So I have used matplotlib cookbook to generate the following grayscale gaussian contours:
import numpy as np
from scipy.interpolate import griddata
import matplotlib.pyplot as plt
import numpy.ma as ma
from numpy.random import uniform, seed
from matplotlib import cm
def gauss(x,y,Sigma,mu):
X=np.vstack((x,y)).T
mat_multi=np.dot((X-mu[None,...]).dot(np.linalg.inv(Sigma)),(X-mu[None,...]).T)
return np.diag(np.exp(-1*(mat_multi)))
def plot_countour(x,y,z):
# define grid.
xi = np.linspace(-2.1,2.1,100)
yi = np.linspace(-2.1,2.1,100)
## grid the data.
zi = griddata((x, y), z, (xi[None,:], yi[:,None]), method='cubic')
# contour the gridded data, plotting dots at the randomly spaced data points.
CS = plt.contour(xi,yi,zi,6,linewidths=0.5,colors='k')
#CS = plt.contourf(xi,yi,zi,15,cmap=plt.cm.jet)
CS = plt.contourf(xi,yi,zi,6,cmap=cm.Greys_r)
#plt.colorbar() # draw colorbar
# plot data points.
#plt.scatter(x,y,marker='o',c='b',s=5)
plt.xlim(-2,2)
plt.ylim(-2,2)
plt.title('griddata test (%d points)' % npts)
plt.show()
# make up some randomly distributed data
seed(1234)
npts = 1000
x = uniform(-2,2,npts)
y = uniform(-2,2,npts)
z = gauss(x,y,Sigma=np.asarray([[1.,.5],[0.5,1.]]),mu=np.asarray([0.,0.]))
plot_countour(x,y,z)
However I want the outermost layer to be colourless so I could export the image consisting only of the few circular contours of the Gaussian. Is there any way of manipulating this code to do that?
Try using levels.
def plot_countour(x,y,z):
# define grid.
xi = np.linspace(-2.1, 2.1, 100)
yi = np.linspace(-2.1, 2.1, 100)
## grid the data.
zi = griddata((x, y), z, (xi[None,:], yi[:,None]), method='cubic')
levels = [0.2, 0.4, 0.6, 0.8, 1.0]
# contour the gridded data, plotting dots at the randomly spaced data points.
CS = plt.contour(xi,yi,zi,len(levels),linewidths=0.5,colors='k', levels=levels)
#CS = plt.contourf(xi,yi,zi,15,cmap=plt.cm.jet)
CS = plt.contourf(xi,yi,zi,len(levels),cmap=cm.Greys_r, levels=levels)
plt.colorbar() # draw colorbar
# plot data points.
# plt.scatter(x, y, marker='o', c='b', s=5)
plt.xlim(-2, 2)
plt.ylim(-2, 2)
plt.title('griddata test (%d points)' % npts)
plt.show()
# make up some randomly distributed data
seed(1234)
npts = 1000
x = uniform(-2, 2, npts)
y = uniform(-2, 2, npts)
z = gauss(x, y, Sigma=np.asarray([[1.,.5],[0.5,1.]]), mu=np.asarray([0.,0.]))
plot_countour(x, y, z)
Related
I would like to make a 3d plot of a surface parametrised by a function, and I would like the surface to be of one color (say white) where it is above some value a, and of another color (say black) where it is below a.
Here is the code to generate and plot the surface (the way the surface is generated is not important, it could be a much simpler function):
from __future__ import division
import numpy as np
import time,random
random.seed(-2)
def build_spden(N,M, alpha):
#computes the spectral density in momentum space
sp_den = np.zeros((N,M))
for k1 in prange(-N//2, N//2):
for k2 in prange(-M//2, M//2):
sp_den[k1,k2] = np.abs(2*(np.cos(2*np.pi*k1/N)+np.cos(2*np.pi*k2/M)-2))
sp_den[0,0]=1
return 1/sp_den**(alpha/2)
def gaussian_field(N,M,alpha):
'''Builds a correlated gaussian field on a surface NxM'''
spectral_density = build_spden(N,M, alpha)
# FFT of gaussian noise:
noise_real = np.random.normal(0, 1, size = (N,M))
noise_fourier = np.fft.fft2(noise_real)
# Add correlations by Fourier Filtering Method:
convolution = noise_fourier*np.sqrt(spectral_density)
# Take IFFT and exclude residual complex part
correlated_noise = np.fft.ifft2(convolution).real
# Return normalized field
return correlated_noise * (np.sqrt(N*M)/np.sqrt(np.sum(spectral_density)) )
#PLOT
N = 2**5
alpha = .75
a = -.1985
surf = gaussian_field(N,N,alpha)
import matplotlib.pyplot as plt
from mpl_toolkits.mplot3d import Axes3D
x = np.outer(np.arange(0, N), np.ones(N))
y = x.copy().T # transpose
z = surf
fig = plt.figure()
ax = plt.axes(projection='3d')
ax.plot_surface(x, y, z,alpha=.4) #plot the surface
z2 = a*np.ones((N,N))
ax.plot_surface(x, y, z2, alpha=0.9) #plot a plane z = a.
plt.show()
The output is:
I would therefore like the surface to be white above the plane and black below.
