isolation_level
iterdump
load_extension
rollback
row_factory
set_authorizer
set_progress_handler
set_trace_callback
text_factory
total_changes
Cursor objects
arraysize
close
connection
description
execute
executemany
executescript
fetchall
fetchmany
fetchone
lastrowid
rowcount
setinputsizes
setoutputsize

Storing information in a file, Python

I'm making a car rental console base program in Python where I need to save data about cars I store (such as brand, registration number etc).
What would be the ideal type of file for such a thing, and how to iniciate it?

You can use sqlite3 to store the information.
You can create a table with columns such as brand,registration number etc.
If the registration number is unique to single type of car you can also take care of that condition in sqlite3
syntax is as simple as:
For creating table:
import sqlite3
conn = sqlite3.connect('test.db')
print "Opened database successfully";
conn.execute('''CREATE TABLE COMPANY
(REGISTRATION_NO INT PRIMARY KEY NOT NULL,
BRAND TEXT NOT NULL
);''')
print "Table created successfully";
conn.close()
For insertion:
import sqlite3
conn = sqlite3.connect('test.db')
print "Opened database successfully";
conn.execute("INSERT INTO COMPANY (REGISTRATION_NO,BRAND) \
VALUES (1, 'PAGANI')");
conn.commit()
conn.close()
For more information:
https://docs.python.org/2/library/sqlite3.html

SQL connector using Python

I have a SQL database which I wish to run a query on through python. I have the following code:
sql='select * from mf where frequency=220258.0;'
cur.execute(sql)
Where I use the same select command in sqlite3 directly it works, but through Python no database entries are outputted.
What am I doing wrong?

Consider this SQLite database.
$ sqlite3 so.sqlite3 .dump
PRAGMA foreign_keys=OFF;
BEGIN TRANSACTION;
CREATE TABLE t (f1 integer, f2 text);
INSERT INTO "t" VALUES(1,'foo');
INSERT INTO "t" VALUES(2,'bar');
INSERT INTO "t" VALUES(3,'baz');
COMMIT;
Python connects and queries this database like this.
import sqlite3
con = sqlite3.connect("so.sqlite3")
cur = con.cursor()
cur.execute("select * from t where f1 = 2")
print(cur.fetchone())
Output:
(2, 'bar')
You have to use one of cur.fetchone(), cur.fetchall(), or cur.fetchmany() to get rows from the cursor. Just doing cur.execute() does not return the rows.

Python with SQLite3: select does not display any data

I am writing a very simply database using python and sqlite3. And when I created a table and some data I wanted to display this data using (in terminal) command "Select * From Data", but no data appears, although I checked using other methods that the data is inserted to the table.
How I create my table and data:
db = connect('database.db')
db_cursor = db.cursor()
db_cursor.execute("CREATE TABLE IF NOT EXISTS Data(Id INT, Name TEXT, City TEXT)")
db_cursor.execute("INSERT INTO Data VALUES (1, 'ABC', 'XYZ')")
If I do:
db_cursor.execute("Select * From Data")
print self.db_cursor.fetchall()
the data is displayed.
But when I run a command line and try to do:
sqlite3 database.db
sqlite> .mode column
sqlite> .headers on
sqlite> SELECT * FROM Data;
no data appears. I checked using
sqlite> .tables
that table is generated correctly.
Why sqlite3 run from command line does not display data?

You need to commit your transaction before it is permanently part of the database:
db.commit()
You can use the database connection as a context manager to commit automatically if a block of code executed successfully:
with db:
db_cursor = db.cursor()
db_cursor.execute("INSERT INTO Data VALUES (1, 'ABC', 'XYZ')")
Note that DDL statements (creating tables and other data definitions) are automatically committed, which is why you saw the table in the database, but not the new row.

Python, Sqlite not saving results on the file

I have this code in Python:
conn = sqlite3.connect("people.db")
cursor = conn.cursor()
sql = 'create table if not exists people (id integer, name VARCHAR(255))'
cursor.execute(sql)
conn.commit()
sql = 'insert into people VALUES (3, "test")'
cursor.execute(sql)
conn.commit()
sql = 'insert into people VALUES (5, "test")'
cursor.execute(sql)
conn.commit()
print 'Printing all inserted'
cursor.execute("select * from people")
for row in cursor.fetchall():
print row
cursor.close()
conn.close()
But seems is never saving to the database, there is always the same elements on the db as if it was not saving anything.
On the other side If I try to access the db file via sqlite it I got this error:
Unable to open database "people.db": file is encrypted or is not a database
I found on some other answers to use conn.commit instead of conn.commit() but is not changing the results.
Any idea?

BINGO ! people! I Had the same problem. One of thr reasons where very simple. I`am using debian linux, error was
Unable to open database "people.db": file is encrypted or is not a database
database file was in the same dir than my python script
connect line was
conn = sqlite3.connect('./testcases.db')
I changed this
conn = sqlite3.connect('testcases.db')
! No dot and slash.
Error Fixed. All works
If someone think it is usefull, you`re welcome

This seems to work alright for me ("In database" increases on each run):
import random, sqlite3
conn = sqlite3.connect("people.db")
cursor = conn.cursor()
sql = 'create table if not exists people (id integer, name VARCHAR(255))'
cursor.execute(sql)
for x in xrange(5):
cursor.execute('insert into people VALUES (?, "test")', (random.randint(1, 10000),))
conn.commit()
cursor.execute("select count(*) from people")
print "In database:", cursor.fetchone()[0]

You should commit after making changes i.e:
myDatabase.commit()

can you open the db with a tool like sqlite administrator ? this would proove thedb-format is ok.
if i search for that error the solutions point to version issues between sqlite and the db-driver used. maybe you can chrck your versions or AKX could post the working combination.
regards,khz