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For example, I have this:
alphabetValues = {"a":1,"b":2,"c":3,"d":4,"e":5,"f":6,"g":7...
Is it possible if instead of having:
print(alphabetValues["c"])
To having something that would get "e" if I searched for 5 in a dict.
"e":5
Thanks in advance.
As suggested by jonrsharpe, you need to reverse your dictionnary :
alphabetValues = {"a":1,"b":2,"c":3,"d":4,"e":5,"f":6,"g":7}
revalpha={v:k for k,v in alphabetValues.iteritems()}
>>> revalpha[5]
'e'
Why not set up an alphabet list?
alphabet = ['a','b','c','d','e','f','g','h','i','j','k','l','m','n','o','p','q','r','s','t','u','v','w','x','y','z']
print(alphabet[0]) #will print out 'a'
print(alphabet[25]) #will print out 'z'
Note that all values are 1 less than expected.
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I'd like to know how I can use a string like order = '8927391' (with 8 being largest and 1 being smallest) and print out an answer according to the order, for example:
Let's say if_no_is_higher(no1, no2) is a function that I have defined already to print yes if the first number is higher than the second, and no if the first number is smaller.
if_no_is_higher(8, 9)
returns
yes
because according to the order 8 is higher than 9
Create a custom order and use the index of that collection to check for your condition:
a = '8927391'
custom_order = [int(item) for item in a]
min(8, 9, key=custom_order.index)
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I have a list in python of the following form:
myList = ['r0x94', 'r0x21', 'r0x51']
I want to sort it based on the last number in each string entry of the list such that:
sorted_myList = ['r0x21', 'r0x51', 'r0x94']
The last number is not hex, rather it is decimal. How to do it?
>>> my_list = ['r0x94', 'r0x21', 'r0x51']
>>> sorted(my_list, key=lambda x: int(x.rpartition('x')[-1]))
['r0x21', 'r0x51', 'r0x94']
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How do I convert def stringParametre(x) x to a list so that if x is hello then it will become a list like ["H","E","l","l","O"] . Capitals don't matter .
Note that you do not have to convert to a list if all you want to do is to iterate over the characters of the string:
for c in "hello":
# do something with c
works
Building on #idjaw's comment:
def stringParametre(x):
return list(x)
Of course this will have an error if x is not a string (or other sequence type).
list(x)
OR
mylist = []
for c in x:
mylist.append(c)
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I have a list of lists of strings such that:
decipher = [['###>>?', '######', '*&*...', '##&#&#'], ['###>>?', '######', '*&*...', '######'], ['###>>?', '######', '*&*...', '######'], ['###>>?', '######', '*&*...', '######']]
I need to concatenate items with the same indeces from each list to print on the same line, each subsequent set of identically indexed items have to print on a new line:
###>>?###>>?###>>?###>>?
########################
*&*...*&*...*&*...*&*...
##&#&###&#&###&#&###&#&#
How can I accomplish that? Thanks!
A simple one line solution would be:
>>> print '\n'.join(''.join(i) for i in zip(*decipher))
###>>?###>>?###>>?###>>?
########################
*&*...*&*...*&*...*&*...
##&#&###################
Here is another solution:
for col in range(len(decipher[0])):
out = ''
for row in range(len(decipher)):
out += decipher[row][col]
print(out)
###>>?###>>?###>>?###>>?
########################
*&*...*&*...*&*...*&*...
##&#&###################
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I'm trying to convert a dictionary
clues={#:A,+:B,6:C}
into
clues1=[#,+,6]
clues2=[A,B,C]
when I use clues.values it doesn't let me iterate through it and any other method I have used has given an error message
Do you want to set keys to clues1 and values to clues2?
clues1 = list(clues.keys())
clues2 = list(clues.values())
If you want the lists to be in alphabetical order, but still have the indicies match, you can do:
clues={'#':'A','+':'B','6':'C'}
cluesKeys = list(clues.iterkeys())
cluesValues = list(clues.itervalues())
If you explicitly want an iteration over the "clues" dictionary:
clues={'#':'A','+':'B','6':'C'}
clues1=list()
clues2=list()
for keys, values in clues.items():
clues1.append(keys)
clues2.append(values)
print clues1
print clues2
['#', '+', '6']
['A', 'B', 'C']