I'm new to python and unicode is starting to give me headaches.
Currently I write to file like this:
my_string = "马/馬"
f = codecs.open(local_filepath, encoding='utf-8', mode='w+')
f.write(my_string)
f.close()
And when I open file with i.e. Gedit, I can see something like this:
\u9a6c/\u99ac\tm\u01ce
While I'd like to see exactly what I've written:
马/馬
I've tried a few different variations, like writing my_string.decode() or my_string.encode('utf-8') instead of just my_string, I know those two methods are the opposites but I was not sure which one I needed. Neither worked anyway.
If I manually write these symbols to text file, then with python read the file, re-write what I've just read back to the same file and save, symbols get turned to the code \u9a6c. Not sure if this is importat, figured I'd just mention it to help identify the problem.
Edit: the strings came from SQL Alchemy objects repr method, which turned out to be where the problem lied. I didn't mention it because it just didn't occur to me it can be related to the problem somehow. Thanks again for your help!
From the comments it is now clear you are using either the repr() function or calling the object.__repr__() method directly.
Don't do that. You are writing debugging information to your file:
>>> my_string = u"马/馬"
>>> print repr(my_string)
u'\u9a6c/\u99ac'
The value produced is meant to be pastable back into a Python session so you can re-produce the exact same value, and as such it is ASCII-safe (so it can be used in Python 2 source code without encoding issues).
From the repr() documentation:
For many types, this function makes an attempt to return a string that would yield an object with the same value when passed to eval(), otherwise the representation is a string enclosed in angle brackets that contains the name of the type of the object together with additional information often including the name and address of the object.
Write the Unicode objects to your file directly instead, codecs.open() handles encoding to UTF-8 correctly if you do.
Related
I'm writing code that I want to make generic to whoever needs to follow it.
Part of the code is reading in an excel file that the user has to download. I know that each user has a specific 6-digit unique ID, and the folder and name of the file remains the same. Is there some way for me to modify the pd.read_csv function so that it is like this:
USERID = '123abc'
pd.read_csv(r'C:\Users\USERID\Documents\Dataset.csv')
I keep getting stuck because there is an ' next to the r so concatenation with a constant does not seem to work.
Similarly, is there a method for code for exporting that would insert the current date in the title?
What you want to use are formatted strings. The r preceding the string literal in your code denotes that you are creating a raw string, which means that you aren't going to ever see the value of your variable get assigned correctly within that string. Python's docs explain what these raw strings are:
Both string and bytes literals may optionally be prefixed with a letter 'r' or 'R'; such strings are called raw strings and treat backslashes as literal characters. (3.10.4 Python Language Reference, Lexical Analysis)
Like Fredericka mentions in her comment, the formatted string is a great way to accomplish what you're trying to do. If you're using Python version 3.6 or greater, you can also use the format method on the string, which does the same thing.
# set the User ID
user_id = "PythonUser1"
# print the full filepath
print("C:\\Users\\{}\\Documents\\Dataset.csv".format(user_id))
# read the CSV file using formatted string literals
my_csv = pd.read_csv("C:\\Users\\{user_id}\\Documents\\Dataset.csv")
# read the CSV file using the format method
my_csv = pd.read_csv("C:\\Users\\{}\\Documents\\Dataset.csv".format(user_id))
For more information, I'd recommend checking out the official Python docs on input and output.
When I declare pass a file to shutil.copy as
shutil.copy(r'i:\myfile.txt', r'UNC to where I want it to go')
I get an error
No such file or directory 'i:\\myfile.txt'
I've experienced this problem before with the os module when I have a UNC path. Usually I just get frustrated enough that I forget using the os module and just put the file path into with open() or whatever I'm using it for.
It is my understanding that placing an r before '' is supposed to cause python to ignore escape characters and treat them as string literals, but the behavior I'm seeing leads me to believe that this is not the case. For some reason it takes the \ and changes it to \\.
I've seen this when using os.path.join where the \\ at the beginning of the the UNC Path gets turned into \\\\.
What is the best way to pass a string literal to ensure that all escape characters are ignored and the string is preserved?
Your string is not being modified by Python. It's the representation of your string that's coming out differently.
