I have been trying to program a maths quiz that both works and is as efficient as possible. Looking over my code I saw I had a lot of integer inputs and that lead to me having the program to ask the question/exit the system if the criteria isn't met, so to help me I thought that it would be useful to create a new function. Here is my attempt:
def prompt_int(prompt=''):
while True:
if status == prompt_int(prompt=''):
val = input(prompt)
if val in (1,2):
return int(val)
return true
elif status != prompt_int(prompt=''):
val = input(prompt)
if val in (1,2,3):
return int(val)
return true
else:
print("Not a valid number, please try again")
However, when I try to implement this function around my code it doesn't work properly as it says that status isn't defined however, when I do define status it goes into a recursion loop. How can I fix this problem?
Here is my original code before i try to implement this function:
import sys
import random
def get_bool_input(prompt=''):
while True:
val = input(prompt).lower()
if val == 'yes':
return True
elif val == 'no':
return False
else:
sys.exit("Not a valid input (yes/no is expected) please try again")
status = input("Are you a teacher or student? Press 1 if you are a student or 2 if you are a teacher")# Im tring to apply the new function here and other places that require integer inputs
if status == "1":
score=0
name=input("What is your name?")
print ("Alright",name,"welcome to your maths quiz."
"Remember to round all answer to 5 decimal places.")
level_of_difficulty = int(input(("What level of difficulty are you working at?\n"
"Press 1 for low, 2 for intermediate "
"or 3 for high\n")))
if level_of_difficulty not in (1,2,3):
sys.exit("That is not a valid level of difficulty, please try again")
if level_of_difficulty == 3:
ops = ['+', '-', '*', '/']
else:
ops = ['+', '-', '*']
for question_num in range(1, 11):
if level_of_difficulty == 1:
number_1 = random.randrange(1, 10)
number_2 = random.randrange(1, 10)
else:
number_1 = random.randrange(1, 20)
number_2 = random.randrange(1, 20)
operation = random.choice(ops)
maths = round(eval(str(number_1) + operation + str(number_2)),5)
print('\nQuestion number: {}'.format(question_num))
print ("The question is",number_1,operation,number_2)
answer = float(input("What is your answer: "))
if answer == maths:
print("Correct")
score = score + 1
else:
print ("Incorrect. The actual answer is",maths)
if score >5:
print("Well done you scored",score,"out of 10")
else:
print("Unfortunately you only scored",score,"out of 10. Better luck next time")
class_number = input("Before your score is saved ,are you in class 1, 2 or 3? Press the matching number")
while class_number not in ("1","2","3"):
print("That is not a valid class, unfortunately your score cannot be saved, please try again")
class_number = input("Before your score is saved ,are you in class 1, 2 or 3? Press the matching number")
else:
filename = (class_number + "txt")
with open(filename, 'a') as f:
f.write("\n" + str(name) + " scored " + str(score) + " on difficulty level " + str(level_of_difficulty))
with open(filename, 'a') as f:
f = open(filename, "r")
lines = [line for line in f if line.strip()]
f.close()
lines.sort()
if get_bool_input("Do you wish to view previous results for your class"):
for line in lines:
print (line)
else:
sys.exit("Thanks for taking part in the quiz, your teacher should discuss your score with you later")
if status == "2":
class_number = input("Which classes scores would you like to see? Press 1 for class 1, 2 for class 2 or 3 for class 3")
if class_number not in (1,2,3):
sys.exit("That is not a valid class")
filename = (class_number + "txt")
with open(filename, 'a') as f:
f = open(filename, "r")
lines = [line for line in f if line.strip()]
f.close()
lines.sort()
for line in lines:
print (line)
Well, just a part:
def prompt_int(prompt=""):
while True:
val = input(prompt)
if val in ("1", "2"):
return int(val), True
Will ask again and again. And return when the user enter "1" or "2"!
But better: "if val in "12":
def prompt_int(prompt=""):
while True:
val = input(prompt)
if val.isdigit():
return int(val)
Hi if you dont want to have valid values send to your you could change your code as the function above.
But you could also change it to do the system exits:
def prompt_int(prompt="", authorized=()):
while True:
val = raw_input(prompt)
if val.isdigit():
if int(val) in authorized:
return int(val)
else:
sys.exit("Bla bla bla too bad")
def prompt_int(prompt=''):
while True:
if status == prompt_int(prompt=''):
This line will look for the name "status" in the global namespace (module's namespace), and raise a NameError if there's no global variable named 'status'.
