def multiply(): #starts sub program when 'multiply()' is called
num1 = random.randint(1,12) #randomly generates a number between 1 and 12
num2 = random.randint(1,12)
while loop == True: #creates loop, and uses previously defined 'loop'
ans = int(input("What is the answer to " + str(num1) + " x " + str(num2) + " ? ")) #asks question and requires a user input
correct = (ans == num1 * num2)
if correct:
print("You are correct! ")
break #if the answer is correct, it prints 'You are correct!' and breaks to avoid the loop
else:
print("Wrong, please try again. ")
loop == False #if the answer is wrong, it loops back to when 'loop' was last 'True'
I am wondering if there is a way for me to include a line of code that allows me to display "That is not an option!" when a symbol other than a number is entered into the 5th line in the code.
Use an exception to catch unexpected inputs.
#!/usr/bin/env python3
# -*- coding: utf-8 -*-
import random
def multiply():
# Randomly generates a number between 1 and 12
num1 = random.randint(1,12)
num2 = random.randint(1,12)
while True:
i = input("What is the answer to {} x {} ".format(
str(num1), str(num2)))
try:
ans = int(i)
except ValueError:
print('That is not an option!')
continue
if ans == num1 * num2:
print("You are correct!")
break
else:
print("Wrong, please try again.")
if __name__ == "__main__":
multiply()
When you convert to int there is the chance that they will enter a non-integer value so the conversion will fail, so you can use a try/except
def multiply(): #starts sub program when 'multiply()' is called
num1 = random.randint(1,12) #randomly generates a number between 1 and 12
num2 = random.randint(1,12)
while loop == True: #creates loop, and uses previously defined 'loop'
try:
ans = int(input("What is the answer to " + str(num1) + " x " + str(num2) + " ? ")) #asks question and requires a user input
correct = (ans == num1 * num2)
if correct:
print("You are correct! ")
break #if the answer is correct, it prints 'You are correct!' and breaks to avoid the loop
else:
print("Wrong, please try again. ")
loop == False
except ValueError:
print("That is not an option")
Note that your previous code is now nested in a try block. If the int() fails because they entered a bad input, it will throw a ValueError that you can catch and notify them.
As a side note, another way to format your question to them would be
'What is the answer to {} x {}?'.format(num1, num2)
This is a nice way to generate a string with injected variable values.
Related
This question already has answers here:
Asking the user for input until they give a valid response
(22 answers)
Closed 10 months ago.
#for project 2
# division
def divide(a, b):
return (a / b)
# palindrome
def isPalindrome(s):
return s == s[::-1]
print("Select operation.")
print("1. Divide")
print("2. Palindrome")
print("3. Square root")
while True:
choice = input("Enter choice(1/2/3): ")
if choice == '1':
num1 = float(input("Enter first number: "))
num2 = float(input("Enter second number: "))
print(num1, "/", num2, "=", divide(num1, num2))
elif choice == '2':
def isPalindrome(s):
return s == s[::-1]
s = str(input("Enter word:"))
ans = isPalindrome(s)
if ans:
print (s+" "+"is a palindrome.")
else:
print (s+" "+"is not a palindrome.")
elif choice == '3':
threenumber = float(input("Enter a number: "))
sqrt = threenumber ** 0.5
print ("The square root of " + str(threenumber) + " is " + "sqrt", sqrt)
next_calculation = input("Let's do next calculation? (yes/no): ")
if next_calculation == "no":
break
else:
print("Invalid Input")
When testing it myself, in the beginning, if I entered any other input rather than 1, 2, or 3, it would jump to the "next_calculation" function. I want it to say "That's not an option, silly." instead.
When I select 1 or 3 if I enter anything other than a number the program will stop. I want it to say "That's not a valid number, silly."
How do I do this?
You can do that with continue to ignore the loop and return to the start after checking if the input is in your list of possible values
if choice not in ('1', '2', '3'):
print("Invalid input")
continue
Put that after the input
I'd add right after choice = input("Enter choice(1/2/3): "), this snippet:
while (choice not in ['1','2','3']):
print("That's not a valid number, silly.")
choice = input("Enter choice(1/2/3): ")
In this way, you won't reach the end of the cycle unless you give a correct number.
I think you should try to use Switch in this case, instead of if/elses.
Check out this answer.
Otherwise, #Icenore answer seems to be correct. Also, remember to correctly ident your code, your current else: code is being executed after your while True:
I am learning python and I cannot figure out how to get back to a certain part of loop depending on the response.
If it reaches:
else :
print('Answer must be yes or no')
I want it to start back at:
print ("We are going to add numbers.")
I have tried several different suggestions I have seen on here, but they result in starting back at the very beginning.
