Rock Paper Scissors Program Not Working (Python) - python

Problems:
Program does not seem to accept the integers entered. Won't add to win/loss/draw count and does not display computer choice in debug mode
Basics Design of the Program:
Write a program that lets the user play the game of Rock, Paper, Scissors against the computer.
The program should work as follows.
A menu is displayed:
Score: 0 wins, 0 draws, 0 losses
(D)ebug to show computer's choice
(N)ew game
(Q)uit
If the user enters "Q" or "q" the program would end. "N" or "n" for a new game, "D" or "d" for debug mode, anything else would cause an error message to be displayed.
When a game begins, a random number in the range of 1 through 3 is generated. If the number is 1, then the computer has chosen rock. If the number is 2, then the computer has chosen paper. If the number is 3, then the computer has chosen scissors. (Don't display the computer's choice yet unless we are in "D"ebug mode.)
The user enters his or her choice of “1-rock”, “2-paper”, or “3-scissors” at the keyboard.
The computer's choice is displayed.
A winner is selected according to the following rules:
• If one player chooses rock and the other player chooses scissors, then rock wins.
(The rock smashes the scissors.)
• If one player chooses scissors and the other player chooses paper, then scissors wins.(Scissors cuts paper.)
• If one player chooses paper and the other player chooses rock, then paper wins.
(Paper wraps rock.)
• If both players make the same choice, the game is a draw.
Your program would keep a running total of the number of wins, loses and draws.
Re-display the menu and repeat the game loop.
My Program:
import random
def main():
continuing = "y"
win = 0
lose = 0
draw = 0
while continuing == "y":
print("Score:", win,"wins,", draw, "draws,", lose,"losses")
print("(D)ebug to show computer's choice")
print("(N)ew game")
print("(Q)uit")
choice = input(" ")
if choice == "n" or choice == "N":
win, draw, lose = playgame(win, draw, lose)
elif choice == "d" or choice == "D":
win, draw, lose = playgame2(win, draw, lose)
elif choice == "q" or choice == "Q":
break
def playgame(win, draw, lose):
computer = random.randint(1,3)
player = input("Enter 1 for Rock, 2 for Paper, or 3 for Scissors: ")
if computer == 1 and player == 2:
Score = "You won"
win += 1
elif computer == 1 and player == 3:
Score = "You lost"
lose += 1
elif computer == 2 and player == 1:
Score = "You lost"
lose += 1
elif computer == 2 and player == 3:
Score = "You won"
win += 1
elif computer == 3 and player == 1:
Score = "You won"
win += 1
elif computer == 3 and player == 2:
Score = "You lost"
lose += 1
elif computer == player:
Score = "Draw"
draw += 1
return (win, draw, lose)
def playgame2(win, draw, lose):
computer = random.randint(1, 3)
player = input("Enter 1 for Rock, 2 for Paper, or 3 for Scissors: ")
if computer == 1 and player == 2:
Score = "You won"
print("Computer chose rock")
win += 1
elif computer == 1 and player == 3:
Score = "You lost"
print("Computer chose rock")
lose += 1
elif computer == 2 and player == 1:
Score = "You lost"
print("Computer chose paper")
lose += 1
elif computer == 2 and player == 3:
Score = "You won"
print("Computer chose paper")
win += 1
elif computer == 3 and player == 1:
Score = "You won"
print("Computer chose scissors")
win += 1
elif computer == 3 and player == 2:
Score = "You lost"
print("Computer chose scissors")
lose += 1
elif computer == player:
Score = "Draw"
print("Computer chose the same as you")
draw += 1
return (win, draw, lose)
main()

I'm no Pythonista, but at a guess, input returns strings, and you'll need to convert to integer before comparing to the computer's int.
I also think you are missing a trick in DRYing up your code - you should be able to have a single playgame method, which takes an additional boolean parameter debugmode, which instead of calling print directly, calls an indirection, e.g.:
def debugPrint(debugString, debugMode)
if debugMode
print(debugString)
Hope this makes sense?

This would work in Python 2.x, but, not in Python 3.x
In Python 3.x, input() returns strings. Thus, the player's input would be of the form "1" or "2" or "3". Since 1 and "1" are different, the program will not execute any of the lines in the if and elif blocks in playgame() and playgame2().
Here is a Python 3.x example:
>>> a = input("Input = ")
Input = 1
>>> print a
SyntaxError: Missing parentheses in call to 'print'
>>> print(a)
1
>>> a
'1'
>>> type(a)
<class 'str'>
Thus, you should use i = int(input("Input = ")) wherever you want an integer input.
However, in Python 2.x, input() will take 1 as 1 itself and not as "1". But, when you want to type a string as an inpu, you will have to give the quotes also. Here is an exxample:
>>> a1 = input("Input = ")
Input = 1
>>> a1
1
>>> type(a1)
<type 'int'>
>>> #I want to input a string now:
>>> a2 = input("Input = ")
Input = string
Traceback (most recent call last):
File "<pyshell#12>", line 1, in <module>
a2 = input("Input = ")
File "<string>", line 1, in <module>
NameError: name 'string' is not defined
>>> a2 = input("Input = ")
Input = "string"
>>> a2
'string'
>>> type(a2)
<type 'str'>
>>> a3 = raw_input("Input = ")
Input = hello
>>> a3
'hello'
>>> type(a3)
<type 'str'>
>>>
In Python 2.x, the raw_input() function takes the input as a string.

