I have a table that has these headers, like this:
How would I select the whole column using xpath to store in an array.
I was hoping for different arrays, like:
courses = []
teacher = []
avg = []
Bare in mind these column don't have any ID's or classes, so I need a way to select just by using the name of the column.
Here is the code for the table:
<table border="0">
<tbody>
<tr>
<td nowrap="nowrap">Courses</td>
<td nowrap="nowrap">Teacher</td>
<td><select name="fldMarkingPeriod" onchange="switchMarkingPeriod(this.value);">
<option value="MP1">MP1</option>
<option selected="selected" value="MP2">MP2</option>
<option value="MP3">MP3</option>
</select>Avg</td>
</tr>
<tr>
<td nowrap="nowrap">[Course Name]</td>
<td nowrap="nowrap">[Teacher Name]</td>
<td>
<table width="100%" cellspacing="0" cellpadding="0">
<tbody>
<tr>
<td title="View Course Summary" width="70%">100%</td>
<td width="30%">A+</td>
</tr>
</tbody>
</table>
</td>
</tr>
<tr>
<td nowrap="nowrap">[Course Name]</td>
<td nowrap="nowrap">[Teacher Name]</td>
<td>
<table width="100%" cellspacing="0" cellpadding="0">
<tbody>
<tr>
<td title="View Course Summary" width="70%">100%</td>
<td width="30%">A+</td>
</tr>
</tbody>
</table>
</td>
</tr>
<tr>
<td nowrap="nowrap">[Course Name]</td>
<td nowrap="nowrap">[Teacher Name]</td>
<td>
<table width="100%" cellspacing="0" cellpadding="0">
<tbody>
<tr>
<td title="View Course Summary" width="70%">100%</td>
<td width="30%">A+</td>
</tr>
</tbody>
</table>
</td>
</tr>
</tbody>
</table>
Any ideas? Thanks.
Not sure why exactly you need the data by columns, but here is a sample implementation:
courses = []
teachers = []
avgs = []
for row in table.find_elements_by_css("table > tbody > tr")[1:]:
course, teacher, _, avg = [td.text for td in row.find_elements_by_xpath(".//td")]
courses.append(course)
teachers.append(teacher)
avgs.append(avg)
Related
Within each of the main tables respectively, there are two tables nested of which the first one contains the data A_A_A_A that i want to extract to a pandas.dataframe
<table>
<tr valign="top">
<td> </td>
<td>
<br/>
<center>
<h2>asd</h2>
</center>
<h4>asd</h4>
<table>
<tr>
</tr>
</table>
<table border="0" cellpadding="0" cellspacing="0" class="tabcol" width="100%">
<tr>
<td> </td>
</tr>
<tr>
<td width="3%"> </td>
<td>
<table border="0" width="100%">
<tr>
<td width="2%"> </td>
<td> A_A_A_A <br/> A_A_A_A 111-222<br/> </td>
<td width="2%"> </td>
</tr>
</table>
</td>
<td width="3%"> </td>
</tr>
<tr>
<td width="3%"> </td>
<td>
<table border="0" cellpadding="0" cellspacing="0" width="100%">
<tr>
<td width="4%"> </td>
<td class="unique"> asd <br/> asd </td>
<td width="4%"> </td>
</tr>
</table>
</td>
<td width="3%"> </td>
</tr>
<tr>
<td> </td>
</tr>
</table>
<table border="0" cellpadding="0" cellspacing="0" class="tabcol" width="100%">
.
.
.
</table>
<br/>
<table>
</table>
</td>
</tr>
</table>
I figured that because of the limited availiability of attributes the only way to go forward would be an iteration over a td siblings with .next_siblings and if needed .next_elements
data1 = []
for item in soup.find_all('td', attrs={'width': '2%'}):
data = item.find_next_sibling().text
data1.append(data)
returns and empty list []. Now i dont know forward because i cannot identify any other helpful attributes/classes that would help me get to the middle td that contains the information.
.find_next(name=None, attrs={}, text=None, **kwargs)
Returns the first item that matches the given criteria and appears after this Tag in the document. So in your case:
item = soup.find('td', attrs={'width': '2%'})
data = item.find_next('td').text
Note that, I removed for loop since the desired data is coming after first td with width: '2%'. After running this, data will be:
' A_A_A_A A_A_A_A 111-222 '
I took #Wiktor Stribiżew answer from here regex for loop over list in python
and kind of merged it with yours #Rustam Garayev
item = soup.find_all('td', attrs={'width': '2%'})
data = [x.find_next('td').text for x in item]
since i needed not only the first AAAA but from all the following tables as well. The code above gives this output:
['A_A_A_A',
'\xa0',
'A_A_A_A',
'\xa0', ...]
which is good enough for my purpose. I think the '\xa0' comes from it trying to do the find_next on the third td sibling, which does not have a consecutive.
