'datetime.datetime' object has no attribute 'read' - python

Users in my app have date_joined fields that are in this format: 2014-12-14 14:46:43.379518+00:00
In order to pass this datetime along to Intercom.io, it must be a UNIX timestamp like this: 1426020706 (this is not the same time, just an example).
I've tried several methods I've read here on Stack Overflow (nothing in this question has the same starting time format: Converting datetime.date to UTC timestamp in Python), but none have worked. mktime() seemed promising, but I got "'datetime.datetime' object has no attribute 'mktime'."
I just tried this:
import time
import dateutil.parser
import member.models import Member
member = Member.objects.get(email="aspeksnijder#outlook.com")
date_joined = member.date_joined
dt = dateutil.parser.parse(date_joined)
print int(time.mktime(dt.timetuple()))
It returned "'datetime.datetime' object has no attribute 'read'". How can I accomplish this?

It seems you have an aware datetime object. If you print it then it looks like:
2014-12-14 14:46:43.379518+00:00
To be sure print(repr(date_joined)).
Converting datetime.date to UTC timestamp in Python shows several ways how you could get the timestamp e.g.,
timestamp = date_joined.timestamp() # in Python 3.3+
Or on older Python versions:
from datetime import datetime
# local time = utc time + utc offset
utc_naive = date_joined.replace(tzinfo=None) - date_joined.utcoffset()
timestamp = (utc_naive - datetime(1970, 1, 1)).total_seconds()
Note: timestamp = calendar.timegm(date_joined.utctimetuple()) would also work in your case but it may return a wrong result silently if you pass it a naive datetime object that represents local time by mistake.
If your input is a time string then convert the time string into a datetime object first.

What about (using the dateutil and pytz packages):
import dateutil.parser
from datetime import datetime
import calendar
import pytz
def str2ts(s):
''' Turns a string into a non-naive datetime object, then get the timestamp '''
# However you get from your string to datetime.datetime object
dt = dateutil.parser.parse(s) # String to non-naive datetime
dt = pytz.utc.normalize(dt) # Normalize datetime to UTC
ts = calendar.timegm(dt.timetuple()) # Convert UTC datetime to UTC timestamp
return int(ts)
def ts2str(ts):
'''Convert a UTC timestamp into a UTC datetime, then format it to a string'''
dt = datetime.utcfromtimestamp(ts) # Convert a UTC timestamp to a naive datetime object
dt = dt.replace(tzinfo=pytz.utc) # Convert naive datetime to non-naive
return dt.strftime('%Y-%m-%d %H:%M:%S.%f%z')
Which we can test with:
# A list of strings corresponding to the same time, with different timezone offsets
ss = [
'2014-12-14 14:46:43.379518+00:00',
'2014-12-14 15:46:43.379518+01:00',
'2014-12-14 16:46:43.379518+02:00',
'2014-12-14 17:46:43.379518+03:00',
]
for s in ss:
ts = str2ts(s)
s2 = ts2str(ts)
print ts, s2
Output:
1418568403 2014-12-14 14:46:43.000000+0000
1418568403 2014-12-14 14:46:43.000000+0000
1418568403 2014-12-14 14:46:43.000000+0000
1418568403 2014-12-14 14:46:43.000000+0000
These output all the same timestamps, and "verification" formatted strings.

You can try the following Python 3 code:
import time, datetime
print(time.mktime(datetime.datetime.strptime("2014-12-14 14:46:43.379518", '%Y-%m-%d %H:%M:%S.%f').replace(tzinfo=datetime.timezone.utc).timetuple()))
which prints:
1418568403.0

I had that problem when I used input from Django's DateField, which is displayed in a form of XXXX-YY-ZZ: parse(django_datefield) causes the exception.
The solution: use str(django_datefield).
parse(str(django_datefield))

I know this is an old post, but I want to highlight that the answer is likely what #Peter said in his comment:
It looks like member.date_joined is already a datetime object, and there's no need to parse it. – Peter Feb 25 '17 at 0:33
So-- your model probably already parses into a datetime.datetime object for you.