Related

Is this correct for rock-paper-scissor game | Python?

The question is :
Make a two-player Rock-Paper-Scissors game. (Hint: Ask for player plays (using input), compare them, print out a message of congratulations to the winner, and ask if the players want to start a new game)
player1 = input("Player 1: ")
player2 = input("Player 2: ")
if player1 == "rock" and player2 == "paper":
print("Player 2 is the winner!!")
elif player1 == "rock" and player2 == "scissor":
print("Player 1 is the winner!!")
elif player1 == "paper" and player2 == "scissor":
print("Player 2 is the winner!!")
elif player1 == player2:
print("It's a tie!!")
After asking if the players want to start a new game, how to restart the code?
You could use a while loop, i.e. something like
play = 'Y'
while play=='Y':
# your original code
play = input("Do you want to play again (Y/N): ")
Also I'd suggest you check that the responses from the user are valid (i.e. what if they type potatoe, in your code nothing will print if one or both players don't respond with rock, scissors or paper. You should also look at the lower() command and convert the answer to lower case for this reason.
options = {"rock" : 0, "paper": 1, "scissors": 2} #correct inputs
ratio = options[player1] - options[player2]
if player1 not in options.keys() and player2 not in options.keys():
return 0 #tie, both inputs wrong
if player1 not in options.keys():
return 2 #Player1 input wrong, Player 2 wins
if player2 not in options.keys():
return 1 #Player2 input wrong, Player 1 wins
if ratio == 0:
return 0 #tie
if ratio == 1 or ratio == -2:
return 1 #Player 1 wins
return 2 #Player 2 wins

Error in rock paper scissors game with Python

I'm trying to create a rock paper scissors game for a class assignment with Python, but I can't get the result out.
The game is supposed to start with the 1) user's input, 2) show what computer randomly chose, 3) the result (You win, You lose, or Tie with how you won or lost), 4) then ask if you want to Play again, and 5) finally escape.
I did succeed on the first 2 parts, but I can't figure out why 3, 4, 5 is not printing...
The result after showing what the computer played(2), it says 'None' then it loops back to (1) getting the input from the user.
Below is the code. Please advise me on how to fix them. Thank you so much!!
import random
while True :
player = input("Enter a number (0 for rock, 1 for paper, 2 for scissors) >>")
RPS = [0,1,2]
computer = random.choics(RPS)
RPS_dict = {0:'Rock', 1:'Paper', 2:'Scissors'}
print("The computer played", RPC_dict.get(computer))
def game(player, computer):
RPS_dict = {0:'Rock', 1:'Paper', 2:'Scissors'}
if player == computer:
print("Tie!")
elif player == 0:
if computer == 1:
print("You lose!", RPS_dict.get(computer), 'covers', RPS_dict.get(player))
else:
print("You win!", RPS_dict.get(player), 'cut', RPS_dict.get(computer))
elif player == 1:
if computer == 2:
print("You lose!", RPS_dict.get(computer), 'cut', RPS_dict.get(player))
else:
print("You win!", RPS_dict.get(player), 'covers', RPS_dict.get(computer))
game(player, computer)
print(game(player, computer))
again = input("Play again? 0 for no, 1 for yes\n")
Your function should be outside your while loop and you don't need to call it within a print statement...
import random
def game(player, computer):
if player == computer:
print('game tied')
else:
if (player == 1 and computer == 3) or (player == 2 and computer == 1) or (player == 3 and computer == 2):
print('you win')
else:
print('computer wins')
def choice(x):
y = None
if x == 1:
y = 'rock'
elif x == 2:
y = 'paper'
elif x == 3:
y = 'scissors'
return y
playing = True
while playing == True:
player_input = int(input("Enter 1 for rock, 2 for paper, 3 for scissors"))
print('You chose:'+ choice(player_input))
computer_input = random.choice([1,2,3])
print('Computer chose:'+ choice(computer_input))
game(player_input, computer_input)
restart = int(input("Enter 1 to play again or 2 to quit"))
if restart == 2:
playing = False

