For my homework I need to make a user registration system in python. I need to make a password section.
What I am meant to do?.
Here is my code, I can't work out whats wrong:
password = input("Please enter your password: ")
passwordl = len(password)
while passwordl <= 8:
print("password must be more than 8 characters - please try agian")
password = input("Please enter your password: ")
passworda = password.isalpha()
passwordi = password.isdigit()
while passworda != True or passwordi != True:
print("password needs to contain digits and characters - please re-enter")
password = input("Please enter your password: ")
The code is in a function btw.
Thanks
The functions isalpha() and isdigit() return true if all the members in the string are alphanumeric and digits, respectively.
What you need to do instead is to check if any characters in the string have the right properties, for example like this:
passworda = any([x.isalpha() for x in password])
passwordi = any([x.isdigit() for x in password])
Additionally, you need to redo all the checks (both length and character set checks) each time when the password is entered anew.
Instead of following
Password = input("Please enter your password")
In the last while loop with the checks over again you would be better just calling the password function as it's more efficient.
Related
I make password genrator using python then the teacher told to create a code that make the user choose what he want in the password
the password contains
1- lower case characters
2- upper case characters
3- numbers
4- punticuation marks
the teacher want me to make the user choose if he want punticution or not
if he dont want it have to be deleted from the password
i tried so hard but i got stuck
from msilib import change_sequence
import string
import random # I import this line to make the password unorgnaized
# this code below is all the characters we need for the password
s1 = list(string.ascii_lowercase)
s2 = list(string.ascii_uppercase)
s3 = list(string.digits)
s4 = list(string.punctuation)
# this code is for the user to put how much characters he need
characters_number = input("how many characters for the password?:")
# this while loop code is to make the user choose only 6 characters and up
while True:
try:
characters_number = int(characters_number)
if characters_number < 6 :
print("you need at least 6 characters") # if the user choose an letter or digits it will not allow him
characters_number = input("please enter the number again:")
else:
break # I break the loop here if the user write the correct data
except: #this code here if the user enter anything except numbers
print("please enter numbers only")
characters_number = input("how many characters for the password?:")
# the random and shuffle is to make the password unorgnized
random.shuffle(s1)
random.shuffle(s2)
random.shuffle(s3)
random.shuffle(s4)
# the password that will appear to the user it contains upper and lower letters, numbers and digit
# part1 here is for the letters I allocated 30% of the password for letters
# part2 here is for the digits and numbers I allocated 20% of the password for letters
part1 = round(characters_number * (30/100))
part2 = round(characters_number * (20/100))
password = []
for x in range(part1):
password.append(s1[x])
password.append(s2[x])
#the for loops here here is to create the password
for x in range(part2):
password.append(s3[x])
password.append(s4[x])
#this code here is to transform the password for list method to a string
password = "".join(password[0:])
print(password)
You can write a function like this:
def isUserNeedPunctuationMarks():
result = None
while True:
inp = input("Do you need punctuation marks in your password? (y/n)")
inp = inp.lower()
if inp == "y":
result = True
break
elif inp == "n":
result == False
break
else:
print("You must enter y or n")
return result
The above function will return True if the user needs punctuation marks, and False otherwise. User has to type y (for yes) or n(for no).
You can call isUserNeedPunctuationMarks() in the right place in your code. For example, removing punctuation marks from password string, you have to write a condition like this:
import re
if not isUserNeedPunctuationMarks():
password = re.sub(r'[^\w\s]', '', password) # This removes punctuation marks from a string using regex
Hope this helps :)
Ok so I am making a password maker in python and I am trying to create a secure password that shows up in the console like this:
Fdm6:yguiI
I also want the user to specify the number of alphabets the password will need (which actually works)
anyway, here is the code
import random
options = '1234567890!##$%^&*()`~-_=+\|]}[{\'";:/?.>,<QWERTYUIOPASDFGHJKLZXCVBNMqwertyuiopasdfghjklzxcvbnm'
char_list = tuple(options)
print("""Password checker
This either checks your password or creates a sequre password.
Your commands are \"create password\" and \"check password\"""")
command = str(input('Type your command: '))
if command.lower() == 'create password':
digit_count = int(input('How many digits do you want your password to be? (Must be more than five and under 35): '))
if digit_count >= 5 and digit_count <= 35:
for i in range(digit_count):
password = random.choice(char_list)
print(password)
else:
print('Bruh I told you to give more than 5 or under 35')
Right now, the output is like this
Someone please help mee
Replace this part
for i in range(digit_count):
password = random.choice(char_list)
print(password)
with:
password = ''.join(random.choices(char_list, k=digit_count))
print(password)
Add an end parameter to your output print statement -
for i in range(digit_count):
password = random.choice(char_list)
print(password,end='')
By default, the end is equal to '\n'. So it changes the line if you do not specify the end as '' (empty)
If you do want to store the password, then use a list comprehension -
p = [random.choice(char_list) for i in range(digit_count)]
password = ''.join(p) # Or, you could just write this into a single line
print(password)
I'm working on a password checker that checks if the string is a valid password. I have to check if there is at least eight characters, must consist of only letters and digits and the last two characters must be digits.
