I wrote code which opens an excel file and iterates through each row and passes the value to another function.
import openpyxl
wb = load_workbook(filename='C:\Users\xxxxx')
for ws in wb.worksheets:
for row in ws.rows:
print row
x1=ucr(row[0].value)
row[1].value=x1 # i am having error at this point
I am getting the following error when I tried to run the file.
TypeError: IndexError: tuple index out of range
Can I write the returned value x1 to the row[1] column. Is it possible to write to excel (i.e using row[1]) instead of accessing single cells like ws.['c1']=x1
Try this:
import openpyxl
wb = load_workbook(filename='xxxx.xlsx')
ws = wb.worksheets[0]
ws['A1'] = 1
ws.cell(row=2, column=2).value = 2
This will set Cells A1 and B2 to 1 and 2 respectively (two different ways of setting cell values in a worksheet).
The second method (specifying row and column) is most useful for your situation:
import openpyxl
wb = load_workbook(filename='xxxxx.xlsx')
for ws in wb.worksheets:
for index, row in enumerate(ws.rows, start=1):
print row
x1 = ucr(row[0].value)
ws.cell(row=index, column=2).value = x1
Related
import openpyxl
i=2
workbook= openpyxl.load_workbook()
sheet = workbook.active
for i, cellObj in enumerate (sheet['I'],2):
cellObj.value = '=IF(ISNUMBER(A2)*(A2<>0),A2,IF(ISNUMBER(F2)*(F2<>0),F2,IF(ISBLANK(A2)*ISBLANK(F2)*ISBLANK(H2),0,H2)))'
workbook.save()
Using openpxl, I tried to apply formula to entire column 'I' its not working as per the formula, I wanted formula to start from I2 but its start from I1 and wrong output as well.
I have attached a screenshot.
.
Can someone please correct the code?
Output of print(list(enumerate(sheet['I']))):
You'd probably be better off to do it this way, auto skip row 1 by starting the iteration at row 2 and update the formula using the cell row number.
import openpyxl
excelfile = 'foo.xlsx'
workbook= openpyxl.load_workbook(excelfile)
sheet = workbook.active
mr = sheet.max_row # Last row to add formula to
for row in sheet.iter_rows(min_col=9, max_col=9, min_row=2, max_row=mr):
for cell in row:
cr = cell.row # Get the current row number to use in formula
cell.value = f'=IF(ISNUMBER(A{cr})*(A{cr} <> 0), A{cr}, IF(ISNUMBER(F{cr})*(F{cr} <> 0), F{cr}, IF(ISBLANK(A{cr})*ISBLANK(F{cr})*ISBLANK(H{cr}), 0, H{cr})))'
workbook.save(excelfile)
If you know the from and to row numbers, then you can use it like this:
from openpyxl import load_workbook
wb = load_workbook(filename="/content/sample_data/Book1.xlsx")
ws = wb.active
from_row = 2
to_row = 4
for i in range(from_row, to_row+1):
ws[f"C{i}"] = f'=_xlfn.CONCAT(A{i}, "_", B{i})'
wb.save("/content/sample_data/formula.xlsx")
Input (Book1.xlsx):
Output (formula.xlsx):
I don't have your data, so I did not test the following formula; but your formula can be translated to format string as:
for i in range(from_row, to_row+1):
ws[f"I{i}"] = f'=IF(ISNUMBER(A{i})*(A{i}<>0),A{i},IF(ISNUMBER(F{i})*(F{i}<>0),F{i},IF(ISBLANK(A{i})*ISBLANK(F{i})*ISBLANK(H{i}),0,H{i})))'
It formats the formula as:
=IF(ISNUMBER(A2)*(A2<>0),A2,IF(ISNUMBER(F2)*(F2<>0),F2,IF(ISBLANK(A2)*ISBLANK(F2)*ISBLANK(H2),0,H2)))
=IF(ISNUMBER(A3)*(A3<>0),A3,IF(ISNUMBER(F3)*(F3<>0),F3,IF(ISBLANK(A3)*ISBLANK(F3)*ISBLANK(H3),0,H3)))
=IF(ISNUMBER(A4)*(A4<>0),A4,IF(ISNUMBER(F4)*(F4<>0),F4,IF(ISBLANK(A4)*ISBLANK(F4)*ISBLANK(H4),0,H4)))
I'm trying to import data from multiple sheets to another in excel, and in order to do this I need python to input the data into the first empty cell, instead of overwriting the data from the last file. It seems to almost work, however, each column is jumping to its "own" empty row, and not staying in the correct row with the rest of its matching data, creating a staircase type pattern.
This is my code
import os
import openpyxl
os.chdir('C:\\Users\\XX\\Desktop')
wb1 = openpyxl.load_workbook('Test file python.xlsx', data_only = True) #open source excel file
ws1 = wb1.worksheets[0]
wb2 = openpyxl.load_workbook('test3.xlsx', data_only = True) #destination excel file
ws2 = wb2.active
#row_offset = ws2.max_row + 1
for i in range(10,150):
for j in range(3,13):
c = ws1.cell(row = i, column = j)
rowOffset = ws2.max_row + 1
rowNum = rowOffset
ws2.cell(row = rowNum, column = j-2).value = c.value
wb2.save('test3.xlsx')
Here is a screenshot of the output in excel Staircase output
You are changing ws2.max_row each time you put something in ws2 (i.e. - ws2.cell(row = rowNum, column = j-2).value = c.value) your max_row goes up by one affecting the entire loop creating that effect.
use current_row = ws2.max_row outside of the nested loop and it should fix your "staircase" issue.
