From here, if you define some objects like that:
class Mixin1(object):
def test(self):
print "Mixin1"
class Mixin2(object):
def test(self):
print "Mixin2"
class BaseClass(object):
pass
class MyClass(Mixin2, Mixin1, BaseClass):
pass
You'll get:
>>> obj = MyClass()
>>> obj.test()
Mixin2
Is there a way to call Mixin1 test() method?
Call it explicitly:
Mixin1.test(obj)
The attribute process in Python is relatively complex. For your given example, this is the process for finding the value of obj.test:
First, look at the instance itself. In this case, the instance does not have a test attribute.
Look at the class which obj is an instance of: MyClass. MyClass does not have a test attribute.
Start looking at the classes in the method resolution order of MyClass. In this case, MyClass.__mro__ tells you to look first at Mixin2, then Mixin1, then object.
Mixin2 has a test attribute, so we finally have a match.
Mixin2.test is a function with a __get__ method, so that is called and the return value is used.
You can safely ignore step 5 here, and just assume that Mixin2.test is a method. One that is returned, you can see that obj.test() calls Mixin2.test.
This might help explain why I asked the question I did in a comment. There is a wide variety of ways you can fiddle with the program to get obj.test() to produce a call to Mixin1.test() instead. You can patch the object, you can fiddle with MyClass.__mro__, you can tweak what Mixin2.test actually does, etc.
Override the test method and call Mixin1.test explicitly:
class MyClass(Mixin2, Mixin1, BaseClass):
def test(self):
Mixin1.test(self)
Related
I have an Object of the following class which inherates from the algorithm class.
class AP(Algorithm):
def evaluate(self, u):
return self.stuff *2 +u
The Algorithm class has a method called StoppingCritiria.
At some point in the project the object objAP = AP() gets created. Later on I can then actually access it.
And at that point in time I want to override the method StoppingCriteria by some function which calls the old StoppingCriteria.
I tried simply
def new_stopping(self):
return super().StoppingCriteria() and custom(self.u)
objAP.StoppingCriteria = newStoppingCriteria
But that did not work. What did work were two rather inconviniend solutions:
New AP class (not desirable since I possibly need to do that for lots of classes)
class AP_custom(AP):
def StoppingCriteria(self):
return super().StoppingCriteria() and custom(self)
Override the Method but not using super but rather copy pasting the code into the new function and adding my code to that. Not desirable since I want to changes in the original method to be applyed to my new function as well.
See Override a method at instance level for many possible solutions. None of them will really work with super though, since you're simply not defining the replacement function in a class. You can define it slightly differently though for it to work:
class Foo:
def bar(self):
print('bar')
f = Foo()
def _bar(self):
type(self).bar(self) # or Foo.bar(self)
print('baz')
from typing import MethodType
f.bar = MethodType(_bar, f)
f.bar() # outputs bar baz
Since you're replacing the method at the instance level, you don't really need to access the method of the super class, you just want to access the method of the class, which still exists in its original form.
For different data types, like string, there are methods that you call by adding a dot after, such as:
"string {0}".format(stringy)
or
listx.remove(x)
How is the information being passed to the method? How can I write a function like that?
class YourObject(object):
def do_something(self):
print('doing something')
Then you can use your object:
your_object = YourObject()
your_object.do_something()
This shows how to create an object, and call a method on it (like theexamples you provided in your post).
There are way more in-depth tutorials/blogs about object creation and custom classes. A good place to start is always the standard documentation.
You can create a custom class and then include whatever methods you want. Below is an example:
>>> class MyClass(object): # Define class MyClass
... def __init__(self): # Define MyClass' constructor method
... self.name = "Me" # Make an attribute
... def getName(self): # Define method getName
... return self.name # Return MyClass' attribute name (self.name)
...
>>> test = MyClass() # Initialize (create an instance of) MyClass
>>> print test.getName() # Print the name attribute by calling the getName method
Me
>>>
Basically, you are working with OOP (Object-Oriented Programming). However, since this concept is so large, I can't demonstrate/explain everything you can do with it here (otherwise my post would be enormous). My advice is to research OOP and Python classes. There are many good tutorials you can find. I gave one above; here is another:
When you decorate a method, it is not bound yet to the class, and therefor doesn't have the im_class attribute yet. I looking for a way to get the information about the class inside the decorator. I tried this:
import types
def decorator(method):
def set_signal(self, name, value):
print name
if name == 'im_class':
print "I got the class"
method.__setattr__ = types.MethodType(set_signal, method)
return method
class Test(object):
#decorator
def bar(self, foo):
print foo
But it doesn't print anything.
