Returing tuple giving an error tuple object is not callable - python

class Foo:
def __init__(self):
pass
#property
def get_features(self):
return (1,2,3,)
def execute(self):
print self.get_features()
f = Foo()
f.execute()
I get:
TypeError: 'tuple' object is not callable
What I am interested in is actually the length of that tuple.

You should not be calling properties. Instead, you access them like normal attributes:
def execute(self):
print self.get_features
The only difference between properties and attributes is that properties have getter and setter functions which get called implicitly when you access or set their values. For more information, see the documentation for property.
Also, your class should be inheriting from object:
class Foo(object):
You should always do this in Python 2.x so that your class becomes a new-style class, which has far more functionality than an old-style one.

The reason is that you have the #property decorator on your get_features() function, making it a property, hence it isn't callable.
This means that execute() simply has to print the attribute, and not call it as a function

Related

How to store functions as class variables in python?

I am writing a framework, and I want my base class to use different functions for renaming in the child classes. I figured the best way would be to use a class attribute, like in case of A, but I got TypeErrors when running it like in rename_columns(). However it worked with implementation like B
import pandas as pd
class A:
my_func_mask = str.lower
foo = 'bar'
def rename_columns(self, data):
return data.rename(columns=self.my_func_mask)
class B(A):
def rename_columns(self, data):
return data.rename(columns=self.__class__.my_func_mask)
So I experimented with the above a bit, and I get the following:
a = A()
a.foo # Works fine, gives back 'bar'
a.__class__.my_func_mask # Works as expected `a.__class__.my_func_mask is str.lower` is true
a.my_func_mask # throws TypeError: descriptor 'lower' for 'str' objects doesn't apply to 'A' object
My questions would be why can I use regular typed (int, str, etc.) values as class attributes and access them on the instance as well, while I cannot do that for functions?
What happens during the attribute lookup in these cases? What is the difference in the attribute resolution process?
Actually both foo and my_func_mask is in __class__.__dict__ so I am a bit puzzled. Thanks for the clarifications!
You are storing an unbound built-in method on your class, meaning it is a descriptor object. When you then try to access that on self, descriptor binding applies but the __get__ method called to complete the binding tells you that it can't be bound to your custom class instances, because the method would only work on str instances. That's a strict limitation of most methods of built-in types.
You need to store it in a different manner; putting it inside another container, such as a list or dictionary, would avoid binding. Or you could wrap it in a staticmethod descriptor to have it be bound and return the original. Another option is to not store this as a class attribute, and simply create an instance attribute in __init__.
But in this case, I'd not store str.lower as an attribute value, at all. I'd store None and fall back to str.lower when you still encounter None:
return data.rename(columns=self.my_func_mask or str.lower)
Setting my_func_mask to None is a better indicator that a default is going to be used, clearly distinguishable from explicitly setting str.lower as the mask.
You need to declare staticmethod.
class A:
my_func_mask = staticmethod(str.lower)
foo = 'bar'
>>> A().my_func_mask is str.lower
>>> True
Everything that is placed in the class definition is bound to the class, but you can't bind a built-in to your own class.
Essentially, all code that you place in a class is executed when the class is created. All items in locals() are then bound to your class at the end of the class. That's why this also works to bind a method to your class:
def abc(self):
print('{} from outside the class'.format(self))
class A:
f1 = abc
f2 = lambda self: print('{} from lambda'.format(self))
def f3(self):
print('{} from method'.format(self))
To not have the function bound to your class, you have to place it in the __init__ method of your class:
class A:
def __init__(self):
self.my_func_mask = str.lower

python when I use the '__slots__'