Related

how to use strtotime to convert time stamp into unixepoch timestamp

I have a datetime string 2021-10-20 15:42:40+00:00that I obtain via S3
s3_object = s3_resource.Object("testunzipping", "DataPump_10000838.zip")
lastModified = s3_object.last_modified
lastModified = str(lastModified)
I need to convert it into a unixepochtimestamp. I was trying this after reading another SO answer
import datetime
time = datetime.datetime.strtotime(lastModified)
but I get this error:
"type object 'datetime.datetime' has no attribute 'strtotime'"
How else can I convert the str or the datetime object into a unixepochtimestamp?
Using fromisoformat (Python 3.7+):
import datetime
lastModified = "2021-10-20 15:42:40+00:00"
ts = datetime.datetime.fromisoformat(lastModified).timestamp()
print(ts)
# 1634744560.0 # Unix time in seconds
Using strptime:
import datetime
lastModified = "2021-10-20 15:42:40+00:00"
ts = datetime.datetime.strptime(lastModified, "%Y-%m-%d %H:%M:%S%z").timestamp()
print(ts)
# 1634744560.0 # Unix time in seconds
Caveat: the input here has a UTC offset (+00:00), which, if parsed correctly, will give aware datetime. All fine then. If that is not the case (no UTC offset or time zone specified), you'll end up with naive datetime, which Python treats as local time. Thus if you call .timestamp(), it will be converted to UTC first (since Unix time refers to UTC).

Subtracting datetime in string format with datetime format

I have 2 variables.
One is datetime in string format and the other is datetime in datetime.datetime format.
For example -
2021-09-06T07:58:19.032Z # string
2021-09-05 14:58:10.209675 # datetime.datetime
I want to find out the difference between these 2 times in seconds.
I think we need to have both in datetime before we can do this subtraction.
I'm having a hard time converting the string to datetime.
Can someone please help.
You can convert the string into datetime object with strptime()
An example with your given dates:
from datetime import datetime
# Assuming this is already a datetime object in your code, you don't need this part
# I needed this part to be able to use it as a datetime object
date1 = datetime.strptime("2021-09-05 14:58:10.209675", "%Y-%m-%d %H:%M:%S.%f")
## The part where the string is converted to datetime object
# Since the string has "T" and "Z", we will have to remove them before we convert
formatted = "2021-09-06T07:58:19.032Z".replace("T", " ").replace("Z", "")
>>> 2021-09-06 07:58:19.032
# Finally, converting the string
date2 = datetime.strptime(formatted, "%Y-%m-%d %H:%M:%S.%f")
# Now date2 variable is a datetime object
# Performing a simple operation
print(date1 - date2)
>>> -1 day, 6:59:51.177675
Convert the str to datetime via strptime() and then get the difference of the 2 datetime objects in seconds via total_seconds().
from datetime import datetime, timezone
# Input
dt1_str = "2021-09-06T07:58:19.032Z" # String type
dt2 = datetime(year=2021, month=9, day=5, hour=14, minute=58, second=10, microsecond=209675, tzinfo=timezone.utc) # datetime type
# Convert the string to datetime
dt1 = datetime.strptime(dt1_str, "%Y-%m-%dT%H:%M:%S.%f%z")
# Subtract the datetime objects and get the seconds
diff_seconds = (dt1 - dt2).total_seconds()
print(diff_seconds)
Output
61208.822325
The first string time you mention could be rfc3339 format.
A module called python-dateutil could help
import dateutil.parser
dateutil.parser.parse('2021-09-06T07:58:19.032Z')
datetime module could parse this time format by
datetime.datetime.strptime("2021-09-06T07:58:19.032Z","%Y-%m-%dT%H:%M:%S.%fZ")
But this way may cause trouble when get a time in another timezone because it doesn't support timezone offset.

