My current code works but when the option menu appears, and i select an option, its supposed to repeat from the selection again, however my code restarts from the start where it asks to enter a number rather than entering an option.
n = 0
amount = 0
total = 0
while n != "":
try:
n=int(input("Enter a number: "))
amount = amount+1
total = total + n
except ValueError:
average = total/amount
print()
print("Which option would you like?")
print("1 - Number of values entered")
print("2 - Total of the values entered")
print("3 - Average of values entered")
print("0 - Exit")
choice = int(input("Enter your choice: "))
if choice == 1:
print(amount, "numbers were input.")
elif choice == 2:
print("The total of the sequence is", total)
elif choice == 3:
print("The average is",average)
elif choice == 0:
print("Exit")
break
So it means that I need to reposition my code within the while loop, or take the input stage to a different position?
You need a nested loop
(tried to change your original code as little as possible) I changed it to include your options menu within a while loop (in addition to another break statement outside the while loop, to make sure the program doesn't repeat itself (unless you want it to...)).
n = 0
amount = 0
total = 0
while n != "":
try:
n=int(input("Enter a number: "))
amount = amount+1
total = total + n
except ValueError:
average = total/amount
choice = -1 # new
while(choice != 0): # new
print()
print("Which option would you like?")
print("1 - Number of values entered")
print("2 - Total of the values entered")
print("3 - Average of values entered")
print("0 - Exit")
choice = int(input("Enter your choice: "))
if choice == 1:
print(amount, "numbers were input.")
elif choice == 2:
print("The total of the sequence is", total)
elif choice == 3:
print("The average is",average)
elif choice == 0:
print("Exit")
break
break # new
keep in mind this COULD be a good deal more robust, and there exists no functionality for handling options selected outside the ones specified (though should someone enter a 5 or something it will just repeat)
Sometimes I find it cleaner to have your cope loop forever with while True and to break out of it as necessary. I also try to reduce nesting where possible, and I don't like to use exception handling for a valid input choice. Here's a slightly reworked example:
amount = 0
total = 0
while True:
n = input("Enter a number: ")
if n == "":
break
amount = amount+1
total = total + int(n)
average = total/amount
while True:
print()
print("Which option would you like?")
print("1 - Number of values entered")
print("2 - Total of the values entered")
print("3 - Average of values entered")
print("0 - Exit")
choice = int(input("Enter your choice: "))
if choice == 1:
print(amount, "numbers were input.")
elif choice == 2:
print("The total of the sequence is", total)
elif choice == 3:
print("The average is",average)
elif choice == 0:
print("Exit")
break
Related
I successfully defined a parameter and passed it to a function but when I return to main menu that parameter's value is completely reset and I cannot use it anywhere. The value of the parameter stays only within the second function. Like, the parameter cannot communicate with the whole program as far as I understand.
def main_menu(subtotal):
while True:
print("1) Appetizers")
print("2) Option 2")
print("3) Option 3")
print("4) Option 4")
print("5) Option 5")
print(" ")
print("Current overall subtotal: $" + str(round(subtotal,2)))
while True:
try:
choice = int(input("What is your choice? "))
break
except ValueError:
print("Please enter whole numbers only.")
while choice > 5 or choice < 1:
print("Please choose an option from 1 to 5")
try:
choice = int(input("what is your choice? "))
except ValueError:
print("Please enter whole numbers only.")
if choice == 1:
appetizers(subtotal)
"""
elif choice == 2:
option_2(subtotal)
elif choice == 3:
option_3(subtotal)
elif choice == 4:
option_4(subtotal)
elif choice == 5:
end(subtotal)
return subtotal
"""
def appetizers(subtotal):
while True:
print("1) Option 1")
print("2) Option 2")
print("3) Option 3")
print("4) Return to Main Menu")
print(" ")
print("Current overall subtotal: $" + str(round(subtotal,2)))
product_amount = 1
while True:
try:
choice = int(input("What is your choice? "))
break
except ValueError:
print("Please enter whole numbers only.")
while choice > 4 or choice < 1:
print("Please choose an option from 1 to 4")
try:
choice = int(input("what is your choice? "))
except ValueError:
print("Please enter whole numbers only.")
if choice == 4:
return subtotal
else:
while True:
try:
product_amount = int(input("How many would you like? "))
break
except ValueError:
print("Please enter whole numbers only.")
while product_amount > 100000 or product_amount < 1:
print("Please choose an option from 1 to 100,000")
product_amount = int(input("How many would you like? "))
if choice == 1:
subtotal = subtotal + (product_amount * 4.99)
elif choice == 2:
subtotal = subtotal + (product_amount * 2.99)
elif choice == 3:
subtotal = subtotal + (product_amount * 8.99)
For this project's sake, I don't want to use global variables. I only want to use the subtotal variable as a parameter throughout the program and continuously alter its value throughout the program and make calculations with it. I want to do this by passing it through other functions.
