I'm trying to use Python to scrape a website, but I have to login first before I can get to the page with the data on it.
The URL for the login page is:
https://tunein.com/account/login/?returnTo=https://amplifier.tunein.com/sessions/new&source=amplifier
I have read numerous threads which seem to answer the question, but I'm struggling to relate it to my own situation.
The code I have (from a response in this thread) is:
import requests
# Fill in your details here to be posted to the login form.
payload = {
'Username': 'user',
'Password': 'password'
}
# Use 'with' to ensure the session context is closed after use.
with requests.Session() as s:
p = s.post('https://tunein.com/account/login/?returnTo=https://amplifier.tunein.com/sessions/new&source=amplifier', data=payload)
# print the html returned or something more intelligent to see if it's a successful login page.
print p.text
I have looked at the source code to see what the name of the form fields are, hence the 'Username' and 'Password' attributes in the payload variable.
When I run the script, p.text just returns the HTML of the same page so it obviously isn't logging in correctly. Any suggestions? Is there a better way to do it?
Edit:
The "Form Data" headers once I log in are:
Username:user
Password:pass
Remember:true
Remember:false
btnLogin:Sign In
ReturnTo:https://amplifier.tunein.com/sessions/new
Source:amplifier
Does this mean I have to add all of these to my payload variable?
Related
Good morning I need your help, I would like to perform some web scraping to this website, but where to login first, I made a code, but I can not understand if it works and the login is done correctly.. also if once I am connected to my account via python the session remains open`?
Thank you!
`import requests
payload = {
'j_username': 'username',
'j_password': 'password'
}
# Use 'with' to ensure the session context is closed after use.
with requests.Session() as s:
p = s.post('https://sgv.ivu-cloud.com/mbweb/j_security_check', data=payload)
# print the html returned or something more intelligent to see if it's a successful login page.
print (p)
# An authorised request.
r = s.get('https://sgv.ivu-cloud.com/mbweb/main/matter/desktop/main-menu#duties')
print (r.text)
# etc...
I am trying to login to a website www.seek.com.au. I am trying to test the possibility to remote login using Python request module. The site is Front end is designed using React and hence I don't see any form action component in www.seek.com.au/sign-in
When I run the below code, I see the response code as 200 indicating success, but I doubt if it's actually successful. The main concern is which URL to use in case if there is no action element in the login submit form.
import requests
payload = {'email': <username>, 'password': <password>}
url = 'https://www.seek.com.au'
with requests.Session() as s:
response_op = s.post(url, data=payload)
# print the response status code
print(response_op.status_code)
print(response_op.text)
When i examine the output data (response_op.text), i see word 'Sign in' and 'Register' in output which indicate the login failed. If its successful, the users first name will be shown in the place. What am I doing wrong here ?
P.S: I am not trying to scrape data from this website but I am trying to login to a similar website.
Try this code:
import requests
payload={"email": "test#test.com", "password": "passwordtest", "rememberMe": True}
url = "https://www.seek.com.au:443/userapi/login"
with requests.Session() as s:
response_op = s.post(url, json=payload)
# print the response status code
print(response_op.status_code)
print(response_op.text)
You are sending the request to the wrong url.
Hope this helps
I checked this question but it only has one answer and it's a little over my head (just started with Python). I'm using Python 3.
I'm trying to scrape data from this page, but if you have a BP account, the page is a lot different/more useful. I need my program to log me in before I have BeautifulSoup get the data for me.
So far I have
from bs4 import BeautifulSoup
import urllib.request
import requests
username = 'myUsername'
password = 'myPassword'
from requests import session
payload = {'action': 'Log in',
'Username: ': username,
'Password: ': password}
# the next 3 lines are pretty much copied from a different StackOverflow
# question. I don't really understand what they're doing, and obviously these
# are where the problem is.
with session() as c:
c.post('https://www.baseballprospectus.com/manageprofile.php', data=payload)
response = c.get('http://www.baseballprospectus.com/sortable/index.php?cid=1820315')
soup = BeautifulSoup(response.content, "lxml")
for row in soup.find_all('tr')[7:]:
cells = row.find_all('td')
name = cells[1].text
print(name)
The script does work, it just pulls the data from the site before it's logged in, so its not the data I want.
