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Django Rest Framework: Order by Serializer Method Field

I am currently using Django REST framework 3.11.0 with Django 3.0.6. I am still very new to DRF and I am not sure how to approach this problem. I am trying to apply sort to SerializerMethodField and an enum. I was able to find some documentation that states that I could make my own OrderFilter but I dont know how. Are there any examples I could use? Here is my code.
View
from rest_framework import generics
from V1.assets.models.asset_main import Asset
from V1.assets.serializers.asset_serializer import AssetSerializer
from rest_framework import filters
from django_filters.rest_framework import DjangoFilterBackend
class AssetsView(generics.ListCreateAPIView):
queryset = Asset.objects.all()
serializer_class = AssetSerializer
filter_backends = [DjangoFilterBackend, filters.SearchFilter, filters.OrderingFilter]
filter_fields = ['asset_type']
search_fields = ['asset_type', 'asset_properties', 'current_employee_name']
Model
class AssetType(models.TextChoices):
LAPTOP = 'LPT', _('Laptop')
MOUSE = 'MSE', _('Mouse')
MONITOR = 'MTR', _('Monitor')
AC_ADAPTER = 'ADR', _('AC Adapter')
TELEPHONE = 'TLP', _('Telephone')
LOCK = 'LCK', _('Lock')
HEADSET = 'HDS', _('Headset')
class Asset(CreatedModified):
asset_type = models.CharField(
max_length=3,
choices=AssetType.choices,
default=None
)
asset_properties = JSONField(default=dict)
current_employee = models.ForeignKey(
Employee,
related_name='assets_current_employees',
related_query_name='assets_current_employee',
default=None,
on_delete=models.CASCADE,
null=True,
blank=True
)
class Meta:
app_label = 'assets'
default_related_name = 'assets'
def __str__(self):
return self.asset_type
Serializer
from V1.general.enums import AssetStatus, AssetType
from V1.accounts.models.employee_main import Employee
class AssetSerializer(serializers.ModelSerializer):
current_employee_name = serializers.SerializerMethodField('get_full_name_from_employee')
asset_type = serializers.CharField(source='get_asset_type_display')
class Meta:
model = Asset
fields = (
'id',
'asset_type',
'asset_properties',
'current_employee',
'current_employee_name'
)
extra_kwargs = {
'asset_type': {
'required': True,
'allow_blank': False
}
}
def get_full_name_from_employee(self, asset):
current_employee_name = asset.current_employee.first_name + ' ' + asset.current_employee.last_name
return current_employee_name
I can't seem to order by current_employee_name or asset_type. What should I do to allow sorting for these two fields?

As far as I can understand from your question you want to order the Assets by the current employee name. Let's take few names for example:
Jean d'Artagnan (first_name: Jean, last_name: d'Artagnan)
Joe Plumber (first_name: Joe, last_name: Plumber)
Jonas Meyer (first_name: Jonas, last_name: Meyer)
The same ordering can be achieved if we sort first by first_name and then by last_name. In case there are multiple entries with the same first_name the ordering will be done be the last_name.
To achieve this you can simply specify the ordering_fields in your view:
class AssetsView(generics.ListCreateAPIView):
filters = [filters.OrderingFilter]
ordering_fields = ['current_employee.first_name', 'current_employee.last_name']

how to add a button/on click action in Django admin page model

I have a model where I have list of servers...
Here is my model:
class Ipaddress(models.Model):
ip_address=models.CharField("Ip address",max_length=20)
device_type= models.ForeignKey("DeviceType", on_delete=models.CASCADE)
slug = models.SlugField(unique=True)
machine_name=models.CharField("Machine Name",max_length=500)
user=models.CharField("User",max_length=200)
department= models.ForeignKey("Department", on_delete=models.CASCADE)
location= models.ForeignKey("Location", on_delete=models.CASCADE)
updated = models.DateField("Date Updated",null=True)
note =models.TextField()
class Meta:
verbose_name = 'IP Management'
def __str__(self):
return self.ip_address[:50]
I want to add ping server action for every model record and store "Yes" if it revived any response. Here is admin page:
from django.contrib import admin
from pages.models import Ipaddress, DeviceGroup, Location,Department,
from django_admin_listfilter_dropdown.filters import DropdownFilter, RelatedDropdownFilter
class DepartmentAdmin(admin.ModelAdmin):
search_fields = ['name']
class LocationAdmin(admin.ModelAdmin):
search_fields = ['description']
list_display =('description',)
class IpaddressAdmin(admin.ModelAdmin):
prepopulated_fields = {'slug': ('ip_address',)}
search_fields = ('ip_address', 'machine_name')
list_display = ('ip_address', 'device_type', 'machine_name', 'user', 'department','location','updated',)
list_display_links =('ip_address', 'device_type', 'machine_name', 'user', 'department','location','updated',)
autocomplete_fields = ['location','department',]
list_filter = (
('user', DropdownFilter),
('department', RelatedDropdownFilter),
('location', RelatedDropdownFilter),
('device_type', RelatedDropdownFilter),
)
I am thinking to add a button to pop up a small dialog box from where user will confirm ping. Need some help how I can do that?

