Python script just printing out blank page - python

I am using xampp and I am able to run simple python script on it so xampp is setup fine for python. I am trying to use pillow.
I have installed anaconda and did following in terminal
conda install pillow
If I run test.py below in terminal, it works fine. It prints format, size, mode.
But if I try it from web browser I'm getting blank page.
Here is test.py
#!/Library/Frameworks/anaconda/bin/python
print("Content-Type: text/html")
print()
print("<html><head><title>Python</title></head><body>")
from PIL import Image, ImageFilter
original = Image.open("Lenna.png")
print("<h5>The size of the Image is: </h5>")
print("<h2>size " + original.format, original.size, original.mode + "</h2>")
if I use cgitb.enable() I get following error
A problem occurred in a Python script. Here is the sequence of function calls leading up to the error, in the order they occurred.
/Applications/XAMPP/xamppfiles/cgi-bin/test7.py in ()
8 print("<html><head><title>Python</title></head><body>");
9 print("<h5>The size of the Image is: </h5>");
=> 10 from PIL import Image
11 original = Image.open("Lenna.png");
12 width, height = original.size;
PIL undefined, Image undefined
/Library/Frameworks/Python.framework/Versions/3.4/lib/python3.4/site-packages/PIL/Image.py in ()
61 # Also note that Image.core is not a publicly documented interface,
62 # and should be considered private and subject to change.
=> 63 from PIL import _imaging as core
64 if PILLOW_VERSION != getattr(core, 'PILLOW_VERSION', None):
65 raise ImportError("The _imaging extension was built for another "
PIL undefined, _imaging undefined, core = <PIL.Image._imaging_not_installed object>
ImportError: dlopen(/Library/Frameworks/Python.framework/Versions/3.4/lib/python3.4/site-packages/PIL/_imaging.so, 2): Library not loaded: #loader_path/.dylibs/libtiff.5.dylib Referenced from: /Library/Frameworks/Python.framework/Versions/3.4/lib/python3.4/site-packages/PIL/_imaging.so Reason: Incompatible library version: _imaging.so requires version 8.0.0 or later, but libtiff.5.dylib provides version 6.0.0
args = ('dlopen(/Library/Frameworks/Python.framework/Vers...later, but libtiff.5.dylib provides version 6.0.0',)
msg = 'dlopen(/Library/Frameworks/Python.framework/Vers...later, but libtiff.5.dylib provides version 6.0.0'
name = '_imaging'
path = '/Library/Frameworks/Python.framework/Versions/3.4/lib/python3.4/site-packages/PIL/_imaging.so'
with_traceback = <built-in method with_traceback of ImportError object>

Kind of an anti-answer, but unless you are doing it this way for academic reasons, you should try one of the more standard frameworks:
Flask
bottle.py
The two frameworks I listed above are examples of minimalist frameworks that do not get in your way. They take care of running your app and setting up routes. The minimum to use Flask is this:
from flask import Flask
from PIL import Image, ImageFilter
app = Flask(__name__)
#app.route("/")
def myview():
original = Image.open("Lenna.png")
return """
<html><head><title>Python</title></head>
<body>
<h5>The size of the Image is: </h5>
<h2>size {format}, {size}, {mode}</h2>
</body></html>""".format(
format=original.format,
size=original.size,
mode=original.mode)
app.run()
Next, if you want to make your app available, you only need to setup a reverse proxy in XAMPP (easy-peasy). I highly suggest using Flask; it comes with an awesome in-page debugger, courtesy of its sister project Werkzeug (lit. "toolbox").
Werkzeug debugger:

Related

Trying to reuse code across multiple Flask servers, stuck on importing with errors "ModuleNotFoundError" or "ImportError"

