Develop Reference

vscode python avoid indent of multiline string

So here is an example of a multiline string in vscode/python:
Cursor is after the p , and then you press enter, and end up like this:
i.e. the string ends up indented, which seems what you almost never want - why have an arbitratly amount of whitespace on the next line of this string ?
Is there any way change this in vscode, i.e. for multiline strings, it should end up with this:

I think this problem is related to different coding styles of different people.
For example,
def example(x):
if x:
a = '''
This is help
'''
def example(x):
if x:
a = '''This is help
'''
The automatic indenting of vscode line breaks is based on code blocks. If you want Vscode can identify multiline string, I think it would be better to submit future request in github. I've submitted this issue for you.

I am not 100% sure if what OP meant is just to refer to the indentation in the editor (namely, VSC) or if, by this:
i.e. the string ends up indented, which seems what you almost never want - why have an arbitrary amount of white space on the next line of this string?
...they also meant to refer to the actual output of the multi-line string,
(or also, just in case anybody else finds this post looking for a way to avoid this affecting the actual output of the multi-line string), I'd like to add as a complementary answer (cannot comment yet) that this was already beautifully answered here.
If that's the case and you're reading this for that reason, in short, all you want is to import the standard lib 'inspect' and post-process your string with it, using the cleandoc method.
Without breaking the indentation in your IDE, this method makes sure to give you the string output you actually expected:
All leading whitespace is removed from the first line. Any leading whitespace that can be uniformly removed from the second line onwards is removed. Empty lines at the beginning and end are subsequently removed. Also, all tabs are expanded to spaces.
(From the docs link above)
Hope that helps anyone.

Python 3.6 - How Do I Format Variables and Literals In A .Write Statement?

... (Be advised the actual values in the data below are not static nor that important, but are only an example.)
Specifically, I am needing assistance on understanding what I did wrong with the format and syntax and what is the proper way. Anyway, here goes.
I need the following Python 3.6 code...
stella = open(stellocation + "\\scripts\\sh4.ssc",'w')
stella.write("core.setDate(\""+date+"T"+time+":00", "UTC""); ")\n)
stella.write("core.setObserverLocation("+longitude +", "+latitude+", 6, 0, "SH4 Navigation Point, ""+ ocean +", "earth")");
stella.close()
...to produce this text...
core.setDate("1943-01-01T10:01:00","UTC");
core.setObserverLocation(-161.605158333, 19.2008553333, 6, 0, "USS Perch (Pacific Ocean)", "Earth");
...I keep getting this error...
File "C:\DAATAPOND\Python Scripts\SH4toStellarium.py", line 54
stella.write("core.setDate(\""+date+"T"+time+":00"") ")\n)
^
SyntaxError: unexpected character after line continuation character
I have been researching and experimenting for three days without success. I have read and attempted to digest a number of websites on the ".write" function statement. They tended to be arcane and left me somewhat confused. I decided it was time to seek help. :)
Please let me know if I can be of any assistance.
Take care,
Calvin
PS - This is my first question on StackOverflow. Please let me know if anything should be different.

Use an f-string to make variable substitution easier. And if you want to put literal double-quotes in the string, wrap it in single quotes so you don't need to escape them.
The syntax error is because you put \n outside the string and added an extra ).
stella.write(f'core.setDate("{date}T{time}:00","UTC");\n')
stella.write(f'core.setObserverLocation({longitude}, {latitude}, 6, 0, "SH4 Navigation Point, ({ocean})", "Earth");')

It should be something like this:
stella.write("core.setDate(\""+date+"T"+time+":00"") \n")
Where you went wrong: You were using an extra bracket at the end of the above line and \n was outside the quoted string.

