How to make Python apscheduler run in background - python

I want to make Python apscheduler run in background , here is my code:
from apscheduler.schedulers.background import BackgroundScheduler, BlockingScheduler
from datetime import datetime
import logging
import sys
logging.basicConfig(level=logging.DEBUG, stream=sys.stdout)
def singleton(cls, *args, **kw):
instances = {}
def _singleton(*args, **kw):
if cls not in instances:
instances[cls] = cls(*args, **kw)
return instances[cls]
return _singleton
#singleton
class MyScheduler(BackgroundScheduler):
pass
def simple_task(timestamp):
logging.info("RUNNING simple_task: %s" % timestamp)
scheduler = MyScheduler()
scheduler.start()
scheduler.add_job(simple_task, 'interval', seconds=5, args=[datetime.utcnow()])
when I run the command:
look:Python look$ python itger.py
I just got this:
INFO:apscheduler.scheduler:Scheduler started
DEBUG:apscheduler.scheduler:Looking for jobs to run
DEBUG:apscheduler.scheduler:No jobs; waiting until a job is added
INFO:apscheduler.scheduler:Added job "simple_task" to job store "default"
And ps:
ps -e | grep python
I just got 54615 ttys000 0:00.00 grep python
My Problem is how to set the code run in background and I can see it's running or it's print log for every 5 secs so the code show?

BackgroundScheduler runs in a background thread which in this case, I guess, doesn't prevent the application main threat to terminate.
Try add at the end of your application:
import time
print("Waiting to exit")
while True:
time.sleep(1)
... and then terminate your application with CTRL+C.

Threads are no magical way of making code run & managed by the OS. They are local to your process only, and so if that process terminates or dies unexpectantly, so does your Thread.
So the answer to your question is: don't use threads, write your program in a normal fashion so you can invoke it on your commandline, and then use a OS-based scheduler such as CRON to schedule it.
Alternatively, if your program needs to run continuously because it e.g. builds up caches that are expensive to re-compute every 5 minutes, use a process-observer such as supervisord to ensure even after a reboot or crash the program continues executing.

Related

Keep process running 24/7 EC2

I have a script that I need to be running 24/7. However, I cannot seem to get EC2 to stop killing the process
I've tried daemonizing it with python-daemon,
I've tried nohup,
I've tried adding & at the end of the command to make it a background process,
I've tried screen to assign it to a virtual session.
All of these work temporarily but when I check it an hour later with ps aux | grep python, it's no longer there/no longer running
I've looked at the output and the nohup.out file to see if it's crashing because of an error but no error/output
I've used signal handlers:
signal.signal(signal.SIGINT, exit_gracefully)
signal.signal(signal.SIGTERM, exit_gracefully)
Still nothing. I suspected that there may be an error that is escaping my tests but I ran it in an open console for an hour and it worked perfectly so there must be something unexpected happening unassociated to my code.
An excerpt:
import signal
import time
from daemon import DaemonContext
import schedule as schedule
global exit_now
def exit_gracefully(*args):
global exit_now
exit_now = True
def run_server():
global exit_now
schedule.every(3).seconds.do(lambda: a_function(param1, param2))
schedule.every(3).hours.do(lambda: another_function(param1, param2))
schedule.every(10).minutes.do(function_with_no_params)
signal.signal(signal.SIGINT, exit_gracefully)
signal.signal(signal.SIGTERM, exit_gracefully)
exit_now = False
while not exit_now:
schedule.run_pending()
time.sleep(1)
my_model.backup()
print("Processes successfully stopped")
if __name__ == "__main__":
with DaemonContext():
run_server()
Edit: I tried adding a log file to my daemon and to my nohup to catch and print whatever's breaking it but upon exit, nothing. No output at all. Additionally, I tried disowning the background process but that didn't work.
The OS is Amazon Linux. Here's a link to the codebase in case you would like to reproduce it: https://github.com/DavidTeju/Tweet-Generator

