Have a problem, try to do simple gallery in django, but when i tried to check how it looks, picture doesn't show anything only title name and there is at terminal "Error 404 not found". Can't realise what actually is wrong... Please help. thx...
Not Found: /media/images/example.png
[16/Mar/2016 17:59:17] "GET /media/images/example.png HTTP/1.1" 404 2168
models.py
class Album(models.Model):
title = models.CharField("Название альбома", max_length=100)
slug = models.SlugField("Ссылка на альбом", max_length=100, unique=True)
img = models.ImageField("Изображение альбома", upload_to='images',
help_text='Размер изображения 200px на 200px')
created_date = models.DateTimeField(default=timezone.now)
published_date = models.DateTimeField(blank=True, null=True)
class Photo(models.Model):
title = models.CharField("Название фотографии", max_length=100)
album = models.ForeignKey(Album, related_name='Альбом')
img = models.ImageField("Фото", upload_to='images',
help_text='Желательно не большой размер')
urls.py - app
from django.conf.urls import url
from django.conf import settings
from django.conf.urls.static import static
from django.views.generic import ListView, DetailView
from .models import Album, Photo
urlpatterns = [
url(r'^$', ListView.as_view(
model=Album,
context_object_name='my_album',
template_name='gallery/album.html'),
name='gallery'
),
url(r'^(?P<slug>[-\w]+)/$', DetailView.as_view(
model=Album,
context_object_name='photos',
template_name='gallery/photo.html'),
name='photo'
),
]
if settings.DEBUG:
urlpatterns += static(settings.MEDIA_URL,
document_root=settings.MEDIA_ROOT)
urls.py - project
from django.conf.urls import url, include
from django.contrib import admin
urlpatterns = [
url(r'^admin/', admin.site.urls),
url(r'^gallery/', include('gallery.urls')),
]
settings.py
STATIC_URL = '/static/'
STATIC_ROOT = os.path.join(BASE_DIR, 'static/')
MEDIA_URL = '/media/'
MEDIA_ROOT = os.path.join(BASE_DIR, 'media/')
template
{% extends "gallery/base.html" %}
{% load thumbnail %}
{% block title %}My Gallery{% endblock %}
{% block text %}
{% for album in my_album %}
<a href='{{ album.slug }}'>
<img src="{{ album.img.url}}" alt="{{ album.title }}">
<!-- {% thumbnail album.img "200x200" crop="center" as im %}
<img src="{{ im.url }}" alt="{{ im.title }}" width="{{ im.width }}"
height="{{ im.height }}">
{% endthumbnail %} -->
</a>
{% endfor %}
{% endblock %}
ProjectStructure
ProjectFolder/
app/
migrations/
static/
templates/
admin.py
models.py
..
project/
settings.py
urls.py
..
media/
images/
example.png
my_env/
manage.py
if in setting.py i do MEDIA_URL = 'media/images' it will work, but only for album template if you will go to see album photos, there photo won't shows too with the same error... Actually i can't understand and realise how to do access to folder media and just bring any of content placed here what i need. Help me...
Related
I have such models.py file
class Product(models.Model):
CATEGORIES = {
('Computer', 'Комп\'ютер'),
('Smartphone', 'Смартфон')
}
photo = models.ImageField(upload_to='images/', blank=True)
title = models.CharField(max_length=128, blank=False)
description = models.CharField(max_length=5000, blank=False)
price = models.PositiveIntegerField(blank=False)
category = models.CharField(max_length=30, choices=CATEGORIES)
count = models.PositiveIntegerField(blank=False)
In settings.py i DON'T have media variables/dirs
Also i try to show images in such way
{% extends 'base.html' %}
{% block title %}Каталог{% endblock %}
{% block content %}
{% for i in products %}
<img src="{ static i.photo.url }">
{{i.title}}
{% endfor %}
{% endblock %}
Result:
I add my model objects in Django Admin
please see below configuration, have you done?
urls.py
from django.conf import settings
from django.conf.urls.static import static
urlpatterns = [
# urls/path
]+ static(settings.MEDIA_URL, document_root=settings.MEDIA_ROOT)
settings.py
MEDIA_ROOT = os.path.join(BASE_DIR, 'media')
MEDIA_URL = '/media/'
your HTML file
{% if i.photo %}
<img src="{{ i.photo.url }}">
{% endif %}
You don't need the static tag.
<img src="{{ i.photo.url }}">
You can add like this.
and run the collectstatic command to
<img src="{% static '/logo.png' %}"/>
python manage.py collectstatic
In settings.py i DON'T have media variables/dirs
you have to set MEDIA_ROOT and MEDIA_URL in settings.py and set the URL of each in urls.py because by default, Django stores files locally, using the MEDIA_ROOT and MEDIA_URL settings. The examples below assume that you’re using these defaults.
check the official doc.
step - 1
configure media and static files like this
add this in your settings.py
STATIC_ROOT = BASE_DIR / 'static_cdn'
STATIC_URL = '/static/'
MEDIA_ROOT = BASE_DIR / 'media'
MEDIA_URL = '/media/'
STATICFILES_DIRS = [
BASE_DIR / "static",
]
and add this in your urls.py
from django.conf import settings
from django.conf.urls.static import static
urlpatterns = [
# ... the rest of your URLconf goes here ...
]
if settings.DEBUG:
urlpatterns += static(settings.STATIC_URL, document_root=settings.STATIC_ROOT)
urlpatterns += static(settings.MEDIA_URL, document_root=settings.MEDIA_ROOT)
I only see the file path in the template. I can't see the file itself.
