Automatically Close Not responding popup windows 7 - python

I'm running a python script that takes a data measurement once every 10 minutes forever. The problem is that it requires I run a httpget.exe that crashes constantly. When it crashes, a popup window appears and tells me that it's "Not Responding" and puts my python script on hold until I press "enter" in the popup or click "ok", then the script continues normally.
Is there a way to make certain programs in windows 7 not have those popup menus appear? So my script would just run over any "Not Responding" errors?
I've tried running a "kill()" in python, but as soon as the httpget.exe stops responding, the python script stops too. I just cant be around my computer all the time pressing "enter" when the window pops up.
What's the best way to go about this?
Thank you!

Perhaps you should not use an external program and use something on the standard library, as in get the content of the page and strip it using string functions:
import urllib2
url = "http://httpbin.org/get"
response = urllib2.urlopen(url)
print response.read()
Or the file:
import urllib
urllib.urlretrieve ("http://www.example.com/songs/mp3.mp3", "mp3.mp3")
More about this: https://stackoverflow.com/a/22776/349420

Related

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Is there any way that I can run a Python script while I'm playing that closes this window every time it opens immediately? I'm thinking of something that continously searches for a window with a specific name or maybe something that listens for the event of a window opening and then checking its name/title. I don't even know if Python can access these processes, but I guess it's worth to just ask.
And before I need to edit the post, I'm using Windows 11.

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I'm using Python and Selenium to write an automation script in Internet Explorer.
When the web page throws up some kind of modal dialog box, the Python code stops running and just waits for some action to be taken on the popup. After you press the "yes" or "no" button, then the Python code continues.
I believe the underlying Javascript function that is getting called (saveClicked()) is generating the popup box using this line of code:
var result=window.showModalDialog('whatever....')
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I've looked to see if there is some kind of default IE capability in Selenium that will just automatically accept all modal dialog boxes but haven't found any. I also thought of maybe wrapping the call to the Javascript function with something that would somehow send a keystroke to the alert. I'm open to anything!
Here is the code: It never moves past the .execute_script line...it just sits there waiting.
print('Saving')
# I have to do this because I can't get the handle to the save button
# using any of the known Selenium methods but calling the JS works
driver.execute_script('saveClicked();')
print('Test')
driver.switch_to().alert().send_keys(Keys.ENTER)
The code just STOPS after the Javascript is executed and never moves to the print('test') line or any other code I put there.
Any python selenium code suggestions to solve this would be greatly appreciated.
one way: you can try to use Alert to manage popups
Alert(driver).accept()
otherwise you can see the active window or tab with:
#get current window handle
p = driver.current_window_handle
#get windows
chwd = driver.window_handles
driver.switch_to.window(chwd[1])
reference:
https://selenium-python.readthedocs.io/api.html#module-selenium.webdriver.common.alert
Try:
message = "saveClicked()" # or any other of your messages
driver.execute_script(f"alert(\"{message}\");")
driver.switch_to.alert.accept()

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I am trying to automate some basic web browser manipulation. As part of this sequence there is a popup window that must be dealt with. Once the python code the causes the popup window to appear happens, no other code past that point will run until I manually close that window. Then all remaining code runs fine.
I've try this below to try to deal with handling the popup but to no avail:
for handle in browser.window_handles:
print "Handle = ",handle
browswer.switch_to_window(handle);
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is it possible to launch a window that does not stop the mainloop in python

OS = windows 7
I have a python program (works) that is listening to activity on the usb bus. I want to perform a lot of tests that require a particular user input at a particular time. I would like to pop up a window that says, "press button xxx". The key point is that the mainloop needs to continue running because it's looking for events. I don't care about the window or if it remains or not and I don't need to capture any information from the window. I just want a message to the user to press the correct button at the correct time. Any type of signaling would work; it doesn't have to be a gui window. It doesn't have to look pretty. Appreciate any suggestions or links to something like this. thx
It sounds like the operation of the Python script you're running does not depend upon the user input you request. To run another process without interrupting the Python script execution you can use:
import subprocess
subprocess.Popen([exe,arg1,arg2,arg3])
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arg2= second argument to pass to exe
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I can send a CTRL+C from the console that I run the program from, and it will close, but, no amount of clicking on the window's "x" button, or Alt+F4s seem to work.
My code is as follows:
'''
justclose.py
'''
import sys
import time
import libtcodpy as libtcod
libtcod.console_set_custom_font(b'lucida12x12_gs_tc.png', libtcod.FONT_TYPE_GREYSCALE | libtcod.FONT_LAYOUT_TCOD)
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libtcod.console_flush()
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time.sleep(1)
sys.exit
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I've tried looking through an strace of the process, but, I'm not sure I'm up to the task of deciphering it. Nothing looked immediately out of the ordinary.
I'd like some advice on how to track down what's going wrong. Thanks.
EDIT: specifically, I'd like to know how I can check that the close window event is propagating at all, and if so, how far, where it's getting trapped/ignored, that sort of thing. When I run through strace, I see absolutely nothing happening when I click the close button. Is there some better way to debug this?
Replace time.sleep(1) with libtcod.console_check_for_keypress(). When the program sleeps 1 millisecond for each iteration, the program can not respond when you press X. It exits when you press CTRL+C because the program receives the SIGINT signal and it exits immediately. Replacing time.sleep(1) with libtcod.console_check_for_keypress() makes the program check the key pressed on the keyboard, if there is one. That way, the program doesn't block the execution.

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