Recent I study Python,but I have a question about __slots__. In my opinion, it is for limiting parameters in Class, but also limiting the method in Class?
For example:
from types import MethodType
Class Student(object):
__slots__=('name','age')
When I run the code:
def set_age(self,age):
self.age=age
stu=Student()
stu.set_age=MethodType(set_age,stu,Student)
print stu.age
An error has occurred:
stu.set_age=MethodType(set_age,stu,Student)
AttributeError: 'Student' object has no attribute 'set_age'
I want to know, why not use set_age for this class?
Using __slots__ means you don't get a __dict__ with each class instance, and so each instance is more lightweight. The downside is that you cannot modify the methods and cannot add attributes. And you cannot do what you attempted to do, which is to add methods (which would be adding attributes).
Also, the pythonic approach is not to instantiate a MethodType, but to simply create the function in the class namespace. If you're attempting to add or modify the function on the fly, as in monkey-patching, then you simply assign the function to the class, as in:
Student.set_age = set_age
Assigning it to the instance, of course, you can't do if it uses __slots__.
Here's the __slots__ docs:
https://docs.python.org/2/reference/datamodel.html#slots
In new style classes, methods are not instance attributes. Instead, they're class attributes that follow the descriptor protocol by defining a __get__ method. The method call obj.some_method(arg) is equivalent to obj.__class__.method.__get__(obj)(arg), which is in turn, equivalent to obj.__class__.method(obj, arg). The __get__ implementation does the instance binding (sticking obj in as the first argument to method when it is called).
In your example code, you're instead trying to put a hand-bound method as an instance variable of the already-existing instance. This doesn't work because your __slots__ declaration prevents you from adding new instance attributes. However, if you wrote to the class instead, you'd have no problem:
class Foo(object):
__slots__ = () # no instance variables!
def some_method(self, arg):
print(arg)
Foo.some_method = some_method # this works!
f = Foo()
f.some_method() # so does this
This code would also work if you created the instance before adding the method to its class.
Your attribute indeed doesn't have an attribute set_age since you didn't create a slot for it. What did you expect?
Also, it should be __slots__ not __slots (I imagine this is right in your actual code, otherwise you wouldn't be getting the error you're getting).
Why aren't you just using:
class Student(object):
__slots__ = ('name','age')
def set_age(self,age):
self.age = age
where set_age is a method of the Student class rather than adding the function as a method to an instance of the Student class.
Instead of __slots__, I'm using the following method. It allow the use of only a predefined set of parameters:
class A(object):
def __init__(self):
self.__dict__['a']=''
self.__dict__['b']=''
def __getattr__(self,name):
d=getattr(self,'__dict__')
if d.keys().__contains__(name):
return d.__dict__[attr]
else:
raise AttributeError
def __setattr__(self,name,value):
d=getattr(self,'__dict__')
if d.keys().__contains__(name):
d[name] = value
else:
raise AttributeError
The use of getattr(..) is to avoid recursion.
There are some merits usin __slots__ vs __dict__ in term of memory and perhaps speed but this is easy to implement and read.

Difference between #classmethod and a method in python [duplicate]

This question already has answers here:
What's an example use case for a Python classmethod?
(7 answers)
Closed 9 years ago.
What is the difference between #classmethod and a 'classic' method in python,
When should I use the #classmethod and when should I use a 'classic' method in python.
Is the classmethod must be an method who is referred to the class (I mean it's only a method who handle the class) ?
And I know what is the difference between a #staticmethod and classic method
Thx
Let's assume you have a class Car which represents the Car entity within your system.
A classmethod is a method that works for the class Car not on one of any of Car's instances. The first parameter to a function decorated with #classmethod, usually called cls, is therefore the class itself. Example:
class Car(object):
colour = 'red'
#classmethod
def blue_cars(cls):
# cls is the Car class
# return all blue cars by looping over cls instances
A function acts on a particular instance of the class; the first parameter usually called self is the instance itself:
def get_colour(self):
return self.colour
To sum up:
use classmethod to implement methods that work on a whole class (and not on particular class instances):
Car.blue_cars()
use instance methods to implement methods that work on a particular instance:
my_car = Car(colour='red')
my_car.get_colour() # should return 'red'
If you define a method inside a class, it is handled in a special way: access to it wraps it in a special object which modifies the calling arguments in order to include self, a reference to the referred object:
class A(object):
def f(self):
pass
a = A()
a.f()
This call to a.f actually asks f (via the descriptor protocol) for an object to really return. This object is then called without arguments and deflects the call to the real f, adding a in front.
So what a.f() really does is calling the original f function with (a) as arguments.
In order to prevent this, we can wrap the function
with a #staticmethod decorator,
with a #classmethod decorator,
with one of other, similiar working, self-made decorators.
#staticmethod turns it into an object which, when asked, changes the argument-passing behaviour so that it matches the intentions about calling the original f:
class A(object):
def method(self):
pass
#staticmethod
def stmethod():
pass
#classmethod
def clmethod(cls):
pass
a = A()
a.method() # the "function inside" gets told about a
A.method() # doesn't work because there is no reference to the needed object
a.clmethod() # the "function inside" gets told about a's class, A
A.clmethod() # works as well, because we only need the classgets told about a's class, A
a.stmethod() # the "function inside" gets told nothing about anything
A.stmethod() # works as well
So #classmethod and #staticmethod have in common that they "don't care about" the concrete object they were called with; the difference is that #staticmethod doesn't want to know anything at all about it, while #classmethod wants to know its class.
So the latter gets the class object the used object is an instance of. Just replace self with cls in this case.
Now, when to use what?
Well, that is easy to handle:
If you have an access to self, you clearly need an instance method.
If you don't access self, but want to know about its class, use #classmethod. This may for example be the case with factory methods. datetime.datetime.now() is such an example: you can call it via its class or via an instance, but it creates a new instance with completely different data. I even used them once for automatically generating subclasses of a given class.
If you need neither self nor cls, you use #staticmethod. This can as well be used for factory methods, if they don't need to care about subclassing.
#classmethod takes the class as first argument while function takes instance of the class
>>> class Test(object):
... def func(self):
... print self
... #classmethod
... def meth(self):
... print self
>>> t = Test()
>>> t.func()
<__main__.Test object at 0x00000000027238D0>
>>> t.meth()
<class '__main__.Test'>
I've used self argument in meth intentionally so it would be very close in syntax to the func. But usually you'd better use cls as argument:
... #classmethod
... def meth(cls):
... print cls

