Python - match directories with pattern (regular expression) - python

I wrote a loop which ignores all sub-directories which contain .txt files within them.
src = raw_input("Enter source disk location: ")
src = os.path.abspath(src)
dst = raw_input("Enter first destination to copy: ")
dst = os.path.abspath(dst)
dest = raw_input("Enter second destination to move : ")
dest = os.path.abspath(dest)
path_patter = '(\S+)_(\d+)_(\d+)_(\d+)__(\d+)_(\d+)_(\d+)'
for dir, dirs, files in os.walk(src):
if any(f.endswith('.txt') for f in files):
dirs[:] = [] # do not recurse into subdirectories
continue
files = [os.path.join(dir, f) for f in files ]
for f in files:
part1 = os.path.dirname(f)
part2 = os.path.dirname(os.path.dirname(part1))
part3 = os.path.split(part1)[1]
path_miss1 = os.path.join(dst, "missing_txt")
path_miss = os.path.join(path_miss1, part3)
path_missing = os.path.join(dest, "missing_txt")
searchFileName = re.search(path_patter, part3)#### update
if searchFileName:#####update
try:
if not os.path.exists(path_miss):
os.makedirs(path_miss)
else:
pass
if os.path.exists(path_miss):
distutils.dir_util.copy_tree(part1, path_miss)
else:
debug_status += "missing_file\n"
pass
if (get_size(path_miss)) == 0:
os.rmdir(path_miss)
else:
pass
if not os.path.exists(path_missing):
os.makedirs(path_missing)
else:
pass
if os.path.exists(path_missing):
shutil.move(part1, path_missing)
else:
pass
if (get_size(path_missing)) == 0:
os.rmdir(path_missing)
else:
pass
except Exception:
pass
else:
continue
How to modify this code to compare directory name with regular expression in this case. (it has to ignore directories with .txt files)

import os
import re
def createEscapedPattern(path,pattern):
newPath = os.path.normpath(path)
newPath = newPath.replace("\\","\\\\\\\\")
return newPath + "\\\\\\\\" + pattern
def createEscapedPath(path):
newPath = os.path.normpath(path)
return newPath.replace("\\","\\\\")
src = 'C:\\Home\\test'
path_patter = '(\S+)_(\d+)_(\d+)_(\d+)__(\d+)_(\d+)_(\d+)$'
p = re.compile(createEscapedPattern(src,path_patter))
for dir, dirs, files in os.walk(src):
if any(f.endswith('.txt') for f in files):
dirs[:] = []
continue
if any(p.match(createEscapedPath(dir)) for f in files):
for f in files:
print createEscapedPath(dir + "/" + f)
p = re.compile(createEscapedPattern(dir,path_patter))
There are a couple of things i did here and hope this example helps
I wrote this for windows fs so used two path convert functions.
This script ignores dirs with .txt files like you implemented it
This script will start at the directory you start the script and will only print file names if the pattern matches. This is done for all subdirectory's that are not ignored by the previous rule.
Used regex in python and made it compile again for each directory so you get: 'directory/(\S+)(\d+)(\d+)_(\d+)__(\d+)(\d+)(\d+)$'

Related

optional command line argument for my script

I'm coding a script that either zips the hall folder or you can choose files with specific extension such as ".txt". I use sys.argv to pass the folder path and extension, if needed. However, when I pass the path the only thing I get is this error:
fileEx = sys.argv[2]
IndexError: list index out of range
How can I make the "file extension" command line optional?
My script:
import zipfile, os, sys
if len(sys.argv) < 2:
folder_path = sys.argv[1]
fileEx = None
else:
folder_path = sys.argv[1]
fileEx = sys.argv[2]
def zipf(folder_path, fileEx=None):
folder_path = os.path.abspath(folder_path)
number = 1
while True:
zipfilename= os.path.basename(folder_path) + "_" + str(number) +'.zip'
if not os.path.exists(zipfilename):
break
number = number + 1
# creat the zip file
print(f'creating {zipfilename}')
backupZip = zipfile.ZipFile(zipfilename, 'w')
# walking through folders
for foldername , subfolders , filenames in os.walk(folder_path):
print(f'Adding files in {foldername}. . . ')
#adding the folder
backupZip.write(foldername)
# adding all files in the folder to zipfile
for filename in filenames:
newBase = os.path.basename(folder_path) + '_'
if filename.startswith(newBase) and filename.endswith('.zip'):
continue
if fileEx:
if filename.endswith(fileEx):
os.chdir(foldername)
backupZip.write(os.path.join(foldername, filename))
else:
backupZip.write(os.path.join(foldername, filename))
backupZip.close()
zipf("folder_path, fileEx")

Python: How to get the full path of a file in order to move it?

