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Calculating AUC for LogisticRegression model

Let's take data
import numpy as np
import pandas as pd
from sklearn.datasets import load_breast_cancer
from sklearn.decomposition import PCA
from sklearn import datasets
from sklearn.preprocessing import StandardScaler
from sklearn import metrics
data = load_breast_cancer()
X = data.data
y = data.target
I want to create model using only first principal component and calculate AUC for it.
My work so far
scaler = StandardScaler()
scaler.fit(X_train)
X_scaled = scaler.transform(X)
pca = PCA(n_components=1)
principalComponents = pca.fit_transform(X)
principalDf = pd.DataFrame(data = principalComponents
, columns = ['principal component 1'])
clf = LogisticRegression()
clf = clf.fit(principalDf, y)
pred = clf.predict_proba(principalDf)
But while I'm trying to use
fpr, tpr, thresholds = metrics.roc_curve(y, pred, pos_label=2)
Following error occurs :
y should be a 1d array, got an array of shape (569, 2) instead.
I tried to reshape my data
fpr, tpr, thresholds = metrics.roc_curve(y.reshape(1,-1), pred, pos_label=2)
But it didn't solve the issue (it outputs) :
multilabel-indicator format is not supported
Do you have any idea how can I perform AUC on this first principal component?

You may wish to try:
from sklearn.datasets import load_breast_cancer
from sklearn.decomposition import PCA
from sklearn import datasets
from sklearn.preprocessing import StandardScaler
from sklearn import metrics
from sklearn.model_selection import train_test_split
from sklearn.linear_model import LogisticRegression
from sklearn.pipeline import Pipeline
X,y = load_breast_cancer(return_X_y=True)
X_train, X_test, y_train, y_test = train_test_split(X,y)
scaler = StandardScaler()
pca = PCA(2)
clf = LogisticRegression()
ppl = Pipeline([("scaler",scaler),("pca",pca),("clf",clf)])
ppl.fit(X_train, y_train)
preds = ppl.predict(X_test)
fpr, tpr, thresholds = metrics.roc_curve(y_test, preds, pos_label=1)
metrics.plot_roc_curve(ppl, X_test, y_test)

The problem is that predict_proba returns a column for each class. Generally with binary classification, your classes are 0 and 1, so you want the probability of the second class, so it's quite common to slice as follows (replacing the last line in your code block):
pred = clf.predict_proba(principalDf)[:, 1]

Standardized data of SVM - Scikit-learn/ Python

This is for an assignment where the SVM methods has to be used for model accuracy.
There were 3 parts, wrote the below code
import sklearn.datasets as datasets
import sklearn.model_selection as ms
from sklearn.model_selection import train_test_split
digits = datasets.load_digits();
X = digits.data
y = digits.target
X_train, X_test, y_train, y_test = train_test_split(X, y, random_state=30, stratify=y)
print(X_train.shape)
print(X_test.shape)
from sklearn.svm import SVC
svm_clf = SVC().fit(X_train, y_train)
print(svm_clf.score(X_test,y_test))
But after this, the question is as below
Perform Standardization of digits.data and store the transformed data
in variable digits_standardized.
Hint : Use required utility from sklearn.preprocessing. Once again,
split digits_standardized into two sets names X_train and X_test.
Also, split digits.target into two sets Y_train and Y_test.
Hint: Use train_test_split method from sklearn.model_selection; set
random_state to 30; and perform stratified sampling. Build another SVM
classifier from X_train set and Y_train labels, with default
parameters. Name the model as svm_clf2.
Evaluate the model accuracy on testing data set and print it's score.
On top of the above code, tried writing this, but seems to be failing. Can anyone help on how the data can be standardized.
std_scale = preprocessing.StandardScaler().fit(X_train)
X_train_std = std_scale.transform(X_train)
X_test_std = std_scale.transform(X_test)
svm_clf2 = SVC().fit(X_train, y_train)
print(svm_clf.score(X_test,y_test))