My code:
import random
num1 = random.randint(1,100)
num2 = random.randint(1,100)
addition = num1 + num2
print("Hello. What is your name?")
name = str(input())
print ("Nice to meet you " + name)
print ("We are going to add numbers.")
print ("Does that sound good?")
answer = str.lower(input())
if answer == str('yes'):
print ('Yay!!')
print ('Add these numbers')
print (num1, num2)
numbers = int(input())
if numbers == addition:
print('Good Job!')
else:
print('Try again')
numbers = int(input())
elif answer == str('no'):
print ('Goodbye')
else :
print('Answer must be yes or no')
You need a loop that starts with the thing you want to get back to:
def start():
import random
num1 = random.randint(1, 100)
num2 = random.randint(1, 100)
addition = num1 + num2
print("Hello. What is your name?")
name = str(input())
print("Nice to meet you " + name)
while True:
print("We are going to add numbers.")
print("Does that sound good?")
answer = str.lower(input())
if answer == "no":
print("Goodbye")
return
elif answer == "yes":
break
else:
print('Answer must be yes or no')
print('Yay!!')
print('Add these numbers')
print(num1, num2)
# This following part might want to be a loop too?
numbers = int(input())
if numbers == addition:
print('Good Job!')
else:
print('Try again')
numbers = int(input())
I'm programming a beginner calculator in Python.
I'm stuck trying to rerun the function automatically after getting the return value.
So far it reruns when the except block is triggered.
However, it does not rerun when a sum is entered correctly.
def better_calc():
num1 = float(input("please enter your first number: "))
op = input("please enter an operator: ")
num2 = float(input("please enter your second number: "))
try:
if op == "+":
result = num1+num2
elif op == "-":
result = num1-num2
elif op == "*":
result = num1*num2
elif op == "/":
result = num1/num2
print()
print(num1, op, num2, "=")
return result
better_calc()
print()
except UnboundLocalError:
print("\nError: please enter an established operator")
print()
except ZeroDivisionError:
print("\nError: Can not divide by zero")
print()
better_calc()
print(better_calc())
So I have two questions.
(1) How do I rerun the function after getting the return value?
(2) Should I bother trying to get a return value (is there any benefit?), or just print the answer without a return?
As someone stated in the comments, anything below a return statement is not run because it ends the function, bearing this in mind, my answer to your second question would be no, there is no benefit (in this case) to getting a return value. Instead, I would change your function to this:
def better_calc():
num1 = float(input("please enter your first number: "))
op = input("please enter an operator: ")
num2 = float(input("please enter your second number: "))
try:
if op == "+":
result = num1+num2
elif op == "-":
result = num1-num2
elif op == "*":
result = num1*num2
elif op == "/":
result = num1/num2
print()
print(str(num1)+" "+ str(op)+" "+ str(num2)+ " = " + str(result))
#You just print the result of the calculation above
except UnboundLocalError:
print("\nError: please enter an established operator")
print()
except ZeroDivisionError:
print("\nError: Can not divide by zero")
print()
answer = input("Would you like to enter another calculation?(type \"yes\" if so): ")
return answer
#You are using this return statement to either continue or end the while loop
I would also recommend encasing your file in a while loop like so:
#start of file
#have your better_calc function definition here
startingAnswer = "yes"
while(startingAnswer = "yes"):
startingAnswer = better_calc()
#end of file
This way, you are able to continue doing calculations as long as you want (while not running into infinite loop issues).
How would I assign the list of operators so that the random numbers are worked out to tell the user if they're correct or not?
# Controlled Assessment - Basic Times Table Test
import random
score = 0
print ("Welcome to the times table test")
name = input("Please type your name: ")
print ("How to play")
print ("Step 1: When you see a question work out the answer and type it in the space.")
print ("Step 2: Once you have typed your answer press the enter key.")
print ("Step 3: The program will tell you if you're right or wrong.")
print ("Step 4: The next question will load and you can repeat from step 1.")
print ("When you have answered all 10 questions your final score will be printed.")
for q in range(10):
Number1 = random.randint(1,12)
Number2 = random.randint(1,12)
ListOfOperator = ['+','-','*']
Operator =random.choice(ListOfOperator)
print ('what is' ,Number1,Operator,Number2)
Answer= input ("Please Type Your Answer: ")
realanswer = (Number1,Operator,Number2)
if ListOfOperator:
ListOfOperator=['+'] = Number1+Number2
ListOfOperator=['-'] = Number1-Number2
ListOfOperator=['*'] = Number1*Number2
if Answer==realanswer:
print("Your answer is correct")
score = score + 1
print (score)
else:
print("Your answer is incorrect, the correct answer is.",realanswer,".")
print (score)
The code that needs to assign to the list of operators is...
if ListOfOperator:
ListOfOperator=['+'] = Number1+Number2
ListOfOperator=['-'] = Number1-Number2
ListOfOperator=['*'] = Number1*Number2
It should work out the answer to each question using the function I'm telling the program that if the operator from the operator list is * to work out Number1*Number2
The current output for telling them if the answer is correct or not prints
Your answer is incorrect, the correct answer is Number1*Number2.
when if the question is what is 10*3 it should be printing
Your answer is incorrect, the correct answer is 30.
