Develop Reference

Python using random within a loop - separated by user action

I'm new to coding and started with a python course now.
I was trying to work on a word bingo game but can't seem to make it work.
import random
from random import randint
print "Let's play Bingo!"
print
# prompt for input
bingo = input("First enter your bingo words: ")
# split up the sentence into a list of words
list = bingo.split()
print
print "Okay, let's go! "
random.shuffle(list)
for choice in random.shuffle(list):
user = raw_input()
if user == "":
print(choice)
raw_input("")
else:
print "That's the end of the game ^.^"
break
#for words in range(len(list)):
#user = raw_input()
#if user == "":
#print(random.sample(list, 1))
#raw_input("")
#else:
#print "That's the end of the game ^.^"
#break
If i use choice in random.shuffle(list) I get a NonType error
before I used a for loop with random.sample (seen in the ## parts at the end)
That worked except in each iteration the words were still repeated.
I tried to search for similar questions but they all either had numbers or more automatic loops.
I want it so the user enters words, then each time they press enter, a new word appears from the list without repetition.
I can't seem to figure out how to get that into a loop - any help?
I tried to use random.choice and random.sample but the words still kept repeating in a for loop.
Tried shuffle and had a nonType error

Two comments:
Don't use list for variable name, it is a keyword in Python for type list
random.shuffle(l) does operation in-place (i.e. after you called it, l will be shuffled). So, you just supply l into the loop. Hope this helps.
import random
from random import randint
print "Let's play Bingo!"
print
# prompt for input
bingo = input("First enter your bingo words: ")
# split up the sentence into a list of words
l = bingo.split()
print
print "Okay, let's go! "
random.shuffle(l)
for choice in l:
user = raw_input()
if user == "":
print(choice)
raw_input("")
else:
print "That's the end of the game ^.^"
break
P.S.
Why did you decide to use Python 2? If you are new to Python it can be better to work with Python 3. It is your decision to make. FYI, https://www.python.org/doc/sunset-python-2/#:~:text=We%20have%20decided%20that%20January,as%20soon%20as%20you%20can.

Making a game like Mastermind in Python

I'm trying to make a game like Mastermind in Python but by using numbers [1-9] instead of colours. The game needs to be a little complex however and that is where I am struggling. I want to be able to randomly generate a password of 5 digits between [0-9] and make the user have 10 tries to get it right. If they guess a number correctly, I want to tell them where it is in their list and ask them to keep going as well. So far, I have this:
import random
random_password = [random.randint(0,9) for i in range (5)]
for counter in range (10):
guess = input ("Crack the Mastermind code ")
if guess != random_password :
print ("Guess again ")
#Here I am trying to make it find out if it has a didgit correct, tell them where
#and ask the them to keep guessing. once count runs out, I want it to say they lost
elif guess
else print ("Sorry, you lose :( ")
if guess == random_password :
print ("Congrats, you win! ")
Any help is appreciated overflow bros, I am lost. I know that I need it to access items from a list. Would using a function like append work?
EDIT: This is my new code. Sorta works however my output is now showing it is wrong even when I guess the number correctly. It wants me to input with '' and , to separate the list but I shouldn't have to have the user do that to make the game function.
import random
random_password = [str (random.randint(0,9)) for i in range (5)]
for counter in range (10):
guess = input(str ("Crack the Mastermind code ") )
if guess != random_password :
print ("Guess again ")
#Here I am tryin to make it find out if it has a didgit correct, tell them where
#and ask the them to keep guessing. once count runs out, I want it to say they lost
for i in random_password:
if(i in guess):
print (i)
if guess == random_password :
print ("Congrats, you win! ")
else :
print ("Sorry, you lose :( the correct answer was.... ")
print (random_password)

One way to do it quickly is to create a small function that will check if any of your string answer (from input) match with any characters of the password list
Also I change the order of your condition statement to make it more clear and efficient.
Finally I change your random_password from LIST to STRING because then you will be able to do guess == random_password properly.
Hope it helps!
PS:
IF you use Python2.X you should change input to raw_input (to get string value) else if you use Python3.X just keep it this way
import random
def any_digits(guess,password):
for character in guess:
if character in password:
return True
return False
random_password = ''.join([str(elem) for elem in [random.randint(0,9) for i in range (5)]])
print(random_password)
print(type(random_password))
for counter in range (10):
guess = input ("Crack the Mastermind code ")
if guess == random_password :
print ("Congrats you win! ")
elif any_digits(guess, random_password):
print ("Some numbers are correct! ")
else:
print ("Guess again ")
print("No more chances, you lose...")
print("The code was ", random_password)

Python; How do I test if something is in a list?

