Develop Reference

Parts of Development Setting does not overide production settings

So I have being trying to separate my dev from production side and of my setting. However parts work and part do not.
I have set my DJANGO_SETTING_MODULE = lms.settings.prod
now in prod I have DEBUG as false and in dev it is set to true and that works fine.
but for the stripe keys they do not change.
#dev.py
from lms.settings.prod import *
from decouple import config
#overide settings
DEBUG = True
STRIPE_PUBLIC_KEY =config('DEV_PUBLIC_KEY')
STRIPE_SECRET_KEY =config("DEV_SECRET_KEY")
STRIPE_WEBHOOK_SECRET =config('DEV_WEBHOOK_SECRET')
#prod.py
from decouple import config
from pathlib import Path
import os
DEBUG = False
STRIPE_PUBLIC_KEY =config('STRIPE_PUBLIC_KEY')
STRIPE_SECRET_KEY =config("STRIPE_SECRET_KEY")
STRIPE_WEBHOOK_SECRET =config('STRIPE_WEBHOOK_SECRET')
My folder structure is
lms
-settings
--__init__.py
--dev.py
--prod.py

flask run giving me ModuleNotFoundError

I'm relatively new to python and am trying to build a flask server. What I would like to do is have a package called "endpoints" that has a list of modules where each module defines a subset of application routes. When I make a file called server.py with the following code this works like so
import os
from flask import Flask
app = Flask(__name__)
from endpoint import *
if __name__ == '__main__':
app.run(debug=True, use_reloader=True)
Right now there's only one endpoint module called hello.py and it looks like this
from __main__ import app
# a simple page that says hello
# #app.route defines the url off of the BASE url e.g. www.appname.com/api +
# #app.route
# in dev this will be literally http://localhost:5000/hello
#app.route('/hello')
def hello():
return 'Hello, World!'
So... the above works when I run python server.py, the issue happens when I try to run the app using flask.
Instead of server.py it just calls __init__.py which looks like this
import os
from flask import Flask
# create and configure the app
# instance_relative_config states that the
# config files are relative to the instance folder
app = Flask(__name__, instance_relative_config=True)
# ensure the instance folder exists
try:
os.makedirs(app.instance_path)
except OSError:
pass
from endpoint import *
When I run flask run in terminal I get ModuleNotFoundError: No module named 'endpoint'
but again if I change the code so it looks like the following below, then flask run works.
import os
from flask import Flask
# create and configure the app
# instance_relative_config states that the
# config files are relative to the instance folder
app = Flask(__name__, instance_relative_config=True)
# ensure the instance folder exists
try:
os.makedirs(app.instance_path)
except OSError:
pass
# a simple page that says hello
# #app.route defines the url off of the BASE url e.g. www.appname.com/api +
# #app.route
# in dev this will be literally http://localhost:5000/hello
#app.route('/hello')
def hello():
return 'Hello, World!'
I'm pretty sure this is happening because I don't fully understand how imports work...
So, how do I set up __init__.py so that it imports all the modules from the "endpoint" package and works when I call flask run?

When you use a __init__.py file, which you should, Python treats the directory as a package.
This means, you have to import from the package, and not directly from the module.
Also, usually you do not put much or any code in a __init__.py file.
Your directory structure could look like this, where stack is the name of the package I use.
stack/
├── endpoint.py
├── __init__.py
└── main.py
You __init__.py file is empty.
main.py
import os
from flask import Flask
# create and configure the app
# instance_relative_config states that the
# config files are relative to the instance folder
app = Flask(__name__, instance_relative_config=True)
# ensure the instance folder exists
try:
os.makedirs(app.instance_path)
except OSError:
pass
from stack.endpoint import *
endpoint
from stack.main import app
# a simple page that says hello
# #app.route defines the url off of the BASE url e.g. www.appname.com/api +
# #app.route
# in dev this will be literally http://localhost:5000/hello
#app.route('/hello')
def hello():
return 'Hello, World!'
You can then run your app...
export FLASK_APP=main.py
# followed by a...
flask run
This all said, when I create a new Flask app, I usually only use one file, this makes initial development easier, and only split into modules when the app really grows bigger.
Also, for separating views or let's call it sub packages, Flask offers so called Blue prints. This is nothing you have to worry about right now, but comes especially handy when trying to split the app into sub applications.