Now that I have this code...
if Operator == '+':
realanswer = Number1+Number2
elif Operator == '-':
realanswer = Number1-Number2
elif Operator == '*':
realanswer = Number1*Number2
if Answer==realanswer:
print("Your answer is correct")
score = score + 1
print (score)
else:
print("Your answer is incorrect, the correct answer is.",realanswer,".")
print (score)
The program always prints that the question is incorrect even with the correct answer inputted, it will then print the correct answer, how would I make it so that It would tell them if it's correct too?
The operator module implements basic operations as functions. Define a dict that maps operator symbols such as "+" to the operator function then use that map to do the calculation.
import random
import operator
op_map = {'+':operator.add, '-':operator.sub, '*':operator.mul}
op_list = list(op_map.keys())
score = 0
print ("Welcome to the times table test")
name = input("Please type your name: ")
print ("How to play")
print ("Step 1: When you see a question work out the answer and type it in the space.")
print ("Step 2: Once you have typed your answer press the enter key.")
print ("Step 3: The program will tell you if you're right or wrong.")
print ("Step 4: The next question will load and you can repeat from step 1.")
print ("When you have answered all 10 questions your final score will be printed.")
for q in range(10):
Number1 = random.randint(1,12)
Number2 = random.randint(1,12)
Operator =random.choice(op_list)
print ('what is' ,Number1,Operator,Number2)
while True:
try:
Answer= int(input("Please Type Your Answer: "))
break
except ValueError:
print("Must be an integer... try again...")
realanswer = op_map[Operator](Number1, Number2)
if Answer==realanswer:
print("Your answer is correct")
score = score + 1
print (score)
else:
print("Your answer is incorrect, the correct answer is.",realanswer,".")
print (score)
To perform multiple check like this you can use if, elif statements:
if Operator == '+':
realanswer = Number1+Number2
elif Operator == '-':
realanswer = Number1-Number2
elif Operator == '*':
realanswer = Number1*Number2
For your reference: Python Docs
...
def realanswer(Num1, Op, Num2):
return {
'+': Num1 + Num2,
'-': Num1 - Num2,
'*': Num1 * Num2,
}[Op]
for q in range(2):
Number1 = random.randint(1,12)
Number2 = random.randint(1,12)
ListOfOperator = ['+','-','*']
Operator =random.choice(ListOfOperator)
print ('what is',Number1,Operator,Number2)
userInput = input("Please Type Your Answer: ")
Answer = 0
try:
Answer = int(userInput)
except ValueError:
print("Input not convertible to int!")
rAnswer = realanswer(Number1,Operator,Number2)
if Answer == rAnswer:
print("Correct!")
else:
print("Incorrect...")
print ("Input a binary number")
num1 = int(input() , 2)
print ("again prease")
num2 = int(input() , 2)
answer = num1 + num2
binaryanswer = bin(answer)[2:]
print ("That's " ,binaryanswer, " In behhieerryy")
input ("Press enter to end Program")
again = raw_input
if again == 'Y':
print("AGAAAINN!!")
return
else:
break
Everythin does it's job, but i just can get the program to repeat itself.
return doest mean it will start again. There is nothing in your program that will cause it to repeat. Put it in a function and if the user presses 'Y' then call the function again.
while 1:
print ("Input a binary number")
num1 = int(input() , 2)
print ("again please")
num2 = int(input() , 2)
answer = num1 + num2
binaryanswer = bin(answer)[2:]
print ("That's " ,binaryanswer, " In behhieerryy")
again = input ("Press enter to end Program")
if again != 'Y':
break
print("AGAAAINN!!")
Not sure exactly what you are trying to do here, but try this:
while True:
print ("Input a binary number")
num1 = int(input() , 2)
print ("again prease")
num2 = int(input() , 2)
answer = num1 + num2
binaryanswer = bin(answer)[2:]
print ("That's " ,binaryanswer, " In behhieerryy")
again = input("Press Y to try again or enter to end Program")
if again == 'Y':
print("AGAAAINN!!")
else:
break