I have a dictionary of lists like
source = {"name":["hans","james","mat"],"country":["spain"],"language":["english","french"]}
and another list like
data_not_avail = ["hans","spain","mat"]
How is it possible to reformat source dictionary into the following format
{
"exist":{"name":["james"], "language":["english","french"]},
"not_exist":{"name":["hans","mat"], "country":["spain"]}
}
I was trying to solve by finding the key of item which are present in list but it was not a success
data_result = {}
keys_list = []
for v in data_not_avail:
keys = [key for key, value in source.items() if v in value]
data_result.update({keys[0]:[v]})
keys_list.extend(keys)
This is a approach, you can use a list comprehension (or python built in filter) to filter every element within source lists with the content of data_not_avail.
data = {"exist": {}, "not_exist": {}}
for key, value in source.items():
data["exist"][key] = [v for v in value if v not in data_not_avail]
data["not_exist"][key] = [v for v in value if v in data_not_avail]
# if you dont need empty list in the result
if not data["exist"][key]:
del data["exist"][key]
if not data["not_exist"][key]:
del data["not_exist"][key]
Naive way of solving it is this, check it out.
values = list(source.values())
exist_values = []
not_values = []
for l in values:
temp_exist = []
temp_not = []
for item in l:
if item not in data_not_avail:
temp_exist.append(item)
else:
temp_not.append(item)
exist_values.append(temp_exist)
not_values.append(temp_not)
exist = {}
not_exist = {}
keys = ['name', 'language', 'country']
for i,key in enumerate(keys):
if len(exist_values[i]) != 0:
exist[key] = exist_values[i]
if len(not_values[i]) != 0:
not_exist[key] = not_values[i]
print(exist, not_exist)
#{'name': ['james'], 'country': ['english', 'french']}
#{'name': ['hans', 'mat'], 'language': ['spain']}
I'm trying to do a dictionary which include countries GMT time (int number)
for example I have a dict and I want to get the value of it, I tried this code:
countires= {('Jerusalem', 'Athens', 'Bucharest'):2 ,('Bahrain','Qatar'):3}
print(countires.get('Athens'))
and the output is:
None
How I can get result 2?
IIUC, You need create temp dict that have seperate key and search what you want like below:
>>> countires= {('Jerusalem', 'Athens', 'Bucharest'):2 ,('Bahrain','Qatar'):3}
>>> dct = {k:value for key,value in countires.items() for k in key}
>>> print(dct.get('Athens'))
2
If you want to use your original dictionary you can define function and search in keys like below:
>>> def search_multi_key(search, dct):
... for key, value in dct.items():
... if search in key:
... return value
... return None
>>> search_multi_key('Athens', countires)
2
One approach is to create a new dictionary, that uses as key each of the elements of the tuples:
countries= {('Jerusalem', 'Athens', 'Bucharest'):2 , ('Bahrain', 'Qatar'):3}
cities = { key : value for keys, value in countries.items() for key in keys }
print(cities.get('Athens'))
Output
2
I have a dictionary:
d = {1:[9,9,9],2:[8,8,8],3:[7,7,7]}
and a list of keys :
newkeylist = [4,2,3]
Now i want check the keys in the dict with the content in the list. If they are different i want to replace the key in the dict with the one in the list.
for i in range(len(newkeylist)):
if d.key()[i] != newkeylist[i]:
d.key()[i] = newkeylist[i]
try something like this
d = {1:[9,9,9],2:[8,8,8],3:[7,7,7]}
newkeylist = [4,2,3]
d_copy = d.copy()
for i, (k, v) in enumerate(d_copy.items()):
if k != newkeylist[i]:
d[newkeylist[i]] = v
del d[k]
but as #jonrsharpe said, it's not an ordered dict: the output is random
I am having trouble converting a 2d list into a 2d dictionary. I haven't worked much with 2d dictionaries prior to this so please bear with me. I am just wondering why this keeps pulling up a KeyError. In this quick example I would want the dictionary to look like {gender: { name: [food, color, number] }}
2dList = [['male','josh','chicken','purple','10'],
['female','Jenny','steak','blue','11']]
dict = {}
for i in range(len(2dList)):
dict[2dList[i][0]][2dList[i][1]] = [2dList[i][2], 2dList[i][3], 2dList[i][4]]
I keep getting the error message: KeyError: 'male'. I know this is how you add keys for a 1d dictionary, but am unsure regarding 2d dictionaries. I always believed it was:
dictionary_name[key1][key2] = value
You can try this :) It will also work if you have more than one male or female in your List
List = [['male','josh','chicken','purple','10'],
['female','Jenny','steak','blue','11']]
d = {}
for l in List:
gender = l[0]
name = l[1]
food = l[2]
color = l[3]
number = l[4]
if gender in d: # if it exists just add new name by creating new key for name
d[gender][name] = [food,color,number]
else: # create new key for gender (male/female)
d[gender] = {name:[food,color,number]}
You are attempting to build a nested dictionary. But are not explicitly initializing the second-layer dictionaries. You need to do this each time, a new key is encountered. Btw, 2dlist is an erroneous way to declare variables in python. This should work for you:
dList = [['male','josh','chicken','purple','10'],
['female','Jenny','steak','blue','11']]
dict = {}
for i in range(len(dList)):
if not dList[i][0] in dict.keys():
dict[dList[i][0]] = {}
dict[dList[i][0]][dList[i][1]] = [dList[i][2], dList[i][3], dList[i][4]]
print(dict)
To get more or less "sane" result use the following (list of dictionaries, each dict is in format {gender: { name: [food, color, number] }}):
l = [['male','josh','chicken','purple','10'], ['female','Jenny','steak','blue','11']]
result = [{i[0]: {i[1]:i[2:]}} for i in l]
print(result)
The output:
[{'male': {'josh': ['chicken', 'purple', '10']}}, {'female': {'Jenny': ['steak', 'blue', '11']}}]
You are getting a KeyError because you are trying to access a non-existing entry on the dictionary with male as the key
You can use defaultdict instead of dict.
