I'm trying to plot two series and have the x-axis ticks labeled every 5 years. If I index the data with a PeriodIndex for some reason I get ticks every 10 years. If I use a list of integers to index, then it works fine. Is there a way to get the right tick labels with a PeriodIndex?
import pandas as pd
import numpy as np
import matplotlib as mpl
import matplotlib.pyplot as plt
np.random.seed(0)
idx = pd.PeriodIndex(range(2000,2021),freq='A')
data = pd.DataFrame(np.random.normal(size=(len(idx),2)),index=idx)
fig,ax = plt.subplots(1,2,figsize=(10,5))
data.loc[:,0].plot(ax=ax[0])
data.iloc[9:,1].plot(ax=ax[1])
ax[1].xaxis.set_major_locator(mpl.ticker.MultipleLocator(5))
plt.show()
idx = range(2000,2021)
The workaround I know is to convert the PeriodIndex to DatetimeIndex and then to an array of datetime.datetimeobjects and use plt.plot_date() to plot and mpl.dates.YearLocator(5) to format. This seems overly complicated.
Related
import pandas as pd
from datetime import datetime
import matplotlib.pyplot as plt
import numpy as np
x=pd.date_range(end=datetime.today(),periods=150,freq='W').to_pydatetime().tolist()
x_1 = np.random.rand(150)
x_2 = np.random.rand(150)/2
fig = plt.figure(figsize=(10,6),dpi=100)
ax=fig.add_subplot(111)
ax.bar(x,x_1,label='x_1')
ax.bar(x,x_2,label='x_2',bottom=x_1)
plt.legend()
plt.show()
The above code will provide this stacked bar chart.
stacked_chart1
Because the x-axis are specified as dates with 1 week apart, the distance between bars are very large.
I would like to change the chart so that the bars are next to each other with no space like the picture below.
x=np.arange(150)
x_1 = np.random.rand(150)
x_2 = np.random.rand(150)/2
fig = plt.figure(figsize=(10,6),dpi=100)
ax=fig.add_subplot(111)
ax.bar(x,x_1,label='x_1')
ax.bar(x,x_2,label='x_2',bottom=x_1)
plt.legend()
plt.show()
stacked_chart2
Except numbers as x-axis, I would still want to keep the dates in chart 1. I am wondering is there a way to do that? Thanks!!
The reason for the difference is that matplotlib will try to simplify the x-axis when you pass a datetime, because usually you cannot fit every date in the x-ticks. It doesn't try this for int or string types, which is why your second sample looks normal.
However I'm unable to figure out why in this particular example why the spacing is so odd. I looked at this post to no avail.
In any case, there are other plotting modules that tend to handle dates a little more elegantly.
import pandas as pd
from datetime import datetime
import plotly.express as px
import numpy as np
x=pd.date_range(end=datetime.today(),periods=150,freq='W').tolist()
x_1 = np.random.rand(150)
x_2 = np.random.rand(150)/2
df = pd.DataFrame({
'date':x,
'x_1':x_1,
'x_2':x_2}).melt(id_vars='date')
px.bar(df, x='date', y='value',color='variable')
Output
I have a situation with my data. I like the behaviour of .plot() over a data frame. But sometimes it doesn't work, because the frequency of the time index is not an integer.
But reproducing the plot in matplotlib is OK. Just ugly.
The part that bother me the most is the settings of the x axis. The tick frequency and the limits. Is there any easy way that I can reproduce this behaviour in matplotlib?
