I'm new at Django and I'm creating a small app that has some really simple models but uses custom users. Now I wish to customize the object listing in the administration for some users. What I wish to do is customize the object listing in
myserver/admin/myapp/myobject but I haven't found which should I extend to do so. I'd be thank to know where should I look.
I would take a thorough look through the Django admin documentation. They do a pretty good job at explaining how to customize the list display.
https://docs.djangoproject.com/en/dev/ref/contrib/admin/
I would focus on learning the following,
https://docs.djangoproject.com/en/dev/ref/contrib/admin/#django.contrib.admin.ModelAdmin.list_display
This will alter the fields being shown for each row in the list.
https://docs.djangoproject.com/en/dev/ref/contrib/admin/#django.contrib.admin.ModelAdmin.list_filter
This will allow you to filter your data which is shown within the list.
https://docs.djangoproject.com/en/dev/ref/contrib/admin/#django.contrib.admin.ModelAdmin.search_fields
This will allow you to add a search box which will let you search against the objects within the list.
Related
First sorry for my poor English.
I came from asp.net mvc. Now I use django with nanoboxio
In asp, I can create sections like below.
Create model and add it to dbcontext
Right click controller folder and create new controller with views.
Modify as you wish
For now, I know Django can create admin interface for your model. I try and happy with it. but i want to develop it.
I want to for example;
Create a post model.
Create a admin interface for it.
Copy generated admin interface controller and views to another app
Modify it
How can I do that?
Django's MVC is quite different to ASP.
Django's MVC pattern is less strict so you sort of combine the view and the controller in the views.py. However, if you want to change the Admin, the Django docs are quite nice here: docs.djangoproject.com
If you want to create a custom admin functionality the docs should give you a first idea and if you're planning to create a blog, I would advice you to use an existing plugin such as Zinnia. There, you can find the desired functionalities and modify them instead of building them from scratch.
Also, there are a couple of tutorials on how to build reusable apps and they usually include a detailed guideline how to implement admin functionalities there. Just look it up on google.
I hope that helps you!
I am new to Django. I have read the official documentations and managed to create models in Django. I have a task to create an estimator tool that could provide the estimate(cost) to the user when he selects the hardware/softwares etc. This could be something similar to this http://calculator.s3.amazonaws.com/index.html. This is only for reference but I want to add details dynamically.
Basically I am curious to know about:
How to add rows in Django?
How is the 'Monthly cost' working in amazon calculator?
I want to achieve something similar to this dynamic estimations.
Any pointers/articles/suggestions will be helpful in my learning and analysis.
You have to override the Django admin template for that.
How to add button next to Add User button in Django Admin Site
for auto-selecting the group value you can use
https://github.com/crucialfelix/django-ajax-selects
I've been searching stack overflow and google for a solution for over an hour now, and I can't seem to find something that, in my opinion, should be easy to obtain (as it's a common use case).
I've checked this thread, and a few others, but I haven't been able to find a real, easy solution:
Django modelform: is inline adding related model possible?
Anyway, say I have a model with three related entities, two foreign keys and a many-to-many related class. Now, I have a ModelForm which displays these in comboboxes and lists, but what I need is that "+" button next to these elements (as seen in the admin interface).
I want the plus to take me to a new form, for that particular entity, allow me to submit the new information, create the database entry, take me back to my original form and have the newly added entity selected in the combobox. I'm really hoping the django ModelForm Meta class has an attribute that I can't seem to find which enables exactly this.
This isn't really a django question.
This has to do with presentation of a particular widget in an html document, and that is governed by either the HTML markup, CSS, or javascript.
Django is a server side application and is primarily responsible for creating a valid http response and receiving a valid http request (of course, there is a lot that happens in the interim and that is why django is so big) but it's not a "one toolkit to kill them all" app.
I think you want to look at bootstrap: http://getbootstrap.com/
Jquery UI: http://jqueryui.com/
Or some combination of the two.
You can also just mark up the document yourself with a stock img or something.
However, if you want to do it exactly how the admin does it, just go into django.contrib.admin and examin the code to figure out how the django developers did it. I believe they are just using Jquery UI and some manual markup to accomplish that.
I have been trying to get my head around Django over the last week or two. Its slowly starting to make some sense and I am really liking it.
My goal is to replace a fairly messy excel spreadsheet with a database and frontend for my users. This would involve pulling the data out of a table, presenting it in a web tabular format, and allowing changes to be made through text fields and drop down menus, with a simple update button that will update all changes to the DB.
My question is, will the built in Django Forms functionality be the best solution? Or would I create some sort of for loop for my objects and wrap them around html form syntax in my template? I'm just not too sure how to approach the solution.
Apologies if this seems like an simple question, I just feel like there is maybe a few ways to do it but maybe there is one perfect way.
Thanks
The fastest way not to implement you own pages and to have a tabular view of your data is to use the django's built-in admin interface. It gives you sorting, filtering and search functionality and quick to start. You just need to define your models in models.py and setup the admin pages as described in the docs.
Normally the admin page is not used as a representation to users or customers but in the case you described it seems a clean and quick choice.
Exporting the excel sheet in Django and have the them rendered as text fields , is not as easy as 2 step process.
you need to know how Django works.
First you need to export the data in mysql in database using either some language or some ready made tools.
Then you need to make a Model for that table and then you can use Django admin to edit them
I'm trying to write my own Trac plugin to notify an external system of changes to tickets matching a certain criteria. From my research so far, I've figured out that implementing the ITicketChangeListener interface is the way to go.
The method definitions are all very straight forward, but what's not straight forward for me is the Ticket object and accessing its custom fields. I've learned that you can access default ticket fields as simply as:
# t is a Ticket object
theStatus = t['status']
I've found several sources that say this won't work:
myCustomField = t['my_custom_field']
Yet none of them tell me what will work.
In addition, I need to know if the old_values argument of the ticket_changed() method will have my custom fields or if I'll have to do something different there as well.
I'm fairly new to Python and very new to Trac. Any help to point me in the right direction is appreciated.
The sources are wrong about custom ticket fields. The value-by-name approach should work. And *old_values* contains all fields values, including custom fields too. That's it.
You may want to look at the TracAnnouncer source for some change-listener coding examples.