Develop Reference

How to get Document Name from DocumentReference in Firestore Python

I have a document reference that I am retreiving from a query on my Firestore database. I want to use the DocumentReference as a query parameter for another query. However, when I do that, it says
TypeError: sequence item 1: expected str instance, DocumentReference found
This makes sense, because I am trying to pass a DocumentReference in my update statement:
db.collection("Teams").document(team).update("Dictionary here") # team is a DocumentReference
Is there a way to get the document name from a DocumentReference? Now before you mark this as duplicate: I tried looking at the docs here, and the question here, although the docs were so confusing and the question had no answer.
Any help is appreciated, Thank You in advance!

Yes,split the .refPath. The document "name" is always the last element after the split; something like lodash _.last() can work, or any other technique that identifies the last element in the array.
Note, btw, the refPath is the full path to the document. This is extremely useful (as in: I use it a lot) when you find documents via collectionGroup() - it allows you to parse to find parent document(s)/collection(s) a particular document came from.
Also note: there is a pseudo-field __name__ available. (really an alias of documentID()). In spite of it's name(s), it returns the FULL PATH (i.e. refPath) to the document NOT the documentID by itself.

I think I figured out - by doing team.path.split("/")[1] I could get the document name. Although this might not work for all firestore databases (like subcollections) so if anyone has a better solution, please go ahead. Thanks!

How to find all cells matching a regex with gspread?

So I am very new to programming and I am using python gspread module to use a google sheet as a database.
There's a function for said module called sheet.findall(query, row, column), and this is great, but there's one issue, the query parameter will only look for an exact match, meaning that if i write "DDG", it will not get me the info from a cell with the value of "DDG-87".
After reading the documentation, I found out that you can use python regular expressions to structure the query parameter, so I did that, but there's a problem; The second parameter in re.findall is WHERE to look for, but the issue is that the whole variable is the action of searching, example shown below:
search = sheet.findall(re.findall("[DDG]", The where to search goes here))
As you can see, the whole variable (SEARCH) is the search function, and therefore, I can not specify where to search.
I have tried to set the second parameter of the regex as (SEARCH), but obviously, it won't work.
Any idea or a clue on how I can set the second parameter of re.findall() to be self, or what I can do so that the function doesn't search for an exact match, but if it contains the text?
Thank you.

From the gspread docs:
Find all cells matching a regexp:
criteria_re = re.compile(r'(Small|Room-tiering) rug')
cell_list = worksheet.findall(criteria_re)
So the following should work in your case:
criteria_re = re.compile(r'DDG.*')
search = sheet.findall(criteria_re)

How to delete document from index by it's path in Whoosh

First i add documents to index like this:
writer.add_document(title=doc_path.split(os.sep)[-1], path=doc_path, content=text, textdata=text)
And then i just need to delete one of them completely from index by it's path. Documentation says there are few no low level method to do this:
delete_by_term(fieldname, termtext)
Deletes any documents where the given (indexed) field contains the
given term. This is mostly useful for ID or KEYWORD fields.
delete_by_query(query)
Deletes any documents that match the given query.
but i can't find suitable and very convenient method for me where i can specify path of the document and just remove it. There is some low level method where i can specify internal doc_number, which i supposed to get somehow.
Can anyone give me advice how it's better to accomplish this task?

ix = open_dir('/my_index_dir_path/..')
writer = ix.writer()
writer.delete_by_term('path', doc_path)
writer.commit()
delete_by_term
method does exactly what i need. Note, that first argument is a text string 'path', and them goes the actual path. My mistake was to put an actual path instead of attribute name.

Google app engine IN filter

I am using python 2.7, jinja2 and google app engine.
I have a database where one of the entities are string in this form:
"test1,test2,test3,test4,test5"
I try to figure a query where I will retrieve all the entities where test1 for example are in the string.
I tried the following where tags is the string property:
category = "test1"
mymodel.gql("WHERE tags in :1", category)
I have this error : BadArgumentError: List expected for "IN" filter
I can imagine that this is logical, since my property is string and not list, but how can I change the query to make it work?

You would have to modify you property to be a StringListProperty rather than string for this to work.
There are not a lot of other choices either. Use FullText Search is or something like WHoosh https://github.com/tallstreet/Whoosh-AppEngine which also does full text search are your other alternatives.
I would personally change it to a StringListProperty.

As the error indicates, the GQL is expecting a list. Try making category a list:
category = ["test1"]

Catch full URL in python

I'm developing application using Bottle. How do I get full query string when I get a GET Request.
I dont want to catch using individual parameters like:
param_a = request.GET.get("a","")
as I dont want to fix number of parameters in the URL.
How to get full query string of requested url

You can use the attribute request.query_string to get the whole query string.

Use request.query or request.query.getall(key) if you have more than one value for a single key.
For eg., request.query.a will return you the param_a you wanted. request.query.b will return the parameter for b and so on.
If you only want the query string alone, you can use #halex's answer.