Rock paper scissors, skipping a result

import random
for i in range(3):
user = str(input("Please enter your choice: "))
if (random.randrange(3)) == 0 :
print("Computer chooses Rock")
if user == "scissors" :
print("computer wins")
elif user == "paper" :
print("player wins")
else :
print("tie")
elif (random.randrange(3)) == 1 :
print("Computer chooses Paper")
if user == "rock" :
print("computer wins")
elif user == "scissors" :
print("player wins")
else :
print("tie")
elif (random.randrange(3)) == 2 :
print("Computer chooses Scissors")
if user == "paper" :
print("computer wins")
elif user == "rock" :
print("player wins")
else :
print("tie")
The formatting is a bit weird on here (havent used this website before). I dont know the reason but i dont know why this code sometimes skips a result. if anyone could help that would be great.
This is what is produced when it is run a couple of times
enter your choice: scissors
Computer chooses Rock
computer wins
enter your choice: scissors
Computer chooses Scissors
tie
enter your choice: scissors
Computer chooses Rock
computer wins
================================ RESTART ================================
Please enter your choice: scissors
Please enter your choice: rock
Computer chooses Rock
tie
Please enter your choice: rock
Computer chooses Rock
tie
I dont understand why it skips a result. Seems to happen randomly
you should not use random.randrange(3) three times. This may e.g. give you the following numbers: 1, 2 and then 0. So the code which is then executed would be:
if (1 == 0):
...
elif (2 == 1):
...
elif (0 == 2):
...
and none of the conditional blocks of the if statements would be executed.
Instead do something like this:
computerChoice = random.randrange(3)
...
if computerCoice == 0:
...
elif computerChoice == 1:
...
elif computerChoice == 2:
...
else
raise Exception("something is definitively wrong here")
you have used random.randrange(3) multiple times and each time there is a possibility of it being a different number.. So i would suggest you assign the value to a variable and then use that in your if statements:
x = random.randrange(3)
I see that you've accepted the excellent answer of Andre, that takes you to understand clearly your error. As I commented your Q saying that there are simpler ways to award a hand, here it is my take
import random
c = random.randrange(3)
u = int(input('1=scissors, 2=paper, 3=rock: '))-1
if u==c:
print '... tie ...'
elif (u==0 and c==1) or (u==1 and c==2) or (u==2 and c==0):
print 'User wins!'
else:
print 'Computer wins... Booh!'
but I'm not sure if it is simpler... shorter for sure it is, but simpler?
One can make it even shorter
import random
def hand():
c = random.randrange(3)
u = int(input('1=scissors, 2=paper, 3=rock: '))-1
print "User played",['scissors,', 'paper,', 'rock,'][u],
print "computer played",['scissors.', 'paper.', 'rock.'][c]
print ['Tie.', 'User wins!', 'Computer wins...'][(c-u)%3]
This is an example session:
>>> hand()
1=scissors, 2=paper, 3=rock: 3
User played rock, computer played scissors.
User wins!
>>>
Yes, it is happening randomly. :)
if (random.randrange(3)) == 0 :
# computer "chooses" a random number
elif (random.randrange(3)) == 1 :
# now the computer's choice is a new choice from 0..2
elif (random.randrange(3)) == 2 :
# and now it's different again
Your mistake is here :
if (random.randrange(3)) == 0 :
elif (random.randrange(3)) == 1 :
elif (random.randrange(3)) == 2 :
In the if statement random.randrange(3) will generate a random number if it doesn't match, it will go to elif statement and random.randrange(3) will generate another random number and it may not be the same as the previously generated random number . Some time because of this your code will skip one , two , three or none of the statement .
If you want your code to be good , you should assign the random number to an integer and then use that integer in your answer .
It should be
ran=random.randrange(3)
if ran == 0 :
elif ran == 2 :
elif ran == 3 :

