Django sorl-thumbnail don't store files in my app - python

I read several topics here about this problem, but I can't manage to resolve it. Everybody asks if the MEDIA_ROOT config is okay, and other answer "yes sure!" But I did not find a real explanation, so:
I can see the generated filename (from db) in my template (a pdf genreated by weasyprint) :
/media/ cache/92/00/9200d02288657e7accae5666d37188a1.jpg
The object.exists in the thumbnail template tags returns, without surprise, False.
The file isn't generated.
In my settings.py I have this config :
MEDIA_URL = '/media/'
MEDIA_ROOT = os.path.join(BASE_DIR, 'media')
That worked fine with a basically FileUpload field.
I think I just don't understand the path configuration of MEDIA stuff.
Some explanations on good practices about dealing with MEDIA will be welcome !
EDIT : I uninstalled sorl-thumbnail and now use easy-thumbnails.

Related

Django setting debug=False breaks href links

I am developing a website using Django framework. It works perfectly well using Django=True, however when I set Django=False, system could not find the other html files which are being accessed in <a href=... links.
Let say, I am developing 'mysite', then the following code:
<li><i class="fab fa-dribbble"></i></li>
is present behind an icon on mysite. Then clicking the icon takes the user to 'mysite.com/index-2.html', however it throws "The requested resource was not found on this server" error.
And this happens only when we set Django=False and in production. No link on the homepage is working due to this.
EDIT-1:
I've already reviewed:
Why does DEBUG=False setting make my django Static Files Access fail?
The static files are already working fine on my app because they are in 'assets' folder. The html files are in the root folder and somehow system is not able to find any file from root folder when debug is set to False. So my question is more regarding finding files at root folder using href links.
No error for files in 'assets' folder, but 404 for root folder files:
try using onclick function instead of href
and In static files you have add some configration to serve the static files in django.
STATIC_ROOT = os.path.join(BASE_DIR, 'staticfiles')
STATIC_URL = '/static/'
#STATIC_ROOT = os.path.join(BASE_DIR, 'static/')
# add manual
STATICFILES_DIRS = [
os.path.join(BASE_DIR, 'static')
]
MEDIA_ROOT = os.path.join(BASE_DIR,'static/images/')
MESSAGE_TAGS = {
messages.ERROR: 'danger'
}
if this is work please contact me , I found this from freelance app
To resolve this, I added specific functions for each of the .html files in views.py file and added link of the function to main html file.
For example:
I added following to my views.py file:
def about(request):
return render(request,'about.html')
and used as follows in index.html:
href = '\about'
Doing this for all used html files resolved the issue for both debug=True and debug=False. Not sure if this is the best way but working for now.

Sending Email with Image inside the body of the html - Django [duplicate]