If there's one, it will then recursively calls prompt_int without any possible termination, resulting theoretically in an endless recursion, but practically (in CPython at least) in a RuntimeError when it will hit the maximum recursion depth.
There are also quite a few other things that won't work as you expect:
val = input(prompt)
if val in (1,2):
In Python 3.x, val will be a string, so it will never compare equal to an int. In Python 2.x, input() is a shortcut for eval(raw_input()), which might return an int, but is also a huge security flaw since it unconditionnally execute untrusted code.
return int(val)
return true
The second return statement will never be executed, obviously, since the function will exit at the first one.
A simpler implementation might look like this:
# rebinds raw_input to input for python < 3
import sys
if sys.version_info.major < 3:
input = raw_input
def prompt_int(prompt='', choices=None):
while True:
val = input(prompt)
try:
val = int(val)
if choices and val not in choices:
raise ValueError("{} is not in {}".format(val, choices))
return val
except (TypeError, ValueError) as e:
print(
"Not a valid number ({}), please try again".format(e)
)
While we're at it, there's room for improvement in other parts of your code. Let's start with this:
def get_bool_input(prompt=''):
while True:
val = input(prompt).lower()
if val == 'yes':
return True
elif val == 'no':
return False
else:
sys.exit("Not a valid input (yes/no is expected) please try again")
First point: your naming is not consistent. If your other function is named prompt_int, this one should be named prompt_bool. Also, you have one function (prompt_int) looping forever and the other one exiting the whole program on invalid input, which is another inconsistency. If you want to allow the user to exit on any prompt, provide an explicit option for it, ie:
def prompt_bool(prompt, quit='Q'):
prompt += " (hit '{}' to exit) : ".format(quit)
while True:
val = input(prompt).strip().upper()
if val == quit:
sys.exit("Goodbye")
elif val == 'yes':
return True
elif val == 'no':
return False
else:
print "Invalid input '{}', please try again".format(val)
Of course you then want to provide the same option in prompt_int(), which leads to a more generic function:
def get_input_or_quit(prompt, quit="Q"):
prompt += " (hit '{}' to exit) : ".format(quit)
val = input(prompt).strip()
if val.upper() == quit:
sys.exit("Goodbye")
return val
def prompt_bool(prompt):
while True:
val = get_input_or_quit(prompt).lower()
if val == 'yes':
return True
elif val == 'no':
return False
else:
print "Invalid input '{}', please try again".format(val)
And of course you also replace the call to input by a call to get_input_or_quit in prompt_int.
We could go on for long - splitting all your code in distinct, self-contained function, writing a "main()" function to drive them (instead of having the "main" part at the top level), and obviously using the operator module instead of eval().
Related
I need to add a validation whilst in a while loop.
However when I use this validation it doesn't work and instead only comes up with the error message saying I haven't used a base 10/an integer when I want it to come up with the validation error message and let the user try again.
I don't know if having it in a while loop makes the validation I use any different, does it?
Also do I need to change this "def inputNumber(message):" to what my input is stored as?
And this "userInput = int(input(message))" to what my input is stored as?
import time
import random
question = 0
score = 0
name = input("What is your full name?")
print ("Hello " + name, "welcome to The Arithmetic Quiz. Use integers to enter the answer!")
time.sleep(2)
operands1 = list(range(2, 12))
operators = ["+","-","x"]
operands2 = list(range(2, 12))
while question < 10:
operand1 = random.choice(operands1)
operand2 = random.choice(operands2)
operator = random.choice(operators)
def inputNumber(message):
while True:
try:
userInput = int(input(message))
except ValueError:
print("Not an integer! Try again.")
continue
else:
return userInput
break
user_answer =int(input('{} {} {} = '.format(operand1, operator, operand2)))
I doubt you want to have your function definitions within a while loop like you're doing here:
while question < 10:
...
def inputNumber(message):
...
Instead, you can define the function outside the loop and call it x number of times from a loop elsewhere. E.g.
def inputNumber(message):
...
return userInput
while question < 10:
# pick random numbers/operators
...
# call inputNumber() with numbers/operators as message. Return user_answer
user_answer = int(inputNumber('{} {} {} = '.format(operand1, operator, operand2)))
# check if the answer is correct
...
# increment question so it doesn't run infinitely
question += 1
#user6104134 has already solved this problem; however, I'd like to provide an answer for anyone else having similar issues.