I'm still a python noob trying to learn beautifulsoup.I looked at solutions on stack but was unsuccessful Please help me to understand this better.
i have extracted the html which is as shown below
<table cellspacing="0" id="ContentPlaceHolder1_dlDetails"
style="width:100%;border-collapse:collapse;">
<tbody><tr>
<td>
<table border="0" cellpadding="5" cellspacing="0" width="70%">
<tbody><tr>
<td> </td>
<td> </td>
</tr>
<tr>
<td bgcolor="#4F95FF" class="listhead" width="49%">Location:</td>
<td bgcolor="#4F95FF" class="listhead" width="51%">On Site </td>
</tr>
<tr>
<td class="listmaintext">ATM ID: </td>
<td class="listmaintext">DAGR00401111111</td>
</tr>
<tr>
<td class="listmaintext">ATM Centre:</td>
<td class="listmaintext"></td>
</tr>
<tr>
<td class="listmaintext">Site Location: </td>
<td class="listmaintext">ADA Building - Agra</td>
</tr>
i tried to parse find_all('tbody') but was unsuccessful
#table = bs.find("table", {"id": "ContentPlaceHolder1_dlDetails"})
html = browser.page_source
soup = bs(html, "lxml")
table = soup.find_all('table', {'id':'ContentPlaceHolder1_dlDetails'})
table_body = table.find('tbody')
rows = table.select('tr')
for row in rows:
cols = row.find_all('td')
cols = [ele.text.strip() for ele in cols]
data.append([ele for ele in cols if ele])values
I'm trying to save values in "listmaintext" class
Error message
AttributeError: ResultSet object has no attribute 'find'. You're probably treating a list of items like a single item. Did you call find_all() when you meant to call find()?
Another way to do this using next_sibling
from bs4 import BeautifulSoup as bs
html ='''
<html>
<table cellspacing="0" id="ContentPlaceHolder1_dlDetails"
style="width:100%;border-collapse:collapse;">
<tbody><tr>
<td>
<table border="0" cellpadding="5" cellspacing="0" width="70%">
<tbody><tr>
<td> </td>
<td> </td>
</tr>
<tr>
<td bgcolor="#4F95FF" class="listhead" width="49%">Location:</td>
<td bgcolor="#4F95FF" class="listhead" width="51%">On Site </td>
</tr>
<tr>
<td class="listmaintext">ATM ID: </td>
<td class="listmaintext">DAGR00401111111</td>
</tr>
<tr>
<td class="listmaintext">ATM Centre:</td>
<td class="listmaintext"></td>
</tr>
<tr>
<td class="listmaintext">Site Location: </td>
<td class="listmaintext">ADA Building - Agra</td>
</tr>
</html>'''
soup = bs(html, 'lxml')
data = [' '.join((item.text, item.next_sibling.next_sibling.text)) for item in soup.select('#ContentPlaceHolder1_dlDetails tr .listmaintext:first-child') if item.text !='']
print(data)
from bs4 import BeautifulSoup
data = '''<table cellspacing="0" id="ContentPlaceHolder1_dlDetails"
style="width:100%;border-collapse:collapse;">
<tbody><tr>
<td>
<table border="0" cellpadding="5" cellspacing="0" width="70%">
<tbody><tr>
<td> </td>
<td> </td>
</tr>
<tr>
<td bgcolor="#4F95FF" class="listhead" width="49%">Location:</td>
<td bgcolor="#4F95FF" class="listhead" width="51%">On Site </td>
</tr>
<tr>
<td class="listmaintext">ATM ID: </td>
<td class="listmaintext">DAGR00401111111</td>
</tr>
<tr>
<td class="listmaintext">ATM Centre:</td>
<td class="listmaintext"></td>
</tr>
<tr>
<td class="listmaintext">Site Location: </td>
<td class="listmaintext">ADA Building - Agra</td>
</tr>'''
soup = BeautifulSoup(data, 'lxml')
s = soup.select('.listmaintext')
for td1, td2 in zip(s[::2], s[1::2]):
print('{} [{}]'.format(td1.text.strip(), td2.text.strip()))
Prints:
ATM ID: [DAGR00401111111]
ATM Centre: []
Site Location: [ADA Building - Agra]
I have stuck with regex syntax. I am trying to create a regex for html code, that looks for a specific string, which is located in a table and gives you back the next column value next to our search string.