I can imagine doing this:
class Test(object):
#decorator(klass=Test)
def bar(self, foo):
print foo
But if I can avoid it, it would make my day.
__setattr__ is only called on explicit object.attribute = assignments; building a class does not use attribute assignment but builds a dictionary (Test.__dict__) instead.
To access the class you have a few different options though:
Use a class decorator instead; it'll be passed the completed class after building it, you could decorate individual methods on that class by replacing them (decorated) in the class. You could use a combination of a function decorator and a class decorator to mark which methods are to be decorated:
def methoddecoratormarker(func):
func._decorate_me = True
return func
def realmethoddecorator(func):
# do something with func.
# Note: it is still an unbound function here, not a method!
return func
def classdecorator(klass):
for name, item in klass.__dict__.iteritems():
if getattr(item, '_decorate_me', False):
klass.__dict__[name] = realmethoddecorator(item)
You could use a metaclass instead of a class decorator to achieve the same, of course.
Cheat, and use sys._getframe() to retrieve the class from the calling frame:
import sys
def methoddecorator(func):
callingframe = sys._getframe(1)
classname = callingframe.f_code.co_name
Note that all you can retrieve is the name of the class; the class itself is still being built at this time. You can add items to callingframe.f_locals (a mapping) and they'll be made part of the new class object.
Access self whenever the method is called. self is a reference to the instance after all, and self.__class__ is going to be, at the very least, a sub-class of the original class the function was defined in.
My strict answer would be: It's not possible, because the class does not yet exist when the decorator is executed.
The longer answer would depend on your very exact requirements. As I wrote, you cannot access the class if it does not yet exists. One solution would be, to mark the decorated method to be "transformed" later. Then use a metaclass or class decorator to apply your modifications after the class has been created.
Another option involves some magic. Look for the implementation of the implements method in zope.interfaces. It has some access to the information about the class which is just been parsed. Don't know if it will be enough for your use case.
You might want to take a look at descriptors. They let you implement a __get__ that is used when an attribute is accessed, and can return different things depending on the object and its type.
Use method decorators to add some marker attributes to the interesting methods, and use a metaclass which iterates over the methods, finds the marker attributes, and does the logic. The metaclass code is run when the class is created, so it has a reference to the newly created class.
class MyMeta(object):
def __new__(...):
...
cls = ...
... iterate over dir(cls), find methods having .is_decorated, act on them
return cls
def decorator(f):
f.is_decorated = True
return f
class MyBase(object):
__metaclass__ = MyMeta
class MyClass(MyBase):
#decorator
def bar(self, foo):
print foo
If you worry about that the programmer of MyClass forgets to use MyBase, you can forcibly set the metaclass in decorator, by exampining the globals dicitionary of the caller stack frame (sys._getframe()).
While integrating a Django app I have not used before, I found two different ways to define functions inside the class. The author seems to use them both distinctively and intentionally. The first one is the one that I myself use a lot:
class Dummy(object):
def some_function(self, *args, **kwargs):
# do something here
# self is the class instance
The other one is the one I never use, mostly because I do not understand when and what to use it for:
class Dummy(object):
#classmethod
def some_function(cls, *args, **kwargs):
# do something here
# cls refers to what?
The classmethod decorator in the python documentation says:
A class method receives the class as the implicit first argument, just
like an instance method receives the instance.
So I guess cls refers to Dummy itself (the class, not the instance). I do not exactly understand why this exists, because I could always do this:
type(self).do_something_with_the_class
Is this just for the sake of clarity, or did I miss the most important part: spooky and fascinating things that couldn't be done without it?
Your guess is correct - you understand how classmethods work.
The why is that these methods can be called both on an instance OR on the class (in both cases, the class object will be passed as the first argument):
class Dummy(object):
#classmethod
def some_function(cls,*args,**kwargs):
print cls
#both of these will have exactly the same effect
Dummy.some_function()
Dummy().some_function()
On the use of these on instances: There are at least two main uses for calling a classmethod on an instance:
self.some_function() will call the version of some_function on the actual type of self, rather than the class in which that call happens to appear (and won't need attention if the class is renamed); and
In cases where some_function is necessary to implement some protocol, but is useful to call on the class object alone.