Django - add image to list display in django admin

Please help me. I gave up. I am trying to add additional field to my django admin. I would like to insert image thumbnail there. This is part of my admin.py:
class SiteAdmin(admin.ModelAdmin):
list_display = ('is_active', 'name', 'description', 'keywords', 'date')
fields = ('name', 'url', 'category', 'subcategory', 'category1',
'subcategory1', 'description',
'keywords', 'date', 'group', 'email', 'is_active')
readonly_fields = ('date',)
list_display_links = ('name',)
list_filter = ('is_active',)
actions = [activate_sites, deactivate_sites]
I wolud like to add 'image' to list_display. Images are generating by thumbalizr. I have a method in models.py:
class Site(models.Model):
category = models.ForeignKey('Category')
subcategory = ChainedForeignKey(
'SubCategory',
chained_field='category',
chained_model_field='category',
show_all=False,
auto_choose=True,
blank=True, null=True, default=None)
name = models.CharField(max_length=70, verbose_name="Tytuł")
description = models.TextField(verbose_name="Opis")
keywords = MyTextField(max_length=100, verbose_name="Słowa kluczowe")
date = models.DateTimeField(default=datetime.now, editable=False)
url = models.URLField()
is_active = models.BooleanField(default=False)
category1 = models.ForeignKey('Category', related_name='category', blank=True, null=True, default=None)
subcategory1 = ChainedForeignKey(
'SubCategory',
chained_field='category1',
chained_model_field='category',
related_name='subcategory',
show_all=False,
auto_choose=True, blank=True, null=True)
group = models.CharField(max_length=10, choices=(('podstawowy', 'podstawowy'),
('premium', 'premium')), default='podstawowy',
help_text="<div id='group'><ul><li>You can add site to 2 <b>categories</b></li></ul></div>")
email = models.EmailField(help_text='Podaj adres email')
def get_absolute_url(self):
return reverse('site', args=[str(self.category.slug),
str(self.subcategory.slug), str(self.id)])
def get_thumb(self):
host = urlparse(self.url).hostname
if host.startswith('www.'):
host = host[4:]
thumb = 'https://api.thumbalizr.com/?url=http://' + host + '&width=125'
return thumb
It is get_thumb(). How can I take image to every site and put in in my django admin page? Should I add additional field to my Site model? I don't want to store images on my server - they are directly from thumbalizr.

You should add a method into your modeladmin class. Then you can add this method into your field list.
class SiteAdmin(admin.ModelAdmin):
list_display = [..., 'thumb']
...
...
def thumb(self, obj):
return "<img src='{}' width='20' height='20' />".format(obj.get_thumb())
thumb.allow_tags = True
thumb.__name__ = 'Thumb'
https://docs.djangoproject.com/en/1.10/ref/contrib/admin/#django.contrib.admin.ModelAdmin.list_display

I was solving this problem in latest django 2.0.6. I wanted to achiave to have image thubnail and some more details in listview in django-admin.
I post answer here:
Django: Display image in admin interface

You can create thumb column by defining thumb() and by assigning thumb() to list_display as shown below:
# "admin.py"
from django.contrib import admin
from .models import Site
from django.utils.html import format_html
#admin.register(Site)
class SiteAdmin(admin.ModelAdmin):
list_display = (
'is_active',
'name',
'description',
'keywords',
'date',
'thumb' # Here
)
# ...
def thumb(self, obj): # Here
return format_html(
f'''<a href="{obj.get_thumb()}" target="_blank">
<img
src="{obj.get_thumb()}" alt="{obj.get_thumb()}"
width="50" height="50"
style="object-fit: cover;"
/>
</a>''')

How to create objects inline for many to many relationships in Django?

