Uploading asset to S3 isn't working - python

I need to upload a css file and a js file to S3 and use them as static resources. If I upload them via web from S3 page, it works. But if I upload via a python script, it uploads the files, but I can't get the css seems not working at all.
Here is my python code,
s3 = boto3.resource('s3')
s3.meta.client.upload_file('sample.css', 'mybucket', 'sample_dir/sample.css', {'ACL': 'public-read'})

The notable condition here is that files uploaded through the console are correctly used by the browser, but files uploaded through the API are not.
The AWS/S3 console, by default, automatically sets the Content-Type: for many uploaded file types, (for CSS, this should probably be text/css)... but the API requires it be set by your code.
But, you don't appear to be setting it, so the browser may be refusing to use the css, even if it downloads successfully, because the Content-Type: response header contains an unexpected value.
(The browser dev tools/console should show an error or warning to confirm this).

Mentioning file type solved this issue.
s3 = boto3.resource('s3')
s3.meta.client.upload_file('sample.css', 'mybucket', 'sample_dir/sample.css', {'ACL': 'public-read','public-read','ContentType': 'text/css'})

Related

Images are not loading from an Amazon S3 bucket

I am doing a Django project. I have hosted my static files on Amazon S3. It has been successfully uploaded to it. But, the images are not loading when I run the server.
When I inspect the image field it shows:
https://django-ecommerce-files.s3.amazonaws.com/images/logo.png%22%20id=%22image%22%20style=%22width:%2040px;%20height:40px%22%3E
When I double clicked it. It shows this error:
<Error>
<Code>AccessDenied</Code>
<Message>Access Denied</Message>
<RequestId>07PX6KHYASHT3008</RequestId>
<HostId>pJCxChq1JHlw/GL0Zy/W+PvX1TevOf/C60Huyidi8+0GMAs8geYlXSrEgo6m9vllL0PouTn6NAA=
</HostId>
</Error>
When working with S3 bucket, there is a need to make your resources(files) publicly accessible. You can either do that programmatically at the point of uploading to S3 or from the AWS console. please check how you can enable public access to your files here
Make sure that you have changed the public access settings for the S3 bucket, such that it allows files to be accessed by your app (with the right credentials).
Your requirement may vary, so take a look at their user manual.
Check the Permissions tab under the bucket.
Or, you can also take a look at the actions allowed on your S3 bucket, it must be configured to allow read/write. Refer the docs for a few examples
im not sure if this works. can you try enabling the static hosting on your s3?
go to your s3.
go to properties, scroll down to the bottom
enable the static hosting
a png file on s3 would look like this(the link works btw):
https://aws-cicd-react.s3.ap-southeast-1.amazonaws.com/logo512.png
addendum:
if you want to see the url of your file:
In your s3, click the file then go to properties
look at the Object URL

AWS: Make a file downloadable by https link

I have a local .exe file and I want to make it available by https so everyone can download it.
example: "download my app here: https://look_how_downloadable_i_am.exe
If I can update the file with python and manually with interface, it would be perfect ! (the possibility to automate the process and keep it simple if done manually).
It's maybe possible with AWS S3 or/and Lambda.
The most straightforward way would be using an s3 bucket to enable downloads to the file.
Steps are:
Upload file to the bucket
Select the file after it gets uploaded, press actions and select make public
This will make the file publicly downloadable through its unique link. In order to use your own custom domain and link you will have to use CloudFront as #jordanm suggested.
You can also use a python script to update or download your file, you can find demo codes and documentations in Reference 3
Reference 1: How to create download link for an Amazon S3 bucket's object?
Reference 2: https://aws.amazon.com/premiumsupport/knowledge-center/read-access-objects-s3-bucket/
Reference 3: https://docs.aws.amazon.com/code-samples/latest/catalog/code-catalog-python-example_code-s3.html
You can use boto3 to programmatically upload a local file to a bucket, than just edit the buckets permissions to allow public read. Or instead of editing the buckets permissions, when uploading the file just edit the ACL s3.upload_file(upload_path, "bucket-name", file-key, ExtraArgs={'ACL': "public-read"})
upload_path just being the local file path, and file-key being the object name

How to view S3 bucket video files into browser

In my current project, my objective is to access the video files (in mp4) from AWS S3 bucket.
I have created S3 bucket, named videostreambucketpankesh . This is a public folder with the following permission (as follows).
The Access Control list (ACL) of videostreambucketpankesh bucket is as follows:
The bucket policy of videostreambucketpankesh bucket is as follows:
Now the bucket “videostreambucketpankesh” contains many subfolders (or sub-buckets), including one subfolder, named “video”. This sub-bucket contains some .mp4 file (as shown in the image below).
My problem is that there are some files (such as firetruck.mp4 and ambulance.mp4) that can be directly accessed by browser, when I click its objectURL. I can play them in the browser.
However, I am not able to play other .mp4 ( 39cf9079-7b65-4aa8-8913-8a6b924021d3.mp4, 45fd1749-95aa-488c-ac2f-be8673b8416e.mp4, 8ba187f2-5148-49f6-9acc-2459e41f547b.mp4) files into the browser, when I click its objectURL.
Please note that I upload 39cf9079-7b65-4aa8-8913-8a6b924021d3.mp4, 45fd1749-95aa-488c-ac2f-be8673b8416e.mp4, 8ba187f2-5148-49f6-9acc-2459e41f547b.mp4 video file using a python program programmatically in Python (See the following code ).
def upload_to_s3(local_file, bucket, s3_file):
data = open(local_file, 'rb')
s3_client.put_object(Key="video/"+frame_id+".mp4", Body=data, ContentType='video/mp4', Bucket = s3_bucket)
print("Upload succcessful")
However, I am not able to play mp4 file (I play them in VLC player) in my Google chrome browser. Can you please suggest how can I resolve this issue?
Select the files and look at Properties / Metadata.
It should show Content-Type : video/mp4 like this:
When uploading via the browser, the metadata is automatically set based upon the filetype.
If you are uploading via your own code, you can set the metadata like this:
s3_client.upload_file('video.mp4', bucketname, key, ExtraArgs={'ContentType': "video/mp4"})
or
bucket.put_object(key, Body=data, ContentType='video/mp4')
See: AWS Content Type Settings in S3 Using Boto3

