Develop Reference

Selenium find a element with no class, div, text (Python)

I want to make a automatic google login with selenium but i cannot find the elements, the buttoenter image description heren "Next", because the class
is modified each time when we come to start a browser with selenium, or when we reset the login page and does not have Id, but the button is in a div that includes just this button,
I would like someone to help me find a solution to find how I can use this button in order to click it to skip the page where you have to put your email address to skip to the password
i would like to use css selector
(Google Chrome the browser I use)
I code with Selenium 4.2.0 on Linux Unbuntu

driver.find_element(By.CSS_SELECTOR, 'button[class="VfPpkd-LgbsSe VfPpkd-LgbsSe-OWXEXe-k8QpJ VfPpkd-LgbsSe-OWXEXe-dgl2Hf nCP5yc AjY5Oe DuMIQc LQeN7 qIypjc TrZEUc lw1w4b"]').click()
That will click the 'Next' button on Google login. Good luck getting any further though. Google seems to block logging in on Chromium.

You can either use jsname as an alternative for finding the element
I found a similar question here How can I inspect element in to div with jsname?
I think the person is doing pretty same thing
Hope this helps :)

How to click on an element with Selenium without using Driver.get?

So I am trying to write a code to automatically join a google meet. So I need to sign into my google account, which runs all fine but when I get to "Verify that it's you" (image 1), and I try to use driver.get it takes me back to the original sign-in page (image 2)
How can I click on the "Continue" button without using driver.get/without getting taken back to the original sign-in page. I know that all I have to do is click on the "Continue" because when I do it manually it works perfectly. Pressing "Tab" and then "Enter" would also work, but it seems you need to use driver.get as well. Thank you

so i think you don't understand driver.get() usage. it is used only to make the browser browse to a specific link which you can specify before hand. what you have to do here is open the google meet page manually and go to your required page where you want to click the button. right click on the button and click on inspect. then go to the higlighted code and locate the button you want and right click on copy and select xpath from the list. now coming to your code.
add this line:
element=driver.find_element_by_xpath('_xpath')
element.click()
replace _xpath with the long string you copied (which is the xpath of the button you want to click).
this is the way to click on buttons or text boxes or anything you name it in selenium.
**beware of one thing. don't make your code click immediately. if the page does not fully load and the click is made then the 1st line will throw an element not found error. put some kind of delay till page loads or use a while loop and exception handling to wait till the element is found

This one should work for you
userName = driver.find_element_by_xpath("//button[#name='username']")
driver.execute_script("arguments[0].click();", userName)

How to find the xpath of a web element already located by selenium? [duplicate]

I am trying to find a way to use FireBug for FF. Unfortunately it's not supported for selenium v3.6. What can be done if I have to locate the elements, will "Inspect" element will be sufficient?
If I get down to less version of selenium, will that help?

If you visit the GitHub Page of FirePath, it clearly mentions that :
FirePath is a Firebug extension that adds a development tool to edit, inspect and generate XPath expressions and CSS3 Selectors
Now if you visit the Home Page of FireBug, it clearly mentions that :
The Firebug extension isn't being developed or maintained any longer. We invite you to use the Firefox DevTools instead, which ship with Firebug next.
So the direction is clear that, we have to use Development Tools which comes integrated with the Mozilla Firefox 56.x + release onwards.
Example Usage :
Now, let us assume we have to identify the xpath or cssSelector of the Search Box on Google Home Page https://www.google.com/.
Open Mozilla Firefox or Google Chrome browser and browse to the url https://www.google.co.in
Press F12 or Ctrl+Shift+I to open the Developer Tools
Within the Developer Tools console, with in the Elements tab, once you click on the Inspector and mouse hover the Search Box and the WebElement pertaining to the Search Box gets highlighted within the DOM Tree.
Within the HTML DOM you can right click and on mouse hover over Copy item you can clck on either of the following sub menu item:
Copy selector: To copy the CssSelector (absolute)
Copy XPath: To copy the XPath (absolute)
Snapshot:
Additional Steps
Referring the copied CssSelector or XPath you can also construct a logical unique XPath or a CssSelector.
Testing your own XPath
To test your own written XPath, within the Developer Tools console, click on the Console tab and within the editor paste the logical unique xpath you have constructed in the following format and hit Enter or Return:
$x("//*[#name='q']")
Example:
Testing your own CssSelector
To test your own written CssSelector, within the Developer Tools console, click on the Console tab and within the editor paste the logical unique cssSelector you have constructed in the following format and hit Enter or Return:
$$("[name='q']")
Example:

Inspect element is sufficient if you only want to inspect element.
I found Firepath helpful with testing the locators. Downgrading to Firefox 30 – 54 should be enough. It has nothing to do with Selenium version.
Also you can look at Chropath for Chrome

Try this step in your case and check.
Open A Blank Tab in Firefox
Type about:config in address bar then press enter (click on I accept the risk!)
Find browser.tabs.remote.autostart
Select the option then click the mouse right side
Turn The Option As False
Close the browser for restart browser
Open browser again, inspect the element. I hope It Works Properly.