The difference with staticmethod: There is another way of defining methods that don't access instance data, called staticmethod. That creates a method which does not receive an implicit first argument at all; accordingly it won't be passed any information about the instance or class on which it was called.
In [6]: class Foo(object): some_static = staticmethod(lambda x: x+1)
In [7]: Foo.some_static(1)
Out[7]: 2
In [8]: Foo().some_static(1)
Out[8]: 2
In [9]: class Bar(Foo): some_static = staticmethod(lambda x: x*2)
In [10]: Bar.some_static(1)
Out[10]: 2
In [11]: Bar().some_static(1)
Out[11]: 2
The main use I've found for it is to adapt an existing function (which doesn't expect to receive a self) to be a method on a class (or object).
One of the most common uses of classmethod in Python is factories, which are one of the most efficient methods to build an object. Because classmethods, like staticmethods, do not need the construction of a class instance. (But then if we use staticmethod, we would have to hardcode the instance class name in the function)
This blog does a great job of explaining it:
https://iscinumpy.gitlab.io/post/factory-classmethods-in-python/
If you add decorator #classmethod, That means you are going to make that method as static method of java or C++. ( static method is a general term I guess ;) )
Python also has #staticmethod. and difference between classmethod and staticmethod is whether you can
access to class or static variable using argument or classname itself.
class TestMethod(object):
cls_var = 1
#classmethod
def class_method(cls):
cls.cls_var += 1
print cls.cls_var
#staticmethod
def static_method():
TestMethod.cls_var += 1
print TestMethod.cls_var
#call each method from class itself.
TestMethod.class_method()
TestMethod.static_method()
#construct instances
testMethodInst1 = TestMethod()
testMethodInst2 = TestMethod()
#call each method from instances
testMethodInst1.class_method()
testMethodInst2.static_method()
all those classes increase cls.cls_var by 1 and print it.
And every classes using same name on same scope or instances constructed with these class is going to share those methods.
There's only one TestMethod.cls_var
and also there's only one TestMethod.class_method() , TestMethod.static_method()
And important question. why these method would be needed.
classmethod or staticmethod is useful when you make that class as a factory
or when you have to initialize your class only once. like open file once, and using feed method to read the file line by line.
Look at this code:
class MyClass():
# Why does this give me "NameError: name 'self' is not defined":
mySelf = self
# But this does not?
def myFunction(self):
mySelf2 = self
Basically I want a way for a class to refer to itself without needing to name itself specifically, hence I want self to work for the class, not just methods/functions. How can I achieve this?
EDIT: The point of this is that I'm trying to refer to the class name from inside the class itself with something like self.class._name_ so that the class name isn't hardcoded anywhere in the class's code, and thus it's easier to re-use the code.
EDIT 2: From what I've learned from the answers below, what I'm trying to do is impossible. I'll have to find a different way. Mission abandoned.
EDIT 3: Here is specifically what I'm trying to do:
class simpleObject(object):
def __init__(self, request):
self.request = request
#view_defaults(renderer='string')
class Test(simpleObject):
# this line throws an error because of self
myClassName = self.__class__.__name__
#view_config(route_name=myClassName)
def activateTheView(self):
db = self.request.db
foo = 'bar'
return foo
Note that self is not defined at the time when you want the class to refer to itself for the assignment to work. This is because (in addition to being named arbitrarily), self refers to instances and not classes. At the time that the suspect line of code attempts to run, there is as of yet no class for it to refer to. Not that it would refer to the class if there was.
In a method, you can always use type(self). That will get the subclass of MyClass that created the current instance. If you want to hard-code to MyClass, that name will be available in the global scope of the methods. This will allow you to do everything that your example would allow if it actually worked. E.g, you can just do MyClass.some_attribute inside your methods.
You probably want to modify the class attributes after class creation. This can be done with decorators or on an ad-hoc basis. Metaclasses may be a better fit. Without knowing what you actually want to do though, it's impossible to say.
UPDATE:
Here's some code to do what you want. It uses a metaclass AutoViewConfigMeta and a new decorator to mark the methods that you want view_config applied to. I spoofed the view_config decorator. It prints out the class name when it's called though to prove that it has access to it. The metaclass __new__ just loops through the class dictionary and looks for methods that were marked by the auto_view_config decorator. It cleans off the mark and applies the view_config decorator with the appropriate class name.