I had files that were in zips. I unzipped them with Zip-7 so they are in folders with the zip file names.
Each of these folders has either a .otf or .ttf (some have both) that I want out of them and moved to another folder.
I have tried a few methods of getting the full path of the files but every one of them leaves out the folder that the file is actually in.
Here is my latest try:
import os
import shutil
from pathlib import Path
result = []
for root, dirs, files in os.walk("."):
for d in dirs:
continue
for f in files:
if f.endswith(".otf"):
print(f)
p = Path(f).absolute()
parent_dir = p.parents[1]
p.rename(parent_dir / p.name)
elif f.endswith(".ttf"):
print(f)
p = Path(f).absolute()
parent_dir = p.parents[1]
p.rename(parent_dir / p.name)
else:
continue
Other attempts:
# parent_dir = Path(f).parents[1]
# shutil.move(f, parent_dir)
#print("OTF: " + f)
# fn = f
# f = f[:-4]
# f += '\\'
# f += fn
# result.append(os.path.realpath(f))
#os.path.relpath(os.path.join(root, f), "."))
I know this is something simple but I just can't figure it out. Thanks!
You should join the file name with the path name root:
for root, dirs, files in os.walk("."):
for d in dirs:
continue
for f in files:
if f.endswith(".otf"):
p = Path(os.path.join(root, f)).absolute()
parent_dir = p.parents[1]
p.rename(parent_dir / p.name)
elif f.endswith(".ttf"):
p = Path(os.path.join(root, f)).absolute()
parent_dir = p.parents[1]
p.rename(parent_dir / p.name)
else:
continue
for root, dirs, files in os.walk(".")
for d in dirs:
continue
for f in files:
print(os.path.abspath(f))
You can use os.path.abspath() to get a path of a full file
You would also need to still filter for the certain file types.

Move file to a folder or make a renamed copy if it exists in the destination folder

I have a piece of code i wrote for school:
import os
source = "/home/pi/lab"
dest = os.environ["HOME"]
for file in os.listdir(source):
if file.endswith(".c")
shutil.move(file,dest+"/c")
elif file.endswith(".cpp")
shutil.move(file,dest+"/cpp")
elif file.endswith(".sh")
shutil.move(file,dest+"/sh")
what this code is doing is looking for files in a source directory and then if a certain extension is found the file is moved to that directory. This part works. If the file already exists in the destination folder of the same name add 1 at end of the file name, and before the extension and if they are multiples copies do "1++".
Like this: test1.c,test2.c, test3.c
I tried using os.isfile(filename) but this only looks at the source directory. and I get a true or false.
To test if the file exists in the destination folder you should os.path.join the dest folder with the file name
import os
import shutil
source = "/home/pi/lab"
dest = os.environ["HOME"]
# Avoid using the reserved word 'file' for a variable - renamed it to 'filename' instead
for filename in os.listdir(source):
# os.path.splitext does exactly what its name suggests - split the name and extension of the file including the '.'
name, extension = os.path.splitext(filename)
if extension == ".c":
dest_filename = os.path.join(dest, filename)
if not os.path.isfile(dest_filename):
# We copy the file as is
shutil.copy(os.path.join(source, filename) , dest)
else:
# We rename the file with a number in the name incrementing the number until we find one that is not used.
# This should be moved to a separate function to avoid code duplication when handling the different file extensions
i = 0
dest_filename = os.path.join(dest, "%s%d%s" % (name, i, extension))
while os.path.isfile(dest_filename):
i += 1
dest_filename = os.path.join(dest, "%s%d%s" % (name, i, extension))
shutil.copy(os.path.join(source, filename), dest_filename)
elif extension == ".cpp"
...
# Handle other extensions
If you want to have put the renaming logic in a separate function using glob and re this is one way:
import glob
import re
...
def rename_file(source_filename, source_ext):
filename_pattern = os.path.join(dest, "%s[0-9]*%s"
% (source_filename, source_ext))
# Contains file such as 'a1.c', 'a2.c', etc...
existing_files = glob.glob(filename_pattern)
regex = re.compile("%s([0-9]*)%s" % (source_filename, source_ext))
# Retrieve the max of the index used for this file using regex
max_index = max([int(match.group(1))
for match in map(regex.search, existing_files)
if match])
source_full_path = os.path.join(source, "%s%s"
% (source_filename, source_ext))
# Rebuild the destination filename with the max index + 1
dest_full_path = os.path.join(dest, "%s%d%s"
% (source_filename,
(max_index + 1),
source_ext))
shutil.copy(source_full_path, dest_full_path)
...
# If the file already exists i.e. replace the while loop in the else statement
rename_file(name, extension)
I din't test the code. But something like this should do the job:-
i = 0
filename = "a.txt"
while True:
if os.isfile(filename):
i+= 1
break
if i:
fname, ext = filename.split('.')
filename = fname + str(i) + '.' + ext

