I know this has been asked dozens of times but I can't see what in the world I'm doing wrong. I'm trying to import a module in python 2.7 from a different directory. I would greatly appreciate some input to help me understand why this method doesn't work. I have the following directory structure on my raspbian system:
/home/pi/
...projects/__init__.py
...projects/humid_temp.py
...python_utilities/__init.py__
...python_utilities/tools.py
I'm calling humid_temp.py and I need to import a function within tools.py This is what their contents look like:
humid_temp.py:
import os
import sys
sys.path.append('home/pi/python_utilities')
print sys.path
from python_utilities.tools import *
tools.py:
def tail(file):
#function contents
return stuff
The print sys.path output contains /home/pi/python_utilities
I'm not messing up my __init__.py's am I?
I've also ruled out possible permission issues with that path as I gave it full 777 access and I still hit the
ImportError: No module named python_utilities.tools.
What did I miss?
When you want to import something like -
from python_utilities.tools import *
You need to add the parent directory of python_utilities to sys.path , not python_utilities itself. So, you should add something like -
sys.path.append('/home/pi') #Assuming the missing of `/` at start was not a copy/paste mistake
Also, just a note, from <module> import * is bad , you should consider only importing the required items, you can check the question - Why is "import *" bad? - for more details.
In humid_temp.py, just write:
from python_utilities import tools
There is no need for appending subfolder to sys.path.
Then when you want to use functions from tools, just
tools.function()
Related
Based on some answers I try to be more specific.
I want to import the print and the models AND code in my main.py
I know the question gets asked a lot, but still I could not figure out whats wrong with my code!
I have a project directory like this
-project
--__init__py
--main.py
--print.py
--requests
--__init__.py
--models.py
--code.py
i want to import from print.py and * from requests
Therefore I tried to add these lines in main.py
from . import print
#or
import print
#for requests I tried
import os.path
import sys
sys.path.append('./requests')
from requests import *
all of those lines cause the same ImportError attempted relative import with no known parent ,
using Python 39
anyone an idea where the problem is?
I am very confused that this seems not to work, was it possible in older versions?
You should definitely not be doing anything with sys.path. If you are using a correct Python package structure, the import system should handle everything like this.
From the directory structure you described, project would be the name of your package. So when using your package in some external code you would do
import package
or to use a submodule/subpackage
import project.print
import project.requests
and so on.
For modules inside the package you can use relative imports. When you write
i want to import from print.py and * from requests Therefore I tried
it's not clear from where you want to import them, because this is important for relative imports.
For example, in project/main.py to import the print module you could use:
from . import print
But if it's from project/requests/code.py you would use
from .. import print
As an aside, "print" is probably not a good name for a module, since if you import the print module it will shadow the print() built-in function.
Your main file should be outside the 'project'-directory to use that as a package.
Then, from your main file, you can import using from project.print import ....
Within the project-package, relative imports are possible.
Well, I have pretty hard task and I'm completely stucked, like in any direction.
What program should do:
Import all modules (names are random) from folder
MainScript.py
modules/
mod1.py
mod2.py
mod3.py
...
Execute specific (known name, and everywhere it's same) function.
mod1.main()
mod2.main()
mod3.main()
...
As I understand it, I should list all files in folder , then make list with them and for each [x] in list import module and execute script. I've found that modules[0].main() works only if modules[0] no string, so, it should be modules[0]=main not modules[0]='main'. So and there I need somehow deal with it... but for import I don't know...
I've already googled about it, only found https://stackoverflow.com/a/1057534/10289135
And I guess it will not work for me (I also don't understand how it works and script didn't work for me)
Any ideas?
You can use the following syntax:
from filename(remove the .py) import *
This is a wild card import it imports every thing from a module literally everything .By doing this you dont need to do the work like 'filename.blabla' ,but simply you can do 'blabla'.
import os
import sys
import importlib
modules = []
for i in os.listdir("C:\\Windows\\path\\to\\your\\modules\\"):
mod = i
modules.append(mod)
sys.path.append("C:\\Windows\\path\\to\\your\\modules\\")
for i in modules:
i = i[:i.find(".")]
module = importlib.import_module(f"{i}")
module.main()
I tried writing some commenly used function in a seperate file and import the same into mainApp file, but not able to use import.