Here's the code.
# This just spoofs the view_config decorator.
def view_config(route=''):
def dec(f):
def wrapper(*args, **kwargs):
print "route={0}".format(route)
return f(*args, **kwargs)
return wrapper
return dec
# Apply this decorator to methods for which you want to call view_config with
# the class name. It will tag them. The metaclass will apply view_config once it
# has the class name.
def auto_view_config(f):
f.auto_view_config = True
return f
class AutoViewConfigMeta(type):
def __new__(mcls, name, bases, dict_):
#This is called during class creation. _dict is the namespace of the class and
# name is it's name. So the idea is to pull out the methods that need
# view_config applied to them and manually apply them with the class name.
# We'll recognize them because they will have the auto_view_config attribute
# set on them by the `auto_view_config` decorator. Then use type to create
# the class and return it.
for item in dict_:
if hasattr(dict_[item], 'auto_view_config'):
method = dict_[item]
del method.auto_view_config # Clean up after ourselves.
# The next line is the manual form of applying a decorator.
dict_[item] = view_config(route=name)(method)
# Call out to type to actually create the class with the modified dict.
return type.__new__(mcls, name, bases, dict_)
class simpleObject(object):
__metaclass__ = AutoViewConfigMeta
class Test(simpleObject):
#auto_view_config
def activateTheView(self):
foo = 'bar'
print foo
if __name__=='__main__':
t = Test()
t.activateTheView()
Let me know if you have any questions.
Python has an "explict is better than implicit" design philosophy.
Many languages have an implicit pointer or variable in the scope of a method that (e.g. this in C++) that refers to the object through which the method was invoked. Python does not have this. Here, all bound methods will have an extra first argument that is the object through which the method was invoked. You can call it anything you want (self is not a keyword like this in C++). The name self is convention rather than a syntactic rule.
Your method myFunction defines the variable self as a parameter so it works. There's no such variable at the class level so it's erroring out.
So much for the explanation. I'm not aware of a straightforward way for you to do what you want and I've never seen such requirement in Python. Can you detail why you want to do such a thing? Perhaps there's an assumption that you're making which can be handled in another way using Python.
self is just a name, your self in this case is a class variable and not this for the object using which it is called,
self is treated as a normal variable and it is not defined, where as the self in the function comes from the object used for calling.
you want to treat the object reference in self as a class variable which is not possible.
self isn't a keyword, it's just a convention. The methods are attributes of the class object (not the instance), but they receive the instance as their first argument. You could rename the argument to xyzzy if you wanted and it would still work the same way.
But (as should be obvious) you can't refer to a method argument outside the body of the method. Inside a class block but outside of any method, self is undefined. And the concept wouldn't even make sense -- at the time the class block is being evaluated, no instance of the class can possibly exist yet.
Because the name self is explicitly defined as part of the arguments to myFunction. The first argument to a method is the instance that the method was called on; in the class body, there isn't an "instance we're dealing with", because the class body deals with every possible instance of the class (including ones that don't necessarily exist yet) - so, there isn't a particular object that could be called self.
If you want to refer to the class itself, rather than some instance of it, this is spelled self.__class__ (or, for new-style classes in Py2 and all classes in Py3, type(self)) anywhere self exists. If you want to be able to deal with this in situations where self doesn't exist, then you may want to look at class methods which aren't associated with any particular instance, and so take the class itself in place of self. If you really need to do this in the class body (and, you probably don't), you'll just have to call it by name.
You can't refer to the class itself within the class body because the class doesn't exist at the time that the class body is executed. (If the previous sentence is confusing, reading up about metaclasses will either clear this up or make you more confused.)
Within an instance method, you can refer to the class of the instance with self.__class__, but be careful here. This will be the instance's actual class, which through the power of inheritance might not be the class in which the method was defined.
Within a class method, the class is passed in as the first argument, much like instances are the first argument to instance methods:
class MyClass(object):
#classmethod
def foo(cls):
print cls.__name__
MyClass.foo() # Should print "MyClass"
As with instance methods, the actual class might differ due to inheritance.
class OtherClass(MyClass):
pass
OtherClass.foo() # Should print "OtherClass"
If you really need to refer to MyClass within a method of MyClass, you're pretty much going to have to refer to it as MyClass unless you use magic. This sort of magic is more trouble than it is worth.