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while loop could not break

there is NameError: name 'user' is not defined
why while loop is not ending please help to find the problem
this program is for dice roll in pyhton
I want to roll the dice with no exception but there are exception accured
rand_num=random.randint(1, 6)
game_is_on=True
while True:
try:
user=int(input("What's your choice : "))
continue
except:
print("Please Enter 1-6")
if user == rand_num:
print("\t congrats ! \n You guessed it right 🎊")
elif user != rand_num:
print("Sorry! your guess is incorrect🥺")
replay=input("Do you want to play again (Yes/No)")
if replay =='yes'.lower():
game_is_on=True
else:
print("Thanks for playing this game")
game_is_on=False```
hlep to find the problem please

For your loop to exit:
Your while loop will forever be true, but you switched a variable game_is_on that was meant to regulated the loop. Instead of the forever loop , game_is_on should be next to while,
You need to remove continue statement as that line will just go to the next iteration as long as the condition is true,
When asked about replaying, the lower part should be on the variable, instead of lowering the string itself.
Below is the code you need:
rand_num=random.randint(1, 6)
game_is_on=True
# while True:
while game_is_on:
try:
user=int(input("What's your choice : "))
# continue
except:
print("Please Enter 1-6")
if user == rand_num:
print("\t congrats ! \n You guessed it right 🎊")
elif user != rand_num:
print("Sorry! your guess is incorrect🥺")
replay=input("Do you want to play again (Yes/No)")
if replay.lower() =='yes':
game_is_on=True
else:
print("Thanks for playing this game")
game_is_on=False
Happy coding!

import random
rand_num=random.randint(1, 6)
game_is_on=True
while game_is_on:
try:
user=int(input("What's your choice : "))
except:
print("Please Enter 1-6")
if user == rand_num:
print("\t congrats ! \n You guessed it right 🎊")
elif user != rand_num:
print("Sorry! your guess is incorrect🥺")
replay=input("Do you want to play again (Yes/No)")
if replay =='yes'.lower():
game_is_on=True
else:
print("Thanks for playing this game")
game_is_on=False
Note:
In while loop you have to write 'game_is_on' as for that variable it is telling whether true or false instead you have written True therefore your loop will never end as nothing is breaking the loop
corrected code is pasted above, hope this might help you.

You can use operator break to end while loop. lower() should be used with variable.
if replay.lower() != 'yes':
print("Thanks for playing this game")
break

Create Loop in if / else statement

I am trying to loop this function in the case the 'else' is reached but I'm having difficulties.
I tried while False and it doesn't do the print statements, I guess it kicks out of the function as soon as it ends up being false. I tried the True and I think that's the way to go but when it hits Else it just repeats. I'm thinking... maybe I need to do another Elif for the repeat of the whole function and the else as just an escape if needed.
def login(answer):
while False:
if answer.lower() == "a":
print("You selected to Login")
print("What is your username? ")
break
elif answer.lower() == "b":
print("You selected to create an account")
print("Let's create an account.")
break
else:
print("I don't understand your selection")

while False:
should be
while True:
otherwise you never enter the loop
Further:
else:
print("I don't understand your selection")
should be:
else:
print("I don't understand your selection")
answer = input("enter a new choice")
You might even refactor your code to call the function without parameter:
def login():
while True:
answer = input("enter a choice (a for login or b for account creation")
if answer.lower() == "a":
print("You selected to Login")
print("What is your username? ")
break
elif answer.lower() == "b":
print("You selected to create an account")
print("Let's create an account.")
break
else:
print("I don't understand your selection")

Why is my loop not stopping at the number I set?

I am writing a program in python for a banking application using arrays and functions. Here's my code:
NamesArray=[]
AccountNumbersArray=[]
BalanceArray=[]
def PopulateAccounts():
for position in range(5):
name = input("Please enter a name: ")
account = input("Please enter an account number: ")
balance = input("Please enter a balance: ")
NamesArray.append(name)
AccountNumbersArray.append(account)
BalanceArray.append(balance)
def SearchAccounts():
accounttosearch = input("Please enter the account number to search: ")
for position in range(5):
if (accounttosearch==NamesArray[position]):
print("Name is: " +position)
break
if position>5:
print("The account number not found!")
print("**** MENU OPTIONS ****")
print("Type P to populate accounts")
print("Type S to search for account")
print("Type E to exit")
choice = input("Please enter your choice: ")
while (choice=="E") or (choice=="P") or (choice=="S"):
if (choice=="P"):
PopulateAccounts()
elif (choice=="S"):
SearchAccounts()
elif (choice=="E"):
print("Thank you for using the program.")
print("Bye")
When the user enters "P" it is supposed to call to def PopulateAccounts() and it does, but the problem is that it doesn't stop and the user keeps having to input account name, account number, and account balance. It is supposed to stop after the 5th name. How do I fix this?

It's because after PopulateAccounts() finishes while loop keeps iterating because choice is still P. If you want to ask user for another action simply ask him again for input.
choice = input("Please enter your choice: ")
while (choice=="E") or (choice=="P") or (choice=="S"):
if (choice=="P"):
PopulateAccounts()
elif (choice=="S"):
SearchAccounts()
elif (choice=="E"):
print("Thank you for using the program.")
print("Bye")
choice = input("Please enter another action: ")
Also I'd recommend you use infinite loop to keep asking user for inputs, and break out of it when user enters 'E', this way you could also track invalid inputs.
while True:
choice = input("Please enter your choice: ")
if choice == "P":
PopulateAccounts()
elif choice == "S":
SearchAccounts()
elif choice == "E":
print("Thank you for using the program.")
print("Bye")
break
else:
print("Invalid action \"{}\", avaliable actions P, S, E".format(choice))
print()

Your code asks for the user's choice only once -- before the loop begins. Because it never changes, that loop will stick with the user's choice for an infinite number of iterations.
choice = input("Please enter your choice: ")
while (choice=="E") or (choice=="P") or (choice=="S"):
if (choice=="P"):
PopulateAccounts()
elif (choice=="S"):
SearchAccounts()
elif (choice=="E"):
print("Thank you for using the program.")
print("Bye")
# here at the end of this loop, you should
# get the user to enter another choice for the next
# iteration.

