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I'm currently developing a website with the framework Django (I'm very beginner), but I have a problem with Python: since I have created my templates, I can't run server anymore for this reason (the stack trace points to a line in file urls.py):
<stacktrace>
...
path('apppath/', include('myapp.urls')),
NameError: name 'include' is not defined
Where can I import include from?
Guessing on the basis of whatever little information provided in the question, I think you might have forgotten to add the following import in your urls.py file.
from django.conf.urls import include
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I'm rinning this GitHub code
It running well but having error in this line after trained model, and while testing to get the accuracy.
a = new_model.predict_generator(test_gen)
it says "NameError: name 'new_model' is not defined"
I want to know how to define 'new_model' before?
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I am trying to use selenium to login to https://www.amazon.co.uk/ap/signin?showRmrMe=1&openid.return_to=https%3A%2F%2Falexa.amazon.co.uk&openid.identity=http%3A%2F%2Fspecs.openid.net%2Fauth%2F2.0%2Fidentifier_select&openid.assoc_handle=amzn_dp_project_dee_uk&openid.mode=checkid_setup&openid.claimed_id=http%3A%2F%2Fspecs.openid.net%2Fauth%2F2.0%2Fidentifier_select&openid.ns=http%3A%2F%2Fspecs.openid.net%2Fauth%2F2.0&
it works, but then it automatically logs me out whenever I do this automated.
What might cause this issue?
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so my python application opens a link that would be found in my config file. I would like to make it so it would like to allow it to go to the website without doubling the %. Heres what I would want config.get('CONFIG', 'Website') the web address has a bunch of %'s in the link but when I run it, the process ends
I'm assuming you are using the configparser module?
If so, you can use ConfigParser(interpolation=None) to disable string interpolation (which controls the behavior of % characters in the config file).
(Or on older versions of Python, you may need to use RawConfigParser instead.)
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I have tried looking this up, but for some reason I cannot find anything about it. How do I run a script by giving the particular file directory in start()?
This works (when Test is in the same folder as the main script):
self.process.start("python3 Test.py")
This does NOT work:
self.process.start("python3 /my/path/Test.py")
Try this:
self.process.start("python3 ../my/path/Test.py") # added two periods before "/m"
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I started learning django and just deployed my first app when this showed up.
Any suggestions would be useful.
(https://i.stack.imgur.com/GgMjG.png)
it should be
from django.conf.urls import url
(without s at the end)
There is an error in your import, it should be:
from django.conf.urls import url
ref:https://docs.djangoproject.com/en/1.11/ref/urls/