My goal is to import code into three separate Flask servers. It's not going well. I am on python 3.10.4. I have read perhaps 10 different posts that say things like "put a __init__.py file in your folders" which I have done.
For context I'm not exactly new to Python but I've never learned the importing/module system properly.
I have three Flask servers that run scraping operations on different (but similar) websites. I need them to be separate for various reasons. Anyway, all three need to run the same procedure of getting an IP for a proxy from my proxy provider. For this I have some code:
# we don't need the details here so I snip it to save space
def get_proxy_ip(choice):
r = requests.get(download_list, headers={"Authorization": "Token " + token})
selected_proxy_ip = r.json()["results"][choice]["proxy_address"]
selected_proxy_port = r.json()["results"][choice]["port"]
print(selected_proxy_ip)
return selected_proxy_ip, selected_proxy_port
I want to use this function across all 3 of my Flask servers. Here are some various ways I've tried to import the code into one of the Flask servers:
scrapers/rentCanada/app.py
import requests
from flask import Flask, request, make_response
print("cats")
app = Flask(__name__)
print(__name__, __package__)
# from ..shared.ipgetter import get_proxy_ip
# from ..shared.checker import check_public_ip
# from scrapers.shared.ipgetter import get_proxy_ip
# from scrapers.shared.checker import check_public_ip
import shared.ipgetter as ipgetter
import shared.checker as checker
None of them work.
import shared.ipgetter as ipgetter yields:
cats
__main__ None
Traceback (most recent call last):
File "/home/rlm/Code/canadaAps/scrapers/rentCanada/app.py", line 10, in <module>
import shared.ipgetter as ipgetter
ModuleNotFoundError: No module named 'shared'
ModuleNotFoundError: No module named 'scrapers' yields: ModuleNotFoundError: No module named 'scrapers'
from ..shared.ipgetter import get_proxy_ip yields: ImportError: attempted relative import with no known parent package
At this point you need to see my folder structure.
/scrapers
..__init__.py
..setup.py
../rentCanada
.....__init__.py
.....app.py
../rentFaster
.....__init__.py
.....app.py
../rentSeeker
.....__init__.py
.....app.py
../shared
.....__init__.py
.....ipgetter.py
.....checker.py
I need to be able to use any of the app.py files as entry points.
I also tried setup.py with this:
from setuptools import setup, find_packages
setup(
name = 'tools',
packages = find_packages(),
)
followed by python setup.py install but that didn't make a "tools" import available in app.py like I wanted.
As a final note I suspect someone will tell me to use a blueprint. To me those look like a tool I'd use if I was adding a route. I'm not sure they're right for a simple function, but maybe I'm wrong.
My solution for now is to run Flask with python rentCanada/app.py from the /scrapers folder and use this code
import sys
from pathlib import Path
sys.path.append(str(Path(__file__).parent.parent)) # necessary so util folder is available
import requests
from flask import Flask, request, make_response
print("cats")
app = Flask(__name__)
print(__name__, __package__)
from util.ipgetter import get_proxy_ip
from util.checker import check_public_ip
So the program appends the app.py file folder's parent folder to the path. That makes the util folder (which used to be shared but had a naming conflict) available within the app.py file.