It all seems to work so far other than the password.isdigit(). sometimes the password comes out valid and sometimes it doesn't. Any suggestions?
# Gets the users password
password = input('Enter a string for password: ')
# Splices the last two characters of the password
lastTwo = password[-2:]
# Checks the password if it is less than 8 characters
while len(password) < 8:
print('The password you entered is too short.')
print()
password = input('Enter a string for password: ')
# Checks the password if it is composed of letters and numbers
while password.isalnum() == False:
print('Your password has special characters not allowed.')
print()
password = input('Enter a string for password: ')
# Checks the spice to verify they are digits
while lastTwo.isdigit() == False:
print('Your last two characters of your password must be digits.')
print()
password = input('Enter a string for password: ')
print('Your password is valid.')
There are a handful of issues with your provided code. Particularly, you only check the subsequent rules while len(password) < 8. If you give it a password of length 10, the rules are never checked. Additionally, you don't update the lastTwo with each new password attempted
One way to fix this would be to replace your several while statements with if...elif..elif...else... wrapped in an overall while statement, as follows:
# Gets the users password
password = input('Enter a string for password: ')
while True:
# Checks the password if it is less than 8 characters
if len(password) < 8:
print('The password you entered is too short.')
# Checks the password if it is composed of letters and numbers
elif not password.isalnum():
print('Your password has special characters not allowed.')
# Checks the spice to verify they are digits
elif not password[:-2].isdigit():
print('Your last two characters of your password must be digits.')
else:
# we only get here when all rules are True
break
print()
password = input('Enter a string for password: ')
print('Your password is valid.')
This should work as you intended it. But while we're at it, why not tell the user every rule their password has broken? From a UI point of view, it helps to keep the user informed.
If we store an information message alongside whether the relevant rule has been met, we can quickly work out all of the rules that have been broken, like so:
valid_password = False
while not valid_password:
# Get a password
password = input('\nEnter a string for password: ')
# applies all checks
checks = {
'- end in two digits': password[-2].isdigit(),
'- not contain any special characters': password.isalnum(),
'- be over 8 characters long': len(password) > 8
}
# if all values in the dictionary are true, the password is valid.
if all(checks.values()):
valid_password = True
# otherwise, return the rules violated
else:
print('This password is not valid. Passwords must:\n{}'.format(
'\n'.join([k for k, v in checks.items() if not v])))
print('Your password is valid.')
You never update your value of lastTwo inside your while loop. Thus imagine if a user first entered a password abc123. Then lastTwo would be calculated as 23.
Now your code would find that the password is too short and prompt the user for a new password. Suppose he enters abcdefgh. This now passes your first and second checks. Notice however that lastTwo is still 23, and thus your third check will incorrectly pass.
You should thus recalculate the value of lastTwo whenever you accept a new password or directly check like this:
while (password[-2:]).isdigit() == False:
I have tried to create an app in Python that makes a user create a password and then makes them verify it. Obviously I had to create a loop so that when the user entered an unmatching password they had to try again. I am not very experienced with loops so here is what I got. How do I make this work?
here is the code:
password = raw_input ("Create a password: ")
passwordv = raw_input ("Retype your password: ")
a = ("Passwords don't match! Please try again!: ")
b = ("Congrats, you have created a password")
def password():
if password == passwordv :
print ("Congrats, you have created a password")
else :
print (a)
return password
return passwordv
while password !=passwordv:
print (a)
here is another set of code trying to do the same thing:
password = raw_input('Create a password: ')
passwordv = raw_input('Veryify your password: ')
while (password != passwordv):
print raw_input('Passwords do not match, try again: ')
if (password == passwordv) :
print ('Password set')
break
Your conditional to test whether the passwords match was included in the loop which checks that they don't match -- so, it never gets run.
Try this instead:
password = raw_input('Create a password: ')
passwordv = raw_input('Verify your password: ')
while (password != passwordv):
print raw_input('Passwords do not match, try again. ')
password = raw_input('Create a password: ')
passwordv = raw_input('Verify your password: ')
continue
print ('Password set')
Note how only the code that should be run if the passwords don't match is included within the while loop.
What you need here is an "N and a half times loop". To avoid repeating code (guided by the DRY principle) you might consider writing a function to get the passwords. The following might work:
def get_passwords():
password = raw_input('Create a password: ')
passwordv = raw_input('Veryify your password: ')
return password, passwordv
pw1, pw2 = get_passwords()
while pw1 != pw2:
print "Sorry, passwords do not match"
pw1, pw2 = get_passwords()
The loop won't be entered at all if the original passwords match. Otherwise it will repeat until they do.
password=raw_input('Enter password: \t\t\t')
passwordv=raw_input('Enter password again to verify: \t')
if password == passwordv:
print "\ncongratz you have created password"
else:
print "\nPlease try again...!"
while password != passwordv:
password=raw_input("Enter password: \t\t\t")
passwordv=raw_input("Enter password again to verify: \t")
if password == passwordv:
print"\ncongratz you have created password"
else:
print"\nPlease try again...!"