Python rock paper scissors score counter

I am working on a rock paper scissors game. Everything seems to be working well except the win/loss/tie counter. I have looked at some of the other games people have posted on here and I still cannot get mine to work. I feel like I am soooooo close but I just can't get it! thanks for any help guys. this is my first time posting in here so I am sorry if I messed up the formatting.
I edited the code but still cannot get the program to recognize the counter without using global variables. at one point of my editing I managed to get it to count everything as a tie... i dont know how and I lost it somewhere along my editing. lol. -thanks again everyone!
here is what I get when I run the program:
Prepare to battle in a game of paper, rock, scissors!
Please input the correct number according
to the object you want to choose.
Select rock(1), paper(2), or scissors(3): 1
Computer chose PAPER .
You chose ROCK .
You lose!
Play again? Enter 'y' for yes or 'n' for no. y
Prepare to battle in a game of paper, rock, scissors!
Please input the correct number according
to the object you want to choose.
Select rock(1), paper(2), or scissors(3): 2
Computer chose PAPER .
You chose PAPER .
It's a tie!
Play again? Enter 'y' for yes or 'n' for no. y
Prepare to battle in a game of paper, rock, scissors!
Please input the correct number according
to the object you want to choose.
Select rock(1), paper(2), or scissors(3): 3
Computer chose SCISSORS .
You chose SCISSORS .
It's a tie!
Play again? Enter 'y' for yes or 'n' for no. n
Your total wins are 0 .
Your total losses are 0 .
Your total ties are 0 .
#import the library function "random" so that you can use it for computer
#choice
import random
#define main
def main():
#assign win, lose, and tie to zero for tallying
win = 0
lose = 0
tie = 0
#control loop with 'y' variable
play_again = 'y'
#start the game
while play_again == 'y':
#make a welcome message and give directions
print('Prepare to battle in a game of paper, rock, scissors!')
print('Please input the correct number according')
print('to the object you want to choose.')
#Get the player and computers choices and
#assign them to variables
computer_choice = get_computer_choice()
player_choice = get_player_choice()
#print choices
print('Computer chose', computer_choice, '.')
print('You chose', player_choice, '.')
#determine who won
winner_result(computer_choice, player_choice)
#ask the user if they want to play again
play_again = input("Play again? Enter 'y' for yes or 'n' for no. ")
#print results
print('Your total wins are', win, '.')
print('Your total losses are', lose, '.')
print('Your total ties are', tie, '.')
#define computer choice
def get_computer_choice():
#use imported random function from library
choice = random.randint(1,3)
#assign what the computer chose to rock, paper, or scissors
if choice == 1:
choice = 'ROCK'
elif choice == 2:
choice = 'PAPER'
else:
choice = 'SCISSORS'
#return value
return choice
#define player choice
def get_player_choice():
#assign input to variable by prompting user
choice = int(input("Select rock(1), paper(2), or scissors(3): "))
#Detect invalid entry
while choice != 1 and choice != 2 and choice != 3:
print('The valid numbers are rock(type in 1), paper(type in 2),')
print('or scissors(type in 3).')
choice = int(input('Enter a valid number please: '))
#assign what the player chose based on entry
if choice == 1:
choice = 'ROCK'
elif choice == 2:
choice = 'PAPER'
else:
choice = 'SCISSORS'
#return value
return choice
#determine the winner from the variables
def winner_result(computer_choice, player_choice):
#if its a tie, add 1 to tie variable and display message
if computer_choice == player_choice:
result = 'tie'
print("It's a tie!")
#if its a win, add to win tally and display message
elif computer_choice == 'SCISSORS' and player_choice == 'ROCK':
result = 'win'
print('ROCK crushes SCISSORS! You win!')
elif computer_choice == 'PAPER' and player_choice == 'SCISSORS':
result = 'win'
print('SCISSORS cut PAPER! You win!')
elif computer_choice == 'ROCK' and player_choice == 'PAPER':
result = 'win'
print('PAPER covers ROCK! You win!')
#if it does not match any of the win criteria then add 1 to lose and
#display lose message
else:
result = 'lose'
print('You lose!')
def result(winner_result,player_choice, computer_choice):
# accumulate the appropriate winner of game total
if result == 'win':
win += 1
elif result == 'lose':
lose += 1
else:
tie += 1
return result
main()
Your winner_result function returns before it increments the win counters. If you remove all the return statements from it, the counters should be updated. The return statements aren't needed anyway because the if/elif/else structure ensures that only one of the possible outcomes will be executed.
As Junuxx says in a comment, you also need to assign values to the winner_result variable properly, i.e. winner_result = 'win' instead of winner_result == 'win'. I'd also rename the winner_result variable or the function, because it's confusing to have both use the same name.
And the win/lose/tie variables are currently local, which means that main and winner_result will have their own copies of these variables, so main's values will always be zero. What you can do is make them global variables: Assign them to zero in the global scope (outside any function), and add the line global win, lose, tie inside the function winner_result.
Obviously been a few years since this question was answered but it came up while I was looking the same info. Here's my code if anyone is interested.
#! usr/bin/python3
import random
def game():
computer_count = 0
user_count = 0
while True:
base_choice = ['scissors', 'paper', 'rock']
computer_choice = random.choice(base_choice)
user_choice = input('(scissors, paper, rock) Type your choice: ').strip().lower()
print()
computer_wins = 'The computer wins!'
you_win = 'You win!'
print(f'You played {user_choice}, the computer played {computer_choice}')
if user_choice == 'scissors' and computer_choice == 'rock' or \
user_choice == 'paper' and computer_choice == 'scissors' or \
user_choice == 'rock' and computer_choice == 'paper':
print(computer_wins)
computer_count += 1
elif user_choice == 'rock' and computer_choice == 'scissors' or \
user_choice == 'scissors' and computer_choice == 'paper' or \
user_choice == 'paper' and computer_choice == 'rock':
print(you_win)
user_count += 1
else:
if user_choice == computer_choice:
print('Its a draw!')
computer_count += 1
user_count += 1
print(f'Computer: {computer_count} - You: {user_count}')
print()
game()
I was trying to do the same project, and I have found a solution that works well for me.
from random import randint
win_count = 0
lose_count = 0
tie_count = 0
# create a list of play options
t = ["Rock", "Paper", "Scissors"]
# assign a random play to the computer
computer = t[randint(0, 2)]
# set player to false
player = False
print()
print("To stop playing type stop at any time.")
print()
while player == False:
# set player to True
player = input("Rock, Paper or Scissors? ")
if player.lower() == "stop":
print()
print(
f"Thanks for playing! Your final record was {win_count}-{lose_count}-{tie_count}")
print()
break
if player.title() == computer:
print()
print("Tie!")
tie_count += 1
print()
elif player.title() == "Rock":
if computer == "Paper":
print()
print(f"You lose. {computer} covers {player.title()}.")
lose_count += 1
print()
else:
print()
print(f"You win! {player.title()} smashes {computer}.")
win_count += 1
print()
elif player.title() == "Paper":
if computer == "Scissors":
print()
print(f"You lose. {computer} cuts {player.title()}.")
lose_count += 1
print()
else:
print()
print(f"You win!, {player.title()} covers {computer}.")
win_count += 1
print()
elif player.title() == ("Scissors"):
if computer == "Rock":
print()
print(f"You lose. {computer} smashes {player.title()}.")
lose_count += 1
print()
else:
print()
print(f"You win! {player.title()} cuts {computer}.")
win_count += 1
print()
else:
print()
print("Sorry, we couldn't understand that.")
print()
# player was set to True, but we want it to be false to continue loop
print(f"Your record is {win_count}-{lose_count}-{tie_count}")
print()
player = False
computer = t[randint(0, 2)]
This works (kinda)
there are many issues with the code at the top of the page.
Firstly, Scoring doesn't work.
Secondly, nothing is indented meaning that nothing inside of the other def functions will work.
Thirdly, The other def functions are referred to in the first def main statement which causes Python to show an invalid syntax due to Python not knowing the other functions as they were referred to before they were introduced to python.

