Unable to change DNS resolver to localhost - python

I configured my windows machine's DNS server to 127.0.0.1 and on localhost I created a basic python server:
from socket import *
serverPort = 53
serverSocket = socket(AF_INET, SOCK_DGRAM)
serverSocket.bind(('127.0.0.1', serverPort))
print "The server is ready to receive on port: {}".format(serverPort)
while 1:
try:
message, clientAddress = serverSocket.recvfrom(512)
except:
continue
print clientAddress, message
modifiedMessage = "127.0.0.1"
serverSocket.sendto(modifiedMessage, clientAddress)
PS :I know that DNS is a binary protocol and sending ASCII text won't do any good, but I am not trying to make a resolver, I am trying to see with transperancy that how the former works.
When I srarted the server, I am greated with the following output:
(('127.0.0.1', 53945), '.\x9c\x01\x00\x00\x01\x00\x00\x00\x00\x00\x00\x03www\x06google\x03com\x00\x00\x01\x00\x01')
(('127.0.0.1', 53945), '.\x9c\x01\x00\x00\x01\x00\x00\x00\x00\x00\x00\x03www\x06google\x03com\x00\x00\x01\x00\x01')
(('127.0.0.1', 53945), '.\x9c\x01\x00\x00\x01\x00\x00\x00\x00\x00\x00\x03www\x06google\x03com\x00\x00\x01\x00\x01')
(('127.0.0.1', 61362), '\xefc\x01\x00\x00\x01\x00\x00\x00\x00\x00\x00\x03www\x06google\x03com\x00\x00\x01\x00\x01')
(('127.0.0.1', 50065), '\xb5\xfc\x01\x00\x00\x01\x00\x00\x00\x00\x00\x00\x06google\x03com\x00\x00\x01\x00\x01')
(('127.0.0.1', 61362), '\xefc\x01\x00\x00\x01\x00\x00\x00\x00\x00\x00\x03www\x06google\x03com\x00\x00\x01\x00\x01')
(('127.0.0.1', 61362), '\xefc\x01\x00\x00\x01\x00\x00\x00\x00\x00\x00\x03www\x06google\x03com\x00\x00\x01\x00\x01')
(('127.0.0.1', 52718), '\xc7\x15\x01\x00\x00\x01\x00\x00\x00\x00\x00\x00\x05tiles\x08services\x07mozilla\x03com\x00\x00\x01\x00\x01')
But unlike as I enticipated, I am still able to open websites. And Wireshark told me that I am making connection to 8.8.8.8(IDK how?).
I tried flushing the DNS cashe from my machine, nada.
What am I missing?
PPS: If I remove the try/catch clause I get this error(a few seconds after the execution of the program):
error: [Errno 10054] An existing connection was forcibly closed by the remote host

You probably have configured Googles 8.8.8.8 as a fallback DNS server.
And since you are destroying the DNS answers, whoever is receiving these broken answers is falling back to the secondary server. The whole path of DNS queries on a typical UN*X machine is quite complicated and the whole system is usually quite robust.

Related

Socket IO returns 127.0.0.1 as host address, randomly, instead of the public IP Of the device

Trying to get host-IP Through Python, using socket module -
Occasionally, i get address 127.0.0.1 and not the real IP Address - i.e 10.210.24.24
I've adjusted my code per the answer in:
Socket IO returns 127.0.0.1 as host address and not 192.168.0.* on my device
But still get random encounters of 127.0.0.1.
The issue occurs in automation - Which SSH's into the remote host (10.210.24.24 for example),
And runs the below code snippet.
Trying to reproduce manually - i always get the correct IP Address.
My code is as follows:
self.host_name = socket.gethostname()
try:
host_ip = socket.gethostbyname(self.host_name)
if host_ip == "127.0.0.1":
s = socket.socket(socket.AF_INET, socket.SOCK_DGRAM)
s.connect(("8.8.8.8", 80))
host_ip = s.getsockname()[0]
self.host_ip = host_ip
except Exception as e: # In case DNS Resolving fails
logger.warning("Failed setting '%s' IP | %s", self.host_name, str(e))
self.host_ip = ""
I'm trying to understand what am I missing here:
Why would "randomly", i would get 127.0.0.1 instead of the actual host IP.
Given the fact the host definitely has IP Assigned (Since i'm using SSH root# in order to run the script)
How to overcome this issue and make sure i always get the correct IP Address?
In case more debug info is needed -
What logs should i look into once this issue does occur?
I can add "fail handling" to at least dump those logs when the issue occurs in my automation.
System is Debian 11, Python 3.9.
Thanks