I did find many questions regarding the this same question but, the solution was to keep the files in the same folder
I tried without .py as well, but the same error:
Can you please help me how can i fix this issue ?
No '.py'. Just import seperate
Try using this in mainApp.py:
from seperate import *
a()
where seperate.py looks like this:
def a():
print('hi')
Well, sorry, those two files need to be in the same folder. This is not a solution to your problem.
The syntax of a relative import depends on the current location as well as the location of the module, package, or object to be imported. Here are a few examples of relative imports:
from .some_module import some_class
from ..some_package import some_function
from . import some_class
Read more about Absolute vs Relative Imports in Python
In your case it should be:
from .seperate import a
Also check this question:
Importing from a relative path in Python
add your project directory into your path variable so that python know from where you want to import file
There are several posts around this error I have already read, but I still don't get what I am doing wrong.
I put it into a minimal example:
Imagine I have a Doc.py, and the package Tools which includes Tool1.py and Tool2.py.
Doc.py:
from Tools import *
import sys
def __main__():
TOOL_REPORT("Tool1","Test")
def TOOL_REPORT(tool, path):
if(tool == 'Tool1'):
Tool1.REPORT(path)
elif(tool == 'Tool2'):
Tool2.REPORT(path)
else:
sys.stderr.write("This tool is not yet included in Doc. Please check TOOLS for more information.")
if __name__=="__main__": __main__()
Tool1.py:
def REPORT(path):
print("Tool1 "+path)
Tool2.py:
def REPORT(path):
print("Tool2 "+path)
If I run this, I always end up with this error:
File "Doc.py", line 15, in TOOL_REPORT
Tool1.REPORT(path)
NameError: global name 'Tool1' is not defined
I'd appreciate any hint to what is going wrong!
Your Tool1 and Tool2 submodules are not visible until explicitly imported somewhere.
You can import them in the Tools/__init__.py package file:
import Tool1, Tool2
at which point they become available for import from Tools.
Another option is to import the modules from your own code:
import Tools.Tool1, Tools.Tool2
from Tools import *
Only when explicitly imported are submodules also set as attributes of the package.
Python will treat any folder as a module when there is __init__.py file present in it. Otherwise it will just be another folder for python and not a module from which it can import things. So just add init.py file in your Tool folder (so it will become module in pythonic terms) and then you can import that module in other python scripts.
One more things for better practice instead of using
from Tools import *
Always provide the file name of library specifically which you want to import like in your case you should use it like this
from Tools import Tool1, Tool2
This will enhance the code readbility for others and for you too.
I have two codefiles in python, let's say mainfile.py and separatecode.py. I would like to run separatecode.py from within mainfile.py, referencing the specific directory where separatecode.py is stored.
So the pseudocode of what I am looking to do would be something like:
import C:\Users\Jack\Documents\MyFolder\separatecode.py
A number of questions discuss importing, but I can't find one that discusses importing a specific file you wrote in a particular directory. I would like to be able to use functions defined in separatecode.py and am looking for the equivalent of the source("separatecode.r") command in R if that helps.
Add that directory to your sys.path by doing:
import sys
sys.path.append('/directory/to/my/file')
Import the module as normal:
import separatecode
The code you used will not work. It will give a syntax error.
Look at the documentation for the import statement, especially the grammar. A module is one or more identifiers separated by dots.
You can make import separatecode work by adding C:\Users\Jack\Documents\MyFolder to the PYTHONPATH environment variable. This will make it available to all Python scripts. Or you can add that path to sys.path in mainfile.py before importing separatecode.
Try something like this:
import imp
foo = imp.load_source('Module_name', 'Path\To\module.py')
foo.MyClass()
you dont need the foo.MyClass() it was just an example to show that the module works like any other module
no you can import a module from anywhere using the path and its name and you can acsess all its functions etc
for anything else check out:
Python Imp
I hope this is what you were looking for