from collections import defaultdict
2dList = [['male','josh','chicken','purple','10'],
['female','Jenny','steak','blue','11']]
dict = defaultdict(list)
for i in range(len(2dList)):
dict[2dList[i][0]][2dList[i][1]] = [2dList[i][2], 2dList[i][3], 2dList[i][4]]
Try this
twodList = [['male','josh','chicken','purple','10'],
['female','Jenny','steak','blue','11']]
dic = {twodList[i][0]: {twodList[i][1]: twodList[i][2:]} for i in range(len(twodList))}
As someone mentioned in the comments, you cannot have a variable starting with a number.
list1=[['male','josh','chicken','purple','10'],['female','Jenny','steak','blue','11'],['male','johnson','chicken','purple','10'],['female','jenniffer','steak','blue','11']]
dict = {}
for i in range(len(list1)):
if list1[i][0] in dict:
if list1[i][1] in dict[list1[i][0]]:
dict[list1[i][0]][list1[i][1]] = [list1[i][2], list1[i][3], list1[i][4]]
else:
dict[list1[i][0]][list1[i][1]] = {}
dict[list1[i][0]][list1[i][1]] = [list1[i][2], list1[i][3], list1[i][4]]
else:
dict[list1[i][0]] = {}
if list1[i][1] in dict[list1[i][0]]:
dict[list1[i][0]][list1[i][1]] = [list1[i][2], list1[i][3], list1[i][4]]
else:
dict[list1[i][0]][list1[i][1]] = {}
dict[list1[i][0]][list1[i][1]] = [list1[i][2], list1[i][3], list1[i][4]]
print dict
Above one gives below output:
{"male":{"josh":["chicken","purple","10"],"johnson":["chicken","purple","10"]},"female":{"jenniffer":["steak","blue","11"],"Jenny":["steak","blue","11"]}}
I have list which have keys of dictionary. How to access the dictionary using these keys dynamically. e.g
key_store = ['test','test1']
mydict = {"test":{'test1':"value"},"test3":"value"}
So how to access mydict using key_store I want to access mydict['test']['test1'].
Note: key_store store depth of keyword means it have keywords only its value will be dictionary like test have dictionary so it have 'test','test1'
You can do this with a simple for-loop.
def get_nested_key(keypath, nested_dict):
d = nested_dict
for key in keypath:
d = d[keypath]
return d
>>> get_nested_key(('test', 'test1'), Dict)
Add error checking as required.
Use recursion:
def get_value(d, k, i):
if not isinstance(d[k[i]], dict):
return d[k[i]]
return get_value(d[k[i]], k, i+1)
The parameters are the dictionary, the list and an index you'll be running on.
The stop condition is simple; Once the value is not a dictionary, you want to return it, otherwise you continue to travel on the dictionary with the next element in the list.
>>> key_store = ['test','test1']
>>> Dict = {"test":{'test1':"value"},"test3":"value"}
>>> def get_value(d, k, i):
... if isinstance(d[k[i]], str):
... return d[k[i]]
... return get_value(d[k[i]], k, i+1)
...
>>> get_value(Dict, key_store, 0)
'value'
You could do this with a simple dictionary reduce:
>>> mydict = {"test": {'test1': "value"}, "test3": "value"}
>>> print reduce(dict.get, ['test', 'test1'], mydict)
value