Your while loop has no counter to make it stop at the 5th name, and position only exists during the execution of the function that it is in. Also, position will never be greater than 4. range(5) starts at 0 and ends at 4.

Your for loop is fine. The problem is that your while loop is repeating. So after PopulateAccounts() is called, it correctly finishes after running through the for loop 5 times, but since choice is still equal to "P" (this hasn't been changed after the user first enters it), you still remain in the while loop, which means PopulateAccounts() will be called again and again. You can verify this by sticking an additional statement like "print("Hey, we're at the top of the While loop!")" after the "while" line.
Try rewriting your while loop with an explicit break if the user selects "E":
while True:
if (choice=="P"):
PopulateAccounts()
elif (choice=="S"):
SearchAccounts()
elif (choice=="E"):
print("Thank you for using the program.")
print("Bye")
quit()
choice = input("Please enter either P, S or E: ")
Note that this extra input at the bottom also conveniently appears if the user typed something else besides "P", "S", or "E". You may also want to consider adding .upper() to the choice checks to make it case insensitive.

Go to a specific raw_input()?

So I'm trying to figure out how I can make this simple little program to go back to the raw_input if the user inputs something else then "yes" or "no".
a = raw_input("test: ")
while True:
if a == "yes":
print("yeyeye")
break
elif a == "no":
print("nonono")
break
else:
print("yes or no idiot")
This is what I got so far, I'm new and it's hard to understand. Thanks in advance.

As #DavidG mentioned, just add your raw_input statement in loop:
while True:
a = raw_input("Enter: ")
if a == "yes":
print("You have entered Yes")
break
elif a == "no":
print("You have entered No")
break
else:
print("yes or no idiot")

Simply you can put the first instruction inside the loop; in this way, every time the user inserts a value different to yes or no you can print a message and wait to a new input.
while True:
a = raw_input("test: ")
if a == "yes":
print("yeyeye")
break
elif a == "no":
print("nonono")
break
else:
print("yes or no idiot")

Describe a condition checker for while and read input everytime when your condition is not meet. Inline returns are good for low quantity conditions but when your choice count is too much or condition in condition situations appear, inline returns are becoming trouble.
Thats why you must use condition checkers(like cloop) instead of inline returns.
cloop=True
while cloop:
a = raw_input("test: ")
if a == "yes":
print("yeyeye")
cloop=False
elif a == "no":
print("nonono")
cloop=False
else:
print("yes or no idiot")
cloop=True

Ask the user if they want to repeat the same task again

If the user gets to the end of the program I want them to be prompted with a question asking if they wants to try again. If they answer yes I want to rerun the program.
import random
print("The purpose of this exercise is to enter a number of coin values")
print("that add up to a displayed target value.\n")
print("Enter coins values as 1-penny, 5-nickel, 10-dime,and 25-quarter.")
print("Hit return after the last entered coin value.")
print("--------------------")
total = 0
final_coin = random.randint(1, 99)
print("Enter coins that add up to", final_coin, "cents, on per line")
user_input = int(input("Enter first coin: "))
total = total + user_input
if user_input != 1 and user_input!=5 and user_input!=10 and user_input!=25:
print("invalid input")
while total != final_coin:
user_input = int(input("Enter next coin: "))
total = total + user_input
if total > final_coin:
print("Sorry - total amount exceeds", (final_coin))
if total < final_coin:
print("Sorry - you only entered",(total))
if total== final_coin:
print("correct")

You can enclose your entire program in another while loop that asks the user if they want to try again.
while True:
# your entire program goes here
try_again = int(input("Press 1 to try again, 0 to exit. "))
if try_again == 0:
break # break out of the outer while loop

This is an incremental improvement on the accepted answer:
Used as is, any invalid input from the user (such as an empty str, or the letter "g" or some such) will cause an exception at the point where the int() function is called.
A simple solution to such a problem is to use a try/except- try to perform a task/ code and if it works- great, but otherwise (except here is like an else:) do this other thing.
Of the three approaches one might try, I think the first one below is the easiest and will not crash your program.
Option 1: Just use the string value entered with one option to go again
while True:
# your entire program goes here
try_again = input("Press 1 to try again, any other key to exit. ")
if try_again != "1":
break # break out of the outer while loop
Option 2: if using int(), safeguard against bad user input
while True:
# your entire program goes here
try_again = input("Press 1 to try again, 0 to exit. ")
try:
try_again = int(try_again) # non-numeric input from user could otherwise crash at this point
if try_again == 0:
break # break out of this while loop
except:
print("Non number entered")
Option 3: Loop until the user enters one of two valid options
while True:
# your entire program goes here
try_again = ""
# Loop until users opts to go again or quit
while (try_again != "1") or (try_again != "0"):
try_again = input("Press 1 to try again, 0 to exit. ")
if try_again in ["1", "0"]:
continue # a valid entry found
else:
print("Invalid input- Press 1 to try again, 0 to exit.")
# at this point, try_again must be "0" or "1"
if try_again == "0":
break