Rock Paper Scissors in Python

I am trying to write a Python program and I am having a hard time getting my score. I have written it as a value returning function and every time I run the program it seems to skip the step where it retrieves the score unless I include an else statement which it will automatcially jump the the else statement.
I will attach the full code below.
Thank you very much for any help, I'm greatful!
This is also my first time posting in this forum I apologize if I screw something up.
#constants
Rock = 1
Paper = 2
Scissors = 3
#Define the main function
def main():
#set control loop
keep_going = 'Y'
#set counter to zero
computer_wins = 0
player_wins = 0
tie_score = 0
#call display message
display_message()
while keep_going == 'y' or keep_going == 'Y':
play_game()
#prompt user to keep going
keep_going = input('would you like to play again? (Y for Yes): ')
print('The computer won', computer_wins, 'times')
print('The player won', player_wins, 'times')
print('There were', tie_score, 'tie scores')
def play_game():
#get random input
computer = get_random()
#get the players input
play = get_play()
#validate input
if play == '1' or play == '2' or play == '3':
play == True
else:
play == False
print('Error: Invalid Entry')
play = input('Please enter 1 for Rock, 2 for Paper, or 3 for Scissors: ')
if play == computer:
print('Tie Score, Please try again')
tie_score += 1
else:
get_score(computer, play)
print('The computer chose:', computer)
print('The player chose: ', play)
#define display message
def display_message():
print('Welcome to Rock Paper Scissors, a game of chance to see who will')
print('outsmart the other. This game is Man VS Computer.')
print('The program will select a random integer and then ask you for an integer')
print('1 for Rock 2 for paper or 3 for Scissors. The program will then tell')
print('you who won the game.')
print('GOOD LUCK!')
print
print
def get_random():
import random
#generate random int
computer = random.randint(1, 3)
return computer
def get_play():
#prompt user to enter an integer 1, 2, or 3
play = input('Select 1 for Rock, 2 for Paper, or 3 for Scissors: ')
return play
def get_score(computer, play):
if computer == 1 and play == 2:
score = 'player wins'
print('Paper covers Rock, Player Wins')
#player wins
player_wins += 1
elif computer == 1 and play == 3:
score = 'computer wins'
print('Scissors cut Paper, Computer Wins')
#computer wins
computer_wins += 1
elif computer == 2 and play == 1:
score = 'computer wins'
print('Paper covers Rock, Computer Wins')
#computer wins
computer_wins += 1
elif computer == 2 and play == 3:
score = 'player wins'
print('Scissors cut Paper, Player Wins')
#player wins
player_wins += 1
elif computer == 3 and play == 1:
score = 'player wins'
print('Rock smashes Scissors, Player Wins')
#player wins
player_wins += 1
elif computer == 3 and play == 2:
score = 'computer wins'
print('Scissors cut Paper, Computer Wins')
#computer wins
computer_wins += 1
#call main function
main()
There's so much wrong with this, it's hard to know where to start (but don't get discouraged)...
First of all, it looks like (mostly from your use of input vs. raw_input and your parens with your print statements) you're using Python 3, which already is going to limit the amount of help you get. Most people are still using Python 2.6 or 2.7. But with that out of the way...
The main remaining issues addressing your question are:
First: you're using strings for player input (e.g. '1', '2', '3'), and numbers for computer choice (e.g. 1, 2, 3). So you need to compare them as such. In other words, instead of:
if computer == 1 and play == 2:
You would need to say:
if computer == 1 and play == '2':
Second: you're trying to reference one function's variables in another one, and that won't work. If you want your computer_wins, etc. variables to be global, you need to initialize them at the global scope, e.g. right after your "#constants" are declared and before you get into main. Then in any function that uses them, you must say e.g. global computer_wins to indicate they are global and not local.
Once you get these issues addressed, it should work a bit better, but you'll still need to do a lot of cleanup and keep working on it!
Keep at it, and soon it will be natural for you.
I answered your question separately, but just for fun here's a little working Rock, Paper, Scissors game to look at. This one is for Python 2.x and probably won't work in Python 3, but it might be helpful for you or somebody in the future searching for this.
# "Rock, Paper, Scissors" demo for Python 2.x
# by Dan Kamins
import random
ROCK = 1
PAPER = 2
SCISSORS = 3
NAMES = { ROCK: 'Rock', PAPER: 'Paper', SCISSORS: 'Scissors' }
WHAT_BEATS_WHAT = { ROCK: SCISSORS, PAPER: ROCK, SCISSORS: PAPER }
WIN_ACTIONS = { ROCK: 'crushes', PAPER: 'smothers', SCISSORS: 'cuts' }
score_player = 0
score_computer = 0
score_ties = 0
def main():
intro()
while main_loop():
pass
summary()
def intro():
print "Welcome to Rock, Paper, Scissors!"
def main_loop():
player = get_player_input()