Tried the below. Seems to be working.
import sklearn.datasets as datasets
import sklearn.model_selection as ms
from sklearn.model_selection import train_test_split
from sklearn.preprocessing import StandardScaler
digits = datasets.load_digits();
X = digits.data
scaler = StandardScaler()
scaler.fit(X)
digits_standardized = scaler.transform(X)
y = digits.target
X_train, X_test, y_train, y_test = train_test_split(digits_standardized, y, random_state=30, stratify=y)
#print(X_train.shape)
#print(X_test.shape)
from sklearn.svm import SVC
svm_clf2 = SVC().fit(X_train, y_train)
print("Accuracy ",svm_clf2.score(X_test,y_test))

Try this as final code includes all Tasks
import sklearn.datasets as datasets
import sklearn.model_selection as ms
from sklearn.model_selection import train_test_split
from sklearn.preprocessing import StandardScaler
from sklearn.svm import SVC
digits = datasets.load_digits()
X = digits.data
y = digits.target
X_train, X_test, y_train, y_test = train_test_split(X, y, random_state=30, stratify=y)
print(X_train.shape)
print(X_test.shape)
svm_clf = SVC().fit(X_train, y_train)
print(svm_clf.score(X_test,y_test))
scaler = StandardScaler()
scaler.fit(X)
digits_standardized = scaler.transform(X)
X_train, X_test, y_train, y_test = train_test_split(digits_standardized, y, random_state=30, stratify=y)
svm_clf2 = SVC().fit(X_train, y_train)
print(svm_clf2.score(X_test,y_test))

Trying to implement XGBoost into my Artificial Neural Network

I'm completely unaware as to why i'm receiving this error. I am trying to implement XGBoost but it returns with error "ValueError: For a sparse output, all columns should be a numeric or convertible to a numeric." Even after i've One Hot Encoded my categorical data. If anyone knows what is causing this and a possible solution i'd greatly appreciate it. Here is my code written in Python:
# Artificial Neural Networks - With XGBoost
# PRE PROCESS
# Importing the libraries
import numpy as np
import matplotlib.pyplot as plt
import pandas as pd
# Importing the dataset
dataset = pd.read_csv('Churn_Modelling.csv')
X = dataset.iloc[:, 3:13].values
y = dataset.iloc[:, 13].values
# Encoding Categorical Data
from sklearn.preprocessing import OneHotEncoder
from sklearn.compose import ColumnTransformer
ct = ColumnTransformer([('encoder', OneHotEncoder(), [1, 2])],
remainder = 'passthrough')
X = np.array(ct.fit_transform(X), dtype = np.float)
# Splitting the dataset into the Training set and Test set
from sklearn.model_selection import train_test_split
x_train, x_test, y_train, y_test = train_test_split(X, y, test_size=0.20, random_state = 0)
# Fitting XGBoost to the training set
from xgboost import XGBClassifier
classifier = XGBClassifier()
classifier.fit(x_train, y_train)
# Predicting the Test set Results
y_pred = classifier.predict(x_test)
# Making the Confusion Matrix
from sklearn.metrics import confusion_matrix
cm = confusion_matrix(y_test, y_pred)
# Applying k-Fold Cross Validation
from sklearn.model_selection import cross_val_score
accuracies = cross_val_score(estimator = classifier, X = X_train, y = y_train, cv = 10)
accuracies.mean()
accuracies.std()

How to perform SMOTE with cross validation in sklearn in python

I have a highly imbalanced dataset and would like to perform SMOTE to balance the dataset and perfrom cross validation to measure the accuracy. However, most of the existing tutorials make use of only single training and testing iteration to perfrom SMOTE.
Therefore, I would like to know the correct procedure to perfrom SMOTE using cross-validation.
My current code is as follows. However, as mentioned above it only uses single iteration.
from imblearn.over_sampling import SMOTE
from sklearn.model_selection import train_test_split
X_train, X_test, y_train, y_test = train_test_split(X, y, test_size=0.3, random_state=0)
sm = SMOTE(random_state=2)
X_train_res, y_train_res = sm.fit_sample(X_train, y_train.ravel())
clf_rf = RandomForestClassifier(n_estimators=25, random_state=12)
clf_rf.fit(x_train_res, y_train_res)
I am happy to provide more details if needed.