Flatten complex directory structure in Python

I want to move files from a complex directory structure to just one place. For example i have this deep hierarchy:
foo/
foo2/
1.jpg
2.jpg
...
I want it to be:
1.jpg
2.jpg
...
My current solution:
def move(destination):
for_removal = os.path.join(destination, '\\')
is_in_parent = lambda x: x.find(for_removal) > -1
with directory(destination):
files_to_move = filter(is_in_parent,
glob_recursive(path='.'))
for file in files_to_move:
shutil.move(file, destination)
Definitions: directory and glob_recursive. Note, that my code only moves files to their common parent directory, not an arbitrary destination.
How can i move all files from a complex hierarchy to a single place succinctly and elegantly?
I don't like testing the name of the file about to be moved to see if we're already in the destination directory. Instead, this solution only scans the subdirectories of the destination
import os
import itertools
import shutil
def move(destination):
all_files = []
for root, _dirs, files in itertools.islice(os.walk(destination), 1, None):
for filename in files:
all_files.append(os.path.join(root, filename))
for filename in all_files:
shutil.move(filename, destination)
Explanation: os.walk walks recursively the destination in a "top down" manner. whole filenames are constructed with the os.path.join(root, filename) call. Now, to prevent scanning files at the top of the destination, we just need to ignore the first element of the iteration of os.walk. To do that I use islice(iterator, 1, None). One other more explicit way would be to do this:
def move(destination):
all_files = []
first_loop_pass = True
for root, _dirs, files in os.walk(destination):
if first_loop_pass:
first_loop_pass = False
continue
for filename in files:
all_files.append(os.path.join(root, filename))
for filename in all_files:
shutil.move(filename, destination)
this would do, it also renames files if they collide (I commented out the actual move and replaced with a copy):
import os
import sys
import string
import shutil
#Generate the file paths to traverse, or a single path if a file name was given
def getfiles(path):
if os.path.isdir(path):
for root, dirs, files in os.walk(path):
for name in files:
yield os.path.join(root, name)
else:
yield path
destination = "./newdir/"
fromdir = "./test/"
for f in getfiles(fromdir):
filename = string.split(f, '/')[-1]
if os.path.isfile(destination+filename):
filename = f.replace(fromdir,"",1).replace("/","_")
#os.rename(f, destination+filename)
shutil.copy(f, destination+filename)
Run recursively through directory, move the files and launch move for directories:
import shutil
import os
def move(destination, depth=None):
if not depth:
depth = []
for file_or_dir in os.listdir(os.path.join([destination] + depth, os.sep)):
if os.path.isfile(file_or_dir):
shutil.move(file_or_dir, destination)
else:
move(destination, os.path.join(depth + [file_or_dir], os.sep))
import os.path, shutil
def move(src, dest):
not_in_dest = lambda x: os.path.samefile(x, dest)
files_to_move = filter(not_in_dest,
glob_recursive(path=src))
for f in files_to_move:
shutil.move(f, dest)
Source for glob_recursive. Does not change name of file, if they collide.
samefile is a safe way to compare paths. But it doesn't work on Windows, so check How to emulate os.path.samefile behaviour on Windows and Python 2.7?.
def splitPath(p):
a,b = os.path.split(p)
return (splitPath(a) if len(a) and len(b) else []) + [b]
def safeprint(s):
try:
print(s)
except UnicodeEncodeError:
if sys.version_info >= (3,):
print(s.encode('utf8').decode(sys.stdout.encoding))
else:
print(s.encode('utf8'))
def flatten(root, doit):
SEP = "¦"
REPL = "?"
folderCount = 0
fileCount = 0
if not doit:
print("Simulating:")
for path, dirs, files in os.walk(root, topdown=False):
if path != root:
for f in files:
sp = splitPath(path)
np = ""
for element in sp[1:]:
e2 = element.replace(SEP, REPL)
np += e2 + SEP
f2 = f.replace(SEP, REPL)
newName = np + f2
safeprint("Moved: "+ newName )
if doit:
shutil.move(os.path.join(path, f), os.path.join(root, f))
# Uncomment, if you want filenames to be based on folder hierarchy.
#shutil.move(os.path.join(path, f), os.path.join(root, newName))
fileCount += 1
safeprint("Removed: "+ path)
if doit:
os.rmdir(path)
folderCount += 1
if doit:
print("Done.")
else:
print("Simulation complete.")
print("Moved files:", fileCount)
print("Removed folders:", folderCount)
directory_path = r"C:\Users\jd\Documents\myFtpData"
flatten(directory_path, True)
Adding on to the answers, I believe my answer will satisfy all your needs, the other answers fail when there is a subdirectory and file with the same filename as the upper directory.
This was SOLVED here, Also look at my Github Repo for Structured File Copy and Flattened File Copy:
import os, fnmatch, shutil
PATTERN = '*.txt' # Regex Pattern to Match files
INPUT_FOLDER = "A" # os.getcwd()
INPUT_FOLDER = os.path.abspath(INPUT_FOLDER)
include_input_foldername = False
prepend = "_included" if include_input_foldername else ""
OUTPUT_FOLDER = f"Structured_Copy_{os.path.basename(INPUT_FOLDER)}{prepend}"
os.makedirs(OUTPUT_FOLDER, exist_ok=True)
def find(pattern, path):
"""Utility to find files wrt a regex search"""
result = []
for root, dirs, files in os.walk(path):
for name in files:
if fnmatch.fnmatch(name, pattern):
result.append(os.path.join(root, name))
return result
all_files = find(PATTERN, INPUT_FOLDER)
for each_path in all_files:
relative_path = os.path.relpath(each_path, os.path.dirname(INPUT_FOLDER)) if include_input_foldername else os.path.relpath(each_path, INPUT_FOLDER)
flattened_relative_fullpath = os.path.join(OUTPUT_FOLDER, relative_path)
os.makedirs(os.path.dirname(flattened_relative_fullpath), exist_ok=True)
shutil.copy(each_path, flattened_relative_fullpath)
print(f"Copied {each_path} to {flattened_relative_fullpath}")
print(f"Finished Copying {len(all_files)} Files from : {INPUT_FOLDER} to : {OUTPUT_FOLDER}")