I have defined such a relation between questions and tags : (is this correct?)
myproject/myapp/models.py :
from django.db import models
from django.contrib.auth.models import User
from vote.managers import VotableManager
from django.utils import timezone
from datetime import datetime, timedelta
class Tag(models.Model):
text = models.CharField(max_length = 20)
user = models.ForeignKey(User)
class Question(models.Model):
text = models.TextField()
user = models.ForeignKey(User) # First writer of the question
tags = models.ManyToManyField(Tag)
votes = VotableManager()
created = models.DateTimeField(auto_now_add=True) # auto_now_add=True
modified = models.DateTimeField(auto_now=True) # auto_now=True
def was_published_recently(self):
return self.pub_date >= timezone.now() - timedelta(days=1)
and I want an admin page to create Questions, as well as Tags, so this is my admin.py:
from django.contrib import admin
from qportal.models import Tag, Question
class TagsInline(admin.TabularInline):
model = Question.tags.through
extra = 3
class QuestionAdmin(admin.ModelAdmin):
fieldsets = [
(None, {'fields': ['text']}),
#('Date information', {'fields': ['created'], 'classes': ['collapse']}),
]
inlines = [TagsInline]
list_display = ('text', 'created', 'was_published_recently')
list_filter = ['created']
search_fields = ['text']
admin.site.register(Question, QuestionAdmin)
however, when I run runserver and login to http://127.0.0.1:8000/admin/qportal/question/add/, the page I see is this :
As you can see, it only allows me to select a pre-existing tag. However I want to be able to create a tag for the first time, while creating the question, inline. How can I do that?
Thanks !

Don't use the inline for the tags. Regular M2M field will work in admin just fine. For more adequate M2M widget add the filter_horizontal property:
class QuestionAdmin(admin.ModelAdmin):
fieldsets = [
(None, {'fields': ['text', 'tags']}),
]
filter_horizontal = ['tags']
...
To create a Tag from the QuestionAdmin press the green + sign at the right side of the widget.

Generic Relations/Generic Foreign Keys in the Django Admin

I've been trying to display a GenericForeignKey in the Django admin but can't get it working. I have a FullCitation class that can be linked to either a NonSupportedProgram or a SupportedProgram class. So, I have used a generic foreign key.
In the admin, I want users to only be able to select 'NonSupportedProgram' or 'SupportedProgram' from the content_type dropdown and then, from the object_id field, I need users to be able to select from a dropdown listing the existing NonSuportedPrograms or the existing SupportedPrograms, with the option of creating a new one. Is this possible? Where am I going wrong?
models.py
class FullCitation(models.Model)
# the software to which this citation belongs
# either a supported software program or a non-supported software program
limit = models.Q(app_label = 'myprograms', model = 'supportedprogram') | models.Q(app_label = 'myprograms', model = 'nonsupportedprogram')
content_type = models.ForeignKey(ContentType), limit_choices_to = limit, )
object_id = models.PositiveIntegerField()
content_object = generic.GenericForeignKey('content_type', 'object_id')
is_primary = models.BooleanField(help_text="Is this the Primary Citation for the software program?")
class Meta:
unique_together = ('content_type', 'object_id')
app_label = 'myprograms'
reversion.register(FullCitation)
class NonSupportedProgram(models.Model):
title = models.CharField(max_length=256, blank = True)
full_citation = generic.GenericRelation('FullCitation')
class Meta:
app_label = 'myprograms'
reversion.register(NonSBGridProgram)
class SupportedProgram(models.Model):
title = models.CharField(max_length=256, blank = True)
full_citation = generic.GenericRelation('FullCitation')
# and a bunch of other fields.....
admin.py
class FullCitationAdmin(reversion.VersionAdmin):
fieldsets = (
('Which Program', {
'fields': ('content_type', 'object_id', ),
}),
('Citation Information', {
'fields': ('is_primary',),
}),)
# autocomplete_lookup_fields = {
# 'generic': [['content_type', 'object_id']],
# }
# inlines = ['NonSupportedProgramInline', ]
list_display = ('content_object', 'is_primary',)
search_fields = ('content_object__title', )
# list_filter = ('content_object',)

This is a module that renders GenericForeignKeys in the Django Admin:
https://github.com/lexich/genericrelationview
It just doesn't work with a no conflict jQuery setup (like the one from Django CMS).