Since you've written the operations into functions and you're passing in the current subtotal, you just need to be updating the subtotal by saving the return value from appetizers() in main_menu(), like here:
# ...
if choice == 1:
subtotal = appetizers(subtotal)
def itemPrices():
items = []
while True:
itemAmount = float(input("Enter the amount for the item: "))
if itemAmount < 0:
continue
again = input("Do you want to add another item? Enter 'y' for yes and 'n' for no: ")
items.append(itemAmount)
if again == "y":
continue
elif again == "n":
numItems = len(items)
print(f"You purchased {numItems} items.")
sumAmount = sum(items)
print(f"The total for this purchase is {sumAmount} before tax.")
print(f"The average amount for this purchase is {sumAmount/numItems}.")
if numItems >= 10:
tax = (9/100)*sumAmount
else:
tax = (9.5/100)*sumAmount
print(f"You owe ${tax} in tax.")
break
else:
print("Invalid input")
continue
itemPrices()
while True:
user_input = input("type a number")
try:
if float(user_input) < 0:
print('this number is less than zero please try again')
continue
else:
print("good job this number is valid")
# place the code you want to execute when number is positive here
break
except ValueError:
print("this is not a number please enter a valid number")
continue
while True:
try:
wins = int(input("enter number of wins: "))
draws = int(input("enter number of draws: "))
losses = int(input("enter number of losses: "))
except ValueError:
print('try again')
continue
if wins>3:
print('qualify')
elif losses>3:
print('disqualify')
elif draws>3:
print('try again')
restart = str(input('enter "restart" to restart or "quit" to quit'))
if restart == 'restart':
continue
elif restart == 'quit':
#quit and display number of occurrences of qualify, disqualify and try again in 'X's
First you need to track the count of each result. You could do this with three different variables, but I think it's a little easier to use a dictionary, or better yet a Counter:
from collections import Counter
counts = Counter()
Make sure to initialize this outside your loop, since you want to keep the same Counter through multiple iterations of the loop; if you reset it inside the loop, it won't keep track of anything!
Then track the results as you see them:
if wins > 3:
result = "qualify"
elif losses > 3:
result = "disqualify"
elif draws > 3:
result = "try again"
else:
print("Not enough of anything to produce a result!")
continue
print(result)
counts[result] += 1
and then at the end, you can convert the counts into "X" marks by string multiplication:
for result in counts:
print(f"{result}: {'X' * counts[result]}")
All together it looks like:
from collections import Counter
counts = Counter()
while True:
try:
wins = int(input("enter number of wins: "))
draws = int(input("enter number of draws: "))
losses = int(input("enter number of losses: "))
except ValueError:
print("try again")
continue
if wins > 3:
result = "qualify"
elif losses > 3:
result = "disqualify"
elif draws > 3:
result = "try again"
else:
print("Not enough of anything to produce a result!")
continue
print(result)
counts[result] += 1
if str(input('enter "restart" to restart or "quit" to quit')) == "quit":
break
for result in counts:
print(f"{result}: {'X' * counts[result]}")
I didn't understand your question but based on what I understood I constructed a solution. This will show you the result of occurrence of qualify and disqualify
qualifycount=0
disqualifycount=0
while True:
try:
wins = int(input("enter number of wins: "))
draws = int(input("enter number of draws: "))
losses = int(input("enter number of losses: "))
except ValueError:
print('try again')
continue
if wins>3:
print('qualify')
qualifycount+=1
elif losses>3:
print('disqualify')
disqualifycount+=1
elif draws>3:
print('try again')
restart = str(input('enter "restart" to restart or "quit" to quit'))
if restart == 'restart':
continue
elif restart == 'quit':
#quit and display number of occurrences of qualify, disqualify and try again in 'X's
print("Number of qualify:"+str(qualifycount))
print("Number of disqualify:"+str(disqualifycount))
restart= str(input('press X to run again or press enter to quit'))
if restart=='X':
continue
else:
break
I am a newbie in python and trying to make a calculator but no getting how to make it
I am making a Calculator which will take input from the user until the user enters 0 and then do the operations
but I am stuck here
if anyone can help me doing this work I will be very thankful to him/her.
num = None
# Asking Users for the Specific Operations
print(("1. For Addition \n 2. For Subtraction. \n 3. For Multiplication. \n 4. For Division \n 5.For Exit"))
options = int(input("Enter Your Choice: "))
# For Addition or Option 1
if options == 1:
total = 0
while(num != 0):
try:
num = float(input("(Enter \'0'\ When Complete.) Enter Number "))
except:
print("Error, Enter Valid Number")
continue
total = total + num
print("Your Calculated Number is: {} ".format(total))
# For Subtraction or Option 2
elif options == 2:
total = 0
while (num != 0):
try:
num = float(input("(Enter \'0'\ When Complete.) Enter Number "))
except:
print("Error, Enter Valid Number")
continue
total = total - num
print("Your Calculated Value is: {}".format(total))
# Multiplication for Option 3
elif options == 3:
total = 1
while (num != 0):
try:
num = float(input("(Enter \'0'\ When Complete.) Enter Number "))
except:
print("Error, Enter Valid Number")
continue
total = total * num
print("Your Calculated Value is: {}".format(total))
# Division for Option 4
elif options == 4:
total = 1
while (num != 0):
try:
num = float(input("(Enter \'0'\ When Complete.) Enter Number "))
except:
print("Error, Enter Valid Number")
continue
total = total / num
print("Your Calculated Value is: {}".format(total))
# When User Wants to Exit
else:
print("Thank You for Using the Calculator")
Here is a better approach using itertools.reduce. Instead of repeating the same code for inputting a number multiple times, put it into a function. This will also help avoid the errors in your code and clarify the logic. A second generator function can be used to get the series of values until the user enters zero.