computer = random.randint(1, 3)
check_result(player, computer)
return ask_play_again()
def check_result(player, computer):
global score_player, score_computer, score_ties
if player == computer:
print "Tie! Computer also chose {0}.".format(NAMES[computer])
score_ties += 1
else:
if WHAT_BEATS_WHAT[player] == computer:
print "Your massive {0} {1} the computer's {2}!".format(
NAMES[player], WIN_ACTIONS[player], NAMES[computer])
score_player += 1
else:
print "The computer's {0} {1} your pathetic {2}!".format(
NAMES[computer], WIN_ACTIONS[computer], NAMES[player])
score_computer += 1
def ask_play_again():
again = raw_input("Enter Y to play again: ")
return again in ('y', 'Y')
def get_player_input():
while True:
print
player = raw_input("Enter 1 for Rock 2 for paper or 3 for Scissors: ")
try:
player = int(player)
if player in (1,2,3):
return player
except ValueError:
pass
print "Please enter a number from 1 to 3."
def summary():
global score_player, score_computer, score_ties
print "Thanks for playing."
print "Player won: ", score_player
print "Computer won: ", score_computer
print "Ties: ", score_ties
if __name__ == '__main__':
main()
A couple quick notes from quickly skimming the code:
In get_score() you could add an else clause to handle any ties that happen and you wouldn't have to check for it explicitly in play_game()
Move the import random to the top of the file. imports are generally always found at the top of the file. Also, there's no need to re-import every time you want a random number.
Not sure if this is a typo, cause play seems to always hold an integer, but you have play == True and play == False inside play_game(). If you want to make play contain either True or False, you need to be using a single equals sign, eg, play = True. But this doesn't seem to make sense because you're comparing play to computer as if they're integers.
Also, what are you trying to accomplish with the score variable in the get_score() method?
Ah, if you made the get_score() method return something so you know who won the match it would be helpful. You can't access computer_wins or player_wins inside the get_score() method because they were defined inside main(). A simple way to do this is return an int from get_score(). here is a rather C-style way of handling it (returning -1/0/1). something like (pseudo code):
def get_score():
score = 0
if computer wins:
score = -1
elif player wins:
score = 1
return score
winner = get_score()
if winner == 0:
print 'tie game'
elif winner == 1
print 'the player won'
else:
print 'the computer won'
Here's another variant that works both in Python 2.x and 3.x:
try: input = raw_input
except NameError: input = input # py3k
import random
import sys
import textwrap
from collections import namedtuple
ROCK, PAPER, SCISSORS = ROCK_PAPER_SCISSORS = range(1, 4)
NAME = dict(zip(ROCK_PAPER_SCISSORS, "Rock Paper Scissors".split()))
Score = namedtuple('Score', 'win verb')
GAME_MATRIX = { # who wins and who does what
(PAPER, ROCK): Score(win=True, verb='covers'),
(SCISSORS, PAPER): Score(win=True, verb='cut'),
(ROCK, SCISSORS): Score(win=True, verb='smashes'),
}
GAME_MATRIX.update(dict(((second, first), Score(not win, verb))
for (first,second), (win,verb) in GAME_MATRIX.items()))
def main():
# keep scores: how many times computer, player win and number of ties
scores = dict(zip("computer player tie".split(), [0]*3))
display_welcome_message()
# set control loop
keep_going = 'Y'
while keep_going.upper() == 'Y':
try: play_game(scores)
except Exception as e:
print("Error: %s" % (e,))
sys.exit(1)
# prompt player to keep going
keep_going = input('Would you like to play again? (Y for Yes): ')
print('\nThe computer won {computer} times\n'
'The player won {player} times\n'
'There were {tie} tie scores'.format(**scores))
def play_game(scores):
# get players choices for this round
computer_choice = random.choice(ROCK_PAPER_SCISSORS)
player_choice = get_player_input()
# print choices
for player, choice in [('computer', computer_choice),
('player', player_choice)]:
print('The {0} chose: {1} ({2})'.format(player, NAME[choice], choice))
# update scores; print who wins
if player_choice == computer_choice:
scores['tie'] += 1
print('Tie Score, Please try again')
else:
score = GAME_MATRIX[computer_choice, player_choice]
if score.win: # computer wins
scores['computer'] += 1
template = '{first} {verb} {second}, Computer wins'
else: # player wins
scores['player'] += 1
template = '{second} {verb} {first}, Player wins'
print(template.format(first=NAME[computer_choice],
second=NAME[player_choice], verb=score.verb))
def display_welcome_message():
print(textwrap.fill(textwrap.dedent("""
Welcome to Rock Paper Scissors, a game of chance to see who
will outsmart the other. This game is Man VS Computer. The
program will select a random integer and then ask you to input
%s for Rock %s for Paper or %s for Scissors. The program will
then tell you who won the game. GOOD LUCK!
""" % tuple(ROCK_PAPER_SCISSORS))))
def get_player_input(ntries=10):
for _ in range(ntries):
try:
choice = int(input('\nSelect %s for Rock, %s for Paper, or '
'%s for Scissors: ' % tuple(ROCK_PAPER_SCISSORS)))
except ValueError:
pass
else:
if choice in ROCK_PAPER_SCISSORS:
return choice # success
print('Error: your choice must be one of: %s' % (
', '.join(map(str, ROCK_PAPER_SCISSORS))))
raise RuntimeError('failed to get player choice in %d tries' % ntries)
if __name__=="__main__":
main()
This code might be a good reference for you. :)
Good Luck !
Note that this is Py2.x code
# Author: Niklas Rosenstein
# Created: 2011/10/23
import sys
import random
PAPER = 0
ROCK = 1
SCISSOR = 2
WIN = 10
LOSS = 11
TIE = 12
TABLE = {
PAPER: 'Paper',
ROCK: 'Rock',
SCISSOR: 'Scissor',
}
if 'expand TABLE':
# just for overvieability
# expands the TABLE conveniently
tableExpand = [
(PAPER,('paper', 'p', '0')),
(ROCK, ('rock', 'r', 'stone', '1')),
(SCISSOR, ('scissor', 's', '2'))
]
exp = None
key = None
for exp in tableExpand:
for key in exp[1]:
TABLE[key] = exp[0]
del tableExpand, exp, key
class Game(object):
wins = 0
losses = 0
ties = 0
def evaluateInput(self, inp):
# evaluate the input
# raises ValueError if input is invalid
# lowercase the string
inp = inp.strip()
inp = inp.lower()
# comparison table
try:
return TABLE[inp]
except KeyError:
raise ValueError, 'Input is invalid.'
def choose(self, choice):
# make a choice and compare it with
# the computers choice
# check if the choice is correct
if choice not in [ROCK, PAPER, SCISSOR]:
raise ValueError, 'Expected Id of either ROCK, PAPER or SCISSOR'
# generate a choice for the computer
com = random.choice([ROCK, PAPER, SCISSOR])
result = choice - com
if result == 0:
self.ties += 1
return TIE, com
elif result < 0:
self.wins += 1
return WIN, com
else:
self.losses += 1
return LOSS, com
TEXT_CHOOSE = 'Choose (or "quit" to quit): '
TEXT_PLAYER_CHOOSE = "You've choosen: "
TEXT_COMPUTER_CHOOSE = 'The computer choosed: '
TEXT_CHOICE_INVALID = 'You choice is invalid.\n'
TEXT_WIN = "You've won this match."
TEXT_LOSS = "You've lost this match."
TEXT_TIE = "This match was tie."
TEXT_GOODBYE = "Thanks for playing."
TEXT_WELCOME = "Welcome to Rock-Paper-Scissor !\n" \
"This game is all about guessing. Try to choose the\n" \
"thing that beats the computers choice. Thereby, the\n" \
"following rules are importan:\n" \
" Paper beats Rock.\n" \
" Rock beats Scissor.\n" \
" Scissor beats Paper.\n" \
"\n" \
"Valid inputs are:\n\n" \
" | for Paper: | p | paper | - | 0 |\n" \
" | for Rock: | r | rock | stone | 1 |\n" \
" | for Scissor: | s | scissor | - | 2 |\n" \
" | To quit the game: | q | quit | - | - |\n" \
"\n" \
"Much fun whishes you: Niklas Rosenstein (2011)\n" \
+ ("-" * 50) + "\n"
def printScores(g):
print "Scores:"
print " Wins: %s" % g.wins
print " Losses: %s" % g.losses
print " Ties: %s" % g.ties
def main():
g = Game()
# play the game ;-)
print TEXT_WELCOME
while True:
inp = raw_input(TEXT_CHOOSE)
if inp.lower() in ('q', 'quit'):
break
try:
inp = g.evaluateInput(inp)
except ValueError:
print TEXT_CHOICE_INVALID
continue
t, com = g.choose(inp)
inp = TABLE[inp]
com = TABLE[com]
print TEXT_PLAYER_CHOOSE, inp
print TEXT_COMPUTER_CHOOSE, com
print
if t == WIN:
print inp, "beats", com + ".",
print TEXT_WIN
elif t == LOSS:
print com, "beats", inp + ".",
print TEXT_LOSS
else:
print inp, "euqals", com + ".",
print TEXT_TIE
print
printScores(g)
print "-" * 50
print
print TEXT_GOODBYE
printScores(g)
print
print "Press any key to exit."
sys.stdin.read(1)
main()
Here is another way to do it:
import random;
print ('Game of chance 1=Rock,2=Paper,3=Scissor');
print ('Type 9 to exit');
while 1:
z=random.randint(1,3);
a=int(input('1=Rock,2=Paper,3=Scissor:--->'));
if a==z:
print ('Tie!!!');
if a==1 and z==2:
print ('Rock covers paper So You Win!!!');
if a==2 and z==3:
print ('Scissor cuts paper so you loose :(');
if a==2 and z==1:
print ('Rock covers paper so you loose :(');
if a==3 and z==2:
print ('Scissor cuts paper So You Win!!!');
if a==9:
break
print ('Thanks for playing the game')
Another way of making Rock, Paper, Scissors but without looping is this...
import random
Rock = '1'
Paper = '2'
Scissors = '3'
print('Welcome to Rock, Paper Scissors! The game of all kids to decide on something. \nIn this game you will have to beat the computer once. \n(Psst if it\'s a draw the start the program again! ;D)\nSo how to play. Well, it\'s simple. Pick 1 for Rock, 2 for Paper and 3 for Scissors. \nSo Rock beats Scissors. Scissors cuts Paper and Paper covers Rock. Got it Lets play')
player=int(input('Please enter number 1 = Rock, 2 = Paper, 3 = Scissors: '))
if player<1 or player>3:
player=int(input('Invalid number. Please enter number 1 = Rock, 2 = Paper, 3 = Scissors: '))
if player<1 or player>3:
print('Well, now you can\'t play this game because you are mucking around. Next time DON\'T!')
else:
computer=random.randint(1, 3)
print(player,computer)
print('Remember Rock = 1, Paper = 2 and Scissors = 3')
if player==1 and computer==1 or player==2 and computer==2 or player==3 and computer==3:
print('It\'s a draw. =l Restart the game if you want to.')