I know this one is long, It is just for basic understanding
The other answers provide the code that will do what you want. I thought that it could be interesting to tell you a little bit more what was wrong with the code you provided because the problem is more about your understanding of how things work.
1st attempt: a variable and a function have the same name
# Here you define your password variable as a string
password = raw_input ("Create a password: ")
[...]
# And then you reassign it here: it contains now the address of that function!
def password():
[...]
# Now you're comparing a function to a string: they'll never be equal
while password !=passwordv:
[...]
This could have been avoided simply by changing the name of your function (which is never called by the way so I'm not sure what you wanted to do but I thought you might find that interesting). Further reading: Python: function and variable with same name
2nd attempt: the values of the variables stay the same
password = raw_input('Create a password: ')
passwordv = raw_input('Veryify your password: ')
# At this point, if the test is true, you'll reach the end of the code without
# displaying the 'Password set' message you wanted
while (password != passwordv):
# This only prints a message
print raw_input('Passwords do not match, try again: ')
# The condition below can never be true: you just tested that they were
# different but did nothing to give them new values!
if (password == passwordv) :
print ('Password set')
break
The way to fix that is what the other answers provide: take your message out of the loop (getting out of the loop means that your condition was met) ; make sure that you do something inside the loop that will assure that the next test will be different from the previous one (otherwise, you will end up testing the same values over and over again) ; to avoid breaking inside the loop, set your values outside the loop, and then get new values inside the loop in case the initial test failed.
Here's an idea:
First define these:
MinPass = 6
MaxPass = 12
Then this:
print ("Now, lets try with a password. Please enter one here")
EnteredPassword = input("Password: ")
while len(EnteredPassword) < MinPass:
print ("That password is too small. Please try again")
EnteredPassword = input("Password: ")
while len(EnteredPassword) > MaxPass:
print ("That password is too long, please try again")
EnteredPassword = input("Password: ")
Hope this helps!
I'm receiving an error in python that says I, "Can't assign to literal". I was hoping that somebody could help me understand why this is coming up. Here's my code:
# Chapter 3 Challenge part 3
# use the code below and the following
# directions to see if you can solve the problem
# Your Co-Worker has been asked to write a
# 1st time "Log-in" program in which a user has to
# sign in with their user name. If they enter
# the correct id name they need to be asked
# to create their password.
# They were required to make sure the user did
# not leave the username entry blank and must have the
# correct user name or the progam should re-ask
# them to sign in... They cannot figure out what
# to do, so they have called on you to help...
# Here is what they have so far...
# They started their program like this....
# and included some of their documentation.
# Get username, check to see if not empty,
# then verify that username is correct.
# using username "jalesch" as test user.
name = False
while not name:
name = raw_input("Enter your user name: ")
print "Welcome," , name , "you must create a password."
password = False
while not password:
password = raw_input("""Enter a password.
Password must be at least 6 characters in length,
and must include one of these symbols (!, $, ?, &): """)
while len(password) < 6:
for "!" in password or "$" in password or "?" in password or "&" in password:
password = raw_input("""Enter a password.
Password must be at least 6 characters in length,
and must include one of these symbols (!, $, ?, &): """)
print "This has met the requirements."
check = raw_input("Please re-enter your password:")
while check != password:
print "You have entered the wrong password"
check = raw_input("Please re-enter your password:")
print "Welcome to the program!"
# prompt user to create a password that meets the
# following requirements:
# - Must be at least 6 characters in length
# - Must include at least one of these 4 symbols
# - ! $ ? &
# Once the user has entered their password, the program
# must check to see if it meets the requirements.
# If the requirements are not met, it should reask them
# to put in a password that meets the requirements
# until they get it correct.
# Test password is: $program!
# If it meets the requirements then prompt the user
# to re enter the password, and check that the
# first and second entry matches.
# If the 1st and 2nd match. display "Welcome to the program"
# If the 1st and 2nd don't match, re-prompt for the password
# until they get a correct match.
I also believe that the code is malfunctioning when I try to find the special characters, because it is skipping one of the while loops. Any help is appreciated, thanks.
on this line:
for "!" in password or "$" in password or "?" in password or "&" in password:
You probably meant to use if:
if "!" in password or "$" in password or "?" in password or "&" in password:
for x in y iterates over y, assigning each member to x sequentially, running the following indented code in a loop for each member of y. You can't assign a value to "!" because that's a literal character, not a variable.
def get_name(prompt):
while True:
name = raw_input(prompt).strip()
if name:
return name
def get_password(prompt):
while True:
name = raw_input(prompt).strip()
if len(name) >= 6 and (set(name) & set("!$?&")):
return name
name = get_name("Enter your user name: ")
print("Welcome, {}, you must create a password.".format(name))
while True:
print("Now enter a password. It must be at least 6 characters in length, and must include a symbols (!, $, ?, &).")
pass1 = get_password("Enter a password: ")
pass2 = get_password("Please re-enter your password: ")
if pass1 == pass2:
print("Welcome to the program")
break
else:
print("No match! Please try again")