[u'<table> <tr> <td>Ingatlan \xe1llapota</td> <td>fel\xfaj\xedtott</td> </tr> <tr> <td>\xc9p\xedt\xe9s \xe9ve</td> <td>2018</td> </tr> <tr> <td>Komfort</td> <td>luxus</td> </tr> <tr> <td>Energiatan\xfas\xedtv\xe1ny</td> <td class="is-empty">nincs megadva</td> </tr> <tr> <td>Emelet</td> <td>1</td> </tr> <tr> <td>\xc9p\xfclet szintjei</td> <td class="is-empty">nincs megadva</td> </tr> <tr> <td>Lift</td> <td>van</td> </tr> <tr> <td>Belmagass\xe1g</td> <td>3 m vagy magasabb</td> </tr> <tr> <td>F\u0171t\xe9s</td> <td>g\xe1z (cirko)</td> </tr> <tr> <td>L\xe9gkondicion\xe1l\xf3</td> <td>van</td> </tr> </table>', u'<table> <tr> <td>Akad\xe1lymentes\xedtett</td> <td>nem</td> </tr> <tr> <td>F\xfcrd\u0151 \xe9s WC</td> <td>k\xfcl\xf6n \xe9s atlan \xe1llapota')
So I would like to create a regex to look for "Ingatlan \xe1llapota" and return "fel\xfaj\xedtott":
Ingatlan \xe1llapota fel\xfaj\xedtott
My current regex expression is the following: \bIngatlan állapota\s+(.*)
I would need to incorporate the td tags and to limit how long string would it return after the search string(Ingatlan állapota)
Any help is much appreciated. Thanks!
As pointed out before use xpath or css instead:
import scrapy
class txt_filter:
sterm='Ingatlan \xe1llapota'
txt= '''<table> <tr> <td>Ingatlan \xe1llapota</td> <td>fel\xfaj\xedtott</td> </tr> <tr> <td>\xc9p\xedt\xe9s \xe9ve</td> <td>2018</td> </tr> <tr> <td>Komfort</td> <td>luxus</td> </tr> <tr> <td>Energiatan\xfas\xedtv\xe1ny</td> <td class="is-empty">nincs megadva</td> </tr> <tr> <td>Emelet</td> <td>1</td> </tr> <tr> <td>\xc9p\xfclet szintjei</td> <td class="is-empty">nincs megadva</td> </tr> <tr> <td>Lift</td> <td>van</td> </tr> <tr> <td>Belmagass\xe1g</td> <td>3 m vagy magasabb</td> </tr> <tr> <td>F\u0171t\xe9s</td> <td>g\xe1z (cirko)</td> </tr> <tr> <td>L\xe9gkondicion\xe1l\xf3</td> <td>van</td> </tr> </table>', u'<table> <tr> <td>Akad\xe1lymentes\xedtett</td> <td>nem</td> </tr> <tr> <td>F\xfcrd\u0151 \xe9s WC</td> <td>k\xfcl\xf6n \xe9s atlan </td></tr></table>
'''
resp = scrapy.http.response.text.TextResponse(body=txt,url='abc',encoding='utf-8')
print(resp.xpath('.//td[.="'+sterm+'"]/following-sibling::td[1]/text()').extract())
Result:
$ python3 so_51590811.py
['felújított']
I am working on python Django templates in which I have a table having column as id, factor A, factor B, factor C. Values for id, factor A, factor B and factor C respectively are 79, 0.56, 1.1, 1.3.
The code for the html template is like this:
<table class="table table-bordered">
<thead>
<tr>
<th class="text-center">id</th>
<th class="text-center">Factor A</th>
<th class="text-center">Factor B</th>
<th class="text-center">Factor C</th>
</tr>
</thead>
<tbody >
<tr ng-class="{'info':aggregateData.Mode, 'closed':!aggregateData.Open}">
<td class="text-center">{{aggregateData.id}}</td>
<td class="text-center">{{aggregateData.factor_a}}</td>
<td class="text-center">{{aggregateData.factor_b}}</td>
<td class="text-center">{{aggregateData.factor_c}}</td>
</tr>
</tbody>
</table
I want to add a clickable icon to this similar like this for rows having aggregateData.Open true.