AttributeError: 'property' object has no attribute

Python (2.6) seems to be derping for no reason, can anyone see a problem with this code?
class DB ():
def doSomething (self, str):
print str
class A ():
__db = DB()
#staticmethod
def getDB ():
return A.__db
db = property(getDB)
A.db.doSomething("blah")
Fails with the exception:
AttributeError: 'property' object has no attribute 'doSomething'
It was my understanding that a property would automatically run its getter when accessed, so why is it complaining about a property object, and why isn't it finding my clearly available method?
In addition to needing to inherit from object, properties only work on instances.
a = A()
a.db.doSomething("blah")
To make a property work on the class, you can define a metaclass. (A class is an instance of a metaclass, so properties defined on the metaclass work on the class, just as properties defined on a class work on an instance of that class.)
You aren't using classes correctly. A class is (normally) two things:
A factory for creating a family of related objects
A definition of the common behaviour of those objects
These related objects are the instances of the class. Normal methods are invoked on instances of the class, not on the class itself. If you want methods that can be invoked from the class, without an instance, you need to label the methods with #classmethod (or #staticmethod).
However I don't actually know whether properties work when retrieved from a class object. I can't check right now, but I don't think so. The error you are getting is that A.db is retrieving the property object which defines the property itself, it isn't "evaluating" the property to get A.__db. Property objects have no doSomething attribute. Properties are designed to be created in classes as descriptions of how the instances of those classes work.
If you did intend to be working with an instance of A, then you'll need to create one:
my_a = A()
my_a.db.doSomething("blah")
However, this will also fail. You have not correctly written getDB as any kind of method. Normal methods need an argument to represent the instance it was invoked on (traditionally called self):
def getDB(self):
...
Static methods don't, but need a decorator to label them as static:
#staticmethod
def getDB():
...
Class methods need both an argument to receive the class they were invoked on, and a decorator:
#classmethod
def getDB(cls):
...
You don't need getters in Python:
class B(object):
def do_something(self, str):
print str
class A(object):
db = B()
A.db.do_something("blah")
(I also PEP8:ed the code)

storing classmethod reference in tuple does not work as in variable

#!/usr/bin/python
class Bar(object):
#staticmethod
def ruleOn(rule):
if isinstance(rule, tuple):
print rule[0]
print rule[0].__get__(None, Foo)
else:
print rule
class Foo(object):
#classmethod
def callRule(cls):
Bar.ruleOn(cls.RULE1)
Bar.ruleOn(cls.RULE2)
#classmethod
def check(cls):
print "I am check"
RULE1 = check
RULE2 = (check,)
Foo.callRule()
Output:
<bound method type.check of <class '__main__.Foo'>>
<classmethod object at 0xb7d313a4>
<bound method type.check of <class '__main__.Foo'>>
As you can see I'm trying to store a reference to a classmethod function in a tuple for future use.
However, it seems to store the object itself rather then reference to the bound function.
As you see it works for a variable reference.
The only way to get it is to use __get__, which requires the name of the class it belongs to, which is not available at the time of the RULE variable assignment.
Any ideas anyone?
This is because method are actually functions in Python. They only become bound methods when you look them up on the constructed class instance. See my answer to this question for more details. The non-tuple variant works because it is conceptually the same as accessing a classmethod.
If you want to assign bound classmethods to class attributes you'll have to do that after you construct the class:
class Foo(object):
#classmethod
def callRule(cls):
Bar.ruleOn(cls.RULE1)
Bar.ruleOn(cls.RULE2)
#classmethod
def check(cls):
print "I am check"
Foo.RULE1 = Foo.check
Foo.RULE2 = (Foo.check,)

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