How can put files in folder in django for settings

I have this folder structure for django
settings/dev.py
settings/prod.py
settings/test.py
Then i have common settings in settings/common.py in which i check the ENV variable like
if PROD:
from settings.prod import *
Based on ENV variable each one of them will be active
I want to use something like this in my code
from myapp import settings
rather than
from myapp.settings import dev

This is the method which I follow. Learnt this from the book Two Scoops of Django.
Have a file, such as, settings/common.py which will contain the properties/settings which are common in dev, prod and test environment. (You already have this.)
The other 3 files should:
Import the common settings from the settings/common.py by adding the line from .common import *
And should contain settings for its own corresponding environment.
The manage.py file decides which settings file to import depending on the OS environment variable, DJANGO_SETTINGS_MODULE. So, for test environment the value of DJANGO_SETTINGS_MODULE should be mysite.settings.test
Links for reference:
Django documentation for django-admin utility - Link
Two Scoops of Django sample project - Link

Preserve your settings folder structure and create __init__.py there.
Please, use code below in your settings/__init__.py:
import os
# DJANGO_SERVER_TYPE
# if 1: Production Server
# else if 2: Test Server
# else: Development Server
server_type = os.getenv('DJANGO_SERVER_TYPE')
if server_type==1:
from prod import *
elif server_type==2:
from test import *
else:
from dev import *
Now you can set environment variable called DJANGO_SERVER_TYPE to choose between Production, Test or Development Server and import settings using:
import settings

How to get config params in another module in flask python?

In my main.py have the below code:
app.config.from_object('config.DevelopmentConfig')
In another module I used import main and then used main.app.config['KEY'] to get a parameter, but Python interpreter says that it couldn't load the module in main.py because of the import part. How can I access config parameters in another module in Flask?

Your structure is not really clear but by what I can get, import your configuration object and just pass it to app.config.from_object():
from flask import Flask
from <path_to_config_module>.config import DevelopmentConfig
app = Flask('Project')
app.config.from_object(DevelopmentConfig)
if __name__ == "__main__":
application.run(host="0.0.0.0")
if your your config module is in the same directory where your application module is, you can just use :
from .config import DevelopmentConfig

The solution was to put app initialization in another file (e.g: myapp_init_file.py) in the root:
from flask import Flask
app = Flask(__name__)
# Change this on production environment to: config.ProductionConfig
app.config.from_object('config.DevelopmentConfig')
Now to access config parameters I just need to import this module in different files:
from myapp_init_file import app
Now I have access to my config parameters as below:
app.config['url']
The problem was that I had an import loop an could not run my python app. With this solution everything works like a charm. ;-)

importing error in python while importing two classes

I am working with a python script, and i face importing problem when i try to import a class from another python script. Here is how my python project folder looks:
Mysql_Main/
checks.py
Analyzer/
config.py
ip.py
op.py
__init__.py
Now i want to import two classes named: Config() and Sqlite() from config.py into the checks.py script.How do i do it?
This is what i tried, but its resulting in an error!
inside checks.py:
from Analyzer import config
config = config.Config()
sqlite = config.Sqlite()
The problem is that Config class is imported properly, but Sqlite class is not getting imported.It is showing error - Config instance has no attribute 'Sqlite'

When you do:
config = config.Config()
You write over the variable config and it no longer points to the module config. It stores the new Config instance.
Try:
from Analyzer import config
config_instance = config.Config()
sqlite_instance = config.Sqlite()