(django 3.x)
settings.py
STATIC_URL = '/static/'
STATICFILES_DIRS = [os.path.join(BASE_DIR, 'static')]
MEDIA_URL = '/media/'
MEDIA_ROOT = os.path.join(BASE_DIR, 'media')
model.py
class EkleModel (models.Model):
aKaydi = models.CharField(max_length=50, verbose_name='A KAYDI')
bKaydi = models.CharField(max_length=50, verbose_name='B KAYDI')
cKaydi = models.CharField(max_length=50, verbose_name='C KAYDI')
upload = models.FileField(upload_to='media/%Y/%m/%d/', verbose_name='DOSYA YÜKLE')
yuklemeTarihi =models.DateTimeField(default =timezone.now)
views.py
def index(request):
girdiler = EkleModel.objects.filter(yuklemeTarihi__lte=timezone.now()).order_by('-yuklemeTarihi')
return render(request, 'sayfalarUygulamasi/index.html', {'girdiler': girdiler})
index.html
<img class="card-img-top" src="girdi.upload">
<h4 class="card-title">{{girdi.aKaydi}}</h4>
<h4 class="card-title">{{girdi.bKaydi}}</h4>
<h4 class="card-title">{{girdi.cKaydi}}</h4>
<h4 class="card-title">{{girdi.yuklemeTarihi}}</h4>
you have to loop through your queryset and .url to the image
{% for girdi in girdiler %}
<img class="card-img-top" src="{{ girdi.upload.url }}">
<h4 class="card-title">{{girdi.aKaydi}}</h4>
<h4 class="card-title">{{girdi.bKaydi}}</h4>
<h4 class="card-title">{{girdi.cKaydi}}</h4>
<h4 class="card-title">{{girdi.yuklemeTarihi}}</h4>
{% endfor %}
<img class="card-img-top" src="girdi.upload.url"> #add url after fieldname like this
try this
{% for girdi in girdiler %}
<img class="card-img-top" src="{{me.upload.url}}">
{% endfor %}
and to your model
class EkleModel (models.Model):
upload = models.FileField(upload_to='image/', null=True, blank=True,FileField)
urls.py
from django.conf import settings
from django.conf.urls.static import static
urlpatterns = [
...
]+ static(settings.STATIC_URL, document_root=settings.STATIC_ROOT)
urlpatterns +=static(settings.MEDIA_URL, document_root=settings.MEDIA_ROOT)
and do migrations
I'm having issues serving images based on the ImageField in Django.
models.py part looks like that:
class Post(models.Model):
author = models.ForeignKey(Author, on_delete=models.CASCADE)
category = models.ManyToManyField(Category)
trip = models.ForeignKey(Trip, on_delete=models.CASCADE)
main_image = models.ForeignKey(Image, on_delete=models.CASCADE, related_name='main_image')
images = models.ManyToManyField(Image, related_name='images')
class Image(models.Model):
name = models.CharField(max_length=32)
picture = models.ImageField(upload_to='pictures/', blank=True)
trip = models.ForeignKey(Trip, on_delete=models.CASCADE)
taken = models.DateTimeField(blank=True, null=True)
uploaded = models.DateTimeField(default=timezone.now)
def __unicode__(self):
return self.name
settings.py contains the MEDIA_URL and MEDIA_ROOT:
# Static files (CSS, JavaScript, Images)
# https://docs.djangoproject.com/en/2.1/howto/static-files/
STATIC_URL = '/static/'
STATIC_ROOT = os.path.join(BASE_DIR, 'static')
MEDIA_URL = '/media/'
MEDIA_ROOT = os.path.join(BASE_DIR, 'media')
Also included what I've found in other SO topics in the urls.py:
from django.contrib import admin
from django.urls import path, include
from django.conf.urls import url
from django.contrib.staticfiles.urls import static, staticfiles_urlpatterns
from django.conf import settings
from markdownx import urls as markdownx
urlpatterns = [
path('admin/', admin.site.urls),
path('', include('blog.urls')),
url(r'^markdownx/', include('markdownx.urls')),
] + staticfiles_urlpatterns() + static(settings.MEDIA_URL, document_root=settings.MEDIA_ROOT)
In the end I put it in the html template like that:
{% extends 'blog/base.html' %}
{% block leftcolumn %}
{% for post in posts %}
<div class="leftcolumn">
<div class="card" style="max-width: 100%">
<h2>{{ post.title }}</h2>
<h5>published: {{ post.published_date }}, by: {{ post.author }}</h5>
<div><img src="{{ post.main_image.url }}"></div>
<p>{{ post.byline }}</p>
</div>
</div>
{% endfor %}
{% endblock %}
But the image is not shown..