Python OpenSSL Specify DNS Server

Has anyone found a way to specify a DNS server for OpenSSL connections on a Linux OS? We have internal and external DNS servers and I am building a monitor for SSL certificate usage. I need the ability to specify a DNS server to be used on hostname connections. It works just fine against the internal DNS, but I am having difficulty finding a way to tie in a DNS server. I am fairly new to changing networks through Python and am not sure where to begin. Is it possible to do this through the dns.resolver module's nameservers function?
This looks like a viable solution for Windows, but I am hoping to find something similar for Linux.
How to Change DNS Servers Programmatically in Windows?
Below is my code that works against the default DNS host.
def readCerts(self,host,port,cast):
"""readCerts prompts terminal for username.
Attributes:
host: Host or IP of SSL connection
port: Port of SSL connection
cast: Format of returned results (JSON currently only structure supported)
Response:
Returns certificate attributes in specified format
"""
sslContext = SSL.Context(SSL.SSLv23_METHOD)
apiSocket = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
sslConnection = SSL.Connection(sslContext,apiSocket)
try:
sslConnection.connect((host,port))
except Exception as e:
raise e
else:
#Block the socket
sslConnection.setblocking(1)
#Set the hostname field for servers that support SNI. Format must be in bytestring.
sslConnection.set_tlsext_host_name(host.encode('utf-8'))
try:
sslConnection.do_handshake()
except:
pass
else:
#print "handshake succeeded"
sslConnection.close()
if cast.upper()=='JSON':
attributes = self._FormatJSON(sslConnection.get_peer_cert_chain())
return attributes

Server connectivity validation through python codes

I have a MySQL server hosted at a particular IP and port. Now, I need to validate this connectivity whether the server is up or down. Also this server uses a self-signed SSL certificate.
Does anyone have any reference python snippet that would comply this connectivity validation along with SSL certificate verification?
Trye the same thing you'd do from a command line. E.g. when you ``telnetserver port, then you get "connection refused" if a server is not listening on the given port, or a timeout if server:port is behind a firewall, or "No route to host" etc. For a successful connection you get something.
Self signed certs can't be validate, AFAIK, and this will work for ssl connections too.
import telnetlib
server_ip = '192.168.2.1'
server_port = 80
timeout = 5
conn_ok = False
try:
tn = telnetlib.Telnet(server_ip, server_port, timeout)
conn_ok = True
except Exception as e:
print(e)
tn.close()

TimeoutError: [Errno 60] Operation timed out (Python socket request)

I am fairly new to Python (just started today) but am really struggling with this:
#! /usr/bin/python
import socket
s=socket.socket()
s.connect(("<my ip addres>", 22))
answer=s.recv(1024)
print(answer)
s.close
I believe I am meant to be getting some sort of 'banner' response but it gives nothing for a few minutes before spouting the following error:
TimeoutError: [Errno 60] Operation timed out
Why would this be happening?
First of all make sure you connect to port 22. Then make sure your operating system's firewall doesn't block incoming connections to port 22. In case the address you have configured for the server is "localhost" and try to connect from another machine you won't be able to connect. In that case you shoud use "" as ip address.

How to ssh over HTTP proxy in Python Paramiko?

