As part of a piece of python work I have to ask for a first name and surname, then repeat it three times if it is correct. When I try it Python puts a syntax error on the colon. What do I need to do to correct it?
Basically whats going on
I've already tried removing the colon, bringing the if line down to one equals, and looking for bracket errors, but I cant find anything.
The colon should be at the end,
if input == yes:
However I cannot see how this can work? Is that the full code? If so, what is the yes variable?
If it was intended to be a string, the line should be,
if input == "yes":
The "" tells Python that it is a string (a word).
A link to Python syntax: https://en.wikipedia.org/wiki/Python_syntax_and_semantics
I don't know how to explain this so I have included a video showing you what's happening.
https://www.youtube.com/watch?v=XCNl24mpko0&feature=youtu.be
Notice how it says it's trying to load "imagesed shield.png" This is because the baskslash is escaping "r". Putting an "r" at the front will fix it by converting the string to a raw string, as will replacing the backslash with a forward slash, or escaping the backslash itself.
red_shield = pyg.image.load(r'images\red shield.png')
red_shield2 = pyg.image.load('images/red shield.png')
red_shield3 = pyg.image.load('images\\red shield.png')
Edit: I suppose I should mention that I assume this is due to IDLE trying to represent a break character (\r is a break character, hence the answer). I don't really know if it's a real issue in the grand scheme of things.
I've scanned the questions here as well as the web and haven't found my answer, this is my first question and I'm a noobie to (wx)Python so go easy on me.
Using TextCtrl I'm trying to remove a single character within a string, this string will always start with the same set of characters but the rest of the string is freely editable by the user.
e.g
self.text=wx.TextCtrl(panel,-1"hello world,, today we're asking a question on stackoverflow, what would you ask?")
poor example but how would I find and remove the 11th(',') character so the sentence is more formatted without affecting the rest of the string?
I've tried standard python indexing but I get an error for that, I can successfully remove chunks of the string from the start outwards of the end inwards but I need only a single character removed.
Again, sorry for the poor terminology, as I said I'm fairly new to python so some of my terms may be a bit iffy.
self.text.SetValue(self.text.GetValue()[:10] + self.text.GetValue()[11:] )
maybe??
self.text.SetValue(self.text.GetValue().replace(",,",",")
maybe?
its not really clear what you are trying to accomplish here ...
I am working on the letter distribution problem from HP code wars 2012. I keep getting an error message that says "invalid character in identifier". What does this mean and how can it be fixed?
Here is the page with the information.
import string
def text_analyzer(text):
'''The text to be parsed and
the number of occurrences of the letters given back
be. Punctuation marks, and I ignore the EOF
simple. The function is thus very limited.
'''
result = {}
# Processing
for a in string.ascii_lowercase:
result [a] = text.lower (). count (a)
return result
def analysis_result (results):
# I look at the data
keys = analysis.keys ()
values \u200b\u200b= list(analysis.values \u200b\u200b())
values.sort (reverse = True )
# I turn to the dictionary and
# Must avoid that letters will be overwritten
w2 = {}
list = []
for key in keys:
item = w2.get (results [key], 0 )
if item = = 0 :
w2 [analysis results [key]] = [key]
else :
item.append (key)
w2 [analysis results [key]] = item
# We get the keys
keys = list (w2.keys ())
keys.sort (reverse = True )
for key in keys:
list = w2 [key]
liste.sort ()
for a in list:
print (a.upper (), "*" * key)
text = """I have a dream that one day this nation will rise up and live out the true
meaning of its creed: "We hold these truths to be self-evident, that all men
are created equal. "I have a dream that my four little children will one day
live in a nation where they will not be Judged by the color of their skin but
by the content of their character.
# # # """
analysis result = text_analyzer (text)
analysis_results (results)
The error SyntaxError: invalid character in identifier means you have some character in the middle of a variable name, function, etc. that's not a letter, number, or underscore. The actual error message will look something like this:
File "invalchar.py", line 23
values = list(analysis.values ())
^
SyntaxError: invalid character in identifier
That tells you what the actual problem is, so you don't have to guess "where do I have an invalid character"? Well, if you look at that line, you've got a bunch of non-printing garbage characters in there. Take them out, and you'll get past this.
If you want to know what the actual garbage characters are, I copied the offending line from your code and pasted it into a string in a Python interpreter:
>>> s=' values = list(analysis.values ())'
>>> s
' values \u200b\u200b= list(analysis.values \u200b\u200b())'
So, that's \u200b, or ZERO WIDTH SPACE. That explains why you can't see it on the page. Most commonly, you get these because you've copied some formatted (not plain-text) code off a site like StackOverflow or a wiki, or out of a PDF file.