I'm new to Django and I'm trying to learn it through a simple project I'm developing called 'dubliners' and an app called 'book'. The directory structure is like this:
dubliners/book/ [includes models.py, views.py, etc.]
dubliners/templates/book/
I have a JPG file that needs to be displayed in the header of each Web page. Where should I store the file? Which path should I use for the tag to display it using a template? I've tried various locations and paths, but nothing is working so far.
...
Thanks for the answer posted below. However, I've tried both relative and absolute paths to the image, and I still get a broken image icon displayed in the Web page. For example, if I have an image in my home directory and use this tag in my template:
<img src="/home/tony/london.jpg" />
The image doesn't display. If I save the Web page as a static HTML file, however, the images display, so the path is correct. Maybe the default Web server that comes with Django will display images only if they're on a particular path?
Try this,
settings.py
# typically, os.path.join(os.path.dirname(__file__), 'media')
MEDIA_ROOT = '<your_path>/media'
MEDIA_URL = '/media/'
urls.py
urlpatterns = patterns('',
(r'^media/(?P<path>.*)$', 'django.views.static.serve',
{'document_root': settings.MEDIA_ROOT}),
)
.html
<img src="{{ MEDIA_URL }}<sub-dir-under-media-if-any>/<image-name.ext>" />
Caveat
Beware! using Context() will yield you an empty value for {{MEDIA_URL}}. You must use RequestContext(), instead.
I hope, this will help.
In production, you'll just have the HTML generated from your template pointing to wherever the host has media files stored. So your template will just have for example
<img src="../media/foo.png">
And then you'll just make sure that directory is there with the relevant file(s).
during development is a different issue. The django docs explain it succinctly and clearly enough that it's more effective to link there and type it up here, but basically you'll define a view for site media with a hardcoded path to location on disk.
Right here.
I do understand, that your question was about files stored in MEDIA_ROOT, but sometimes it can be possible to store content in static, when you are not planning to create content of that type anymore.
May be this is a rare case, but anyway - if you have a huge amount of "pictures of the day" for your site - and all these files are on your hard drive?
In that case I see no contra to store such a content in STATIC.
And all becomes really simple:
static
To link to static files that are saved in STATIC_ROOT Django
ships with a static template tag. You can use this regardless if
you're using RequestContext or not.
{% load static %} <img src="{% static "images/hi.jpg" %}" alt="Hi!" />
copied from Official django 1.4 documentation / Built-in template tags and filters
In development
In your app folder create folder name 'static' and save your picture in that folder.
To use picture use:
<html>
<head>
{% load staticfiles %} <!-- Prepare django to load static files -->
</head>
<body>
<img src={% static "image.jpg" %}>
</body>
</html>
In production:
Everything same like in development, just add couple more parameters for Django:
add in settings.py STATIC_ROOT = os.path.join(BASE_DIR, "static/")(this will prepare folder where static files from all apps will be stored)
be sure your app is in INSTALLED_APPS = ['myapp',]
in terminall run command python manage.py collectstatic (this will make copy of static files from all apps included in INSTALLED_APPS to global static folder - STATIC_ROOT folder )
Thats all what Django need, after this you need to make some web server side setup to make premissions for use static folder. E.g. in apache2 in configuration file httpd.conf (for windows) or sites-enabled/000-default.conf. (under site virtual host part for linux) add:
Alias \static "path_to_your_project\static"
Require all granted
And that's all
I have spent two solid days working on this so I just thought I'd share my solution as well. As of 26/11/10 the current branch is 1.2.X so that means you'll have to have the following in you settings.py:
MEDIA_ROOT = "<path_to_files>" (i.e. /home/project/django/app/templates/static)
MEDIA_URL = "http://localhost:8000/static/"
*(remember that MEDIA_ROOT is where the files are and MEDIA_URL is a constant that you use in your templates.)*
Then in you url.py place the following:
import settings
# stuff
(r'^static/(?P<path>.*)$', 'django.views.static.serve',{'document_root': settings.MEDIA_ROOT}),
Then in your html you can use:
<img src="{{ MEDIA_URL }}foo.jpg">
The way django works (as far as I can figure is:
In the html file it replaces MEDIA_URL with the MEDIA_URL path found in setting.py
It looks in url.py to find any matches for the MEDIA_URL and then if it finds a match (like r'^static/(?P.)$'* relates to http://localhost:8000/static/) it searches for the file in the MEDIA_ROOT and then loads it
/media directory under project root
Settings.py
BASE_DIR = os.path.dirname(os.path.dirname(__file__))
MEDIA_URL = '/media/'
MEDIA_ROOT = os.path.join(BASE_DIR, 'media')
urls.py
urlpatterns += patterns('django.views.static',(r'^media/(?P<path>.*)','serve',{'document_root':settings.MEDIA_ROOT}), )
template
<img src="{{MEDIA_URL}}/image.png" >
If your file is a model field within a model, you can also use ".url" in your template tag to get the image.
For example.
If this is your model:
class Foo(models.Model):
foo = models.TextField()
bar = models.FileField(upload_to="foo-pictures", blank = True)
Pass the model in context in your views.
return render (request, "whatever.html", {'foo':Foo.objects.get(pk = 1)})
In your template you could have:
<img src = "{{foo.bar.url}}">
Your
<img src="/home/tony/london.jpg" />
will work for a HTML file read from disk, as it will assume the URL is file:///home/.... For a file served from a webserver though, the URL will become something like: http://www.yourdomain.com/home/tony/london.jpg, which can be an invalid URL and not what you really mean.