Try this solution
import random
import time
question = 0
score = 0
def inputnumber(prompt):
while True:
response = raw_input(prompt)
try:
if isinstance(response, int):
return int(response)
else:
print "Not an integer! Try again."
except ValueError:
print "Not an integer! Try again."
name = raw_input("What is your full name? ")
print ("Hello " + name, "welcome to The Arithmetic Quiz. Use integers to enter the answer!")
time.sleep(2)
operands1 = list(range(2, 12))
operators = ["+", "-", "x"]
operands2 = list(range(2, 12))
while question < 10:
operand1 = random.choice(operands1)
operand2 = random.choice(operands2)
operator = random.choice(operators)
user_answer = int(inputnumber('{} {} {} = '.format(operand1, operator, operand2)))
question += 1
Issues
First, you should declare function definitions outside of your script and call the function by identifier 'inputNumber()'
Also notice the slight change in Try/Except, and the PEP 8 Style Guide compliant formatting.
Thanks to this site I was able to get this far, being the python novice I am, however I'm kind of stuck. I'm trying to loop 'selection', so after a user does some math, rather than just ending it will give them the option to do something else until they select 0 to quit. I tried a bunch of other try and conditional statements but just end up getting answers and such stuck in an infinite loop.
Also, I'm pretty here, but any help is appreciated, also I'm a python nub. I'm writing this with python 2.7, if that matters.
def sum ( arg1, arg2):
total = a + b
return total;
def subtract ( arg1 , arg2):
total = a - b
return total;
def mult ( arg1, arg2):
total = a * b
return total;
def division ( arg1, arg2):
total = (a / b)
return total;
options = ["1", "2", "3", "4", "5", "0"]
print ("Please choose an option for mathing")
print ("1 for addition")
print ("2 for division")
print ("3 for subtraction")
print ("4 for multiplication")
print ("5 ")
print ("0 to exit")
#this will keep prompting the user to provide an input that is listed in 'options'
while True:
selection = input("Please select choose an option to continue")
if selection in options:
break
else:
print("Please choose a valid option")
#user input for mathing
#input will be validated as follows
a = None
while a is None:
try:
a = int(input("please provide a number for A"))
except ValueError:
print "please use a valid integer"
pass
b = None
while b is None:
try:
b = int(input("please provide a number for B"))
except ValueError:
print "please use a valid integer"
pass
#performing the operations
if selection == '1':
print "The sum is", str(sum(a, b))
elif selection == '2':
print "The quotient is", str(division(a, b))
elif selection == '3':
print "The difference is", str(subtract(a, b))
elif selection == '4':
print "The product is", str(mult(a, b))
elif selection == '0':
exit()
heres a few things I would do to make this more efficient..
options should be a dictionary... your in is a lot more efficient on a dictionary than on a list. the beauty of this is the value for each key can be function methods.
ex. options = {1: 'sum', 2: 'subtract' ..... }
then make a class with your math operations in it
class Calculator(object):
def sum(self, x, y):
return x + y
def subtract(self, x, y):
return x - y
#add more operations here
#staticmethod
def start():
while True:
#prompt for input and the operator
whats nice about this is in your checks for the selection you can dynamically call the class method to clean the code up a lot
if selection in options:
getattr(options[selection], Calculator)(a, b)
if you want me to explain more I can finish the example.
for your loop, you can add a method that starts the action and continues looping and doing more operations each time
here is a basic class you can use using those methods I described
class Calculator(object):
loop = None
calculations = 1
current_value = 0
selection = 0
options = {1: 'add', 2: 'subtract', 3: 'multiply', 4: 'divide'}
def __init__(self, loop=True):
self.loop = loop
print 'Welcome to my basic calculator!'
if not self.loop: # dont loop just execute once
self.run()
else:
while True:
self.run()
#staticmethod
def add(x, y):
return x + y
#staticmethod
def subtract(x, y):
return x - y
#staticmethod
def multiply(x, y):
return x * y
#staticmethod
def divide(x, y):
if y != 0: #cant divide by 0
return x / y
#staticmethod
def quit():
exit(0)
def run(self):
if self.calculations == 1:
self.current_value = self.prompt_user_input('please provide a number: ')
self.prompt_operator('Please choose an operator to continue\n1 for addition\n2 for subtraction\n3 for multiplication \n4 for division\n0 to quit\n')
y = self.prompt_user_input('please provide a number: ')
self.current_value = getattr(Calculator, self.options[self.selection])(self.current_value,y)
self.calculations += 1
print 'New value is: ' + str(self.current_value)
def prompt_operator(self, prompt_message):
while True:
self.selection = input(prompt_message)
if self.selection in self.options:
break
elif self.selection == 0:
self.quit()
else:
print("Please choose a valid option")
def prompt_user_input(self, prompt_message):
val = None
while val is None:
try:
val = int(input(prompt_message))
except ValueError:
print "please use a valid integer"
pass
return val
finally to start your calculator off you can just call it and either pass true to continue loops or pass false to only do one calculation
Calculator(loop=True)
Just put a loop around the prompting and calculation. If they enter 0, break from the outer-most loop:
while True:
#this will keep prompting the user to provide an input that is listed in 'options'
while True:
selection = input("Please select choose an option to continue")
if selection in options:
break
else:
print("Please choose a valid option")
if selection == '0':
break
...