Serving files from BlobStore in GAE

I want to ask if I can download files from the blobstore in google app engine (zip files especially) without using the handlers(class handlers). I mean serve files directly without downloadhandler class usage.
Have any idea??
No. (if I understand the question properly) There is no direct URL for blobstore items, so you can't get at them directly. However you can serve blobs from URLs that you define with less than 10 lines of code.
EDIT: The send_blob also takes a save_as argument. Try save_as=True to use the blob's uploaded filename as the attachment filename.

Asynchronous File Upload to Amazon S3 with Django

I am using this file storage engine to store files to Amazon S3 when they are uploaded:
http://code.welldev.org/django-storages/wiki/Home
It takes quite a long time to upload because the file must first be uploaded from client to web server, and then web server to Amazon S3 before a response is returned to the client.
I would like to make the process of sending the file to S3 asynchronous, so the response can be returned to the user much faster. What is the best way to do this with the file storage engine?
Thanks for your advice!
I've taken another approach to this problem.
My models have 2 file fields, one uses the standard file storage backend and the other one uses the s3 file storage backend. When the user uploads a file it get's stored localy.
I have a management command in my application that uploads all the localy stored files to s3 and updates the models.
So when a request comes for the file I check to see if the model object uses the s3 storage field, if so I send a redirect to the correct url on s3, if not I send a redirect so that nginx can serve the file from disk.
This management command can ofcourse be triggered by any event a cronjob or whatever.
It's possible to have your users upload files directly to S3 from their browser using a special form (with an encrypted policy document in a hidden field). They will be redirected back to your application once the upload completes.
More information here: http://developer.amazonwebservices.com/connect/entry.jspa?externalID=1434
There is an app for that :-)
https://github.com/jezdez/django-queued-storage
It does exactly what you need - and much more, because you can set any "local" storage and any "remote" storage. This app will store your file in fast "local" storage (for example MogileFS storage) and then using Celery (django-celery), will attempt asynchronous uploading to the "remote" storage.
Few remarks:
The tricky thing is - you can setup it to copy&upload, or to upload&delete strategy, that will delete local file once it is uploaded.
Second tricky thing - it will serve file from "local" storage until it is not uploaded.
It also can be configured to make number of retries on uploads failures.
Installation & usage is also very simple and straightforward:
pip install django-queued-storage
append to INSTALLED_APPS:
INSTALLED_APPS += ('queued_storage',)
in models.py:
from queued_storage.backends import QueuedStorage
queued_s3storage = QueuedStorage(
'django.core.files.storage.FileSystemStorage',
'storages.backends.s3boto.S3BotoStorage', task='queued_storage.tasks.TransferAndDelete')
class MyModel(models.Model):
my_file = models.FileField(upload_to='files', storage=queued_s3storage)
You could decouple the process:
the user selects file to upload and sends it to your server. After this he sees a page "Thank you for uploading foofile.txt, it is now stored in our storage backend"
When the users has uploaded the file it is stored temporary directory on your server and, if needed, some metadata is stored in your database.
A background process on your server then uploads the file to S3. This would only possible if you have full access to your server so you can create some kind of "deamon" to to this (or simply use a cronjob).*
The page that is displayed polls asynchronously and displays some kind of progress bar to the user (or s simple "please wait" Message. This would only be needed if the user should be able to "use" (put it in a message, or something like that) it directly after uploading.
[*: In case you have only a shared hosting you could possibly build some solution which uses an hidden Iframe in the users browser to start a script which then uploads the file to S3]
You can directly upload media to the s3 server without using your web application server.
See the following references:
Amazon API Reference : http://docs.amazonwebservices.com/AmazonS3/latest/dev/index.html?UsingHTTPPOST.html
A django implementation : https://github.com/sbc/django-uploadify-s3
As some of the answers here suggest uploading directly to S3, here's a Django S3 Mixin using plupload:
https://github.com/burgalon/plupload-s3mixin
I encountered the same issue with uploaded images. You cannot pass along files to a Celery worker because Celery needs to be able to pickle the arguments to a task. My solution was to deconstruct the image data into a string and get all other info from the file, passing this data and info to the task, where I reconstructed the image. After that you can save it, which will send it to your storage backend (such as S3). If you want to associate the image with a model, just pass along the id of the instance to the task and retrieve it there, bind the image to the instance and save the instance.
When a file has been uploaded via a form, it is available in your view as a UploadedFile file-like object. You can get it directly out of request.FILES, or better first bind it to your form, run is_valid and retrieve the file-like object from form.cleaned_data. At that point at least you know it is the kind of file you want it to be. After that you can get the data using read(), and get the other info using other methods/attributes. See https://docs.djangoproject.com/en/1.4/topics/http/file-uploads/
I actually ended up writing and distributing a little package to save an image asyncly. Have a look at https://github.com/gterzian/django_async Right it's just for images and you could fork it and add functionalities for your situation. I'm using it with https://github.com/duointeractive/django-athumb and S3

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