infile1 = open("D:/p/non_rte_header_path.txt","r")
infile2 = open("D:/p/fnsinrte.txt","r")
for line in infile1:
for item in infile2:
eachfile = open(line,"r")
For the above code I am getting the below error. infile1 contains paths of may files like D:/folder/Src/em.h but here \n is automatically at the end of the path.I am not sure why it happens. Please help.
IOError: [Errno 22] invalid mode ('r') or filename: 'D:/folder/Src/em.h\n'
Everyone has provided comments telling you what the problem is but if you are a beginner you probably don't understand why it's happening, so i'll explain that.
Basicly, when opening a file with python, each new line (when you press the Enter Key) is represented by a "\n".
As you read the file, it reads line by line, but unless you remove the "\n", it your line variable will read
thethingsonthatline\n
This can be useful to see if a file contains multiple lines, but you'll want to get rid of it. Edchum and alvits has given a good way of doing this !
Your corrected code would be :
infile1 = open("D:/p/non_rte_header_path.txt","r")
infile2 = open("D:/p/fnsinrte.txt","r")
for line in infile1:
for item in infile2:
eachfile = open(line.rstrip('\n'), "r")
Related
I am stuck on this revision exercise which asks to copy an input file to an output file and return the first and last letters.
def copy_file(filename):
input_file = open(filename, "r")
content = input_file.read()
content[0]
content[1]
return content[0] + content[-1]
input_file.close()
Why do I get an error message which I try get the first and last letters? And how would I copy the file to the output file?
Here is the test:
input_f = "FreeAdvice.txt"
first_last_chars = copy_file(input_f)
print(first_last_chars)
print_content('cure737.txt')
Error Message:
FileNotFoundError: [Errno 2] No such file or directory: 'hjac737(my username).txt'
All the code after a return statement is never executed, a proper code editor would highlight it to you, so I recommend you use one. So the file was never closed. A good practice is to use a context manager for that : it will automatically call close for you, even in case of an exception, when you exit the scope (indentation level).
The code you provided also miss to write the file content, which may be causing the error you reported.
I explicitely used the "rt" (and "wt") mode for the files (althought they are defaults), because we want the first and last character of the file, so it supports Unicode (any character, not just ASCII).
def copy_file(filename):
with open(filename, "rt") as input_file:
content = input_file.read()
print(input_file.closed) # True
my_username = "LENORMJU"
output_file_name = my_username + ".txt"
with open(output_file_name, "wt") as output_file:
output_file.write(content)
print(output_file.closed) # True
# last: return the result
return content[0] + content[-1]
print(copy_file("so67730842.py"))
When I run this script (on itself), the file is copied and I get the output d) which is correct.
I have a set of placemarks, which include quite a wide description included in its balloon within the property. Next each single description (former column header) is bounded in . Because of the shapefile naming restriction to 10 characters only.
https://gis.stackexchange.com/questions/15784/bypassing-10-character-limit-of-field-name-in-shapefiles
I have to retype most of these names manually.
Obviously, I use Notepad++, where I can swiftly press Ctrl+F and toggle Replace mode, as you can see below.
The green bounded strings were already replaced, the red ones still remain.
Basically, if I press "Replace All" then it works fine and quickly. Unfortunately, I have to go one by one. As you can see I have around 20 separate strings to "Replace all". Is there a possibility to do it quicker? Because all the .kml files are similar to each other, this is going to be the same everywhere. I need some tool, which will be able to do auto-replace for these headers cut by 10 characters limit. I think, that maybe Python tools might be helpful.
https://pythonhosted.org/pykml/
But in the tool above there is no information about bulk KML editing.
How can I set something like the "Replace All" tool for all my strings preferably if possible?
UPDATE:
I tried the code below:
files = []
with open("YesNF016.kml") as f:
for line in f.readlines():
if line[-1] == '\n':
files.append(line[:-1])
else:
files.append(line)
old_expression = 'ab'
new_expression = 'it worked'
for file in files:
new_file = ""
with open(file) as f:
for line in f.readlines():
new_file += line.replace(old_expression, new_expression)
with open(file, 'w') as f:
f.write(new_file)
The debugger shows:
[Errno 22] Invalid argument: ''
File "\test.py", line 13, in
with open(file) as f:
whereas line 13 is:
with open(file) as f:
The solutions here:
https://www.reddit.com/r/learnpython/comments/b9cljd/oserror_while_using_elementtree_to_parse_simple/
and
OSError: [Errno 22] Invalid argument Getting invalid argument while parsing xml in python
weren't helpful enough for me.
So you want to replace all occurence of X to Y in bunch of files ?
Pretty easy.
Just create a file_list.txt containing the list of files to edit.
python code:
files = []
with open("file_list.txt") as f:
for line in f.readlines():
if line[-1] == '\n':
files.append(line[:-1])
else:
files.append(line)
old_expression = 'ab'
new_expression = 'it worked'
for file in files:
new_file = ""
with open(file) as f:
for line in f.readlines():
new_file += line.replace(old_expression, new_expression)
with open(file, 'w') as f:
f.write(new_file)
Goal = Open file, encrypt file, write encrypted file.