return text file path

I want to return the path of a file, If it is found by the program, but I want it to continue to loop(or recursively repeat) the program until all files are checked.
def findAll(fname, path):
for item in os.listdir(path):
n = os.path.join(path, item)
try:
findAll(n, fname)
except:
if item == fname:
print(os.idontknow(item))
So I'm having trouble with calling the path, right now I have
os.idontknow(item)
as a place holder
Input is :
findAll('fileA.txt', 'testpath')
The output is:
['testpat\\fileA.txt', 'testpath\\folder1\\folder11\\fileA.txt','testpath\\folder2\\fileA.txt']
Per my comment above, here is an example that will start at the current directory and search through all sub-directories, looking for files matching fname:
import os
# path is your starting point - everything under it will be searched
path = os.getcwd()
fname = 'file1.txt'
my_files = []
# Start iterating, and anytime we see a file that matches fname,
# add to our list
for root, dirs, files in os.walk(path):
for name in files:
if name == fname:
# root here is the path to the file
my_files.append(os.path.join(root, name))
print my_files
Or as a function (more appropriate for your case :) ):
import os
def findAll(fname, start_dir=os.getcwd()):
my_files = []
for root, dirs, files in os.walk(start_dir):
for name in files:
if name == fname:
my_files.append(os.path.join(root, name))
return my_files
print findAll('file1.txt')
print findAll('file1.txt', '/some/other/starting/directory')
Something like this, maybe?
import os
path = "path/to/your/dir"
for (path, dirs, files) in os.walk(path):
print files

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