Also, mind that when you run in the first iteration max_row == 1 that is why your sheet starts at row 2 and not at row 1.
I would like to get a specific row from Workbook 1 and append it after the existing data in Workbook 2.
The code that I tried so far can be found down below:
import openpyxl as xl
from openpyxl.utils import range_boundaries
min_cols, min_rows, max_cols, max_rows = range_boundaries('A:GH')
#Take source file
source = r"C:\Users\Desktop\Python project\Workbook1.xlsx"
wb1 = xl.load_workbook(source)
ws1 = wb1["P2"] #get the needed sheet
#Take destination file
destination = r"C:\Users\Desktop\Python project\Workbook2.xlsx"
wb2 = xl.load_workbook(destination)
ws2 = wb2["A3"] #get the needed sheet
row_data = 0
#Get row & col position and store it in row_data & col_data
for row in ws1.iter_rows():
for cell in row:
if cell.value == "Positive":
row_data += cell.row
for row in ws1.iter_rows(min_row=row_data, min_col = 1, max_col=250, max_row = row_data):
ws2.append((cell.value for cell in row[min_cols:max_cols]))
wb2.save(destination)
wb2.close()
But when I use the above mentioned code, I get the result but with a shift of 1 row.
I want the data that is appended to row 8, to be on row 7, right after the last data in Workbook 2.
(See image below)
Workbook 2
Does anyone got any feedback?
Thanks!
I found the solution and will post it here in case anyone will have the same problem. Although the cells below looked empty, they had apparently, weird formatting. That's why the Python script saw the cells as Non-empty and appended/shifted the data in another place(the place where there was no formatting).
The Solution would be to format every row below your data as empty cells. (Just copy a range of empty cells from a new Workbook and paste it below your data)
Hope that helps! ;)
Question: Can someone please let me know how I can achieve the following task:
I've defined the column, but i need a specific value to go into each cell within that column.
Also, if column 6 only has x amount of rows, then i want column 7 to also have only x amount of rows with the values pasted in it.
This is the code i've tried.
import openpyxl
wb = openpyxl.load_workbook(filename=r'C:\Users\.spyder-py3\data\BMA.xlsx')
ws = wb.worksheets[0]
for row in ws.iter_rows('G{}:G{}'.format(ws.min_row,ws.max_row)):
for cell in row:
ws.cell(row=cell, column=7).value = 'BMA'
wb.save(r'C:\Users\.spyder-py3\data\BMA.csv')
wb.close()
I figured out most of the issue by looking at this answer:
https://stackoverflow.com/a/15004956/9649146
This is the code i end up with:
import openpyxl
wb = openpyxl.load_workbook(filename=r'C:\Users\.spyder-py3\data\AAXN.xlsx')
ws = wb.worksheets[0]
r = 2
for row in ws.iter_rows('G{}:G{}'.format(ws.min_row,ws.max_row)):
for cell in row:
ws.cell(row=r, column=7).value = 'AAXN'
r += 1
wb.save(r'C:\Users\.spyder-py3\data\AAXN.csv')
wb.close()
Or, you can do something like this:
for row in filesheet.iter_rows(min_row=2, max_row=file_sheet.max_row):
filesheet.cell(row=row[0].row, column=7).value = 'my value'
I'm working on a script that modifies an existing excel document and I need to have the ability to insert a column between two other columns like the VBA macro command .EntireColumn.Insert.
Is there any method with openpyxl to insert a column like this?
If not, any advice on writing one?
Here is an example of a much much faster way:
import openpyxl
wb = openpyxl.load_workbook(filename)
sheet = wb.worksheets[0]
# this statement inserts a column before column 2
sheet.insert_cols(2)
wb.save("filename.xlsx")
Haven't found anything like .EntireColumn.Insert in openpyxl.
First thought coming into my mind is to insert column manually by modifying _cells on a worksheet. I don't think it's the best way to insert column but it works:
from openpyxl.workbook import Workbook
from openpyxl.cell import get_column_letter, Cell, column_index_from_string, coordinate_from_string
wb = Workbook()
dest_filename = r'empty_book.xlsx'
ws = wb.worksheets[0]
ws.title = "range names"
# inserting sample data
for col_idx in xrange(1, 10):
col = get_column_letter(col_idx)
for row in xrange(1, 10):
ws.cell('%s%s' % (col, row)).value = '%s%s' % (col, row)
# inserting column between 4 and 5
column_index = 5
new_cells = {}
ws.column_dimensions = {}
for coordinate, cell in ws._cells.iteritems():
column_letter, row = coordinate_from_string(coordinate)
column = column_index_from_string(column_letter)
# shifting columns
if column >= column_index:
column += 1
column_letter = get_column_letter(column)
coordinate = '%s%s' % (column_letter, row)
# it's important to create new Cell object
new_cells[coordinate] = Cell(ws, column_letter, row, cell.value)
ws._cells = new_cells
wb.save(filename=dest_filename)
I understand that this solution is very ugly but I hope it'll help you to think in a right direction.