Trying to use the PyPDF2 module to accomplish this. I have verified theat "input" is a file type object. I have researched this error and it translates to "file not found". I believe that it is linked somehow to the file/file path but am unsure how to debug or troubleshoot. and getting the following error:
Traceback (most recent call last):
File "CommissionSecurity.py", line 52, in <module>
inputStream = PyPDF2.PdfFileReader(input)
File "build\bdist.win-amd64\egg\PyPDF2\pdf.py", line 1065, in __init__
File "build\bdist.win-amd64\egg\PyPDF2\pdf.py", line 1660, in read
IOError: [Errno 22] Invalid argument
Below is the relevant code. I'm not sure how to correct this issue because I'm not really sure what the issue is. Any guidance is appreciated.
for ID in FileDict:
if ID in EmailDict :
path = "C:\\Apps\\CorVu\\DATA\\Reports\\AlliD\\Monthly Commission Reports\\Output\\pdcom1\\"
#print os.listdir(path)
file = os.path.join(path + FileDict[ID])
with open(file, 'rb') as input:
print type(input)
inputStream = PyPDF2.PdfFileReader(input)
output = PyPDF2.PdfFileWriter()
output = inputStream.encrypt(EmailDict[ID][1])
with open(file, 'wb') as outputStream:
output.write(outputStream)
else : continue
I think your problem might be caused by the fact that you use the same filename to both open and write to the file, opening it twice:
with open(file, 'rb') as input :
with open(file, 'wb') as outputStream :
The w mode will truncate the file, thus the second line truncates the input.
I'm not sure what you're intention is, because you can't really try to read from the (beginning) of the file, and at the same time overwrite it. Even if you try to write to the end of the file, you'll have to position the file pointer somewhere.
So create an extra output file that has a different name; you can always rename that output file to your input file after both files are closed, thus overwriting your input file.
Or you could first read the complete file into memory, then write to it:
with open(file, 'rb') as input:
inputStream = PyPDF2.PdfFileReader(input)
output = PyPDF2.PdfFileWriter()
output = input.encrypt(EmailDict[ID][1])
with open(file, 'wb') as outputStream:
output.write(outputStream)
Notes:
you assign inputStream, but never use it
you assign PdfFileWriter() to output, and then assign something else to output in the next line. Hence, you never used the result from the first output = line.
Please check carefully what you're doing, because it feels there are numerous other problems with your code.
Alternatively, here are some other tips that may help:
The documentation suggests that you can also use the filename as first argument to PdfFileReader:
stream – A File object or an object that supports the standard read
and seek methods similar to a File object. Could also be a string
representing a path to a PDF file.
So try:
inputStream = PyPDF2.PdfFileReader(file)
You can also try to set the strict argument to False:
strict (bool) – Determines whether user should be warned of all
problems and also causes some correctable problems to be fatal.
Defaults to True.
For example:
inputStream = PyPDF2.PdfFileReader(file, strict=False)
Using open(file, 'rb') was causing the issue becuase PdfFileReader() does that automagically. I just removed the with statement and that corrected the problem.
with open(file, 'rb') as input:
inputStream = PyPDF2.PdfFileReader(input)
This error raised up because of PDF file is empty.
My PDF file was empty that's why my error was raised up. So First of all i fill my PDF file with some data and Then start reeading it using PyPDF2.PdfFileReader,
And it solved my Problem!!!
Late but, you may be opening an invalid PDF file or an empty file that's named x.pdf and you think it's a PDF file
I am totally new to python.
I was trying to read a file which I already created but getting the below error
File "C:/Python25/Test scripts/Readfile.py", line 1, in <module>
filename = open('C:\Python25\Test scripts\newfile','r')
IOError: [Errno 2] No such file or directory: 'C:\\Python25\\Test scripts\newfile
My code:
filename = open('C:\Python25\Test scripts\newfile','r')
print filename.read()
Also I tried
filename = open('C:\\Python25\\Test scripts\\newfile','r')
print filename.read()
But same errors I am getting.
Try:
fpath = r'C:\Python25\Test scripts\newfile'
if not os.path.exists(fpath):
print 'File does not exist'
return
with open(fpath, 'r') as src:
src.read()
First you validate that file, that it exists.
Then you open it. With wrapper is more usefull, it closes your file, after you finish reading. So you will not stuck with many open descriptors.
I think you're probably having this issue because you didn't include the full filename.
You should try:
filename = open('C:\Python25\Test scripts\newfile.txt','r')
print filename.read()
*Also if you're running this python file in the same location as the target file your are opening, you don't need to give the full directory, you can just call:
filename = open(newfile.txt
I had the same problem. Here's how I got it right.
your code:
filename = open('C:\\Python25\\Test scripts\\newfile','r')
print filename.read()
Try this:
with open('C:\\Python25\\Test scripts\\newfile') as myfile:
print(myfile.read())
Hope it helps.
I am using VS code. If I am not using dent it would not work for the print line. So try to have the format right then you will see the magic.
with open("mytest.txt") as myfile:
print(myfile.read())
or without format like this:
hellofile=open('mytest.txt', 'r')
print(hellofile.read())
I'm having a problem opening the names.txt file. I have checked that I am in the correct directory. Below is my code:
import os
print(os.getcwd())
def alpha_sort():
infile = open('names', 'r')
string = infile.read()
string = string.replace('"','')
name_list = string.split(',')
name_list.sort()
infile.close()
return 0
alpha_sort()
And the error I got:
FileNotFoundError: [Errno 2] No such file or directory: 'names'
Any ideas on what I'm doing wrong?
You mention in your question body that the file is "names.txt", however your code shows you trying to open a file called "names" (without the ".txt" extension). (Extensions are part of filenames.)
Try this instead:
infile = open('names.txt', 'r')
As a side note, make sure that when you open files you use universal mode, as windows and mac/unix have different representations of carriage returns (/r/n vs /n etc.). Universal mode gets python to handle this, so it's generally a good idea to use it whenever you need to read a file. (EDIT - should read: a text file, thanks cameron)
So the code would just look like this
infile = open( 'names.txt', 'rU' ) #capital U indicated to open the file in universal mode
This doesn't solve that issue, but you might consider using with when opening files:
with open('names', 'r') as infile:
string = infile.read()
string = string.replace('"','')
name_list = string.split(',')
name_list.sort()
return 0
This closes the file for you and handles exceptions as well.