I can see the image if I go to the url host:8000/media/pictures/test_photo.jpgand in general I can display images on the page (e.g. within django-markdownx field) but not through ImageField url.
Any ideas what's wrong here?
This line:
<div><img src="{{ post.main_image.url }}"></div>
should be:
<div><img src="{{ post.main_image.picture.url }}"></div>
The reason is your model Image does not have an url method. The method belongs to the ImageField, in this case picture.
To be clear, I have tried researching this on my own but since I'm still very new to Django I am unable to understand the solutions here. I also have read the documentation and I don't understand what I'm doing wrong. I cannot get the images located in the "ad_pictures" directory to display in the HTML.
Here's my code:
settings.py
STATIC_URL = '/static/'
MEDIA_ROOT = os.path.join(BASE_DIR, 'media')
MEDIA_URL = '/media/'
urls.py (project)
from django.conf.urls import url, include
from django.contrib import admin
from django.conf import settings
from django.conf.urls.static import static
urlpatterns = [
url(r'^admin/', admin.site.urls),
url(r'^accounts/', include('accounts.urls')),
url(r'^classifieds/', include('classifieds.urls')),
] +static(settings.MEDIA_URL, document_ROOT=settings.MEDIA_ROOT)
urls.py (classifieds app)
from django.conf.urls import url
from . import views
app_name = 'classifieds'
urlpatterns = [
url(r'^create/', views.create, name='create'),
url(r'^latestads/', views.latestads, name='latestads'),
]
models.py
class Post(models.Model):
title = models.CharField(max_length=150)
price = models.CharField(max_length=100)
body = models.TextField()
pub_date = models.DateTimeField(null=True)
author = models.ForeignKey(User, null=True)
category = models.CharField(max_length=150, null=True)
picture = models.ImageField(upload_to='ad_pictures', default='')
latestads.html
{% for post in posts.all %}
<div class="advertisements">
<div class="a-title">
<h3>{{ post.title }}</h3>
</div>
<div class="a-image">
<img src="{{ post.picture.url }}">
</div>
<div class="a-content">
<p>{{ post.body }}</p>
</div>
<div class="a-date">
<p>{{ post.pub_date }} by {{ post.author }}</p>
</div>
</div>
<img src="{{ post.image.url }}">
{% endfor %}
Picture of directory structure:
here
Html output:
here
I'm sure part of the problem is the "post.picture.url" in the HTML.
Any insight is greatly appreciated.
Thanks
urlpatterns = [
url(r'^admin/', admin.site.urls),
url(r'^accounts/', include('accounts.urls')),
url(r'^classifieds/', include('classifieds.urls')),
] +static(settings.MEDIA_URL, document_root=settings.MEDIA_ROOT)
please change document_ROOT to document_root
I hope you can help me withmy Django project. I am able to upload an images under a media_cdn folder, inside a folder based on the name of the slug. The problem occurs when I try to display the image inside my post list and post.
Can you please have a look at my code and offer a solution. I spent hours trying to get it to work. Please help.
settings.py
STATIC_URL = '/static/'
STATIC_ROOT = os.path.join(BASE_DIR, 'static/')
MEDIA_URL = "/media/"
MEDIA_ROOT = os.path.join(BASE_DIR, 'media_cdn/')
models.py
def upload_location(instance, filename):
return "%s/%s" %(instance.slug, filename)
class Post(models.Model):
category = models.ForeignKey(Category)
title = models.CharField(max_length=250)
slug = models.SlugField(max_length=250, unique=True)
image = models.ImageField(upload_to=upload_location,
null=True,
blank=True,
width_field="width_field",
height_field="height_field")
height_field = models.IntegerField(default=0)
width_field = models.IntegerField(default=0)
body = models.TextField()
date = models.DateTimeField()
updated = models.DateTimeField(auto_now=True)
postlist.html
{% block content %}
{% for post in posts %}
<div class="container w3-card-4">
{% if post.image %}
<img src="{{ post.instance.image.url }}">
{% endif %}
...
post.html
{% block content %}
<div class="row">
<div class="container w3-card-4">
{% if instance.image %}
<img src= "{{ instance.image.url }}" class="img-responsive">
{% endif %}
...
url.py
from django.conf.urls import include, url
from django.contrib import admin
from django.conf.urls.static import static
from django.conf import settings
urlpatterns = [
url(r'^admin/', admin.site.urls),
url(r'^', include('personal.urls')),
url(r'^blog/', include('blog.urls', namespace='blog', app_name='blog')),
]
if settings.DEBUG:
urlpatterns += static(settings.STATIC_URL, document_root=settings.STATIC_ROOT)
urlpatterns += static(settings.MEDIA_URL, document_root=settings.MEDIA_ROOT)
I don't know what else to try to call that image from the folder. Any advice would be greatly appreciated. Thank you!
Use post.image.url instead of post.instance.image.url. Check the documentation.
ImageField inherits all the attributes of the FileField which includes url.