I am trying to develop a small python application that allows it's user to send multiple mails through python, I am using gmail, I have allowed Access for less secure apps, it doesn't send.
I have searched stackoverflow for similar problems, but it seemed that most of the used codes are completely different in implementation, even after trying many of hem, they all through exception
import smtplib
from telnetlib import Telnet
def addSenders(message):
num = input("enter number of recievers : ")
num = int (num)
i = 0
emailList = []
while i < num :
nameStr = input("enter name")
mailStr = input("enter e-mail")
emailList.append(mailStr)
if i == 0:
message += nameStr + " <" + mailStr + ">"
print(message)
else:
message += "," + nameStr + " <" + mailStr + ">"
i = i + 1
return emailList, message
sender = 'xxxx#gmail.com'
password = "xxxx"
message = """From: xxxx xxxx <xxxxx#gmail.com>
To: To """
to, message = addSenders(message)
message += """
MIME-Version: 1.0
Content-type: text/html
Subject: Any Subject!
<h1> Good Morning :D <h1>
"""
server = smtplib.SMTP('smtp.gmail.com',587)
server.ehlo()
server.starttls()
server.login(sender, password)
try:
server.sendmail(sender, [to], message)
print ("Successfully sent email")
except:
print ("Error: unable to send email")
server.quit()
output : Error: unable to send email
Related
Where am I going wrong here. as far as i can tell this should work.
import socket, string
#some user data, change as per your taste
SERVER = 'irc.freenode.net'
PORT = 6667
NICKNAME = 'echoquote'
CHANNEL = '#python'
PASSWORD = 'nope'
import time
#open a socket to handle the connection
IRC = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
#open a connection with the server
def irc_conn():
IRC.connect((SERVER, PORT))
#simple function to send data through the socket
def send_data(command):
IRC.send(command + '\n')
#join the channel
def join(channel):
send_data("JOIN %s" % channel)
#send login data (customizable)
def login(nickname, username='user', password = None, realname='Pythonist', hostname='Helena', servername='Server'):
send_data("USER %s %s %s %s" % (username, hostname, servername, realname))
send_data("NICK " + nickname)
send_data("nickserv identify %s %s\r\n" % (NICKNAME, PASSWORD))
time.sleep(3)
irc_conn()
login(NICKNAME)
join(CHANNEL)
while (1):
buffer = IRC.recv(1024)
msg = string.split(buffer)
message = ' '.join(msg[3:])
message = ''.join([x for x in message if x in string.printable])
if message:
print message + '\n'
if msg[0] == "PING": #check if server have sent ping command
send_data("PONG %s" % msg[1]) #answer with pong as per RFC 1459
if msg [1] == 'PRIVMSG' and msg[2] == NICKNAME:
filetxt = open('/tmp/msg.txt', 'a+') #open an arbitrary file to store the messages
nick_name = msg[0][:string.find(msg[0],"!")] #if a private message is sent to you catch it
message = ' '.join(msg[3:])
filetxt.write(string.lstrip(nick_name, ':') + ' -> ' + string.lstrip(message, ':') + '\n') #write to the file
filetxt.flush() #don't wait for next message, write it now!
send_data("nickserv identify %s %s\r\n" % (NICKNAME, PASSWORD))
There is no nickserv command in IRC. This is an alias in some IRC clients, and all it does is send a private message to NickServ. Read the IRC specification, and stop reinventing wheels — use an existing IRC library, eg. twisted.words, or an existing IRC bot solution.
Is there any way to forward email(gmail like - you know... with additional text under) using smtp?
Here is a piece of my code:
def forward_email(email_id, email_to):
client, messages = get_original_email(email_id)
typ, data = client.fetch(messages[0].split(' ')[-1], '(RFC822)')
email_data = data[0][1]
message = email.message_from_string(email_data)
smtp = smtplib.SMTP(EMAIL_HOST, EMAIL_PORT)
smtp.ehlo()
smtp.starttls()
smtp.login(IMAP_LOGIN, IMAP_PASSWORD)
result = smtp.sendmail(email.utils.parseaddr(message['From']),
email_to, message.as_string())
smtp.quit()
return result
Now it's not working because message.as_string() has special headers and other unused info.
I guess gmail blocked it because this.
below code worked for me correctly, even sending mail continuously on function call
def send_email(to='example#email.com', f_host='send.one.com', f_port=587, f_user='from#me.com', f_passwd='my_pass', subject='subject for email', message='content message'):
smtpserver = smtplib.SMTP(f_host, f_port)
smtpserver.ehlo()
smtpserver.starttls()
smtpserver.ehlo
smtpserver.login(f_user, f_passwd) # from email credentialssssssssss
header = 'To:' + to + '\n' + 'From: ' + f_user + '\n' + 'Subject:' + subject + '\n'
message = header + '\n' + message + '\n\n'
smtpserver.sendmail(f_user, to, str(message))
smtpserver.close()
DBG('Mail is sent successfully!!')