Removing a control character using Python

I have a script that processes the output of a command (the aws help cli command).
I step through the output line-by-line and don't start the actual real parsing until I encounter the text "AVAILABLE COMMANDS" at which point I set a flag to true and start further processing on each line.
I've had this working fine - BUT on Ubuntu we encounter a problem which is this :
The CLI highlights the text in a way I have not seen before:
The output is very long, so I've grep'd the particular line in question - see below:
># aws ec2 help | egrep '^A'
>AVAILABLE COMMANDS
># aws ec2 help | egrep '^A' | cat -vet
>A^HAV^HVA^HAI^HIL^HLA^HAB^HBL^HLE^HE C^HCO^HOM^HMM^HMA^HAN^HND^HDS^HS$
What I haven't seen before is that each letter that is highligted is in the format X^HX.
I'd like to apply a simple transformation of the type X^HX --> X (for all a-zA-Z).
What have I tried so far:
well my workaround is this - first I remove control characters like this:
String = re.sub(r'[\x00-\x1f\x7f-\x9f]','',String)
but I still have to search for 'AAVVAAIILLAABBLLEE' which is totally ugly. I considered using a further regex to turn doubles to singles but that will catch true doubles and get messy.
I started writing a function with an iteration across a constructed list of alpha characters to translate as described, and I used hexdump to try to figure out the exact \x code of the control characters in question but could not get it working - I could remove H but not the ^.
I really don't want to use any additional modules because I want to make this available to people without them having to install extras. In conclusion I have a workaround that is quite ugly, but I'm sure someone must know a quick an easy way to do this translation. It's odd that it only seems to show up on Ubuntu.

After looking at this a little further I was able to put in place a solution:
from string import ascii_lowercase
from string import ascii_uppercase
def RemoveUbuntuHighlighting(String):
for Char in ascii_uppercase + ascii_lowercase:
Match = Char + '\x08' + Char
String = re.sub(Match,Char,String)
return(String)
I'm still a little confounded to see characters highlighted in the format (X\x08X), the arrangement does seem to repeat the same information unnecessarily.
The other thing I would advise to anyone not familiar with reading hexcode is that each pair of hexes is swapped around with respect to the order of their appearance.

A much simpler and more reliable fix is to replace a backspace and duplicate of any character.
I have also augmented this to handle underscores using the same mechanism (character, backspace, underscore).
String = re.sub(r'(.)\x08(\1|_)', r'\1', String)
Demo: https://ideone.com/yzwd2V
This highlighting was standard back when output was to a line printer; backspacing and printing the same character again would add pigmentation to produce boldface. (Backspacing and printing an underscore would produce underlining.)
Probably the AWS CLI can be configured to disable this by setting the TERM variable to something like dumb. There is also a utility col which can remove this formatting (try col-b; maybe see also colcrt). Though perhaps really the best solution would be to import the AWS Python code and extract the help message natively.

EOL SyntaxError in python [duplicate]

I have the above-mentioned error in s1="some very long string............"
Does anyone know what I am doing wrong?

You are not putting a " before the end of the line.
Use """ if you want to do this:
""" a very long string ......
....that can span multiple lines
"""

I had this problem - I eventually worked out that the reason was that I'd included \ characters in the string. If you have any of these, "escape" them with \\ and it should work fine.

(Assuming you don't have/want line breaks in your string...)
How long is this string really?
I suspect there is a limit to how long a line read from a file or from the commandline can be, and because the end of the line gets choped off the parser sees something like s1="some very long string.......... (without an ending ") and thus throws a parsing error?
You can split long lines up in multiple lines by escaping linebreaks in your source like this:
s1="some very long string.....\
...\
...."

In my situation, I had \r\n in my single-quoted dictionary strings. I replaced all instances of \r with \\r and \n with \\n and it fixed my issue, properly returning escaped line breaks in the eval'ed dict.
ast.literal_eval(my_str.replace('\r','\\r').replace('\n','\\n'))
.....

I faced a similar problem. I had a string which contained path to a folder in Windows e.g. C:\Users\ The problem is that \ is an escape character and so in order to use it in strings you need to add one more \.
Incorrect: C:\Users\
Correct: C:\\Users\\

You can try this:
s = r'long\annoying\path'

I too had this problem, though there were answers here I want to an important point to this
after
/ there should not be empty spaces.Be Aware of it

I also had this exact error message, for me the problem was fixed by adding an " \"
It turns out that my long string, broken into about eight lines with " \" at the very end, was missing a " \" on one line.
Python IDLE didn't specify a line number that this error was on, but it red-highlighted a totally correct variable assignment statement, throwing me off. The actual misshapen string statement (multiple lines long with " \") was adjacent to the statement being highlighted. Maybe this will help someone else.