Can someone suggest a way how I can achieve this.
Try this.
<table class="table table-bordered">
<thead>
<tr>
<th class="text-center">id</th>
<th class="text-center">Factor A</th>
<th class="text-center">Factor B</th>
<th class="text-center">Factor C</th>
</tr>
</thead>
<tbody >
<tr ng-class="{'info':aggregateData.Mode, 'closed':!aggregateData.Open}">
<td class="text-center">{{aggregateData.id}}</td>
<td class="text-center">{{aggregateData.factor_a}}</td>
<td class="text-center">{{aggregateData.factor_b}}</td>
<td class="text-center">{{aggregateData.factor_c}}</td>
{% if aggregateData.open == True %}
<td class="text-center">
<a href="https://www.google.co.in">
<img src="/path_toicon.png">
</a>
</td>
{% endif %}
</tr>
</tbody>
</table>
I have a table formed like this from a website:
<table>
<tr class="head">
<td class="One">
Column 1
</td>
<td class="Two">
Column 2
</td>
<td class="Four">
Column 3
</td>
<td class="Five">
Column 4
</td>
</tr>
<tr class="DataSet1">
<td class="One">
<table>
<tr>
<td class="DataType1">
Data 1
</td>
</tr>
<tr>
<td class="DataType_2">
<ul>
<li> Data 2a</li>
<li> Data 2b</li>
<li> Data 2c</li>
<li> Data 2d</li>
</ul>
</td>
</tr>
</table>
</td>
<td class="Two">
<table>
<tr>
<td class="DataType_3">
Data 3
</td>
</tr>
<tr>
<td class="DataType_4">
Data 4
</td>
</tr>
</table>
</td>
<td class="Three">
<table>
<tr>
<td class="DataType_5">
Data 5
</td>
</tr>
</table>
</td>
<td class="Four">
<table>
<tr>
<td class="DataType_6">
Data 6
</td>
</tr>
</table>
</td>
</tr>
<tr class="Empty">
<td class="One">
</td>
<td class="Two">
</td>
<td class="Four">
</td>
<td class="Five">
</td>
</tr>
<tr class="DataSet2">
<td class="One">
<table>
<tr>
<td class="DataType_1">
Data 7
</td>
</tr>
<tr>
<td class="DataType_2">
Data 8
</td>
</tr>
</table>
</td>
<td class="Two">
<table>
<tr>
<td class="DataType_3">
Data 9
</td>
</tr>
<tr>
<td class="DataType_4">
Data 10
</td>
</tr>
</table>
</td>
<td class="Three">
<table>
<tr>
<td class="DataType_5">
Data 11
</td>
</tr>
</table>
</td>
<td class="Four">
<table>
<tr>
<td class="DataType_6">
Data 12
</td>
</tr>
</table>
</td>
</tr>
<!-- and so on -->
</table>
The tags sometimes are also empty, for example:
<td class="DataType_6> </td>
I tried to scrape the content with Scrapy and the following script:
from scrapy.spider import BaseSpider
from scrapy.selector import HtmlXPathSelector
from project.items import ProjectItem
class MySpider(BaseSpider):
name = "SpiderName"
allowed_domains = ["url"]
start_urls = ["url"]
def parse(self, response):
hxs = HtmlXPathSelector(response)
rows = hxs.select('//tr')
items = []
item = ProjectItem()
item["Data_1"] = rows.select('//td[#class="DataType_1"]/text()').extract()
item["Data_2"] = rows.select('//td[#class="DataType_2"]/text()').extract()
item["Data_3"] = rows.select('//td[#class="DataType_3"]/text()').extract()
item["Data_4"] = rows.select('//td[#class="DataType_4"]/text()').extract()
item["Data_5"] = rows.select('//td[#class="DataType_5"]/text()').extract()
item["Data_6"] = rows.select('//td[#class="DataType_6"]/text()').extract()
items.append(item)
return items
If I crawl using this command:
scrapy crawl SpiderName -o output.csv -t csv
I only get crap like as many times as I have got the Dataset all the values for "Data_1".
Had a similar problem. First of all, rows = hxs.select('//tr') is going to loop on everything from the first child. You need to dig a bit deeper, and use relative paths. This link gives an excellent explanation on how to structure your code.
When I finally got my head around it, I realised that in that order to parse each item separately, row.select should not have the // in it.
Hope this helps.