Conceptually, there is no problem with your code. You're using a session object to send a login request, then with the same session you're sending a request for the desired page. This means that the cookies set by the login request should be kept for the second request. If you want to read more about the workings of the Session object, here's the relevant Requests documentation.
Since I don't have a valid login for Baseball Prospectus, I'll have to guess that something is wrong with the data you're sending to the login page. A quick inspection using the 'Network' tab in Chrome's Developer Tools, shows that the login page, manageprofile.php, accepts four POST parameters:
username: myUsername
password: myPassword
action: muffinklezmer
nocache: some long number, e.g. 2417395155
However you're sending a different set of parameters, and specifying a different value for the 'action' parameter. Note that the parameter names have to match the original request exactly, otherwise manageprofile.php will not accept the login.
Try replacing the payload dictionary with this version:
payload = {
'action': 'muffinklezmer',
'username': username,
'password': password}
If this doesn't work, try adding the 'nocache' parameter too, e.g.:
'nocache': '1437955145'
I came across this question: How to use Python to login to a webpage and retrieve cookies for later usage?
So, I'm trying to log into a page, (using the request method, second answer).
When I print the HTML using
print request.text
It will print the HTML of the login page, but not the subpage that I put on request.
Is there a problem with the code (which I don't think) or is it mine?
The code is similar to the one on that question, with different pages and usernames.
Thanks!
from requests import session
USERNAME = 'myuser'
PASSWORD = 'mypwd'
payload = {
'action': 'login',
'username': USERNAME,
'password': PASSWORD
}
with session() as c:
c.post('https://www.bricklink.com/login.asp', data=payload) #Login page
request = c.get('http://www.bricklink.com/orderExcelFinal.asp?') #Page I want to access
print request.headers
print request.text
Output
HTML code for the Login page, but not the page I want to access
Your code isn't sending the correct data on the login request.
Each web page is different, and sends different data in order to log in. Yours should be structured like this:
from requests import session
USERNAME = 'myuser'
PASSWORD = 'mypwd'
query = {
'logInTo': '',
'logFolder': 'p',
'logSub': 'w',
}
payload = {
'a': 'a',
'logFrmFlag': 'Y',
'frmUsername': USERNAME,
'frmPassword': PASSWORD,
}
with session() as c:
c.post('https://www.bricklink.com/login.asp', params=query, data=payload) #Login page
request = c.get('http://www.bricklink.com/orderExcelFinal.asp') #Page I want to access
print request.headers
print request.text
In the future, when you need to work out what data needs to be send on an attempt to submit a form, you should use Chrome or Firefox's Developer Tools. Use these to record your login attempt, and then structure the data accordingly. Getting started with using Chrome's developer tools is a bit beyond the scope of this answer, but there are lots of good resources on the web for finding out how you get this information.
I am trying to post a request to log in to a website using the Requests module in Python but its not really working. I'm new to this...so I can't figure out if I should make my Username and Password cookies or some type of HTTP authorization thing I found (??).
from pyquery import PyQuery
import requests
url = 'http://www.locationary.com/home/index2.jsp'
So now, I think I'm supposed to use "post" and cookies....
ck = {'inUserName': 'USERNAME/EMAIL', 'inUserPass': 'PASSWORD'}
r = requests.post(url, cookies=ck)
content = r.text
q = PyQuery(content)
title = q("title").text()
print title
I have a feeling that I'm doing the cookies thing wrong...I don't know.
If it doesn't log in correctly, the title of the home page should come out to "Locationary.com" and if it does, it should be "Home Page."
If you could maybe explain a few things about requests and cookies to me and help me out with this, I would greatly appreciate it. :D
Thanks.
...It still didn't really work yet. Okay...so this is what the home page HTML says before you log in:
</td><td><img src="http://www.locationary.com/img/LocationaryImgs/icons/txt_email.gif"> </td>
<td><input class="Data_Entry_Field_Login" type="text" name="inUserName" id="inUserName" size="25"></td>
<td><img src="http://www.locationary.com/img/LocationaryImgs/icons/txt_password.gif"> </td>
<td><input class="Data_Entry_Field_Login" type="password" name="inUserPass" id="inUserPass"></td>
So I think I'm doing it right, but the output is still "Locationary.com"
2nd EDIT:
I want to be able to stay logged in for a long time and whenever I request a page under that domain, I want the content to show up as if I were logged in.