I am adapting a Python script to be OS independent and run on Windows. I have changed its ssh system calls to calls to paramiko functions. I am stuck with the issue of http proxy authentication. In Unix (actually Cygwin) environment I would use ~/.ssh/config
Host *
ProxyCommand corkscrew http-proxy.example.com 8080 %h %p
Is there a way to obtain the same using paramiko (or the Python ssh module) either using or not using corkscrew? This post seems to suggest that, but I don't know how.
Note: I am behind a firewall that allows me to use only port 80. I need to control Amazon ec2 instances so I configured the sshd server on those machines to listen to port 80. Everything is working fine in my cygwin+corkscrew prototype, but I would like to have a Python script that works without Cygwin.
You can use any pre-established session to paramiko via the sock parameter in SSHClient.connect(hostname,username,password,...,sock).
Below is a code-snippet that tunnels SSH via HTTP-Proxy-Tunnel (HTTP-CONNECT). At first the connection to the proxy is established and the proxy is instructed to connect to localhost:22. The result is a TCP tunnel over the established session that is usually used to tunnel SSL but can be used for any tcp based protocol.
This scenario works with a default installation of tinyproxy with Allow <yourIP> and ConnectPort 22 being set in /etc/tinyproxy.conf. The proxy and the sshd are running on the same host in my example but all you need is any proxy that allows you to CONNECT to your ssh port. Usually this is restricted to port 443 (hint: if you make your sshd listen on 443 this will work with most of the public proxies even thought I do not recommend to do this for interop and security reasons). If this ultimately allows you to bypass your firewall depends on what kind of firewall is employed. If there's no DPI/SSL-Interception features involved, you should be fine. If there's SSL-Interception involved you could still try to tunnel it via ssl or as part of HTTP payload :)
import paramiko
import socket
import logging
logging.basicConfig(loglevel=logging.DEBUG)
LOG = logging.getLogger("xxx")
def http_proxy_tunnel_connect(proxy, target,timeout=None):
sock = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
sock.settimeout(timeout)
sock.connect(proxy)
LOG.debug("connected")
cmd_connect = "CONNECT %s:%d HTTP/1.1\r\n\r\n"%target
LOG.debug("--> %s"%repr(cmd_connect))
sock.sendall(cmd_connect)
response = []
sock.settimeout(2) # quick hack - replace this with something better performing.
try:
# in worst case this loop will take 2 seconds if not response was received (sock.timeout)
while True:
chunk = sock.recv(1024)
if not chunk: # if something goes wrong
break
response.append(chunk)
if "\r\n\r\n" in chunk: # we do not want to read too far ;)
break
except socket.error, se:
if "timed out" not in se:
response=[se]
response = ''.join(response)
LOG.debug("<-- %s"%repr(response))
if not "200 connection established" in response.lower():
raise Exception("Unable to establish HTTP-Tunnel: %s"%repr(response))
return sock
if __name__=="__main__":
LOG.setLevel(logging.DEBUG)
LOG.debug("--start--")
sock = http_proxy_tunnel_connect(proxy=("192.168.139.128",8888),
target=("192.168.139.128",22),
timeout=50)
ssh = paramiko.SSHClient()
ssh.set_missing_host_key_policy(paramiko.AutoAddPolicy())
ssh.connect(hostname="192.168.139.128",sock=sock, username="xxxx", password="xxxxx")
print "#> whoami \n%s"% ssh.exec_command("whoami")[1].read()
output:
DEBUG:xxx:--start--
DEBUG:xxx:connected
DEBUG:xxx:--> 'CONNECT 192.168.139.128:22 HTTP/1.1\r\n\r\n'
DEBUG:xxx:<-- 'HTTP/1.0 200 Connection established\r\nProxy-agent: tinyproxy/1.8.3\r\n\r\n'
#> whoami
root
here are some other resources on how to tunnel through proxies. Just do whatever is needed to establish your tunnel and pass the socket to SSHClient.connect(...,sock)
There's paraproxy, which implements proxy support for Paramiko.
The post you linked to suggets that Paramiko can operate over an arbitrary socket, but that doesn't appear to be the case. In fact, paraproxy works by completing replacing specific methods inside paramiko, since the existing code simply calls socket.socket() to obtain a socket and does not offer any way of hooking in a proxy.

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