import numpy as np
import pandas as pd
import matplotlib.pyplot as plt
# Create Data
f = lambda x: np.sin(0.1*x) + 0.1*np.random.randn(1,x.shape[0])
x = np.arange(0,217,0.001)
y = f(x)
# Create DataFrame
data = pd.DataFrame(y.transpose(), columns=['dp'], index=None)
data['t'] = pd.date_range('2021-01-01 14:32:09', periods=len(data['dp']),freq='ms')
data.set_index('t', inplace=True)
# Pandas plot()
data.plot()
# Matplotlib plot (ugly x-axis)
plt.plot(data.index,data['dp'])
EDIT: Basically, what I want to achieve is a similar spacing in the xtics labels, and the tight margin adjust of the values. Legends and axis title, I can do them
Pandas output
Matplotlib output
Thanks
You can use some matplotlib date utilities:
Figure.autofmt_xdate() to unrotate and center the date labels
Axis.set_major_locator() to change the interval to 1 min
Axis.set_major_formatter() to reformat as %H:%M
fig, ax = plt.subplots()
ax.plot(data.index, data['dp'])
import matplotlib.dates as mdates
fig.autofmt_xdate(rotation=0, ha='center')
ax.xaxis.set_major_locator(mdates.MinuteLocator(interval=1))
ax.xaxis.set_major_formatter(mdates.DateFormatter('%H:%M'))
# uncomment to remove the first `xtick`
# ax.set_xticks(ax.get_xticks()[1:])
import pandas as pd
import matplotlib.pyplot as plt
from datetime import datetime
corona_data = pd.read_csv("서울시 코로나19 확진자 현황 csv.csv", encoding="cp949")
confirmed_dates = corona_data["확진일"]
confirmed_date = [datetime.strptime(date, "%Y-%m-%d") for date in confirmed_dates]
corona_data["확진일"]= confirmed_date
plt.rc('font', family='Malgun Gothic')
corona_data["확진일"].plot(title="확진일 별 확진자 추이")
plt.show()
This plot show x-axis is just number and y-axis is date but I wanna change x-axis is date and y-axis is number how can I solve it?
If your data is in a dataframe, I recommend using Seaborn to visualize it. It has a great API that allows you to plot elements of your dataframe by referening column names. Here is a toy example:
import seaborn as sns
import matplotlib.pyplot as plt
import pandas as pd
# Load data
df = pd.read_csv(...)
# Plot scatter plot
sns.scatter(x='col_1', y='col_2', data=df)
plt.show()
Check out the Seaborn documentation for more
The problem seems to be that your dataframe only contains one dataset which are the dated. You could add a column that contains the row numbers and then select what you want to have on x and y axis by passing the column name to the plot function:
import matplotlib.pyplot as plt
from datetime import datetime
corona_data = pd.read_csv("서울시 코로나19 확진자 현황 csv.csv", encoding="cp949")
confirmed_dates = corona_data["확진일"]
confirmed_date = [datetime.strptime(date, "%Y-%m-%d") for date in confirmed_dates]
corona_data["확진일"]= confirmed_date
# now add the numbers to the dataset
corona_data["numbers"]=[i for i in len(confirmed_dates)]
plt.rc('font', family='Malgun Gothic')
# and tell the plot function that you want "확진일" as x ans "numbers" as y axis
corona_data.plot("확진일","numbers",title="확진일 별 확진자 추이")
plt.show()```
I have a distribution that changes over time for which I would like to plot a violin plot for each time step side-by-side using seaborn. My initial attempt failed as violinplot cannot handle a np.ndarray for the y argument:
import numpy as np
import seaborn as sns
time = np.arange(0, 10)
samples = np.random.randn(10, 200)
ax = sns.violinplot(x=time, y=samples) # Exception: Data must be 1-dimensional
The seaborn documentation has an example for a vertical violinplot grouped by a categorical variable. However, it uses a DataFrame in long format.
Do I need to convert my time series into a DataFrame as well? If so, how do I achieve this?
A closer look at the documentation made me realize that omitting the x and y argument altogether leads to the data argument being interpreted in wide-form:
import numpy as np
import seaborn as sns
import matplotlib.pyplot as plt
samples = np.random.randn(20, 10)
ax = sns.violinplot(data=samples)
plt.show()
In the violin plot documentation it says that the input x and y parameters do not have to be a data frame, but they have a restriction of having the same dimension. In addition, the variable y that you created has 10 rows and 200 columns. This is detrimental when plotting the graphics and causes a dimension problem.