If your editor doesn't give you a way to find and fix those characters, just delete and retype the line.
Of course you've also got at least two IndentationErrors from not indenting things, at least one more SyntaxError from stay spaces (like = = instead of ==) or underscores turned into spaces (like analysis results instead of analysis_results).
The question is, how did you get your code into this state? If you're using something like Microsoft Word as a code editor, that's your problem. Use a text editor. If not… well, whatever the root problem is that caused you to end up with these garbage characters, broken indentation, and extra spaces, fix that, before you try to fix your code.
If your keyboard is set to English US (International) rather than English US the double quotation marks don't work. This is why the single quotation marks worked in your case.
Similar to the previous answers, the problem is some character (possibly invisible) that the Python interpreter doesn't recognize. Because this is often due to copy-pasting code, re-typing the line is one option.
But if you don't want to re-type the line, you can paste your code into this tool or something similar (Google "show unicode characters online"), and it will reveal any non-standard characters. For example,
s=' values = list(analysis.values ())'
becomes
s=' values U+200B U+200B = list(analysis.values U+200B U+200B ())'
You can then delete the non-standard characters from the string.
Carefully see your quotation, is this correct or incorrect! Sometime double quotation doesn’t work properly, it's depend on your keyboard layout.
I got a similar issue. My solution was to change minus character from:
—
to
-
I got that error, when sometimes I type in Chinese language.
When it comes to punctuation marks, you do not notice that you are actually typing the Chinese version, instead of the English version.
The interpreter will give you an error message, but for human eyes, it is hard to notice the difference.
For example, "，" in Chinese; and "," in English.
So be careful with your language setting.
Not sure this is right on but when i copied some code form a paper on using pgmpy and pasted it into the editor under Spyder, i kept getting the "invalid character in identifier" error though it didn't look bad to me. The particular line was grade_cpd = TabularCPD(variable='G',\
For no good reason I replaced the ' with " throughout the code and it worked. Not sure why but it did work
A little bit late but I got the same error and I realized that it was because I copied some code from a PDF. Check the difference between these two:
-
−
The first one is from hitting the minus sign on keyboard and the second is from a latex generated PDF.
This error occurs mainly when copy-pasting the code. Try editing/replacing minus(-), bracket({) symbols.
You don't get a good error message in IDLE if you just Run the module. Try typing an import command from within IDLE shell, and you'll get a much more informative error message. I had the same error and that made all the difference.
(And yes, I'd copied the code from an ebook and it was full of invisible "wrong" characters.)
My solution was to switch my Mac keyboard from Unicode to U.S. English.
it is similar for me as well after copying the code from my email.
def update(self, k=1, step = 2):
if self.start.get() and not self.is_paused.get(): U+A0
x_data.append([i for i in range(0,k,1)][-1])
y = [i for i in range(0,k,step)][-1]
There is additional U+A0 character after checking with the tool as recommended by #Jacob Stern.
I'm getting some content from Twitter API, and I have a little problem, indeed I sometimes get a tweet ending with only one backslash.
More precisely, I'm using simplejson to parse Twitter stream.
How can I escape this backslash ?
From what I have read, such raw string shouldn't exist ...
Even if I add one backslash (with two in fact) I still get an error as I suspected (since I have a odd number of backslashes)
Any idea ?
I can just forget about these tweets too, but I'm still curious about that.
Thanks : )
Prepending the string with r (stands for "raw") will escape all characters inside the string. For example:
print r'\b\n\\'
will output
\b\n\\
Have I understood the question correctly?
I guess you are looking a method similar to stripslashes in PHP. So, here you go:
Python version of PHP's stripslashes
You can try using raw strings by prepending an r (so nothing has to be escaped) to the string or re.escape().
I'm not really sure what you need considering I haven't seen the text of the response. If none of the methods you come up with on your own or get from here work, you may have to forget about those tweets.
Unless you update your question and come back with a real problem, I'm asserting that you don't have an issue except confusion.
You get the string from the Tweeter API, ergo the string does not show up in your code. “Raw strings” exist only in your code, and it is “raw strings” in code that can't end in a backslash.
Consider this:
def some_obscure_api():
"This exists in a library, so you don't know what it does"
return r"hello" + "\\" # addition just for fun
my_string = some_obscure_api()
print(my_string)
See? my_string happily ends in a backslash and your code couldn't care less.