How to use Azure-Python SDK `ResourcesMoveInfo` class in python

I came across this python class ResourcesMoveInfo for moving resources(Azure Images) from one subscription to another with Azure python SDK.
But it's failing when I use it like below:
Pattern 1
reference from https://buildmedia.readthedocs.org/media/pdf/azure-sdk-for-python/v1.0.3/azure-sdk-for-python.pdf
Usage:
metadata = azure.mgmt.resource.resourcemanagement.ResourcesMoveInfo(resources=rid,target_resource_group='/subscriptions/{0}/resourceGroups/{1}'.format(self.prod_subscription_id,self.resource_group))
Error:
AttributeError: module 'azure.mgmt.resource' has no attribute 'resourcemanagement'
Pattern 2
reference from - https://learn.microsoft.com/en-us/python/api/azure-mgmt-resource/azure.mgmt.resource.resources.v2019_07_01.models.resourcesmoveinfo?view=azure-python
Usage:
metadata = azure.mgmt.resource.resources.v2020_06_01.models.ResourcesMoveInfo(resources=rid,target_resource_group='/subscriptions/{0}/resourceGroups/{1}'.format(self.prod_subscription_id,self.resource_group))
Error:
AttributeError: module 'azure.mgmt.resource.resources' has no attribute 'v2020_06_01'
Any help on this requirement/issue would be helpful. Thanks!
Adding code snippet here:
import sys
import os
import time
from azure.common.credentials import ServicePrincipalCredentials
from azure.mgmt.resource import ResourceManagementClient
import azure.mgmt.resource
#from azure.mgmt.resource.resources.v2020_06_01.models import ResourcesMoveInfo
from azure.identity import ClientSecretCredential
from cred_wrapper import CredentialWrapper
class Move():
def __init__(self):
self.nonprod_subscription_id = "abc"
self.prod_subscription_id = "def"
self.credential = ClientSecretCredential(
client_id= os.environ["ARM_CLIENT_ID"],
client_secret= os.environ["ARM_CLIENT_SECRET"],
tenant_id= os.environ["ARM_TENANT_ID"]
)
#resource client for nonprod
self.sp = CredentialWrapper(self.credential)
self.resource_client = ResourceManagementClient(self.sp,self.nonprod_subscription_id)
self.resource_group = "imgs-rg"
def getresourceids(self):
resource_ids = list(resource.id for resource in self.resource_client.resources.list_by_resource_group("{0}".format(self.resource_group)) if resource.id.find("latest")>=0)
return resource_ids
def getresourcenames(self):
resource_names = list(resource.name for resource in self.resource_client.resources.list_by_resource_group("{0}".format(self.resource_group)) if resource.id.find("latest")>=0)
return resource_names
def deleteoldimages(self,name):
#resource client id for prod
rc = ResourceManagementClient(self.sp,self.prod_subscription_id)
for resource in rc.resources.list_by_resource_group("{0}".format(self.resource_group)):
if resource.name == name:
#2019-12-01 is the latest api_version supported for deleting the resource type "image"
rc.resources.begin_delete_by_id(resource.id,"2020-06-01")
print("deleted {0}".format(resource.name))
def moveimages(self):
rnames = self.getresourcenames()
for rname in rnames:
print(rname)
#self.deleteoldimages(rname)
time.sleep(10)
rids = self.getresourceids()
rid = list(rids[0:])
print(rid)
metadata = azure.mgmt.resource.resources.v2020_06_01.models.ResourcesMoveInfo(resources=rid,target_resource_group='/subscriptions/{0}/resourceGroups/{1}'.format(self.prod_subscription_id,self.resource_group))
#moving resources in the rid from nonprod subscription to prod subscription under the resource group avrc-imgs-rg
if rid != []:
print("moving {0}".format(rid))
print(self.resource_client.resources.move_resources(source_resource_group_name="{0}".format(self.resource_group),parameters=metadata))
#self.resource_client.resources.move_resources(source_resource_group_name="{0}".format(self.resource_group),resources=rid,target_resource_group='/subscriptions/{0}/resourceGroups/{1}'.format(self.prod_subscription_id,self.resource_group))
#self.resource_client.resources.begin_move_resources(source_resource_group_name="{0}".format(self.resource_group),parameters=metadata)
if __name__ == "__main__":
Move().moveimages()
From your inputs we can see that the code looks fine. From your error messages, the problem is with importing the modules.
Basically when we import a module few submodules will get installed along with and few will not. This will depend on the version of the package, to understand which modules are involved in a specific version we need to check for version-releases in official documentation.
In your case, looks like some resource modules were missing, if you could see the entire error-trace, there will be a path with sitepackages in our local. Try to find that package and its subfolder(Modules) and compare them with Azure SDK for Python under Resource module, you can find this here.
In such situation we need to explicitly add those sub modules under our package. In your case you can simple download the packaged code from Git link which I gave and can merge in your local folder.