When the error is printed, Python calls repr() to print the value. This function will
Return a string containing a printable representation of an object. For many types, this function makes an attempt to return a string that would yield an object with the same value when passed to eval(), otherwise the representation is a string enclosed in angle brackets that contains the name of the type of the object together with additional information often including the name and address of the object. A class can control what this function returns for its instances by defining a repr() method.
This can be very nice when debugging: if I paste that string (quotes, escapes, and all) into the REPL I'll get the string in memory that you were working with. I can use this to interactively try your copy command, maybe tweaking the string a bit.
If you want to see your string in a printed form, you could do
source_path = r'i:\myfile.txt'
target_path = r'UNC to where I want it to go'
print(f'Copying {source_path} to {target_path}...')
shutil.copy(source_path, target_path)
This is a rather generic question, but I have a textfile that I want to edit using a script.
What are some ways to format text, so that it will visually stand out but still be recognized by my script?
It works fine when I use text_to_be_replaced, but it is hard to find when you have a large file.
Tried searching, and it seems that the common ways are:
%text_to_be_replaced%
<text_to_be_replaced>
$(text_to_be_replaced)
But maybe there is a commonly used/widely accepted way to format text for visibility?
The language the script is written in is python, if that matters... but I'm looking for a more-or-less generic soluting which will work 90% of the time.
I'm not aware of any generic standard here, but if it's meant to be replaced, you can use the new string formatting method as follows:
string = 'some text {add_text_here} some more text'
Then to replace it when you need to:
value = 'formatted'
string = string.format(add_text_here=value)
Now print it out:
>>> string
'some text formatted some more text'
In fact, this quite neat at the addition of curly {brackets} around the text that needs to be replaced also may make it stand out a little.
At first I thought that {{curly braces}} would be fine, but than I went with $ALLCAPS.
First of all, caps really stands out, while lowercase may be confused with the rest of the code.
And while it $REALLYSTANDSOUT, it shouldn't cause any problems, since it's just a "bookmark" in a text file, and will be replaced with the appropriate stuff determined by the script.
The Code Furies have turned their baleful glares upon me, and it's fallen to me to implement "Secure Transport" as defined by The Direct Project. Whether or not we internally use DNS rather than LDAP for sharing certificates, I'm obviously going to need to set up the former to test against, and that's what's got me stuck. Apparently, an X509 cert needs some massaging to be used in a CERT record, and I'm trying to work out how that's done.
The clearest thing I've found is a script on Videntity's blog, but not being versed in python, I'm hitting a stumbling block. Specifically, this line crashes:
decoded_clean_pk = clean_pk.decode('base64', strict)
since it doesn't seem to like (or rather, to know) whatever 'strict' is supposed to represent. I'm making the semi-educated guess that the line is supposed to decode the base64 data, but I learned from the Debian OpenSSL debacle some years back that blindly diddling with crypto-related code is a Bad Thing(TM).
So I turn the illustrious python wonks on SO to ask if that line might be replaced by this one (with the appropriate import added):
decoded_clean_pk = base64.b64decode(clean_pk)
The script runs after that change, and produces correct-looking output, but I've got enough instinct to know that I can't necessarily trust my instincts here. :)
This line should've work if you would've called like this:
decoded_clean_pk = clean_pk.decode('base64', 'strict')
Notice that strict has to be a string, otherwise python interpreter would try to search for a variable named strict and if it didn't find it or otherwise has other value than: strict, ignore, and replace, it'll probably would've complain about it.
Take a look at this code:
>>>b=base64.b64encode('hello world')
>>>b.decode('base64')
'hello world'
>>>base64.b64decode(b)
'hello world'
Both decode and b64decode works the same when .decode is passed the base64 argument string.
The difference is that str.decode will take a string of bytes as arguments and will return it's Unicode representation depending on the encoding argument you pass as first parameter. In this case, you're telling it to handle a bas64 string so it will do it ok.
To answer your question, both works the same, although b64decode/encode are meant to work only with base64 encodings and str.decode can handle as many encodings as the library is aware of.
For further information take a read at both of the doc sections: decode and b64decode.