I know you've found another solution, but for those like me who find this question, looking for the same thing, it can be achieved with requests as follows:
Firstly, as Marcus did, check the source of the login form to get three pieces of information - the url that the form posts to, and the name attributes of the username and password fields. In his example, they are inUserName and inUserPass.
Once you've got that, you can use a requests.Session() instance to make a post request to the login url with your login details as a payload. Making requests from a session instance is essentially the same as using requests normally, it simply adds persistence, allowing you to store and use cookies etc.
Assuming your login attempt was successful, you can simply use the session instance to make further requests to the site. The cookie that identifies you will be used to authorise the requests.
Example
import requests
# Fill in your details here to be posted to the login form.
payload = {
'inUserName': 'username',
'inUserPass': 'password'
}
# Use 'with' to ensure the session context is closed after use.
with requests.Session() as s:
p = s.post('LOGIN_URL', data=payload)
# print the html returned or something more intelligent to see if it's a successful login page.
print p.text
# An authorised request.
r = s.get('A protected web page url')
print r.text
# etc...
If the information you want is on the page you are directed to immediately after login...
Lets call your ck variable payload instead, like in the python-requests docs:
payload = {'inUserName': 'USERNAME/EMAIL', 'inUserPass': 'PASSWORD'}
url = 'http://www.locationary.com/home/index2.jsp'
requests.post(url, data=payload)
Otherwise...
See https://stackoverflow.com/a/17633072/111362 below.
Let me try to make it simple, suppose URL of the site is http://example.com/ and let's suppose you need to sign up by filling username and password, so we go to the login page say http://example.com/login.php now and view it's source code and search for the action URL it will be in form tag something like
<form name="loginform" method="post" action="userinfo.php">
now take userinfo.php to make absolute URL which will be 'http://example.com/userinfo.php', now run a simple python script
import requests
url = 'http://example.com/userinfo.php'
values = {'username': 'user',
'password': 'pass'}
r = requests.post(url, data=values)
print r.content
I Hope that this helps someone somewhere someday.
The requests.Session() solution assisted with logging into a form with CSRF Protection (as used in Flask-WTF forms). Check if a csrf_token is required as a hidden field and add it to the payload with the username and password:
import requests
from bs4 import BeautifulSoup
payload = {
'email': 'email#example.com',
'password': 'passw0rd'
}
with requests.Session() as sess:
res = sess.get(server_name + '/signin')
signin = BeautifulSoup(res._content, 'html.parser')
payload['csrf_token'] = signin.find('input', id='csrf_token')['value']
res = sess.post(server_name + '/auth/login', data=payload)
Find out the name of the inputs used on the websites form for usernames <...name=username.../> and passwords <...name=password../> and replace them in the script below. Also replace the URL to point at the desired site to log into.
login.py
#!/usr/bin/env python
import requests
from requests.packages.urllib3.exceptions import InsecureRequestWarning
requests.packages.urllib3.disable_warnings(InsecureRequestWarning)
payload = { 'username': 'user#email.com', 'password': 'blahblahsecretpassw0rd' }
url = 'https://website.com/login.html'
requests.post(url, data=payload, verify=False)
The use of disable_warnings(InsecureRequestWarning) will silence any output from the script when trying to log into sites with unverified SSL certificates.
Extra:
To run this script from the command line on a UNIX based system place it in a directory, i.e. home/scripts and add this directory to your path in ~/.bash_profile or a similar file used by the terminal.
# Custom scripts
export CUSTOM_SCRIPTS=home/scripts
export PATH=$CUSTOM_SCRIPTS:$PATH
Then create a link to this python script inside home/scripts/login.py
ln -s ~/home/scripts/login.py ~/home/scripts/login
Close your terminal, start a new one, run login
Some pages may require more than login/pass. There may even be hidden fields. The most reliable way is to use inspect tool and look at the network tab while logging in, to see what data is being passed on.