Unable to import scipy library using Flask & Elastic Beanstalk

I am trying to set up a Flask web app using Elastic Beanstalk on AWS. I have followed the tutorial here and that works fine. I am now looking to expand the Flask webapp, and this works fine, until I import scipy.spatial as spatial, when this is part of my import statements, running eb open just times out. I receive
>>>> HTTP ERROR 504
running the webapp locally works absolutely fine even with the scipy import, it is only when I try and deploy to beanstalk that it doesn't want to work. Below is my code
import os
import requests
from bs4 import BeautifulSoup
import pandas as pd
import scipy.spatial as spatial ##### Removing this and everything works!
from flask import Flask
from flask_cors import CORS
from flask_restful import Resource, Api
from flask_jsonpify import jsonify
# print a nice greeting.
def say_hello(username = "World"):
df = pd.DataFrame({"a":[1,2,3]})
return '<p>Hello %s!</p>\n' % username
# some bits of text for the page.
header_text = '''
<html>\n<head> <title>EB Flask Test</title> </head>\n<body>'''
instructions = '''
<p><em>Hint</em>: This is a RESTful web service! Append a username
to the URL (for example: <code>/Thelonious</code>) to say hello to
someone specific.</p>\n'''
home_link = '<p>Back</p>\n'
footer_text = '</body>\n</html>'
# EB looks for an 'application' callable by default.
application = Flask(__name__)
# add a rule for the index page.
application.add_url_rule('/', 'index', (lambda: header_text +
say_hello() + instructions + footer_text))
# add a rule when the page is accessed with a name appended to the site
# URL.
application.add_url_rule('/<username>', 'hello', (lambda username:
header_text + say_hello(username) + home_link + footer_text))
# run the app.
if __name__ == "__main__":
# Setting debug to True enables debug output. This line should be
# removed before deploying a production app.
application.debug = True
application.run()
I have tried increasing the command timeout for the environment from 600 to 900, although the timeout error occurs well before 600 seconds has elapsed.
Right, I am not sure why this is the case but I updated the version of scipy in my requirements.txt and the app is working as expected!
Originally I had
scipy==1.4.1
Now I have
scipy==1.2.3
I have no idea why this has fixed the deployment issue, especially given 1.4.1 works perfectly locally. If anyone has an idea, or if this a bug I should be reporting it would be good to know!

Python : no JSON object could be decoded

I am trying to run this app:
https://github.com/bmjr/guhTrends
I have python 2.7.x running the following script at command line. I reckon it was written using python3.x. What is deprecated in the code below?
import urllib
import json
import matplotlib.pyplot as plt
dates = urllib.request.urlopen('http://charts.spotify.com/api/tracks/most_streamed/global/weekly/')
dataDates = json.loads(dates.read().decode())
the error:
Traceback (most recent call last):
File "DataMining.py", line 6, in <module>
dates = urllib.request.urlopen('http://charts.spotify.com/api/tracks/most_streamed/global/weekly/')
AttributeError: 'module' object has no attribute 'request'
That script won't work under python2 as urllib of python2 has no request module.
Use urllib2.urlopen instead of urllib.request if you want start running that script under python2 .
To get python script work on bith (python2 and python3) use six module which is Python 2 and 3 Compatibility Library.
from six.moves import urllib
import json
import matplotlib.pyplot as plt
dates = urllib.request.urlopen('http://charts.spotify.com/api/tracks/most_streamed/global/weekly/')
dataDates = json.loads(dates.read().decode())
You're requesting a resource that is not currently available (I'm seeing a 504). Since this could potentially happen any time you request a remote service, always check the status code on the response; it's not that your code is necessarily wrong, in this case it's that you're assuming the response is valid JSON without checking whether the request was successful.
Check the urllib documentation to see how to do this (or, preferably, follow the recommendation at the top of that page and use the requests package instead).

django admin : TclError : Can't find a usable init.tcl

I use django, python 2.7, virtualenv
I try in the admin to open a file with a dialogbox
def import_csv(self, request, queryset):
import csv
from Tkinter import *
from tkFileDialog import *
fileName = askopenfilename()
I have the error :
Can't find a usable init.tcl in the following directories:
C:/Python27/lib/tcl8.5 C:/mat4/env/lib/tcl8.5 C:/mat4/lib/tcl8.5 C:/mat4/env/library C:/mat4/library C:/mat4/tcl8.5.2/library C:/tcl8.5.2/library
This probably means that Tcl wasn't installed properly.
I tried to use easygui but it is the same
How to fix this error ?
This can't possibly work. Django is a web framework. You can't run a desktop GUI like Tkinter in a website.
You need to create a web form with a file field and a view to process the upload.

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