For about how to serve and where to place your static files, check out this document. Basicly, if you're using django's development server, you want to show him the place where your media files live, then make your urls.py serve those files (for example, by using some /static/ url prefix).
Will require you to put something like this in your urls.py:
(r'^site_media/(?P<path>.*)$', 'django.views.static.serve',
{'document_root': '/path/to/media'}),
In production environment you want to skip this and make your http server (apache, lighttpd, etc) serve static files.
Another way to do it:
MEDIA_ROOT = '/home/USER/Projects/REPO/src/PROJECT/APP/static/media/'
MEDIA_URL = '/static/media/'
This would require you to move your media folder to a sub directory of a static folder.
Then in your template you can use:
<img class="scale-with-grid" src="{{object.photo.url}}"/>
I tried various method it didn't work.But this worked.Hope it will work for you as well. The file/directory must be at this locations:
projec/your_app/templates
project/your_app/static
settings.py
import os
PROJECT_DIR = os.path.realpath(os.path.dirname(_____file_____))
STATIC_ROOT = '/your_path/static/'
example:
STATIC_ROOT = '/home/project_name/your_app/static/'
STATIC_URL = '/static/'
STATICFILES_DIRS =(
PROJECT_DIR+'/static',
##//don.t forget comma
)
TEMPLATE_DIRS = (
PROJECT_DIR+'/templates/',
)
proj/app/templates/filename.html
inside body
{% load staticfiles %}
//for image
img src="{% static "fb.png" %}" alt="image here"
//note that fb.png is at /home/project/app/static/fb.png
If fb.png was inside /home/project/app/static/image/fb.png then
img src="{% static "images/fb.png" %}" alt="image here"
I've had the hardest time figuring this out so I am making this post to explain as clearly as i can, what worked for me, to help someone else.
Let's say you have a project called project_name. and an app called app_name. your root directory should look like this:
/app_name
/project_name
manage.py
DEVELOPMENT.
while in development mode, your CSS and JS files should be inside ./app_name/static/app_name/..
however your images should be inside ./app_name/static/media/..
now add these to settings.py :
If this not already there, add
STATIC_URL = '/static/'
This tells Django where to find all the static files.
MEDIA_URL = '/media/'
This points Django to the folder where your images are, after it loads static. In this case it is /media/ because our images are in /static/media.
next, you should put this in the individual template where you need the image (I thought putting a single {% load static %} in the general layout.html template would suffice, it didn't):
{% load static %}
<img src="{% static image_name %}>
depending on how you set up your project, image_name could be the exact name of the image file like "image.jpg", a variable for an image field like user.image etc
lastly, go into the project_name urls.py (same folder as settings.py) and add this line to the end:
from django.conf import settings
from django.conf.urls.static import static
if settings.DEBUG:
urlpatterns += static(settings.MEDIA_URL, document_root=settings.MEDIA_ROOT)
basically telling Django to use a work around so you can see use the images in development.
That is all. your project will now display images while you are writing and testing your code(development)
PRODUCTION.
When you want to deploy your project, there are some extra steps you need to take.
Because Django does not serve images as static files during production, you have to install a Middleware called Whitenoise.
http://whitenoise.evans.io/en/stable/#installation
pip install whitenoise
Then add the following to settings.py:
look for MIDDLEWARE and add just under django.middleware.security.SecrutiyMiddleware:
'whitenoise.middleware.WhiteNoiseMiddleware',
Next we have to define our paths, this is because in production Django will basically collect all the static files from all our apps and rearrange them in a single folder.
Add the following to settings.py:
STATIC_ROOT = os.path.join(BASE_DIR, 'static')
This tells Django where to put static files when it collects them. In this case we are telling Django to put the files in the root folder. so after collectstatic runs our app would look like
/app_name
/project_name
/static
manage.py
Then add:
MEDIA_ROOT = os.path.join(BASE_DIR, 'media')
This tells django where to put files that a user who on our site uploads..
Next,we want to go up and change Debug to False.
Debug = False
Debug mode is used for testing in development, and in production you don't want your app displaying error codes and the names of files and lines where something went wrong. potential security threat. Once you turn debug mode to false, Django changes how it serves the static files. so ordinarily, if you were to run your app now, you won't see the images..
with these done, now you are ready for production. to test that everything is okay, you can run:
python manage.py collectstatic
(type yes if prompted)
Django will collect all the static files and arrange them as necessary. if you run your project now, with debug still turned off you should see your images. you can even now delete the individual static folders in app_name or any other apps you have, if you want because Django will not use them in production. Once debug is off, Django only uses static from the collected static folder.
You can now deploy your project
If you give the address of online image in your django project it will work.
that is working for me. You should take a shot.
Also check that the problem may not be due to path, but file name or extension. While failing to dislay an image added to base.html template, the error was found related to image file extension. If you are storing the image in jpeg format, use .jpg as the extension in the img tag
<img src="{% static 'logo.jpg' %}" alt="Logo">.
Just give a try copying static folder from base path to public_html folder.
cp -r static/ ~/public_html/