I tested it and this code has no problems when reading the python file.
import numpy as np
import seaborn as sns
import pandas as pd
time = np.arange(0, 200)
samples = np.random.randn(10, 200)
for sample in samples:
ax = sns.violinplot(x=time, y=sample)
You can then group the resulting graphs using this link:
https://python-graph-gallery.com/199-matplotlib-style-sheets/
If you want to convert your data into data frames it is also possible. You just need to use pandas.
example
import pandas as pd
x = [1,2,3,4]
df = pd.DataFrame(x)
I am plotting time series using pandas .plot() and want to see every month shown as an x-tick.
Here is the dataset structure
Here is the result of the .plot()
I was trying to use examples from other posts and matplotlib documentation and do something like
ax.xaxis.set_major_locator(
dates.MonthLocator(revenue_pivot.index, bymonthday=1,interval=1))
But that removed all the ticks :(
I also tried to pass xticks = df.index, but it has not changed anything.
What would be the rigth way to show more ticks on x-axis?
No need to pass any args to MonthLocator. Make sure to use x_compat in the df.plot() call per #Rotkiv's answer.
import pandas as pd
import numpy as np
import matplotlib.pylab as plt
import matplotlib.dates as mdates
df = pd.DataFrame(np.random.rand(100,2), index=pd.date_range('1-1-2018', periods=100))
ax = df.plot(x_compat=True)
ax.xaxis.set_major_locator(mdates.MonthLocator())
plt.show()
formatted x-axis with set_major_locator
unformatted x-axis
You could also format the x-axis ticks and labels of a pandas DateTimeIndex "manually" using the attributes of a pandas Timestamp object.
I found that much easier than using locators from matplotlib.dates which work on other datetime formats than pandas (if I am not mistaken) and thus sometimes show an odd behaviour if dates are not converted accordingly.
Here's a generic example that shows the first day of each month as a label based on attributes of pandas Timestamp objects:
import numpy as np
import pandas as pd
import matplotlib.pyplot as plt
# data
dim = 8760
idx = pd.date_range('1/1/2000 00:00:00', freq='h', periods=dim)
df = pd.DataFrame(np.random.randn(dim, 2), index=idx)
# select tick positions based on timestamp attribute logic. see:
# https://pandas.pydata.org/pandas-docs/stable/generated/pandas.Timestamp.html
positions = [p for p in df.index
if p.hour == 0
and p.is_month_start
and p.month in range(1, 13, 1)]
# for date formatting, see:
# https://docs.python.org/2/library/datetime.html#strftime-and-strptime-behavior
labels = [l.strftime('%m-%d') for l in positions]
# plot with adjusted labels
ax = df.plot(kind='line', grid=True)
ax.set_xlabel('Time (h)')
ax.set_ylabel('Foo (Bar)')
ax.set_xticks(positions)
ax.set_xticklabels(labels)
plt.show()
yields:
Hope this helps!
The right way to do that described here
Using the x_compat parameter, it is possible to suppress automatic tick resolution adjustment
df.A.plot(x_compat=True)
If you want to just show more ticks, you can also dive deep into the structure of pd.plotting._converter:
dai = ax.xaxis.minor.formatter.plot_obj.date_axis_info
dai['fmt'][dai['fmt'] == b''] = b'%b'
After plotting, the formatter is a TimeSeries_DateFormatter and _set_default_format has been called, so self.plot_obj.date_axis_info is not None. You can now manipulate the structured array .date_axis_info to be to your liking, namely contain less b'' and more b'%b'
Remove tick labels:
ax = df.plot(x='date', y=['count'])
every_nth = 10
for n, label in enumerate(ax.xaxis.get_ticklabels()):
if n % every_nth != 0:
label.set_visible(False)
Lower every_nth to include more labels, raise to keep fewer.