I was writing a code that will ask you to play a guessing game. It will ask you whether you want to play or not and proceed.
It was supposed to ask a number again if the entered value is not in the list but It is not working. I couldn't get it. Thx by now!
import random
import math
import time
repeat=True
numbers = ["1","2","3","4","5"]
gamestart=False
gamecontinue=True
def guess():
chosennumber=random.choice(numbers)
guessnumber=raw_input(">Guess the number I chose between 0 and 6:")
if guessnumber==chosennumber and guessnumber in numbers:
print ">Congratulations, I chose %d too!" % (int(chosennumber))
print
elif guessnumber!=chosennumber:
print "That is not right."
print "I chose %d." % (int(chosennumber))
print
elif not guessnumber in numbers:
while not guessnumber in numbers:
guessnumber=raw_input(">Please enter a number between 0 and 6:")
if raw_input(">Do you want to play guessing game? Y or N:") == "Y":
gamestart=True
else:
print "Okay, I will play myself."
time.sleep(2)
print "Bye :("
while gamestart==True and gamecontinue==True:
guess()
if raw_input (">Do you want to play again? Y or N:") == "N":
gamecontinue=False
print "Okay, I will play myself."
time.sleep(2)
print "Bye :("

so you figured out what was the issue, good! but i have one more tip for you, a better approach to achieve this is check if the input is correct as soon is readed, if it is correct you keep going, if it not, you ask for it again right there:
while True:
guessnumber=raw_input(">Guess the number I chose between 0 and 6:")
if guessnumber in numbers:
print "good!"
break
else:
print "bad!"
and now you're sure that the input is correct so you only check:
if guessnumber==chosennumber:
print ">Congratulations, I chose %d too!" % (int(chosennumber))
else:
print "That is not right."
print "I chose %d." % (int(chosennumber))

if number not in numbers
That will do the trick
It checks if it is true that the selected number is in the list

The problem is that if you put two elif statements the first one will proceed first.
elif guessnumber!=chosennumber:
print "That is not right."
print "I chose %d." % (int(chosennumber))
print
This condition will be asked first. But if you look again at it whether the input (guessnumber) is in the list or not it will proceed. So if we want it to become a condition which we enter a number that is in a list but not matching with the chosen number, we will add another condition to elif statement.
code will be like this
elif guessnumber!=chosennumber and guessnumber in numbers:
Slight detail but good to keep in mind I think.

Show me the way to calling my function

So I'm learning to code and I started with Python.
I've learned the very basics of programming in python, like what are variables, operators, some functions etc.
I have this code:
def guessGame():
import random
guesses = 0
randomNo = random.randint(0, 100)
print "I think of a number between 0 and 100, you have 10 guesses to get it right!"
while guesses < 10:
guess = input("Take a guess ")
guess = int(guess)
guesses += 1
if guess < randomNo:
print "The number is higher than your guess"
if guess > randomNo:
print "The number is lower than your guess"
if guess == randomNo:
break
if guess == randomNo:
guesses = str(guesses)
print "You got it in %s guesses!" % guesses
if guess != randomNo:
print "You failed to guess!"
guessGame()
when I run the code in cmd it just ends before the function gets "recalled".
cmd output

You called the game only once in your main program -- which consists of the last line only. It runs the game once and quits. There is no second call in your code. Perhaps you want a classic "play again?" loop:
play = True
while play:
guessGame()
play = lower(raw_input("Play again?")[0]) == 'y'
after each game, you ask the player for input. If that input begins with the letter 'y' (upper or lower case), then you continue playing; otherwise, play becomes False and you drop out of the loop.
Is that what you wanted?

Need help using the random.randint command making a word guessing game

I have been set some homework to make a word guessing game, I have got it to work for the most part but at this point I am using random.choice and that command allows the same string to repeat more than once. I need to know how to use random.randint in this instance.
""" This is a guessing game which allows the person operating the program to
guess what i want for christmas"""
import random
sw = ("Trainers")
print ("In this game you will have 10 chances to guess what I want for christmas, you start with 10 points, each time you guess incorrectly you will be deducted one point. Each time you guess incorrectly you will be given another clue.")
clue_list = ["They are an item of clothing", "The item comes in pairs", "The Item is worn whilst playing sport", "The item is an inanimate object", "The item can be made of leather","They come in differant sizes", "They have laces", "can be all differant colours", "the item has soles", "Im getting it for christmas ;)"]
def guessing_game(sw, clue_list):
x = 10
while x<=10 and x > 0:
answer = input("What do I want for christmas?")
if sw.lower() == answer and answer.isalpha():
print ("Good Guess thats what I want for christmas")
print ("You scored %s points" % (x))
break
else:
print ("incorrect, " + random.choice(clue_list))
x -=1
if x == 0:
print ("You lost, try again")
guessing_game(sw, clue_list)

for your implementation I think you want:
clueint = random.randint(0, len(clue_list))
print("incorrect, " + clue_list[clueint])
to ensure the same clues are not displayed twice declare an empty list to store guess in OUTSIDE the function definition:
clues_shown = []
and then add each int to the list:
def showClue():
clueint = random.randint(0, len(clue_list))
if clueint in clues_shown:
showClue()
else:
clues_shown.append(clueint)
print("incorrect, " + clue_list[clueint])