MEDIA_ROOT django read and delete

I'm working on a Django application, which permits to manage music files (upload, read, delete, ...).
I'm using MEDIA_ROOT system for the music uploads, which works perfectly !
But, to read or delete a file in MEDIA_ROOT, I don't know ... (except with variable in script..).
For example, if I need to read a music with Mplayer, my actual solution in views.py :
media_root = "/home/music/"
command = ("sudo /usr/bin/mplayer "+media_root)
path = music.path
p = subprocess.Popen(command+str(music.path), shell=True)
Is there any (secure) way to access to the MEDIA_ROOT from views.py / models.py ??
Thanks
You can access the settings by simply doing
from django.conf import settings
settings.MEDIA_URL
https://docs.djangoproject.com/en/dev/topics/settings/#using-settings-in-python-code

django ImageField not uploading the file

So i've been googling this issue for the past hour and can't come up with a solution. Basically this is it: in my model.py i have a class that has this
class Case(models.Model):
zoomOutImage = models.ImageField('Label', upload_to="zoomOutImage")
and in my settings.py i have my media URL/ROOT set up like this
MEDIA_ROOT = os.path.join(os.path.abspath(''),'app/static/ds/')
MEDIA_URL = '/static/ds/'
which from the webserver should serve out like this:
http://127.0.0.1:8000/static/ds/zoomOutImage/actinic_granuloma_3.jpg
I've installed PIL (inside virtualENV) and there are no errors in uploading, the only issue is when i try uploading the file via the admin panel nothing happens. No errors nothing. The file just simply doesn't get uploaded to the zoomOutImage folder by the development server. Can anyone point me towards why?
I guess your file is in a subdir of your root, subdir named 'zoomOutImage'. Or even a file called like that in the root. I remember putting a function call in the upload to string. That function creates a path and filename, using os.join and the filename from the instance. Doing this by head, no example code available right now. But must be able to google this.
Look here https://stackoverflow.com/questions/1190697/django-filefield-with-upload-to-determined-at-runtime
And by the way, I totally disagree with your answer, you should NEVER use absolute paths in your settings! See this answer use css in django 1.4 development for how to use the correct settings and refer to your Project PATH
EDIT (after reading your own answer)
Guess you are missing this first step:
this is the path to your settings.py file:
SETTINGS_DIR = os.path.dirname(os.path.realpath(__file__))
and than this is the path to your project dir: (I Am using buildout, so call it buildout, but it's the root of your project):
BUILDOUT_DIR = os.path.abspath(os.path.join(SETTINGS_DIR, '..'))
and from there on you can define everything you want:
STATIC_ROOT = os.path.join(BUILDOUT_DIR, 'var', 'static')
STATIC_URL = '/static_media/'
MEDIA_ROOT = os.path.join(BUILDOUT_DIR, 'var', 'media')
MEDIA_URL = '/media/'
and in your template file refer to the image like:
<img src="{{MEDIA_URL}}{{ case.zoomOutImage }}" width="100%">
when your object given to the template is called case
about your question of the urls.
you should add this:
if settings.DEBUG:
urlpatterns += patterns('',
(r'', include('staticfiles.urls')),
)
and see the link above to the question about using css, it's the same problem, but there for finding the css files during development. It's all about the static file places.
import os
# get abspath
def rel(*x):
return os.path.join(os.path.abspath(os.path.dirname(__file__)), *x)
MEDIA_ROOT = rel('media')
MEDIA_URL = '/media/'
STATIC_URL = '/static/'
STATIC_ROOT = '' #if only your static files are in project folder
STATICFILES_DIRS = ( rel('static'),) #if only your static files are in project folder
use this settings, and everything will work
so i finally solved my problem. For anyone having this issue in the future do the following:
if you're trying to serve static media files locally on the development server use absolute paths for MEDIA_ROOT and MEDIA_URL.

Django "SuspiciousOperation" Error While Deleting Uploaded File

I'm developing in Django on Windows XP using the manage.py runserver command to serve files. Apache isn't involved. When I login to the administration and try to delete a file I get a "SuspiciousOperation" error.
Here's the traceback:
http://dpaste.com/123112/
Here's my full model:
http://dpaste.com/hold/123110/
How can I get rid of this "SuspiciousOperation" error?
EDIT: Here are my media settings:
MEDIA_ROOT = 'C:/Server/Projects/postnzb/static/'
MEDIA_URL = '/static/'
What is your MEDIA_ROOT in settings.py? From the back-trace, it seems you have set your MEDIA_ROOT to /static/.
This error is coming since Django is trying to access /static/ to which it has no access. Put an absolute pathname for MEDIA_ROOT like C:/Documents/static/ and give full permissions to Django to access that directory.
That should solve your problem.
Addendum: Since your MEDIA_ROOT seems to be OK, I am guessing that you are using MEDIA_URL for deleting the file instead of MEDIA_ROOT. Indeed, from the error it seems that Django was trying to access the /static/files/8.nzb and was denied access. Clearly, /static/ is your MEDIA_URL and not your MEDIA_ROOT. The model methods should never try accessing the files using the MEDIA_URL. I am sure a review of your code will spot the error.
Update: I skimmed your code and it seems you are setting File.nzb to %(1)sfiles/%(2)s.nzb' % {'1': settings.MEDIA_URL, '2': self.pk} which uses its MEDIA_URL and then in the delete() method you are calling the delete() method of the super-class of File as super(File, self).delete() which is obviously wrong as it will try deleting File.nzb and will try accessing the file through the MEDIA_URL. Fixing that will get rid of the error. I will leave the exact solution as an exercise to you :)

Categories

Resources