Apscheduler keeps spawned processes alive for no reason

EDIT: I found the issue. It was a problem with PyCharm. I ran the .py outside of PyCharm and it worked as expected. In PyCharm I enabled "Emulate terminal in output console" and it now also works there...
Expectations:
Apscheduler spawns a thread that checks a website for something.
If the something was found (or multiple of it), the thread spawns (multiple) processes to download it/them.
After five seconds the next check thread spawns. While the other downloads may continue in the background.
Problem:
The spawned processes never stop to exist, which makes other parts of the code (not included) not work, because I need to check if the processes are done etc.
If I use a simple time.sleep(5) instead (see code), it works as expected.
No I cannot set max_instances to 1 because this will stop the scheduled job from running if there is one active download process.
Code:
import datetime
import multiprocessing
from apscheduler.schedulers.background import BackgroundScheduler
class DownloadThread(multiprocessing.Process):
def __init__(self):
super().__init__()
print("Process started")
def main():
print(multiprocessing.active_children())
# prints: [<DownloadThread name='DownloadThread-1' pid=3188 parent=7088 started daemon>,
# <DownloadThread name='DownloadThread-3' pid=12228 parent=7088 started daemon>,
# <DownloadThread name='DownloadThread-2' pid=13544 parent=7088 started daemon>
# ...
# ]
new_process = DownloadThread()
new_process.daemon = True
new_process.start()
new_process.join()
if __name__ == '__main__':
sched = BackgroundScheduler()
sched.add_job(main, 'interval', args=(), seconds=5, max_instances=999, next_run_time=datetime.datetime.now())
sched.start()
while True:
# main() # works. Processes despawn.
# time.sleep(5)
input()

Apscheduler only single instance running in background

I have a script that runs every 5 minutes and performs some actions (check for products back in stock and notify me when they are).
I only want a single instance of apscheduler running because I do not want a website being checked multiple times in a 5 minute window.
Here is my code:
from apscheduler.schedulers.background import BackgroundScheduler
sched = BackgroundScheduler()
def check1():
requests.get("https://somewebsite.com/product-i-want")
# check if item in stock
# notify me
def check2():
requests.get("https://someotherwebsite.com/another-product-i-want")
# check if item in stock
# notify me
def main():
# Schedule jobs to run every 5min
sched.add_job(check1, 'interval', minutes=5, max_instances=1)
sched.add_job(check2, 'interval', minutes=5, max_instances=1)
# Also run jobs on start
for job in sched.get_jobs():
job.modify(next_run_time=datetime.now())
# Start jobs
sched.start()
# Keep-alive
try:
while True:
time.sleep(2)
except (KeyboardInterrupt, SystemExit):
sched.shutdown()
if __name__ == '__main__':
main()
And then I have a shell script that is run:
screen -X -S scrape quit # quit screen with name 'scrape'
screen -dmS scrape python3 Scrapers.py # create screen with name 'scrape' to run python script
I am constantly adding jobs to this script so I have a cronjob that calls the above shell script every hour to kill the current running script and restart it.
But having a cronjob call a script to refresh this python script is a little counterintuitive. My original thought was to give the job an id but it seems like sched.get_jobs() returns empty after you run sched.start().
Is my understanding of BackgroundScheduler completely incorrect? Is there a better way to achieve running only a single instance of certain apscheduler jobs even if the script crashes? I am using apscheduler V3.9.1 (latest).