if player==1 and computer==2 or player==2 and computer==3 or player==3 and computer==1:
print('Computer wins! You lose. Sorry. =(')
if player==1 and computer==3 or player==2 and computer==1 or player==3 and computer==2:
print('You have won. Well done. =D')
If that is any help.
Yet another way, adding Lizard and Spock
import random
def winner(p1, p2):
actors = ['Paper', 'Scissors', 'Spock', 'Lizard', 'Rock']
verbs = {'RoLi':'crushes', 'RoSc':'breaks', 'LiSp':'poisons',
'LiPa':'eats', 'SpSc':'smashes', 'SpRo':'vaporizes',
'ScPa':'cut', 'ScLi':'decapitate', 'PaRo':'covers',
'PaSp':'disproves'}
p1, p2 = actors.index(p1), actors.index(p2)
winner, looser = [(p1, p2), (p1, p2), (p2, p1), (p1, p2), (p2, p1)][p1 - p2]
return ' '.join([actors[winner],
verbs.get(actors[winner][0:2] + actors[looser][0:2],
'ties'),
actors[looser]])
more = True
while more:
z=random.randint(0,4);
a=int(input('1=Rock, 2=Paper, 3=Scissors, 4=Lizard, 5=Spock:--->'))-1;
if a==z:
print 'Tie\n';
else:
try:
print winner(a,z) + '\n'
except IndexError:
more = False
print ('Thanks for playing the game')
Output:
1=Rock, 2=Paper, 3=Scissors, 4=Lizard, 5=Spock:--->1
Rock crushes Lizard
1=Rock, 2=Paper, 3=Scissors, 4=Lizard, 5=Spock:--->2
Paper covers Rock
1=Rock, 2=Paper, 3=Scissors, 4=Lizard, 5=Spock:--->3
Scissors tie Scissors
1=Rock, 2=Paper, 3=Scissors, 4=Lizard, 5=Spock:--->4
Lizard poisons Spock
well... I would use a dictionary. If/elif/else statements work fine, but they are often messy. This is how I would approach it.
By the way, I am using Python 2. It seems like you are using Python 3 based on the way you use print and input. Don't copy off this code; just take the idea. I am using Python 2 because I am more comfortable with it; make the changes from both versions.
# Imports
import random
# Constants
SELECTION = ["rock", "paper", "scissors"]
WIN = -1 # This is a dummy assignment: we will return this value later.
WIN_LOSE_DICT = {("rock", "paper"): False,
("paper", "rock"): True,
("paper", "scissors"): False,
("scissors", "paper"): True,
("scissors", "rock"): False,
("rock", "scissors"): True}
# Variables
total_wins = 0
# Functions
def do_round():
comp = random.choice(SELECTION)
player = raw_input("Rock, paper, scissors, SHOOT! ").lower() # Set player response
# to lowercase
# Use input() on Python 3 and not raw_input()
while player not in SELECTION:
player = raw_input("Please choose either rock, paper, or scissors. ").lower()
if player == comp:
print "The computer chose %s: it is a tie." % comp
else:
result = WIN_LOSE_DICT[(player, comp)]
if result: # If you want to be clear, do - if result == True:
print "The computer chose %s: you win!" % comp
return WIN
else:
print "The computer chose %s: you lose" % comp
# Main
if __name__ == "__main__":
running = True
while running:
this_round = do_round()
if this_round == WIN:
total_wins += 1
print "You won %s times so far." % total_wins
continue_ = raw_input("Do you want to play another round (y/n) ?").lower()
if continue_ == "n":
continue
else:
running = False
print "Thank you for playing!"
I might have made a few mistakes here and there, but the concept is still there: use a dictionary and set a constant to be a negative number. You should also work on following PEP8 a bit more.
import random
lst=['rock','scisor','paper']
player_score=0
comp_score=0
print('''Welcome to the game of our childhood Rock, Paper and scisor.
play this game against the computer.You must input the
rock,paper,scisor .So let's start the game.''')
def new_game():
user_input=input("START A NEW GAME![Y/N]: \n")
if user_input.upper()=="Y":
global player_score
player_score=0
global comp_score
comp_score=0
RPS_game()
else:
print("Have a great day ahead!\n")
def again():
user_input=input("WANNA PLAY AGAIN![Y/N]: \n")
if user_input.upper()=="Y":
RPS_game()
else:
print("YOUR FINAL SCORE: ",player_score)
print("COMPUTER'S FINAL CORE: ",comp_score)
if comp_score>player_score:
print("OOPS!YOU LOOSE THE GAME\n")
new_game()
elif comp_score<player_score:
print("GREAT! YOU WON THE GAME\n")
new_game()
else:
print("IT'S A DRAW!\n")
new_game()
def RPS_game():
comp_move=random.choice(lst)
player_move=input("Enter your move: ")
if player_move=='rock' or player_move=='paper' or player_move=='scisor':
print("Computers Move:",comp_move)
if player_move=="rock":
if comp_move=="scisor":
print("YOU WON!")
global player_score
player_score=player_score+1
elif comp_move=="paper":
print("YOU lOOSE!")
global comp_score
comp_score=comp_score+1
elif comp_move=="rock":
print("TRY AGAIN!")
elif player_move=="paper":
if comp_move=="paper":
print("TRY AGAIN!")
elif comp_move=="scisor":
print("YOU lOOSE!")
comp_score=comp_score+1
elif comp_move=="rock":
print("YOU WON!")
player_score+=1
elif player_move=="scisor":
if comp_move=="paper":
print("YOU WON!")
player_score+=1
elif comp_move=="scisor":
print("TRY AGAIN!")
elif comp_move=="rock":
print("YOU LOOSE!")
comp_score=comp_score+1
again()
else:
print('''Enter correct spellings !
as "rock,paper,scisor"''' )
RPS_game()
RPS_game()

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