#this will keep prompting the user to provide an input that is listed in 'options'
while True:
selection = input("Please select choose an option to continue")
if selection in options:
if selection == 1:
sum()
if selection == 2:
subtract()
.....
if selection == 'q'
break
Change the logic to what I did above, for option,take some action and do break on the quit character/
Firstly, your code should not work as it is now:
if selection == '1': #should return false
That's because using input you are taking a numeric quantity and then comparing it to a string.
change the input of selection to raw_input
Or change the conditional statements like below:
if selection == 1:
Then add a while True over the entire execution block to go through the execution again and again, until 0 is selected.
I have a program that saves a file that you can write values to. What I am trying to do is use the saved files to calculate my mean/median/mode and to be able to delete values. functions. I am able to add values to the file through the open("filename","a")...but how do I make it so that I am able to import the file values to calculate my other functions?
Sorry its so long, but if anyone can help I would really appreciate it, I am new to figuring out File IO a stuff.
filename = input("What do you want to name your file? Be sure to include .txt after the filename!:")
def main(filename):
print("Now what would you like to do?")
print("--------------------------------------------------------------------------------")
print("Press 1 if you would like to ADD a Value to your list")
print("Press 2 if you would like to DELETE a Value from your list according to its value")
print("Press 3 if you would like to DELETE a Value from your list according to its location")
print("Press 4 if you would like to DISPLAY your List")
print("Press 5 if you would like to COMPUTE MEAN for your list")
print("Press 6 if you would like to COMPUTE MEDIAN for you list")
print("Press 7 if you would like to COMPUTE MIDPOINT for you list")
print("Press 8 if you would like to COMPUTE MODE(S) for your list")
print("Press 9 if you would like to COMPUTE STANDARD DEVIATION for your list")
print("Press 10 if you would like to READ values from a FILE you have made")
print("Press 0 if you would like to EXIT")
print()
execute = int(input("which action would you like to do next?"))
if execute == 1:
add_Values(filename)
if execute == 2:
remove_Value_List(filename)
if execute == 3:
del_Value_Location(filename)
if execute == 4:
read_file(filename)
if execute == 5:
computing_Mean(filename)
if execute == 6:
computing_Median(filename)
if execute == 7:
computing_Midpoint(filename)
if execute == 8:
computing_Modes(filename)
if execute == 9:
computing_Standard_Dev(filename)
if execute == 10:
read_file(filename)
if execute == 0:
print()
print("That's too bad I was having so much fun...but okay...bye!")
if execute >= 12:
print("Sorry but that is not one of the options")
if execute <= -1:
print("Sorry but that is not one of the options")
def add_Values(filename):
fout = open(filename,"a")
again = 'y'
while again == 'y':
fout.write(input("Enter a number you want to write to the file:")+"\n")
print("Do you want to add another number?")
again = input("y = yes, anything else = no:")
fout.close()
print("The numbers have been saved to the file")
main(filename)
def remove_Value_List(filename):
fout = open(filename, "r")
fout.readlines()
remove = "y"
while remove == "y":
print()
print("Here is your list:")
add_Values(filename)
number_list = float(input("Which value should I remove?"))
try:
values.remove(number_list)
print("Here is the revised list:")
print()
print()
except ValueError:
print("That item is not found in the list.")
number_list = float(input("which value should I remove?"))
remove = input("Would you like to remove a value? y = yes, amything else = no:")
fout.close()
print()
main(filename)
def del_Value_Location(filename):
remove = "y"
fout = open(filename,"r")
fout.readlines()
while remove == "y":
print()
print("Here is your list:")
add_Values(filename)
number_list = int(input("Which position should I remove?"))