UPDATE: Actually, and this is the most important example I guess :) take a look at the source code for encodings/base64_codec.py which is that decode() uses:
def base64_decode(input,errors='strict'):
""" Decodes the object input and returns a tuple (output
object, length consumed).
input must be an object which provides the bf_getreadbuf
buffer slot. Python strings, buffer objects and memory
mapped files are examples of objects providing this slot.
errors defines the error handling to apply. It defaults to
'strict' handling which is the only currently supported
error handling for this codec.
"""
assert errors == 'strict'
output = base64.decodestring(input)
return (output, len(input))
As you may see, it actually uses base64 module to do it :)
Hope this clarify in some way your question.
Given two nearly identical text files (plain text, created in MacVim), I get different results when reading them into a variable in Python. I want to know why this is and how I can produce consistent behavior.
For example, f1.txt looks like this:
This isn't a great example, but it works.
And f2.txt looks like this:
This isn't a great example, but it wasn't meant to be.
"But doesn't it demonstrate the problem?," she said.
When I read these files in, using something like the following:
f = open("f1.txt","r")
x = f.read()
I get the following when I look at the variables in the console. f1.txt:
>>> x
"This isn't a great example, but it works.\n\n"
And f2.txt:
>>> y
'This isn\'t a great example, but it wasn\'t meant to be. \n"But doesn\'t it demonstrate the problem?," she said.\n\n'
In other words, f1 comes in with only escaped newlines, while f2 also has its single quotes escaped.
repr() shows what's going on. first for f1:
>>> repr(x)
'"This isn\'t a great example, but it works.\\n\\n"'
And f2:
>>> repr(y)
'\'This isn\\\'t a great example, but it wasn\\\'t meant to be. \\n"But doesn\\\'t it demonstrate the problem?," she said.\\n\\n\''
This kind of behavior is driving me crazy. What's going on and how do I make it consistent? If it matters, I'm trying to read in plain text, manipulate it, and eventually write it out so that it shows the properly escaped characters (for pasting into Javascript code).
Python is giving you a string literal which, if you gave it back to Python, would result in the same string. This is known as the repr() (short for "representation") of the string. This may not (probably won't, in fact) match the string as it was originally specified, since there are so many ways to do that, and Python does not record anything about how it was originally specified.
It uses double quotes around your first example, which works fine because it doesn't contain any double quotes. The second string contains double quotes, so it can't use double quotes as a delimiter. Instead it uses single quotes and uses backslashes to escape the single quotes in the string (it doesn't have to escape the double quotes this way, and there are more of them than there are single quotes). This keeps the representation as short as possible.
There is no reason for this behavior to drive you crazy and no need to try to make it consistent. You only get the repr() of a string when you are peeking at values in Python's interactive mode. When you actually print or otherwise use the string, you get the string itself, not a reconstituted string literal.
If you want to get a JavaScript string literal, the easiest way is to use the json module:
import json
print json.dumps('I said, "Hello, world!"')
Both f1 and f2 contain perfectly normal, unescaped single quotes.
The fact that their repr looks different is meaningless.
There are a variety of different ways to represent the same string. For example, these are all equivalent literals:
"abc'def'ghi"
'abc\'def\'ghi'
'''abc'def'ghi'''
r"abc'def'ghi"
The repr function on a string always just generates some literal that is a valid representation of that string, but you shouldn't depend on exactly which one it generate. (In fact, you should rarely use it for anything but debugging purposes in the first place.)
Since the language doesn't define anywhere what algorithm it uses to generate a repr, it could be different for each version of each implementation.
Most of them will try to be clever, using single or double quotes to avoid as many escaped internal quotes as possible, but even that isn't guaranteed. If you really want to know the algorithm for a particular implementation and version, you pretty much have to look at the source. For example, in CPython 3.3, inside unicode_repr, it counts the number of quotes of each type; then if there are single quotes but no double quotes, it uses " instead of '.
If you want "the" representation of a string, you're out of luck, because there is no such thing. But if you want some particular representation of a string, that's no problem. You just have to know what format you want; most formats, someone's already written the code, and often it's in the standard library. You can make C literal strings, JSON-encoded strings, strings that can fit into ASCII RFC822 headers… But all of those formats have different rules from each other (and from Python literals), so you have to use the right function for the job.