from functools import reduce
import operator
def input_number():
while True:
try:
return float(input("(Enter '0' When Complete.) Enter Number "))
except:
print("Error, Enter Valid Number")
def input_series():
while True:
n = input_number()
if n == 0:
return
yield n
operations = {
1: operator.add,
2: operator.sub,
3: operator.mul,
4: operator.truediv
}
# Asking Users for the Specific Operations
print(("1. For Addition \n 2. For Subtraction. \n 3. For Multiplication. \n 4. For Division \n 5.For Exit"))
option = int(input("Enter Your Choice: "))
# For Addition or Option 1
if option == 5:
print("Thank You for Using the Calculator")
else:
total = reduce(operations[option], input_series())
print("Your Calculated Value is: {}".format(total))
Instead of
elif options == 2:
total = 0
while (num != 0):
try:
num = float(input("(Enter \'0'\ When Complete.) Enter Number "))
except:
print("Error, Enter Valid Number")
continue
total = total - num
use (the changes are only in the 2nd line and in the last one)
elif options == 2:
total = None
while (num != 0):
try:
num = float(input("(Enter \'0'\ When Complete.) Enter Number "))
except:
print("Error, Enter Valid Number")
continue
total = total - num if total is not None else num
The same method you may use for the elif options == 4: branch.
The problem with subtraction is that the variable total is not initialized.
The problem with multiplication and division is that when the user inputs "0", the variable total is multiplied or divided by zero before it is checked in the while statement. what I would normally do is this:
elif options == 3:
total = 1
while True:
try:
num = float(input("(Enter '0' When Complete.) Enter Number ")) # No need to escape single quotes when your string uses double quotes
if num == 0:
break
except ValueError:
print("Error, Enter Valid Number")
continue
total = total * num
print("Your Calculated Value is: {}".format(total))
However, if you wanted a quick fix, you can have the user input 1 instead of 0 for multiplication and division:
elif options == 4:
total = 1
while (num != 1):
try:
num = float(input("(Enter '1' When Complete.) Enter Number "))
except:
print("Error, Enter Valid Number")
continue
total = total / num
print("Your Calculated Value is: {}".format(total))
Edit: If you want division to work the way you specified, you could do something like this:
elif options == 2:
total = 1
try:
first_number = float(input("(Enter '0' When Complete.) Enter Number "))
if first_number == 0:
print("Your Calculated Value is: 0")
exit()
except ValueError:
print("Error, Enter Valid Number")
continue
total = 1
while True:
try:
num = float(input("(Enter '0' When Complete.) Enter Number "))
if num == 0:
break
except ValueError:
print("Error, Enter Valid Number")
continue
total = total * num
print("Your Calculated Value is: {}".format(total + first_number))
I need to be able to prompt the user to enter an empty string so it can check if the answer is correct. but every time I do that I can error saying invalid literal for int()
so I need to change my user_input so it can accept int() and strings(). how do I make that possible ?
# program greeting
print("The purpose of this exercise is to enter a number of coin values")
print("that add up to a displayed target value.\n")
print("Enter coins values as 1-penny, 5-nickel, 10-dime,and 25-quarter.")
print("Hit return after the last entered coin value.")
print("--------------------")
#print("Enter coins that add up to 81 cents, one per line.")
import sgenrand
#prompt the user to start entering coin values that add up to 81
while True:
total = 0
final_coin= sgenrand.randint(1,99)
print ("Enter coins that add up to", final_coin, "cents, on per line")
user_input = int(input("Enter first coin: "))
if user_input != 1 and user_input!=5 and user_input!=10 and user_input!=25:
print("invalid input")
else:
total = total + user_input
while total <= final_coin:
user_input = int(input("Enter next coin:"))
if user_input != 1 and user_input!=5 and user_input!=10 and user_input!=25:
print("invalid input")
else:
total = total + user_input
if total > final_coin :
print("Sorry - total amount exceeds", (final_coin))
elif total < final_coin:
print("Sorry - you only entered",(total))
else:
print("correct")
goagain= input("Try again (y/n)?:")
if goagain == "y":
continue
elif goagain == "n":
print("Thanks for playing ... goodbye!" )
break
Store the value returned by input() in a variable.
Check that the string is not empty before calling int().
if it's zero, that's the empty string.
otherwise, try int()ing it.