try:
del values[number_list]
print("Here is the revised list:")
read_file_one(filename)
print()
except ValueError:
print("That item is not found in the list.")
number_list = float(input("which value should I remove?"))
remove = input("Would you like to remove a value? y = yes, amything else = no:")
fout.close()
print()
main(filename)
def computing_Mean(filename):
with open(filename,"r") as fout:
summ = 0
cnt = 0
for line in fout.readlines():
cnt += 1
summ += float(line.strip())
print ("Mean value is:" (summ/cnt))
def computing_Median(filename):
fin = open(filename,"r")
fin.readlines()
ordered = sorted(filename)
length = len(filename)
print("The median of this list is:")
print(float((ordered[length//2] + ordered[-(length+1)//2]))/2)
main(filename)
def computing_Midpoint(filename):
with open(filename,"r") as fout:
filename.sort(key=int)
minNum = min(float(filename))
maxNum = max(float(filename))
print("The midpoint of this list is:")
print((minNum + maxNum) / 2)
main(filename)
def computing_Modes(filename):
from collections import Counter
data = Counter(filename)
print("The Mode(s) of this list is/are:")
print(data.most_common(1))
main(filename)
def computing_Standard_Dev(filename):
mean = sum(filename)/len(filename)
for i in values:
total = 0
newDev = i - mean
squared = newDev**2
total = (total + squared)
divider = (total/(len(values)-1))
standardDev = divider**.5
print("The standard deviation is:")
print(standardDev)
main(filename)
def read_file(filename):
fin = open(filename, 'r')
L = fin.readlines()
for ix in range(len(L)):
L[ix]=L[ix].strip()
while "" in L:
L.remove("")
for ix in range(len(L)):
L[ix]=float(L[ix])
fin.close()
print(L)
main(filename)
main(filename)
There are lots of errors in your code which are very similar to each other so I will explain only one of those similar ones and you should fix others by examining fixed one.
For startes you are opening a file named filename. Using quotes around it makes it a string. You should use it like this:
def add_Values(filename):
fout = open(filename,"w")
But using with statement to open files is much more better because file is closed automatically even if exception is raised.
def add_Values(filename):
with open(filename) as fout:
#do smth
There is no file to work with in def del_Value_Location(filename): and some others. You should open your file in those as well.
To make calculations you need read your data from your file. Which can be achieved by using file.readlines()
def computing_Mean(filename):
with open(filename,"r") as fout:
summ = 0
cnt = 0
for line in fout.readlines():
cnt += 1
summ += int(line.strip())
print ("Mean value is: %.1f" % (summ/cnt))
If you want to change how many digits you want to see, you should change %.1f part.
With this you should fix your other computations by yourself.
About menu, you can do something like this to make it appear again without using a second function.
filename = input("What do you want to name your file? Be sure to include .txt after the filename!:")
#exclude this filename in main and use it as `main`s argument.
def main(filename):
print("Now what would you like to do?")
Ofcoure after this, you should change all main_two()s to main(filename).
I'm very very new to programming and for a school project (50% of my final grade) I had to create a Python program that did roughly this.
I've had some help from my older brother and my teacher but mainly did it myself with some flow charts etc, so please forgive me if I haven't followed conventional rules and things of this nature, or if my code is messy. I will finalise it, just needed bait of help/support from the pro's.
This is my code and I have an issue with it. Once I have pressed 'y' and then 'y' again on the displayMenu() why doesn't it run oldUser()
Also, if any of you have any suggestion on what could make my code better, or I could improve it would be very helpful and I will take it on board.
import os # allows me to use functions defined elsewhere. os module allows for multi platforming.
import sys
words = []
users = {}
status = ""
def teacher_enter_words():
done = False
print 'Hello, please can you enter a word and definition pair.'
while not done:
word = raw_input('\nEnter a word: ')
deff = raw_input('Enter the definition: ')
# append a tuple to the list so it can't be edited.
words.append((word, deff))
add_word = raw_input('Add another word? (y/n): ')
if add_word.lower() == 'n':
done = True
def student_take_test():
student_score = 0
for pair in words:
print 'Definition:', pair[1]
inp = raw_input('Enter word: ')
student_score += check_error(pair[0], inp)
print 'Correct spelling:', pair[0], '\n'
print 'Your score:', student_score
def check_error(correct, inputt):
len_c = len(correct)
len_i = len(inputt)
# threshold is how many incorrect letters do we allow before a
# minor error becomes a major error.
# 1 - allow 1 incorrect letter for a minor error ( >= 2 becomes major error)
threshold = 1
# immediately check if the words are the same length
num_letters_incorrect = abs(len_c - len_i) # abs() method returns value of x - positive dist between x and zero
if num_letters_incorrect == 0:
for i in xrange(0, len(correct)):
if correct[i] != inputt[i]:
num_letters_incorrect += 1
if num_letters_incorrect <= threshold:
if num_letters_incorrect == 0:
return 2 # no incorrect letter.