ChroPath extension for xpath and best replacement for FirePath. It has no dependency on other extension like firepath was dependent on firebug. Just add ChroPath to Chrome browser and use it.
Download link- ChroPath
Features-
gives unique xpath and css selectors
It opens as sidebar tab in devtools panel where you can access DOM, inspect element in left side and write the XPath/CSS in right side.
verify xpath and css selectors
gives the list of matched node
highlight the web element on hover
scroll the hidden element in view area on hover.
ChroPath is the only extension which gives unique CSS selectors for selected or inspected element.

Python/Selenium:Different ways to click this specific button

I am trying to understand Python in general as I just switched over from using VBA. I interested in the possible ways you could approach this single issue. I already went around it by just going to the link directly, but I need to understand and apply here.
from selenium import webdriver
chromedriver = r'C:\Users\dd\Desktop\chromedriver.exe'
browser = webdriver.Chrome(chromedriver)
url = 'https://www.fake.com/'
browser.get(url)
browser.find_element_by_id('txtLoginUserName').send_keys("Hello")
browser.find_element_by_id('txtLoginPassword').send_keys("There")
browser.find_element_by_id('btnLogin').click()
At this point, I am trying to navigate to a particular button/link.
Here is the info from the page/element
T-Mobile
Here are some of the things I tried:
for elem in browser.find_elements_by_xpath("//*[contains(text(), 'T-Mobile')]"):
elem.click
browser.execute_script("InitiateCallBack(187, True, T-Mobile, https://www.fake.com/, TMobile)")
I also attempted to look for tags and use css selector all of which I deleted out of frustration!
Specific questions
How do I utilize the innertext,"T-Mobile", to click the button?
How would I execute the onclick event?
I've tried to read the following links, but still have not succeeded incoming up with a different way. Part of it is probably because I don't understand the specific syntax yet. This is just some of the things I looked at. I spent about 3 hours trying various things before I came here!
selenium python onclick() gives StaleElementReferenceException
http://selenium-python.readthedocs.io/locating-elements.html
Python: Selenium to simulate onclick
https://stackoverflow.com/questions/43531654/simulate-a-onclick-with-selenium-https://stackoverflow.com/questions/45360707/python-selenium-using-onclick
Running javascript in Selenium using Python

How do I utilize the innertext,"T-Mobile", to click the button?
find_elements_by_link_text would be appropriate for this case.
elements = driver.find_elements_by_link_text('T-Mobile')
for elem in elements:
elem.click()
There's also a by_partial_link_text locator as well if you don't have the full exact text.
How would I execute the onclick event?
The simplest way would be to simply call .click() on the element as shown above and the event should, naturally, execute at that time.
Alternatively, you can retrieve the onclick attribute and use driver.execute_script to run the js.
for elem in elements:
script = elem.get_attribute('onlcick')
driver.execute_script(script)
Edit:
note that in your code you did element.click -- this does nothing. element.click() (note the parens) calls the click method.
is there a way to utilize browser.execute_script() for the onclick event
execute_script can fire the equivalent event, but there may be more listeners that you miss by doing this. Using the element click method is the most sound. There may very well be many implementation details of the site that may hinder your automation efforts, but those possibilities are endless. Without seeing the actual context, it's hard to say.
You can use JS methods to click an element or otherwise interact with the page, but you may miss certain event listeners that occur when using the site 'normally'; you want to emulate, more or less, the normal use as closely as possible.

As per the HTML you have shared it's pretty clear the website uses JavaScript. So to click() on the link with text as T-Mobile you have to induce WebDriverWait with expected_conditions clause as element_to_be_clickable and your can use the following code block :
WebDriverWait(driver, 20).until(expected_conditions.element_to_be_clickable((By.XPATH, "//a[contains(.,'T-Mobile')]"))).click()

you can use it
<div class="button c_button s_button" onclick="submitForm('rMTF')" style="margin-bottom: 30px;">
<input class="v_small" type="button"></input>
<span>
Reset
</span>

Clicking JavaScript links in Selenium WebDriver and Python

I am using Selenium Webdriver in Python and I got stuck trying to activate a javascript button.
What I need to do here is to click the Go to Previous Month button twice so that I have August 2014.
And then I need to click on one of the days.
The images below show the code. Please tell me if I need to provide more info.
THIS IS THE "GO TO PREVIOUS MONTH BUTTON" + INSPECT ELEMENT
AND HERE I'VE CLICKED ON THE 1ST OF AUGUST + INSPECT ELEMENT ON "1"
How do I do it?

First find your element with CSS selectors (you need to be familiar how CSS selectors work - this is prerequisite for most web development):
elem = webdriver.find_element_by_css_selector("a[title='Go to previous month']")[0]
Related WebDriver documentantion.
Then when you get your elem (there might paeg loading time, etc. issues you need to deal with) you can click it.
elem.click()
See also: Wait for page load in Selenium
Related click() documentation.