Django - run a function every x seconds

I'm working on a Django app. I have an API endpoint, which if requested, must carry out a function that must be repeated a few times (until a certain condition is true). How I'm dealing with it right now is -
def shut_down(request):
# Do some stuff
while True:
result = some_fn()
if result:
break
time.sleep(2)
return True
While I know that this is a terrible approach and that I shouldn't be blocking for 2 seconds, I can't figure out how to get around it.
This works, after say a wait of 4 seconds. But I'd like something that keeps the loop running in the background, and stop once some_fn returns True. (Also, it is certain that some_fn will return True)
EDIT -
Reading Oz123's response gave me an idea which seems to work. Here's what I did -
def shut_down(params):
# Do some stuff
# Offload the blocking job to a new thread
t = threading.Thread(target=some_fn, args=(id, ), kwargs={})
t.setDaemon(True)
t.start()
return True
def some_fn(id):
while True:
# Do the job, get result in res
# If the job is done, return. Or sleep the thread for 2 seconds before trying again.
if res:
return
else:
time.sleep(2)
This does the job for me. It's simple but I don't know how efficient multithreading is in conjunction with Django.
If anyone can point out pitfalls of this, criticism is appreciated.
For many small projects celery is overkill. For those projects you can use schedule, it's very easy to use.
With this library you can make any function execute a task periodically:
import schedule
import time
def job():
print("I'm working...")
schedule.every(10).minutes.do(job)
schedule.every().hour.do(job)
schedule.every().day.at("10:30").do(job)
schedule.every().monday.do(job)
schedule.every().wednesday.at("13:15").do(job)
while True:
schedule.run_pending()
time.sleep(1)
The example runs in a blocking manner, but if you look in the FAQ, you will find that you can also run tasks in a parallel thread, such that you are not blocking, and remove the task once not needed anymore:
import threading
import time
from schedule import Scheduler
def run_continuously(self, interval=1):
"""Continuously run, while executing pending jobs at each elapsed
time interval.
#return cease_continuous_run: threading.Event which can be set to
cease continuous run.
Please note that it is *intended behavior that run_continuously()
does not run missed jobs*. For example, if you've registered a job
that should run every minute and you set a continuous run interval
of one hour then your job won't be run 60 times at each interval but
only once.
"""
cease_continuous_run = threading.Event()
class ScheduleThread(threading.Thread):
#classmethod
def run(cls):
while not cease_continuous_run.is_set():
self.run_pending()
time.sleep(interval)
continuous_thread = ScheduleThread()
continuous_thread.setDaemon(True)
continuous_thread.start()
return cease_continuous_run
Scheduler.run_continuously = run_continuously
Here is an example for usage in a class method:
def foo(self):
...
if some_condition():
return schedule.CancelJob # a job can dequeue it
# can be put in __enter__ or __init__
self._job_stop = self.scheduler.run_continuously()
logger.debug("doing foo"...)
self.foo() # call foo
self.scheduler.every(5).seconds.do(
self.foo) # schedule foo for running every 5 seconds
...
# later on foo is not needed any more:
self._job_stop.set()
...
def __exit__(self, exec_type, exc_value, traceback):
# if the jobs are not stop, you can stop them
self._job_stop.set()
This answer expands on Oz123's answer a little bit.
In order to get things working, I created a file called mainapp/jobs.py to contain my scheduled jobs. Then, in my apps.py module, I put from . import jobs in the ready method. Here's my entire apps.py file:
from django.apps import AppConfig
import os
class MainappConfig(AppConfig):
name = 'mainapp'
def ready(self):
from . import jobs
if os.environ.get('RUN_MAIN', None) != 'true':
jobs.start_scheduler()
(The RUN_MAIN check is because python manage.py runserver runs the ready method twice—once in each of two processes—but we only want to run it once.)
Now, here's what I put in my jobs.py file. First, the imports. You'll need to import Scheduler, threading and time as below. The F and UserHolding imports are just for what my job does; you won't import these.
from django.db.models import F
from schedule import Scheduler
import threading
import time
from .models import UserHolding
Next, write the function you want to schedule. The following is purely an example; your function won't look anything like this.
def give_admin_gold():
admin_gold_holding = (UserHolding.objects
.filter(inventory__user__username='admin', commodity__name='gold'))
admin_gold_holding.update(amount=F('amount') + 1)
Next, monkey-patch the schedule module by adding a run_continuously method to its Scheduler class. Do this by using the below code, which is copied verbatim from Oz123's answer.
def run_continuously(self, interval=1):
"""Continuously run, while executing pending jobs at each elapsed
time interval.
#return cease_continuous_run: threading.Event which can be set to
cease continuous run.
Please note that it is *intended behavior that run_continuously()
does not run missed jobs*. For example, if you've registered a job
that should run every minute and you set a continuous run interval
of one hour then your job won't be run 60 times at each interval but
only once.
"""
cease_continuous_run = threading.Event()
class ScheduleThread(threading.Thread):
#classmethod
def run(cls):
while not cease_continuous_run.is_set():
self.run_pending()
time.sleep(interval)
continuous_thread = ScheduleThread()
continuous_thread.setDaemon(True)
continuous_thread.start()
return cease_continuous_run
Scheduler.run_continuously = run_continuously
Finally, define a function to create a Scheduler object, wire up your job, and call the scheduler's run_continuously method.
def start_scheduler():
scheduler = Scheduler()
scheduler.every().second.do(give_admin_gold)
scheduler.run_continuously()
I recommend you use Celery's task management. You can refer this to set up this app (package if you're from javaScript background).
Once set, you can alter the code to:
#app.task
def check_shut_down():
if not some_fun():
# add task that'll run again after 2 secs
check_shut_down.delay((), countdown=3)
else:
# task completed; do something to notify yourself
return True
I can't comment on oz123's (https://stackoverflow.com/a/44897678/1108505) and Tanner Swett's (https://stackoverflow.com/a/60244694/5378866) excellent post, but as a final note I wanted to add that if you use Gunicorn and you have X number of workers, the section:
from django.apps import AppConfig
import os
class MainappConfig(AppConfig):
name = 'mainapp'
def ready(self):
from . import jobs
if os.environ.get('RUN_MAIN', None) != 'true':
jobs.start_scheduler()
will be executed that same number of times, launching X schedulers at the same time.
If we only want it to run only one instance (for example if you're going to create objects in the database), we would have to add in our gunicorn.conf.py file something like this:
def on_starting(server):
from app_project import jobs
jobs.start_scheduler()
And finally in the gunicorn call add the argument --preload
Here is my solution, with sources noted. This function will allow you to create a scheduler that you can start with your app, then add and subtract jobs at will. The check_interval variable allows you to trade-off between system resources and job execution timing.
from schedule import Scheduler
import threading
import warnings
import time
class RepeatTimer(threading.Timer):
"""Add repeated run of target to timer functionality. Source: https://stackoverflow.com/a/48741004/16466191"""
running: bool = False
def __init__(self, *args, **kwargs):
threading.Timer.__init__(self, *args, **kwargs)
def start(self) -> None:
"""Protect from running start method multiple times"""
if not self.running:
super(RepeatTimer, self).start()
self.running = True
else:
warnings.warn('Timer is already running, cannot be started again.')
def cancel(self) -> None:
"""Protect from running stop method multiple times"""
if self.running:
super(RepeatTimer, self).cancel()
self.running = False
else:
warnings.warn('Timer is already canceled, cannot be canceled again.')
def run(self):
"""Replace run method of timer to run continuously"""
while not self.finished.wait(self.interval):
self.function(*self.args, **self.kwargs)
class ThreadedScheduler(Scheduler, RepeatTimer):
"""Non-blocking scheduler. Advice taken from: https://stackoverflow.com/a/50465583/16466191"""
def __init__(
self,
run_pending_interval: float,
):
"""Initialize parent classes"""
Scheduler.__init__(self)
super(RepeatTimer, self).__init__(
interval=run_pending_interval,
function=self.run_pending,
)
def print_work(what_to_say: str):
print(what_to_say)
if __name__ == '__main__':
my_schedule = ThreadedScheduler(run_pending_interval=1)
job1 = my_schedule.every(1).seconds.do(print_work, what_to_say='Did_job1')
job2 = my_schedule.every(2).seconds.do(print_work, what_to_say='Did_job2')
my_schedule.cancel()
my_schedule.start()
time.sleep(7)
my_schedule.cancel_job(job1)
my_schedule.start()
time.sleep(7)
my_schedule.cancel()

