I am trying to use Python and Beautifulsoup to get this page from sfglobe website: http://sfglobe.com/2015/04/28/stirring-pictures-from-the-riots-in-baltimore.
This is the code:
import urllib2
from bs4 import BeautifulSoup
url = 'http://sfglobe.com/2015/04/28/stirring-pictures-from-the-riots-in-baltimore'
req = urllib2.urlopen(url)
html = req.read()
soup = BeautifulSoup(html)
desc = soup.find('span', class_='articletext intro')
Could anyone help me to solve this problem?
From the question title, I assuming that the only thing you want is the description of the article, which can be found in the <meta> tag within the HTML <head>.
You were on the right track, but I'm not exactly sure why you did:
desc = soup.find('span', class_='articletext intro')
Regardless, I came up with something using requests (see http://stackoverflow.com/questions/2018026/should-i-use-urllib-or-urllib2-or-requests) rather than urllib2
import requests
from bs4 import BeautifulSoup
url = 'http://sfglobe.com/2015/04/28/stirring-pictures-from-the-riots-in-baltim\
ore'
req = requests.get(url)
html = req.text
soup = BeautifulSoup(html)
tag = soup.find(attrs={'name':'description'}) # find meta tag w/ description
desc = tag['value'] # get value of attribute 'value'
print desc
If that isn't what you are looking for, please clarify so I can try and help you more.
EDIT: after some clarification, I pieced together why you were originally using desc = soup.find('span', class_='articletext intro').
Maybe this is what you are looking for:
import requests
from bs4 import BeautifulSoup, NavigableString
url = 'http://sfglobe.com/2015/04/28/stirring-pictures-from-the-riots-in-baltimore'
req = requests.get(url)
html = req.text
soup = BeautifulSoup(html)
body = soup.find('span', class_='articletext intro')
# remove script tags
[s.extract() for s in body('script')]
text = ""
# iterate through non-script elements in the content body
for stuff in body.select('*'):
# get contents of tags, .contents returns a list
content = stuff.contents
# check if the list has the text content a.k.a. isn't empty AND is a NavigableString, not a tag
if len(content) == 1 and isinstance(content[0], NavigableString):
text += content[0]
print text
Related
Seems like i can scrape any tag and class, except h3 on this page. It keeps returning None or an empty list. I'm trying to get this h3 tag:
...on the following webpage:
https://www.empireonline.com/movies/features/best-movies-2/
And this is the code I use:
from bs4 import BeautifulSoup
import requests
from pprint import pprint
from bs4 import BeautifulSoup
URL = "https://www.empireonline.com/movies/features/best-movies-2/"
response = requests.get(URL)
web_html = response.text
soup = BeautifulSoup(web_html, "html.parser")
movies = soup.findAll(name = "h3" , class_ = "jsx-4245974604")
movies_text=[]
for item in movies:
result = item.getText()
movies_text.append(result)
print(movies_text)
Can you please help with the solution for this problem?
As other people mentioned this is dynamic content, which needs to be generated first when opening/running the webpage. Therefore you can't find the class "jsx-4245974604" with BS4.
If you print out your "soup" variable you actually can see that you won't find it. But if simply you want to get the names of the movies you can just use another part of the html in this case.
The movie name is in the alt tag of the picture (and actually also in many other parts of the html).
import requests
from pprint import pprint
from bs4 import BeautifulSoup
URL = "https://www.empireonline.com/movies/features/best-movies-2/"
response = requests.get(URL)
web_html = response.text
soup = BeautifulSoup(web_html, "html.parser")
movies = soup.findAll("img", class_="jsx-952983560")
movies_text=[]
for item in movies:
result = item.get('alt')
movies_text.append(result)
print(movies_text)
If you run into this issue in the future, remember to just print out the initial html you can get with soup and just check by eye if the information you need can be found.
I'm trying to get the plain text of a website article using python. I've heard about the BeautifulSoup library, but how to retrieve a specific tag in html page?
