I have code which runs immediately when I run using python. The code has tkinter module and bunch of if statements. I created a standalone executable and it takes about 8 minutes to give the output for the GUI. I was wondering why it takes so much time to run ?
Thanks in advance.
If you do a bunch of work before calling mainloop, you won't see anything appear until you call mainloop or update. The only way a window will appear is in response to an event that asks for the window to be displayed, and tkinter can't process events if mainloop isn't running.
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I am making turn based game in python using Pyglet. The game has a player-vs-AI mode in which the bot calculates a move to play against the player. However, the function which calculates the bot's move takes around 3-5 seconds to run, blocking the game's UI. In order to get around this, I am running the bot's calculation on a second process using multiprocessing.Process. I got it to work well without blocking the UI, however every time I open the second process to run the function a new Pyglet window opens, then closes again when the process is closed. Is there any way to open a second process in a Pyglet program without a second window opening? Let me know if examples of my code is required, and I will try to come up with similar code to share. Thanks in advance to anyone who can help.
You can fix the problem by moving the initialization of the window inside of the main block
I want to make a program stop running for a certain amount of time to save CPU power. I have a self.after function that I want to run to make the program stop running for a set amount of time. However, it always crashes the program.
self.after(int(self.timeSleep*1000),print("Sleeping."))
The word Sleeping. is printed but the window crashes. I thought that Sleeping. should only be printed after the "sleep" was done. I'm not sure what I'm doing wrong and I couldn't find another question like this. Forgive me if it's a stupid mistake as it's my first time using TKinter.
Thanks in advance.
EDIT:
I am not getting any errors in my terminal. By crash I mean the window stops responding.
Your code has the same effect as below:
execute print("Sleeping.")
execute self.after(int(self.timeSleep*1000), None) which is the same as time.sleep(int(self.timeSleep*1000)).
You need to change it to use lambda:
self.after(int(self.timeSleep*1000), lambda: print("Sleeping."))
I found a solution that doesn't require using self.after. Instead, you can use a thread to run this specific method, allowing you to use while loops and time.sleep without crashing the main GUI program.
I have created GUI using Tkinter and one main script to run. I have some conditions in the main script. if conditions are not satisfied I want to terminate the further execution but keep the GUI active and open. Currently I am using sys.exit() to terminate the script but it is also affecting GUI and Gui goes in not responding mode right away.
for all false conditions in the main script, I am using error dialogue box(messagebox.showerror) on screen and I want to terminate the script once I click OK on the dialogue box.
Could anyone please help me get this working?
Thanks in advance.
i tried what furas said and it worked.
"if you run some function then use return to end this function. – furas Jan 24 at 13:38"
I have a program that I'm currently using tkinter to pop up a window and use the root.title of the window as a counter. I call this program through subprocess mutliple times, aka multiple windows pop up and display that I only have to look at the counter to see how long before each of the programs is finished running.
I want to know how long before each and every process is finished. Doing a bit of testing I don't believe using subprocess it will report back to IDLE and show a counter using print(). At least it doesn't appear to be doing so right now for me.
Is there any way of accomplishing this same task without using tkinter?
Below is the link to the other open question right now that I'm currently using to open the tkinter window that closes on me unexpectedly. I'm not completely sure when a windows closes if the whole program stops running or if just the windows closes. Hence why I want the counter...hence why I have always been using a tkinter window as I don't know of any other way of doing this that serves the same purpose.
I want the counter so I can tell the program was finished if my internet connection gets dropped. I don't have internet access at home so I'm always using free-wifi which quite often has timeouts on it. I want to know for sure whether the programs have finished running or if I got timedout and need to rerun the program.
Python program terminating unexpectedly
So I have a Tkinter application that I use at work. I wrote another Tkinter application that I wanted to call from the main Tkinter application. I know that Tkinter isn't 'thread safe', but I'm not 100% sure what that means. Does it mean that it can 'work', but it isn't guaranteed to work as written? Or should it just not work at all?
The reason I ask is because when I run the code below(self.thread_easy_imaging() is triggered by a filemenu option), it works just fine. So far I haven't encountered any issues and both GUIs are operational so far as I can tell. Is this because I'm using subprocess.call to call the script? I'm having a hard time wrapping my head around this because I know you can't use thread in a Tkinter app to do something like run a function while still being able to use buttons in the GUI, but for some reason when I use a thread to call the script with subprocess.call it does it just fine. When I wrote it, I assumed it wouldn't work, but for some odd reason it does. Here is an example of the code I'm using:
def thread_easy_imaging(self):
thread.start_new_thread(self.start_easy_imaging, ('EASY-IMAGING-1', 0))
def start_easy_imaging(self, thread_name, delay):
time.sleep(delay) #have to have args for some reason? I just did a delay of 0 seconds so I could use the tuple.
subprocess.call(['c:/python27/python.exe', 'EasyImaging.py'])
self.thread_easy_imaging()
I have only used this on a windows machine, but I'm guessing that it should work on any OS.
Edit: The scripts don't have to interact at all, I just want to add my other GUI application into the filemenu so I can call it as a separate application. If needed, I'll just use a Toplevel widget to recreate the application I want to call because it won't muck up the main thread at all.
Thanks in advance!