python daemon thread exits but process still run in the background

I am using python 2.7 and Python thread doesn't kill its process after the main program exits. (checking this with the ps -ax command on ubuntu machine)
I have the below thread class,
import os
import threading
class captureLogs(threading.Thread):
'''
initialize the constructor
'''
def __init__(self, deviceIp, fileTag):
threading.Thread.__init__(self)
super(captureLogs, self).__init__()
self._stop = threading.Event()
self.deviceIp = deviceIp
self.fileTag = fileTag
def stop(self):
self._stop.set()
def stopped(self):
return self._stop.isSet()
'''
define the run method
'''
def run(self):
'''
Make the thread capture logs
'''
cmdTorun = "adb logcat > " + self.deviceIp +'_'+self.fileTag+'.log'
os.system(cmdTorun)
And I am creating a thread in another file sample.py,
import logCapture
import os
import time
c = logCapture.captureLogs('100.21.143.168','somefile')
c.setDaemon(True)
c.start()
print "Started the log capture. now sleeping. is this a dameon?", c.isDaemon()
time.sleep(5)
print "Sleep tiime is over"
c.stop()
print "Calling stop was successful:", c.stopped()
print "Thread is now completed and main program exiting"
I get the below output from the command line:
Started the log capture. now sleeping. is this a dameon? True
Sleep tiime is over
Calling stop was successful: True
Thread is now completed and main program exiting
And the sample.py exits.
But when I use below command on a terminal,
ps -ax | grep "adb"
I still see the process running. (I am killing them manually now using the kill -9 17681 17682)
Not sure what I am missing here.
My question is,
1) why is the process still alive when I already killed it in my program?
2) Will it create any problem if I don't bother about it?
3) is there any other better way to capture logs using a thread and monitor the logs?
EDIT: As suggested by #bug Killer, I added the below method in my thread class,
def getProcessID(self):
return os.getpid()
and used os.kill(c.getProcessID(), SIGTERM) in my sample.py . The program doesn't exit at all.
It is likely because you are using os.system in your thread. The spawned process from os.system will stay alive even after the thread is killed. Actually, it will stay alive forever unless you explicitly terminate it in your code or by hand (which it sounds like you are doing ultimately) or the spawned process exits on its own. You can do this instead:
import atexit
import subprocess
deviceIp = '100.21.143.168'
fileTag = 'somefile'
# this is spawned in the background, so no threading code is needed
cmdTorun = "adb logcat > " + deviceIp +'_'+fileTag+'.log'
proc = subprocess.Popen(cmdTorun, shell=True)
# or register proc.kill if you feel like living on the edge
atexit.register(proc.terminate)
# Here is where all the other awesome code goes
Since all you are doing is spawning a process, creating a thread to do it is overkill and only complicates your program logic. Just spawn the process in the background as shown above and then let atexit terminate it when your program exits. And/or call proc.terminate explicitly; it should be fine to call repeatedly (much like close on a file object) so having atexit call it again later shouldn't hurt anything.

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