Many thanks !
You can define a custom color map and pass to plot_surface:
from matplotlib.colors import ListedColormap, BoundaryNorm
cmap = ListedColormap(['r', 'b'])
norm = BoundaryNorm([z.min(), a, z.max()], cmap.N)
ax.plot_surface(x, y, z, cmap=cmap, norm=norm, alpha=.4) #plot the surface
z2 = a*np.ones((N,N))
ax.plot_surface(x, y, z2, colalpha=0.9) #plot a plane z = a.
plt.show()
Output:
I'd like to make a triangle plot in matplotlib with a mostly-transparent surface. I'm running the example code at https://matplotlib.org/mpl_examples/mplot3d/trisurf3d_demo.py:
from mpl_toolkits.mplot3d import Axes3D
import matplotlib.pyplot as plt
import numpy as np
n_radii = 8
n_angles = 36
# Make radii and angles spaces (radius r=0 omitted to eliminate duplication).
radii = np.linspace(0.125, 1.0, n_radii)
angles = np.linspace(0, 2*np.pi, n_angles, endpoint=False)
# Repeat all angles for each radius.
angles = np.repeat(angles[..., np.newaxis], n_radii, axis=1)
# Convert polar (radii, angles) coords to cartesian (x, y) coords.
# (0, 0) is manually added at this stage, so there will be no duplicate
# points in the (x, y) plane.
x = np.append(0, (radii*np.cos(angles)).flatten())
y = np.append(0, (radii*np.sin(angles)).flatten())
# Compute z to make the pringle surface.
z = np.sin(-x*y)
fig = plt.figure()
ax = fig.gca(projection='3d')
ax.plot_trisurf(x, y, z, linewidth=0.2, antialiased=True)
plt.show()
I can set
ax.plot_trisurf(x, y, z, linewidth=0.2, alpha = 0.2, antialiased=True)
to set the opacity to 0.2, but then the lines disappear. Furthermore, when I change the linewidth, even without the alpha, I see no change in the thickness of the lines between the points. How can I have a triangle plot where the faces are mostly transparent and the lines are clearly visible?
I have a set of points (> 1k) in this form:
y,x
173.549,308.176
173.549,313.328
213.26,419.588
Using KDE, i can plot points density with pcolormesh and contourf. This is an example result, plotting points too:
This is the code i used to have the plot:
import matplotlib.pyplot as plt
import matplotlib
import numpy as np
from scipy.stats.kde import gaussian_kde
x, y = np.genfromtxt('terzinoSX.csv', delimiter=',', unpack=True)
y = y[np.logical_not(np.isnan(y))]
x = x[np.logical_not(np.isnan(x))]
k = gaussian_kde(np.vstack([x, y]))
xi, yi = np.mgrid[x.min():x.max():x.size**0.5*1j,y.min():y.max():y.size**0.5*1j]
zi = k(np.vstack([xi.flatten(), yi.flatten()]))
fig = plt.figure(figsize=(7,4))
ax2 = fig.add_subplot(111)
#alpha=0.5 will make the plots semitransparent
#ax1.pcolormesh(yi, xi, zi.reshape(xi.shape), alpha=0.5)
ax2.contourf(yi, xi, zi.reshape(xi.shape), alpha=0.5)
plt.axis('off')
ax2.plot(y,x, "o")
ax2.set_xlim(0, 740)
ax2.set_ylim(515, 0)
#overlay soccer field
im = plt.imread('statszone_football_pitch.png')
ax2.imshow(im, extent=[0, 740, 0, 515], aspect='auto')
fig.savefig('test.png', bbox_inches='tight')
I would like to have one point representing coordinates of most populated zone (middle point for example), like a middle point over the "red" zone. Is it possible in some way?