How to convert the local time into utc time in python

I am trying to convert the local time into UTC time. But getting the below error.
Error: an integer is required (got type str)
from datetime import datetime
starts_date = '2021-07-30 09:30:00'(timestamp without time zone)
ts = starts_date
x = datetime.utcfromtimestamp(ts)
x_ts = x.timestamp()
Be sure that datetime is imported correctly as from datetime import datetime. Can be a bit confusing but the method utcfromtimestamp belongs to datetime.datetime and not datetime itself.
Here is a working example to convert a timestamp of (now) to a UTC timestamp.
from datetime import datetime as dt
# Create a timestamp object for now.
ts = dt.timestamp(dt.now())
# Convert now to a UTC timestamp.
dt.utcfromtimestamp(ts).timestamp()
>>> 1627637013.657752
datetime.utcfromtimestamp() takes an integer that represent the amount of seconds passed since January 1st 1970.
This means with
from datetime import datetime as dt
print(dt.utcfromtimestamp(0))
you get
1970-01-01 00:00:00

Converting a unixtime to human readable date format [duplicate]

I have a string representing a unix timestamp (i.e. "1284101485") in Python, and I'd like to convert it to a readable date. When I use time.strftime, I get a TypeError:
>>>import time
>>>print time.strftime("%B %d %Y", "1284101485")
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
TypeError: argument must be 9-item sequence, not str
Use datetime module:
from datetime import datetime
ts = int('1284101485')
# if you encounter a "year is out of range" error the timestamp
# may be in milliseconds, try `ts /= 1000` in that case
print(datetime.utcfromtimestamp(ts).strftime('%Y-%m-%d %H:%M:%S'))
>>> from datetime import datetime
>>> datetime.fromtimestamp(1172969203.1)
datetime.datetime(2007, 3, 4, 0, 46, 43, 100000)
Taken from http://seehuhn.de/pages/pdate
The most voted answer suggests using fromtimestamp which is error prone since it uses the local timezone. To avoid issues a better approach is to use UTC:
datetime.datetime.utcfromtimestamp(posix_time).strftime('%Y-%m-%dT%H:%M:%SZ')
Where posix_time is the Posix epoch time you want to convert
>>> import time
>>> time.ctime(int("1284101485"))
'Fri Sep 10 16:51:25 2010'
>>> time.strftime("%D %H:%M", time.localtime(int("1284101485")))
'09/10/10 16:51'
There are two parts:
Convert the unix timestamp ("seconds since epoch") to the local time
Display the local time in the desired format.
A portable way to get the local time that works even if the local time zone had a different utc offset in the past and python has no access to the tz database is to use a pytz timezone:
#!/usr/bin/env python
from datetime import datetime
import tzlocal # $ pip install tzlocal
unix_timestamp = float("1284101485")
local_timezone = tzlocal.get_localzone() # get pytz timezone
local_time = datetime.fromtimestamp(unix_timestamp, local_timezone)
To display it, you could use any time format that is supported by your system e.g.:
print(local_time.strftime("%Y-%m-%d %H:%M:%S.%f%z (%Z)"))
print(local_time.strftime("%B %d %Y")) # print date in your format
If you do not need a local time, to get a readable UTC time instead:
utc_time = datetime.utcfromtimestamp(unix_timestamp)
print(utc_time.strftime("%Y-%m-%d %H:%M:%S.%f+00:00 (UTC)"))
If you don't care about the timezone issues that might affect what date is returned or if python has access to the tz database on your system:
local_time = datetime.fromtimestamp(unix_timestamp)
print(local_time.strftime("%Y-%m-%d %H:%M:%S.%f"))
On Python 3, you could get a timezone-aware datetime using only stdlib (the UTC offset may be wrong if python has no access to the tz database on your system e.g., on Windows):
#!/usr/bin/env python3
from datetime import datetime, timezone
utc_time = datetime.fromtimestamp(unix_timestamp, timezone.utc)
local_time = utc_time.astimezone()
print(local_time.strftime("%Y-%m-%d %H:%M:%S.%f%z (%Z)"))
Functions from the time module are thin wrappers around the corresponding C API and therefore they may be less portable than the corresponding datetime methods otherwise you could use them too:
#!/usr/bin/env python
import time
unix_timestamp = int("1284101485")
utc_time = time.gmtime(unix_timestamp)
local_time = time.localtime(unix_timestamp)
print(time.strftime("%Y-%m-%d %H:%M:%S", local_time))
print(time.strftime("%Y-%m-%d %H:%M:%S+00:00 (UTC)", utc_time))