In my case, I use Windows so I have to use double quotes instead of single.
C:\Users\Dr. Printer>python -mtimeit -s"a = 0"
100000000 loops, best of 3: 0.011 usec per loop

In my case with Mac OS X, I had the following statement:
model.export_srcpkg(platform, toolchain, 'mymodel_pkg.zip', 'mymodel.dylib’)
I was getting the error:
File "<stdin>", line 1
model.export_srcpkg(platform, toolchain, 'mymodel_pkg.zip', 'mymodel.dylib’)
^
SyntaxError: EOL while scanning string literal
After I change to:
model.export_srcpkg(platform, toolchain, "mymodel_pkg.zip", "mymodel.dylib")
It worked...
David

In my case, I forgot (' or ") at the end of string. E.g 'ABC' or "ABC"

I was getting this error in postgresql function. I had a long SQL which I broke into multiple lines with \ for better readability. However, that was the problem. I removed all and made them in one line to fix the issue. I was using pgadmin III.

Your variable(s1) spans multiple lines. In order to do this (i.e you want your string to span multiple lines), you have to use triple quotes(""").
s1="""some very long
string............"""

In this case, three single quotations or three double quotations both will work!
For example:
"""Parameters:
...Type something.....
.....finishing statement"""
OR
'''Parameters:
...Type something.....
.....finishing statement'''

I had faced the same problem while accessing any hard drive directory.
Then I solved it in this way.
import os
os.startfile("D:\folder_name\file_name") #running shortcut
os.startfile("F:") #accessing directory
The picture above shows an error and resolved output.

All code below was tested with Python 3.8.3
Simplest -- just use triple quotes.
Either single:
long_string = '''some
very
long
string
............'''
or double:
long_string = """some
very
long
string
............"""
Note: triple quoted strings retain indentation, it means that
long_string = """some
very
long
string
............"""
and
long_string = """some
very
long
string
............"""
or even just
long_string = """
some
very
long
string
............"""
are not the same.
There is a textwrap.dedent function in standard library to deal with this, though working with it is out of question's scope.
You can, as well, use \n inside a string, residing on single line:
long_string = "some \nvery \nlong \nstring \n............"
Also, if you don't need any linefeeds (i.e. newlines) in your string, you can use \ inside regular string:
long_string = "some \
very \
long \
string \
............"

Most previous answers are correct and my answer is very similar to aaronasterling, you could also do 3 single quotations
s1='''some very long string............'''

[Python]How to deal with a string ending with one backslash?

I'm getting some content from Twitter API, and I have a little problem, indeed I sometimes get a tweet ending with only one backslash.
More precisely, I'm using simplejson to parse Twitter stream.
How can I escape this backslash ?
From what I have read, such raw string shouldn't exist ...
Even if I add one backslash (with two in fact) I still get an error as I suspected (since I have a odd number of backslashes)
Any idea ?
I can just forget about these tweets too, but I'm still curious about that.
Thanks : )

Prepending the string with r (stands for "raw") will escape all characters inside the string. For example:
print r'\b\n\\'
will output
\b\n\\
Have I understood the question correctly?

I guess you are looking a method similar to stripslashes in PHP. So, here you go:
Python version of PHP's stripslashes

You can try using raw strings by prepending an r (so nothing has to be escaped) to the string or re.escape().
I'm not really sure what you need considering I haven't seen the text of the response. If none of the methods you come up with on your own or get from here work, you may have to forget about those tweets.

Unless you update your question and come back with a real problem, I'm asserting that you don't have an issue except confusion.
You get the string from the Tweeter API, ergo the string does not show up in your code. “Raw strings” exist only in your code, and it is “raw strings” in code that can't end in a backslash.
Consider this:
def some_obscure_api():
"This exists in a library, so you don't know what it does"
return r"hello" + "\\" # addition just for fun
my_string = some_obscure_api()
print(my_string)
See? my_string happily ends in a backslash and your code couldn't care less.