I have Django function view with two forms inside. What is the best solution to detect which form has data typed by user? I know how form.is_valid() works, but still I want to check firstly which form was filled with data.
My code:
def edit_profile_view(request):
if request.method == "POST":
edit_form = EditProfileForm(request.POST)
pass_form = ChangePasswordForm(request.POST)
# here I want to detect which form has data inside,
# and then save this form
else:
edit_form = EditProfileForm()
pass_form = ChangePasswordForm()
template = get_template("profiles/profile_edit.html")
variables = RequestContext(request, {'edit_form': edit_form, 'pass_form': pass_form})
output = template.render(variables)
return HttpResponse(output)
Just have two different actions/views for the forms then the form that has data is the one that the user clicked submit on.
You could, like you say, just check what the form errors actually are or make a method on your forms for is_filled_in but this all seems overkill to me.
Related
I'm having big trouble understanding the whole forms business in django. As I understand it the cleaned form data is a dictionary. So all my defined form fields should be in the dictionary like so: {'definedform': userinput, ...}. Is this correct?
I want to create a form in which a user can input data. This data should then be send to a different view, in which the inputted data is rendered with a latex template (and subsequently rendered into a pdf). This works more or less fine if I define the context in the /create_pdf/ view and grab the user input manually. But I suppose there is a nicer way. What I think should work:
def index(request):
if request.method == "POST":
persoform = PersonalForm(request.POST, prefix='personal')
if persoform.is_valid():
content = persoform.cleaned_data()
content = Context(content)
return HttpResponseRedirect('/create_pdf/')
else:
persoform = PersonalForm()
return render(request, 'app/template.html', {'persoform': persoform})
And in my /create_pdf/ view:
def create_pdf(request):
template = get_template('app/latextemplate.tex')
rendered_tpl = template.render(content)
[...]
So, how can I make sure, to pass the data from my index view to my create_pdf view?
EDIT:
Forgot to mention: The error is "'content' not defined". So I understand that the /create_pdf/ view doesn't get content dictionary, but I have no idea how I would make sure that it does.
Put the data in to the session on submit, and pop it out in the second view.
if form.is_valid():
request.session['perso'] = form.cleaned_data
return HttpResponseRedirect('/create_pdf/')
...
def create_pdf(request):
data = request.session.pop('perso'], {})
I have two form pages:
Start Form - where you input the basic information
Add product form - uses data from start form to populate some fields. And there you can also give more information in the form.
In the urls.py I have this:
urlpatterns = patterns('',
url(r'^$',add_product_start),
url(r'^add_product/$', add_product),
)
This is my add_product_start form view:
def add_product_start(request):
form = add_product_start_form()
if request.method == "POST":
form = add_product_start_form(request.POST)
if form.is_valid:
#return respose to the add_product url with request data
return render(request,'index.html',{'form':form})
And this is my add_product view:
def add_product(request):
images = []
if request.method == "POST":
initial = {field:value for (field,value) in request._post.iteritems() if value}
#a bunch of other code
#point is I want to receive post data from add_product_start view and at the same time redirect to a different url, because I don't want to have the same url of two different forms.
return render(request,'add_product.html' ,{'form':form,'images':images})
I know there is something like HttpResponseRedirect but they just redirect me to the page without any type of data.I want to get the data from the start form, validate it, and if valid pass it to the second view with a different page.
Can someone please help me. Thank you very much!
The best way is using the form wizard https://docs.djangoproject.com/en/1.7/ref/contrib/formtools/form-wizard/
I solved similar issue using redirect(obj).
This video may help
https://www.youtube.com/watch?v=YsHd-l7QdI8
im having some trouble with displaying form errors within one view. I'm currently a student and have been taking python classes for 2 semesters. I decided to learn some Django on my own.