else:
return 1 # minor error.
else:
return 0 # major error.
def displayMenu():
status = raw_input('Are you a registered user? y/n?: ')
if status == raw_input == 'y':
oldUser()
elif status == 'n':
newUser()
def newUser():
createLogin = raw_input('Create login name: ')
if createLogin in users:
print '\nLogin name already exist!\n'
else:
createPassw = raw_input('Create password: ')
users[createLogin] = createPassw
print '\nUser created!\n'
def oldUser():
login = raw_input('Enter login name: ')
passw = raw_input('Enter password: ')
if login in users and users[login] == passw:
print '\nLogin successful!\n'
else:
print "\nUser doesn't exist or wrong password!\n"
if __name__ == '__main__':
running = True
while running:
os.system('cls' if os.name == 'nt' else 'clear') # multi-platform, executing a shell command
reg = raw_input('Do you want to start the program? y/n?').lower()
if reg == 'y' or reg == 'yes':
displayMenu()
else: sys.exit(0)
inp = raw_input('Are you a Teacher or a Student? (t/s): ').lower()
if inp == 't' or inp == 'teacher':
teacher_enter_words()
else:
student_take_test()
running = False
raw_input is a function. status == raw_input == 'y' will never be true: that is comparing status with the function, and with 'y'.
I suspect that's simply a typo, and you just meant if status == 'y':
I was just wondering if I could remove some redundancy for a help function in a text-game. What I have right now is at the start of every function hint = 0, and hint is increased one every time an invalid answer is entered.
Here is what I have at the moment (inside every function):
hint = 0
valid = False
while valid == False:
print "Would you like to begin?"
begin = raw_input("> ")
if "yes" in begin:
valid = True
print "Great!\n"
start.start()
elif "no" in begin:
quit.quit()
else:
error.error(1)
hint += 1
if hint > 4:
print "\nYou may choose from \"yes\" and \"no\"."
The following code use decorator to separate hint logic and command logic. Every command is handled by a function which can be decorated by Hint object.
When the function return False, the count in Hint object will increase and when it's larger than the limit, it will print out a hint message.
When the function return a tuple it will be called by the main loop.
class Hint(object):
def __init__(self, n, msg):
self.n = n
self.msg = msg
def __call__(self, f):
def wrap(*args, **kw):
count = 1
while True:
ret = f(*args, **kw)
if ret == False:
count += 1
if count > self.n:
print self.msg
count = 0
else:
break
return ret
return wrap
def start_at(place):
print "start at %d" % place
return "start"
#Hint(3, "You may choose from 1, 2, 3.")
def start():
print "What place will you start?"
cmd = raw_input("> ")
try:
place = int(cmd)
if place not in (1,2,3):
return False
else:
return start_at, (place,)
except ValueError:
return False
def quit():
print "I will quit"
return "quit"
#Hint(4, "You may choose from yes and no.")
def begin():
print "Would you like to begin?"
cmd = raw_input("> ")
if "yes" in cmd:
print "Great!\n"
return start, ()
elif "no" in cmd:
print "Bad!\n"
return quit, ()
else:
return False
call_func, args = begin, ()
while True:
ret = call_func(*args)
if isinstance(ret, tuple):
call_func, args = ret
else:
break
Here is some test:
Would you like to begin?
> abc
Would you like to begin?
> def
Would you like to begin?
> 123
Would you like to begin?
> 345
You may choose from yes and no.
Would you like to begin?
> yes
Great!
What place will you start?
> 5
What place will you start?
> fg
What place will you start?
> sd
You may choose from 1, 2, 3.
What place will you start?
> 2
start at 2
from itertools import count
for hint in count()
print "Would you like to begin?"
begin = raw_input("> ")
if "yes" in begin:
print "Great!\n"
start.start()
break
elif "no" in begin:
quit.quit()
else:
error.error(1)
if hint > 4:
print "\nYou may choose from \"yes\" and \"no\"."
Now the next problem is what does start.start() do? It looks/feels like you might be using function calls like a GOTO