This is what I have done:
base_url = 'http://www.nytimes.com'
r = requests.get(base_url)
soup = BeautifulSoup(r.text, "html.parser")
Look this:
import bs4 as bs
import requests as rq
html = rq.get('site.com')
s = bs.BeautifulSoup(html.text, features="html.parser")
div = s.find('div', {'class': 'yourclass'}) # or id
print(str(div.text)) # print text
I want to extract the text here
a lot of text
I used
url = ('https://osu.ppy.sh/users/1521445')
page = requests.get(url, headers=headers)
soup = BeautifulSoup(page.content, 'html.parser')
mestuff = soup.find("div", {"class":"bbcode bbcode--profile-page"})
but it never fails to return with "None" in the terminal.
How can I go about this?
Link is "https://osu.ppy.sh/users/1521445"
(This is a repost since the old question was super old. I don't know if I should've made another question or not but aa)
Data is dynamically loaded from script tag so, as in other answer, you can grab from that tag. You can target the tag by its id then you need to pull out the relevant json, then the html from that json, then parse html which would have been loaded dynamically on page (at this point you can use your original class selector)
import requests, json, pprint
from bs4 import BeautifulSoup as bs
r = requests.get('https://osu.ppy.sh/users/1521445')
soup = bs(r.content, 'lxml')
all_data = json.loads(soup.select_one('#json-user').text)
soup = bs(all_data['page']['html'], 'lxml')
pprint.pprint(soup.select_one('.bbcode--profile-page').get_text('\n'))
You could try this:
url = ('https://osu.ppy.sh/users/1521445')
page = requests.get(url)
soup = BeautifulSoup(page.content, 'html.parser')
x = soup.findAll("script",{"id":re.compile(r"json-user")})
result = re.findall('raw\":(.+)},\"previous_usernames', x[0].text.strip())
print(result)
Im not sure why the div with class='bbcode bbcode--profile-page' is string inside script tag with class='json-user', that's why you can't get it's value by div with class='bbcode bbcode--profile-page'
Hope this could help
I'm trying to get the text from a website but can't find a way do to it. How do I need to write it?
link="https://www.ynet.co.il/articles/0,7340,L-5553905,00.html"
response = requests.get(link)
soup = BeautifulSoup(response.text,'html.parser')
info = soup.find('div', attrs={'class':'text14'})
name = info.text.strip()
print(name)
This is how it looks:
i'm getting none everytime
import requests
from bs4 import BeautifulSoup
import json
link="https://www.ynet.co.il/articles/0,7340,L-5553905,00.html"
response = requests.get(link)
soup = BeautifulSoup(response.text,'html.parser')
info = soup.findAll('script',attrs={'type':"application/ld+json"})[0].text.strip()
jsonDict = json.loads(info)
print(jsonDict['articleBody'])
The page seems to store all the article data in json in the <script> tag so try this code.
The solution is :
info = soup.find('meta', attrs={'property':'og:description'})
It gave me the text i needed
I'm coding a script to get all the links from the divs with a class="pntc-txt" and after I want to get from the <a> tags the href attribute and also the text between the Something. For after take that url and text and insert them in a database. I'll post the code that I've done so far:
import urllib.request
from bs4 import *
sock = urllib.request.urlopen("http://as.com/tag/moto_gp/a/")
htmlSource = sock.read()
sock.close()
soup = BeautifulSoup(htmlSource)
for div in soup.findAll('div', {'class': 'pntc-txt'}):
a = div.findAll('a')
print (a)
Try this:
import requests
from bs4 import *
srcCode = requests.get("http://as.com/tag/moto_gp/a/")
plainText = srcCode.text
soup = BeautifulSoup(plainText)
for div in soup.findAll('div', {'class': 'pntc-txt'}):
for each in div.findAll('a'): #get all elements with 'a' tag
href = each.get('href')
print href #print href
print each.string #print the text in tags
print each #print whole tag
Note: also removed the urllib part to read the html page. Instead used package requests