Is this an valid example from Python's smtplib? How, from this example, would one send email without giving the password?
import smtplib
def prompt(prompt):
return raw_input(prompt).strip()
fromaddr = prompt("From: ")
toaddrs = prompt("To: ").split()
print "Enter message, end with ^D (Unix) or ^Z (Windows):"
# Add the From: and To: headers at the start!
msg = ("From: %s\r\nTo: %s\r\n\r\n"
% (fromaddr, ", ".join(toaddrs)))
while 1:
try:
line = raw_input()
except EOFError:
break
if not line:
break
msg = msg + line
print "Message length is " + repr(len(msg))
server = smtplib.SMTP('localhost')
server.set_debuglevel(1)
server.sendmail(fromaddr, toaddrs, msg)
server.quit()
You can send emails without using a password assuming the server configuration allow that.
I am currently trying to make a program that send multiple emails to my self in a loop. I have already written 2 patches of code but i can not seem to get them to work. (I am running this on a raspberry pi so exsuse any weird directorys).
This is my first patch of while loop code
import os
i = 0
while i < 2:
os.pause(4)
os.system("home/Tyler/desktop/test.py")
i += 1
This opens the email "sending" part /\ .
This down here is the "sending" part /
import smtplib
smtpUser = 'smilingexample#gmail.com'
smtpPass = 'password'
toAdd = 'Example#aim.com'
fromAdd = smtpUser
subject = 'yep'
header = 'to: ' + toAdd + '\n' + 'From: ' + fromAdd + '\n' + 'Subject: ' + subject
body = 'hi'
print header + '\n' + body
s = smtplib.SMTP('smtp.gmail.com',587)
s.ehlo()
s.starttls()
s.ehlo()
s.login(smtpUser, smtpPass)
s.sendmail(fromAdd, toAdd, header + '\n\n' + body)
s.quit ()
import datetime
import smtplib
from email.mime.multipart import MIMEMultipart
from email.mime.text import MIMEText
from email.header import Header
from email import Charset
Charset.add_charset('utf-8', Charset.QP, Charset.QP, 'utf-8')
maillist = []
def send_email(messages_list, smtpUser=None, smtpPass=None, tls=False):
failed = []
try:
s = smtplib.SMTP('smtp.gmail.com',587)
s.ehlo()
if tls:
s.starttls()
s.ehlo()
if smtpUser and smtpPass:
s.login(smtpUser, smtpPass)
except:
print "ehlo failed"
failed = [x[0] for x in messages_list]
else:
for to_address,from_address,subject,encoding,mesg in messages_list:
try:
if len(mesg) == 2:
msg = MIMEMultipart('alternative')
else:
msg = MIMEText(mesg[0],'plain','utf-8')
msg['Subject'] = "%s" % Header(subject, 'utf-8')
if len(from_address) == 2:
msg['From'] = "\"%s\" <%s>" % (Header(from_address[0], 'utf-8'), from_address[-1])
else:
msg['From'] = from_address[-1]
if len(to_address) == 2:
msg['From'] = "\"%s\" <%s>" % (Header(to_address[0], 'utf-8'), to_address[-1])
else:
msg['To'] = to_address[-1]
msg.set_charset("utf-8")
if len(mesg) == 2:
part1 = MIMEText(mesg[0], 'plain','utf-8')
part2 = MIMEText(mesg[1], 'html','utf-8')
msg.attach(part1)
msg.attach(part2)
s.sendmail(from_address[-1], to_address[-1], msg.as_string())
except:
traceback.print_exc()
failed.append(to_address[-1])
try:
s.quit()
except:
pass
return failed
maillist.append(( ['someone#gmail.com'],["Me","noreply#example.com"],'Subject','utf-8',['text_message','html but you can delete this list element'] ))
for k in send_email(maillist, smtpUser='you#gmail.com', smtpPass='pwd', tls=True):
print k, 'not delivered'
Here's what we use to send alternative Mime messages with alternative body. It is not necessary though so you can send simple text messages as well.
It's prepared to send from localhost but you can easily modify it to use it properly.
My email program is emailing each line of the message as a separate email, i would like to know how to send all of the message in one email, when the email is sent the program will return to the beginning.
import smtplib
from email.mime.text import MIMEText
a = 1
while a == 1:
print " "
To = raw_input("To: ")
subject = raw_input("subject: ")
input_list = []
print "message: "
while True:
input_str = raw_input(">")
if input_str == "." and input_list[-1] == "":
break
else:
input_list.append(input_str)
for line in input_list:
# Create a MIME text message and populate its values
msg = MIMEText(line)
msg['Subject'] = subject
msg['From'] = '123#example.com'
msg['To'] = To
server = smtplib.SMTP_SSL('server', 465)
server.ehlo()
server.set_debuglevel(1)
server.ehlo()
server.login('username', 'password')
# Send a properly formatted MIME message, rather than a raw string
server.sendmail('user#example.net', To, msg.as_string())
server.close()
(the part that takes multiple lines was made with the help Paul Griffiths, Multiline user input python)
for line in input_list:
# Create a MIME text message and populate its values
msg = MIMEText(line)
You are calling server.sendmail in this loop.
Build your entire msg first (in a loop), THEN add all of your headers and send your message.