The issue that i have come across is that im trying to have a multistep process so a user can post a book. But, i want to do it within the same url. so when the user finishes the first form and clicks submit it will go on to the next form but the url wont change. I have figured this out. my issues is that when i get to the second form there are form errors already displaying that appear along with the form. I spend like 3 hours yesterday trying to figure out and no luck.
so if anyone can give a helping hand that would be great! thanks!
def book_post(request):
if request.method == 'POST':
formone = bookFormOne(request.POST)
formtwo = bookFormTwo(request.POST, request.FILES)
if formtwo.is_valid():
#.....do form2 valid stuff
return HttpResponseRedirect('/success')
if formone.is_valid() :
#....do form1 valid stuff
#formtwo = bookFormTwo()..if i add this the errors wont display but then errors from the first form spill over and it wont allow the second form to be valid...###
args = {'form2':formtwo,'isbn':isbn,'subject':subject}
args.update(csrf(request))
return render_to_response('book_post_form2.html', args,context_instance=RequestContext(request))
else:
args = {}
args['form'] = formone
args['form2'] = formtwo
args.update(csrf(request))
else:
form = bookFormOne()
args = {'form':form}
args.update(csrf(request))
return render_to_response('book_post.html', args,context_instance=RequestContext(request))
You don't have any case in which you're displaying an empty formtwo. Passing request.POST to the form and calling is_valid() is going to cause validation to run, which presumably isn't what you intend when the user POSTS formone. As #karthikr suggests, you need to figure out a way to tell what step you're so you can validate and display the appropriate form.
The easiest way might be to add something like args['step'] = 1 when rendering book_post.html and args['step'] = 2 when rendering book_post_form2.html. Then pass that variable back to the server again on POST using a hidden form field, and check it to decide which form you need to validate.
I'm brand new to django and fairly new to programming in general. I've done the django tutorial and searched the web for an answer to this question, but to no avail, so now I'm here. I am confused how post works with django. All of the tutorials I've looked at how have a return function in views that displays the webpage. I get that. But then how does a user update data if the page is being rendered from that return statement? After the return there can't be any more updates because the function stops, right? What am I missing here? Any help would be greatly appreciated, I'm getting fairly desperate here.
One pattern for Django views (by no means the only pattern) is to check the request method (GET or POST) at the beginning of the view. If it is POST, then handle the incoming data (before the view returns), and then return either a rendered template, or a redirect.
def view_function(request):
if request.method == 'POST':
if data_is_valid(request.POST):
save_data(request.POST)
return HttpResponseRedirect('/somewhere/good')
else:
return render('template', {'errors': what_went_wrong}
else:
return render('template')
The user updates data in the logic of the view function. That is to say, if the user wishes to update something, you place the update logic in the view function before the return. For example, you would do this:
def update(request):
item = <some model>.objects.get(<something>)
<more code>
return <something>
Usually an edit view function contains two parts -- one for updating data, and the other for displaying the update form. For example,
def user_edit(request):
if request.method == 'POST': # is this a save action?
# save the user data
user_id = request.POST.get('user_id')
username = request.POST.get('username')
description = request.POST.get('description')
user = User.objects.get(id=user_id)
user.username = username
user.description = description
user.save()
return HttpResponseRedirect('/user/') # redirect to index
else:
# show the edit form
user_id = request.GET.get('user_id')
user = User.object.get(id=user_id)
return render_to_response('/user/edit.html', { 'user': user })
There are many different choices for the if request.method == 'POST' line. You can also use if request.POST.get('user_id') to check if specified field is set, to determine if this is a save action.
My view calls some backend classes which need some user input. When user input is required, i halt processing and store the questions into the session - request.session['questions']. request.session['questions'] is a list of dictionaries. e.g.
request.session['question'] = []
request.session['question'].append({'question' : 'Whats your firstname', 'answer' : ''})
request.session['question'].append({'question' : 'Whats your firstname', 'answer' : ''})
I need to display these questions to the user along with an input box for each question. When the user submits the form, I need to dump the input into the answers part of the session variable. Could someone show me how to do this? I'm a little lost as this isn't really based on Django forms or models as such.
Thanks
You could use forms that aren't associated with models, like this:
class QuestionForm(forms.Form):
answer = forms.CharField()
def questions(request):
if request.method == 'POST':
form = QuestionForm(request.POST)
if form.is_valid():
# Process the data in form.cleaned_data
return HttpResponseRedirect('/done/')
else:
form = QuestionForm() # An unbound form
return render_to_response('questions.html', {'form': form,})
More documentation here.