In Python 3.6+:
import datetime
timestamp = 1642445213
value = datetime.datetime.fromtimestamp(timestamp)
print(f"{value:%Y-%m-%d %H:%M:%S}")
Output (local time)
2022-01-17 20:46:53
Explanation
Line #1: Import datetime library.
Line #2: Unix time which is seconds since 1970-01-01.
Line #3: Converts this to a unix time object, check with: type(value)
Line #4: Prints in the same format as strp. Local time. To print in UTC see example below.
Bonus
To save the date to a string then print it, use this:
my_date = f"{value:%Y-%m-%d %H:%M:%S}"
print(my_date)
To output in UTC:
value = datetime.datetime.fromtimestamp(timestamp, tz=datetime.timezone.utc)
# 2022-01-17 18:50:52
Other than using time/datetime package, pandas can also be used to solve the same problem.Here is how we can use pandas to convert timestamp to readable date:
Timestamps can be in two formats:
13 digits(milliseconds) -
To convert milliseconds to date, use:
import pandas
result_ms=pandas.to_datetime('1493530261000',unit='ms')
str(result_ms)
Output: '2017-04-30 05:31:01'
10 digits(seconds) -
To convert seconds to date, use:
import pandas
result_s=pandas.to_datetime('1493530261',unit='s')
str(result_s)
Output: '2017-04-30 05:31:01'
For a human readable timestamp from a UNIX timestamp, I have used this in scripts before:
import os, datetime
datetime.datetime.fromtimestamp(float(os.path.getmtime("FILE"))).strftime("%B %d, %Y")
Output:
'December 26, 2012'
You can convert the current time like this
t=datetime.fromtimestamp(time.time())
t.strftime('%Y-%m-%d')
'2012-03-07'
To convert a date in string to different formats.
import datetime,time
def createDateObject(str_date,strFormat="%Y-%m-%d"):
timeStamp = time.mktime(time.strptime(str_date,strFormat))
return datetime.datetime.fromtimestamp(timeStamp)
def FormatDate(objectDate,strFormat="%Y-%m-%d"):
return objectDate.strftime(strFormat)
Usage
=====
o=createDateObject('2013-03-03')
print FormatDate(o,'%d-%m-%Y')
Output 03-03-2013
timestamp ="124542124"
value = datetime.datetime.fromtimestamp(timestamp)
exct_time = value.strftime('%d %B %Y %H:%M:%S')
Get the readable date from timestamp with time also, also you can change the format of the date.
Note that utcfromtimestamp can lead to unexpected results since it returns a naive datetime object. Python treats naive datetime as local time - while UNIX time refers to UTC.
This ambiguity can be avoided by setting the tz argument in fromtimestamp:
from datetime import datetime, timezone
dtobj = datetime.fromtimestamp(1284101485, timezone.utc)
>>> print(repr(dtobj))
datetime.datetime(2010, 9, 10, 6, 51, 25, tzinfo=datetime.timezone.utc)
Now you can format to string, e.g. an ISO8601 compliant format:
>>> print(dtobj.isoformat(timespec='milliseconds').replace('+00:00', 'Z'))
2010-09-10T06:51:25.000Z
Use the following codes, I hope it will solve your problem.
import datetime as dt
print(dt.datetime.fromtimestamp(int("1284101485")).strftime('%Y-%m-%d %H:%M:%S'))
Use datetime.strftime(format):
from datetime import datetime
unixtime = int('1284101485')
# Print with local time
print(datetime.fromtimestamp(unixtime).strftime('%Y-%m-%d %H:%M:%S'))
# Print with UTC time
print(datetime.utcfromtimestamp(unixtime).strftime('%Y-%m-%d %H:%M:%S'))
datetime.fromtimestamp(timestamp): Return the local date corresponding to the POSIX timestamp, such as is returned by time.time().
datetime.utcfromtimestamp(timestamp): Return the UTC datetime corresponding to the POSIX timestamp, with tzinfo None. (The resulting object is naive.)
import datetime
temp = datetime.datetime.fromtimestamp(1386181800).strftime('%Y-%m-%d %H:%M:%S')
print temp
Another way that this can be done using gmtime and format function;
from time import gmtime
print('{}-{}-{} {}:{}:{}'.format(*gmtime(1538654264.703337)))
Output: 2018-10-4 11:57:44
If you are working with a dataframe and do not want the series cannot be converted to class int error. Use the code below.
new_df= pd.to_datetime(df_new['time'], unit='s')
i just successfully used:
>>> type(tstamp)
pandas.tslib.Timestamp
>>> newDt = tstamp.date()
>>> type(newDt)
datetime.date
You can use easy_date to make it easy:
import date_converter
my_date_string = date_converter.timestamp_to_string(1284101485, "%B %d, %Y")
quick and dirty one liner:
'-'.join(str(x) for x in list(tuple(datetime.datetime.now().timetuple())[:6]))
'2013-5-5-1-9-43'

