I'm trying to parse some directories and identifying folders witch do not have a specific correct pattern. Let's exemplify:
Correct: Level1\\Level2\\Level3\\Level4_ID\\Date\\Hour\\file.txt
Incorrect: Level1\\Level2\\Level3\\Level4\\Date\\Hour\\file.txt
Notice that the incorrect one does not have the _ID. My final desired goal is parse the data replacing the '\' for a delimiter to import for MS excel:
Level1;Level2;Level3;Level4;ID;Date;Hour;file.txt
Level1;Level2;Level3;Level4; ;Date;Hour;file.txt
I had successfully parsed all the correct data making this steps:
Let files be a list of my all directories
for i in arange(len(files)):
processed_str = files[i].replace(" ", "").replace("_", "\\")
processed_str = processed_str.split("\\")
My issue is detecting whether or not Level4 folder does have an ID after the underscore using the same script, since "files" contains both correct and incorrect directories.
The problem is that since the incorrect one does not have the ID, after performing split("\") I end up having the columns mixed without a blanck between Level4 and Date:
Level1;Level2;Level3;Level4;Date;Hour;file.txt
Thanks,
Do the "_ID" check after splitting the directories, that way you don't loose information. Assuming the directory names themselves don't contain escaped backslashes and that the ID field is always in level 4 (counting from 1), this should do it:
for i in arange(len(files)):
parts = files[i].split("\\")
if parts[3].endswith("_ID"):
parts.insert(4, parts[3][:-len("_ID")])
else:
parts.insert(4, " ")
final = ";".join(parts)
Related
Sample environment:
Dictionary = {"camel":"create-para","donkey":"monkey","cat":"dog"}
cwd = os.getcwd(".")
for files in cwd
if files.endswith(".doc") or files.endswith(".doc"):
for Dictionary in files:
do the changes
2 things to notice:
create-para in dictionary means that remove string1 and create a new paragraph in place of string1.
In VBA macro it is like this:
Dictionary = {"camel":"^p","donkey":"monkey","cat":"dog"}
However, how to do that?
For example, I want to remove the word materials and replace it with a paragraph
Before
After
I'm not fully sure what you are trying to do here, what is for Dictionary in files:? Aren't Dictionary and files two separate variables? Also, I think your if condition should be:
if files.endswith(".doc") or files.endswith(".docx"):
If you are trying to change a doc/docx file, you can achieve it using python-docx. The documentation should be able to help you out. If you want to replace paragraphs, you can use this snippet from the library's GitHub page. If you want to add paragraphs, you can use the add_paragraph function:
document.add_paragraph('A plain paragraph having some ')
I have the following folder structure in S3.
myBucket/20190313/20190313_100000/_SUCCESS
I need to check whether there is _SUCCESS File present
Query I am currently using:
date = 20190313
bucket = s3Resource.Bucket(myBucket)
objs = list(bucket.objects.filter(Prefix=date+'/'))
I do not know what will be inside of the date folder. But is in yyyymmdd_hhmmss format.
Is there a way to query for that specific "_SUCCESS" file, if only "myBucket/20190313/" is known?
The API docs says that you cant use a regex
Limits the response to keys that begin with the specified prefix. You can use prefixes to separate a bucket into different groupings of keys. (You can think of using prefix to make groups in the same way you would use a folder in a file system.)
It's a long shot, depending on your object keys, but you could combine the prefix and the delimiter properties.
e.g.:
Prefix = date+'/'
Delimiter = '_'
As I'm sure that you are aware, there is no folder structure in S3 keys, rather a unique string to identify the object. The use of a delimiter of '/' creates a hierarchy, or more of a virtual folder structure.
Use of the delimiter property will change the virtual folder structure from using '/' to '_'. Provided that you don't use underscores in other keys, it will return a collection of strings between the end of the prefix, and the start of the next prefix, i.e. the '_' in '_SUCCESS'
I have various files that are formatted like so;
file_name_twenty_135032952.txt
where file_name_twenty is a description of the contents, and 13503295 is the id.
I want two different regexes; one to get the description out of the filename, and one to get the id.
Here are some other rules that the filenames follow:
The filename will never contains spaces, or uppercase characters
the id will always come directly before the extension
the id will always follow an underscore
the description may sometimes have numbers in it; for example, in this filename: part_1_of_file_324980332.txt, part_1_of_file is the description, and 324980332 is the id.
I've been toiling for a while and can't seem to figure out a regex to solve this. I'm using python, so any limitations thereof with its regex engine follow.
rsplit once on an underscore and to remove the extension from id.
s = "file_name_twenty_13503295.txt"
name, id = s.rsplit(".",1)[0].rsplit("_", 1)
print(name, id)
file_name_twenty 13503295
I am trying to find a sub-string in a string, but I am not achieving the results I want.