You need to perform SMOTE within each fold. Accordingly, you need to avoid train_test_split in favour of KFold:
from sklearn.model_selection import KFold
from imblearn.over_sampling import SMOTE
from sklearn.metrics import f1_score
kf = KFold(n_splits=5)
for fold, (train_index, test_index) in enumerate(kf.split(X), 1):
X_train = X[train_index]
y_train = y[train_index] # Based on your code, you might need a ravel call here, but I would look into how you're generating your y
X_test = X[test_index]
y_test = y[test_index] # See comment on ravel and y_train
sm = SMOTE()
X_train_oversampled, y_train_oversampled = sm.fit_sample(X_train, y_train)
model = ... # Choose a model here
model.fit(X_train_oversampled, y_train_oversampled )
y_pred = model.predict(X_test)
print(f'For fold {fold}:')
print(f'Accuracy: {model.score(X_test, y_test)}')
print(f'f-score: {f1_score(y_test, y_pred)}')
You can also, for example, append the scores to a list defined outside.

from sklearn.model_selection import StratifiedKFold
from imblearn.over_sampling import SMOTE
cv = StratifiedKFold(n_splits=5)
for train_idx, test_idx, in cv.split(X, y):
X_train, y_train = X[train_idx], y[train_idx]
X_test, y_test = X[test_idx], y[test_idx]
X_train, y_train = SMOTE().fit_sample(X_train, y_train)
....

I think you can also solve this with a pipeline from the imbalanced-learn library.
I saw this solution in a blog called Machine Learning Mastery https://machinelearningmastery.com/smote-oversampling-for-imbalanced-classification/
The idea is to use a pipeline from imblearn to do the cross-validation. Please, let me know if that works. The example below is with a decision tree, but the logic is the same.
#decision tree evaluated on imbalanced dataset with SMOTE oversampling
from numpy import mean
from sklearn.datasets import make_classification
from sklearn.model_selection import cross_val_score
from sklearn.model_selection import RepeatedStratifiedKFold
from sklearn.tree import DecisionTreeClassifier
from imblearn.pipeline import Pipeline
from imblearn.over_sampling import SMOTE
# define dataset
X, y = make_classification(n_samples=10000, n_features=2, n_redundant=0,
n_clusters_per_class=1, weights=[0.99], flip_y=0, random_state=1)
# define pipeline
steps = [('over', SMOTE()), ('model', DecisionTreeClassifier())]
pipeline = Pipeline(steps=steps)
# evaluate pipeline
cv = RepeatedStratifiedKFold(n_splits=10, n_repeats=3, random_state=1)
scores = cross_val_score(pipeline, X, y, scoring='roc_auc', cv=cv, n_jobs=-1)
score = mean(scores))

The newcomer learns the knn algorithm and hopes to help solve a small problem

the code
from sklearn.model_selection import train_test_split
from sklearn import datasets
from sklearn.neighbors import KNeighborsClassifier
iris = datasets.load_iris()
X = iris.data
y = iris.target
X_train, X_test, y_train, y_test = train_test_split(X, y, test_size=0.2, random_state=666)
neigh = KNeighborsClassifier(n_neighbors=3)
neigh.fit(X_train, y_train)
y_predict = neigh.predict(X_test)`
print(sum(y_predict == y_test) / len(y_test))
my question
I don't know why the result is 1.0,and if I change the test_size,the result is also 1.0.
I hope someone can help answer, thank you

The last line of your code is accuracy on test set. It tells you how many percent of predictions are the same as true labels.
If you get acc=1.0 it means you predict all examples correctly.