Converting datetime to POSIX time

How do I convert a datetime or date object into a POSIX timestamp in python? There are methods to create a datetime object out of a timestamp, but I don't seem to find any obvious ways to do the operation the opposite way.
import time, datetime
d = datetime.datetime.now()
print time.mktime(d.timetuple())
For UTC calculations, calendar.timegm is the inverse of time.gmtime.
import calendar, datetime
d = datetime.datetime.utcnow()
print calendar.timegm(d.timetuple())
Note that Python now (3.5.2) includes a built-in method for this in datetime objects:
>>> import datetime
>>> now = datetime.datetime(2020, 11, 18, 18, 52, 47, 874766)
>>> now.timestamp() # Local time
1605743567.874766
>>> now.replace(tzinfo=datetime.timezone.utc).timestamp() # UTC
1605725567.874766 # 5 hours delta (I'm in UTC-5)
In python, time.time() can return seconds as a floating point number that includes a decimal component with the microseconds. In order to convert a datetime back to this representation, you have to add the microseconds component because the direct timetuple doesn't include it.
import time, datetime
posix_now = time.time()
d = datetime.datetime.fromtimestamp(posix_now)
no_microseconds_time = time.mktime(d.timetuple())
has_microseconds_time = time.mktime(d.timetuple()) + d.microsecond * 0.000001
print posix_now
print no_microseconds_time
print has_microseconds_time
Best conversion from posix/epoch to datetime timestamp and the reverse:
this_time = datetime.datetime.utcnow() # datetime.datetime type
epoch_time = this_time.timestamp() # posix time or epoch time
this_time = datetime.datetime.fromtimestamp(epoch_time)
It depends
Is your datetime object timezone aware or naive?
Timezone Aware
If it is aware it's simple
from datetime import datetime, timezone
aware_date = datetime.now(tz=timezone.utc)
posix_timestamp = aware_date.timestamp()
as date.timestamp() gives you "POSIX timestamp"
NOTE: more accurate to call it an epoch/unix timestamp as it may not be POSIX compliant
Timezone Naive
If it's not timezone aware (naive), then you'd need to know what timezone it was originally in so we can use replace() to convert it into a timezone aware date object. Let's assume that you've stored/retrieved it as UTC Naive. Here we create one, as an example:
from datetime import datetime, timezone
naive_date = datetime.utcnow() # this date is naive, but is UTC based
aware_date = naive_date.replace(tzinfo=timezone.utc) # this date is no longer naive
# now we do as we did with the last one
posix_timestamp = aware_date.timestamp()
It's always better to get to a timezone aware date as soon as you can to prevent issues that can arise with naive dates (as Python will often assume they are local times and can mess you up)
NOTE: also be careful with your understanding of the epoch as it is platform dependent

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