I have several strings that contains the direction to different directories:
'/Users/mymac/Desktop/test_python/result_files_Sample_8_11/logs',
'/Users/mymac/Desktop/test_python/result_files_Sample_8_1/logs',
'/Users/mymac/Desktop/test_python/result_files_Sample_8_9/logs'
Here is the part of my code here I am trying to find the exact match to the sub-string:
for name in sample_names:
if (dire.find(name)!=-1):
for files in os.walk(dire):
for file in files:
list_files=[]
list_files.append(file)
file_dict[name]=list_files
Everything works fine except that when it looks for Sample_8_1 in the string that contains the directory, the if condition also accepts the name Sample_8_11. How can I make it so that it makes an exact match to prevent from entering the same directory more than once?
You could try searching for sample_8_1/ (i.e., include the following slash). I guess given your code that would be dire.find(name+'/'). This just a quick and dirty approach.
Assuming that dire is populated with absolute path names
for name in sample_names:
if name in dire:
...
e.g.
samples = ['/home/msvalkon/work/tmp_1',
'/home/msvalkon/work/tmp_11']
dirs = ['/home/msvalkon/work/tmp_11']
for name in samples:
if name in dirs:
print "Entry %s matches" % name
Entry /home/msvalkon/work/tmp_11 matches
I have a bunch of files (TV episodes, although that is fairly arbitrary) that I want to check match a specific naming/organisation scheme..
Currently: I have three arrays of regex, one for valid filenames, one for files missing an episode name, and one for valid paths.
Then, I loop though each valid-filename regex, if it matches, append it to a "valid" dict, if not, do the same with the missing-ep-name regexs, if it matches this I append it to an "invalid" dict with an error code (2:'missing epsiode name'), if it matches neither, it gets added to invalid with the 'malformed name' error code.
The current code can be found here
I want to add a rule that checks for the presence of a folder.jpg file in each directory, but to add this would make the code substantially more messy in it's current state..
How could I write this system in a more expandable way?
The rules it needs to check would be..
File is in the format Show Name - [01x23] - Episode Name.avi or Show Name - [01xSpecial02] - Special Name.avi or Show Name - [01xExtra01] - Extra Name.avi
If filename is in the format Show Name - [01x23].avi display it a 'missing episode name' section of the output
The path should be in the format Show Name/season 2/the_file.avi (where season 2 should be the correct season number in the filename)
each Show Name/season 1/ folder should contain "folder.jpg"
.any ideas? While I'm trying to check TV episodes, this concept/code should be able to apply to many things..
The only thought I had was a list of dicts in the format:
checker = [
{
'name':'valid files',
'type':'file',
'function':check_valid(), # runs check_valid() on all files
'status':0 # if it returns True, this is the status the file gets
}
I want to add a rule that checks for
the presence of a folder.jpg file in
each directory, but to add this would
make the code substantially more messy
in it's current state..
This doesn't look bad. In fact your current code does it very nicely, and Sven mentioned a good way to do it as well:
Get a list of all the files
Check for "required" files
You would just have have add to your dictionary a list of required files:
checker = {
...
'required': ['file', 'list', 'for_required']
}
As far as there being a better/extensible way to do this? I am not exactly sure. I could only really think of a way to possibly drop the "multiple" regular expressions and build off of Sven's idea for using a delimiter. So my strategy would be defining a dictionary as follows (and I'm sorry I don't know Python syntax and I'm a tad to lazy to look it up but it should make sense. The /regex/ is shorthand for a regex):
check_dict = {
'delim' : /\-/,
'parts' : [ 'Show Name', 'Episode Name', 'Episode Number' ],
'patterns' : [/valid name/, /valid episode name/, /valid number/ ],
'required' : ['list', 'of', 'files'],
'ignored' : ['.*', 'hidden.txt'],
'start_dir': '/path/to/dir/to/test/'
}
Split the filename based on the delimiter.
Check each of the parts.
Because its an ordered list you can determine what parts are missing and if a section doesn't match any pattern it is malformed. Here the parts and patterns have a 1 to 1 ratio. Two arrays instead of a dictionary enforces the order.
Ignored and required files can be listed. The . and .. files should probably be ignored automatically. The user should be allowed to input "globs" which can be shell expanded. I'm thinking here of svn:ignore properties, but globbing is natural for listing files.
Here start_dir would be default to the current directory but if you wanted a single file to run automated testing of a bunch of directories this would be useful.
The real loose end here is the path template and along the same lines what path is required for "valid files". I really couldn't come up with a solid idea without writing one large regular expression and taking groups from it... to build a template. It felt a lot like writing a TextMate language grammar. But that starts to stray on the ease of use. The real problem was that the path template was not composed of parts, which makes sense but adds complexity.
Is this strategy in tune with what you were thinking of?
maybe you should take the approach of defaulting to: "the filename is correct" and work from there to disprove that statement:
with the fact that you only allow filenames with: 'show name', 'season number x episode number' and 'episode name', you know for certain that these items should be separated by a "-" (dash) so you have to have 2 of those for a filename to be correct.
if that checks out, you can use your code to check that the show name matches the show name as seen in the parent's parent folder (case insensitive i assume), the season number matches the parents folder numeric value (with or without an extra 0 prepended).
if however you don't see the correct amount of dashes you instantly know that there is something wrong and stop before the rest of the tests etc.
and separately you can check if the file folder.jpg exists and take the necessary actions. or do that first and filter that file from the rest of the files in that folder.