I solved this by adding these lines that calculate the point in the most populated area:
xy = np.vstack([x,y])
kde = stats.gaussian_kde(xy)
density = kde(xy)
pts = xy.T[np.argmax(density)]
You can use np.argmax to get the coordinates of the maximum. For example:
kde = compute_my_kde() # Returns a two-dimensional array
y, x = np.argmax(kde) # x and y are swapped because matplotlib displays images as a matrix (first index is rows, second index is colums)
plt.imshow(kde) # Show the kde
plt.scatter(x, y) # Show the maximum point
I've collected tweets from twitter now I'm trying to draw the distribution of tweets geographically. To do that, I divide the entire square area into small square and count number of tweets in each square. Finally, I use matplotlib to draw the following figure:
ax.plot_surface(X, Y, Z, rstride=1, cstride=1, alpha=0.3, cmap='Accent')
The problem is that the elevation map is not smooth. I'd like a way to draw smooth curve from the data. One example for that in 2D is when we have a histogram of image, we can draw smooth curve over the distribution as follows:
So my question is that is there a way to draw a smooth surface from the discrete data?
Expanding on my answer, here's what you can get with resampling and smoothing (gaussian_filter())/spline interpolation (RectBivariateSpline). Note that it would be nice of you to provide a template code that plots your graph, but since you haven't, I had to improvise.
import numpy
import matplotlib
matplotlib.use('Agg')
import matplotlib.pyplot as plt
from mpl_toolkits.mplot3d import Axes3D
def plot(name, method):
numpy.random.seed(123)
x = numpy.linspace(0, 50, 51)
X, Y = numpy.meshgrid(x, x)
Z = numpy.zeros((x.size, x.size))
for n in range(50):
i = numpy.random.randint(0, x.size)
j = numpy.random.randint(0, x.size)
Z[i, j] = numpy.abs(numpy.random.normal()) * 1000
fig = plt.figure()
ax = fig.add_subplot(111, projection='3d')
if method == 0:
# regular plot
ax.plot_surface(X, Y, Z, rstride=1, cstride=1, alpha=0.3, cmap='Accent')
else:
# create a finer grid
resample_coeff = 2
Z2 = numpy.repeat(Z, resample_coeff, 0).repeat(resample_coeff, 1)
x2 = numpy.linspace(x[0], x[-1], x.size * resample_coeff)
X2, Y2 = numpy.meshgrid(x2, x2)
if method == 1:
# smoothing
from scipy.ndimage.filters import gaussian_filter
Z2 = gaussian_filter(Z2, 1)
elif method == 2:
# interpolation
from scipy.interpolate import RectBivariateSpline
spline = RectBivariateSpline(
x, x, Z, bbox=[x[0], x[-1], x[0], x[-1]])
Z2 = spline.ev(X2, Y2)
ax.plot_surface(X2, Y2, Z2, rstride=1, cstride=1, alpha=0.3, cmap='Accent')
fig.savefig(name)
if __name__ == '__main__':
plot('t0.png', 0)
plot('t1.png', 1)
plot('t2.png', 2)
Initial graph:
Smoothing:
Interpolation (notice the negative regions; that's polynomial interpolation for you):
I'm looking to plot a heatmap for which I have the value (=heatmap color) z at each couple of spatial x,y coordinates but I want to mark out the z values between [z0,z1] with z0=0.0 and z1=0.4 while some of interpolated z values are under and above those boundaries.
from numpy.random import uniform, seed
from matplotlib.mlab import griddata
import matplotlib.pyplot as plt
import numpy as np
# make up data.
#npts = int(raw_input('enter # of random points to plot:'))
seed(0)
npts = 200
x = uniform(-2, 2, npts)
y = uniform(-2, 2, npts)
z = x*np.exp(-x**2 - y**2)
# define grid.
xi = np.linspace(0, 1, 1000)
yi = np.linspace(0, 1, 1000)
# grid the data.
zi = griddata(x, y, z, xi, yi, interp='linear')
# contour the gridded data, plotting dots at the nonuniform data points.
CS = plt.contourf(xi, yi, zi, 15, cmap=plt.cm.rainbow,
vmax=abs(zi).max(), vmin=-abs(zi).max())
plt.colorbar() # draw colorbar
# plot data points.
plt.show()
I would like to restrict the colorbar and heatmap color from 0.0 to 0.4 (so avoid in the heatmap and in the colorbar valies under 0.0 and above 0.4).
How to do that? Thanks
You can set the values in a numpy array to None to leave them unplotted. For example,
zmin = 0.0
zmax = 0.4
zi[(zi<zmin) | (zi>zmax)] = None
CS = plt.contourf(xi, yi, zi, 15, cmap=plt.cm.rainbow,
vmax=zmax, vmin=zmin)