Now I'm working in a project that going to allow the user to send HTML files an E-mails . The problem here is : I made a script that going to allow him to send the HTML files as an E-mail but the HTML file must be wirtten inside the code it self , here is the question : How can I let him to chose pre-made HTML to be sent instead of integrating it into the code , and here is my current code
import smtplib
from email.mime.multipart import MIMEMultipart
from email.mime.text import MIMEText
# me == my email address
# you == recipient's email address
me = "Sender mail"
you = "reciver mail"
# Create message container - the correct MIME type is multipart/alternative.
msg = MIMEMultipart('alternative')
msg['Subject'] = "HR report"
msg['From'] = me
msg['To'] = you
# Create the body of the message (a plain-text and an HTML version).
text = "Hi!\nHow are you?\nHere is the link you wanted:\nhttp://www.python.org"
html = """\
<html>
<head></head>
<body>
<p>Hi!<br>
How are you?<br>
Here is the link you wanted.
</p>
</body>
</html>
"""
# Record the MIME types of both parts - text/plain and text/html.
part1 = MIMEText(text, 'plain')
part2 = MIMEText(html, 'html')
# Attach parts into message container.
# According to RFC 2046, the last part of a multipart message, in this case
# the HTML message, is best and preferred.
msg.attach(part1)
msg.attach(part2)
# Send the message via local SMTP server.
mail = smtplib.SMTP('smtp.gmail.com', 587)
mail.ehlo()
mail.starttls()
mail.login(me, 'the Password ')
mail.sendmail(me, you, msg.as_string())
mail.quit()
Looking for a way to send the contents of a HTML file that is generated once a day using this script below. Running into road blocks getting it to work. I can sent HTML and see it, just not sure how to print out the contents of the file and send it.
File Format is export_MM-DD-YY.html
Id rather have it display the contents of the HTML in the email not the HTML file.
#!/usr/bin/env python3
import smtplib
import config
from email.mime.multipart import MIMEMultipart
from email.mime.text import MIMEText
filename = 'name_of_file'
# Read a file and encode it into base64 format
fo = open(filename, "rb")
filecontent = fo.read()
encodedcontent = base64.b64encode(filecontent) # base64
filename = os.path.basename(filename)
# me == my email address
# you == recipient's email address
me = "From#example.com"
you = "TO#example.com"
subject = 'Test Subject v5'
# Create message container - the correct MIME type is multipart/alternative.
msg = MIMEMultipart('alternative')
msg['Subject'] = subject
msg['From'] = me
msg['To'] = you
# Create the body of the message (a plain-text and an HTML version).
text = "Hi!\nHow are you?\nHere is the link you wanted:\nhttps://www.python.org"
html = """\
**INSERT HTML FILE CONTENTS HERE...**
"""
# Record the MIME types of both parts - text/plain and text/html.
part1 = MIMEText(text, 'plain')
part2 = MIMEText(html, 'html')
# Attach parts into message container.
# According to RFC 2046, the last part of a multipart message, in this case
# the HTML message, is best and preferred.
msg.attach(part1)
msg.attach(part2)
# Send the message via local SMTP server.
server = smtplib.SMTP('smtp.gmail.com:587')
server.starttls()
server.login(config.EMAIL_ADDRESS, config.PASSWORD)
server.sendmail(me,you,msg.as_string())
server.quit()
So I think I got it working but im sure theres more code here than is needed (If anyone sees anything I can clean up?)
#!/usr/bin/env python3
import smtplib
import os
import config
from email.mime.multipart import MIMEMultipart
from email.mime.text import MIMEText
raport_file = open('export.html','rb')
alert_msg = MIMEText(raport_file.read(),"html", "utf-8")
# me == my email address
# you == recipient's email address
me = "From#example.com"
you = "TO#example.com"
subject = 'Test Subject v5'
# Create message container - the correct MIME type is multipart/alternative.
msg = MIMEMultipart('alternative')
msg['Subject'] = subject
msg['From'] = me
msg['To'] = you
# Create the body of the message (a plain-text and an HTML version).
text = "Hi!\nHow are you?\nHere is the link you wanted:\nhttps://www.python.org"
html = """\
"""
# Record the MIME types of both parts - text/plain and text/html.
part1 = MIMEText(text, 'plain')
part2 = MIMEText(html, 'html')
# Attach parts into message container.
# According to RFC 2046, the last part of a multipart message, in this case
# the HTML message, is best and preferred.
msg.attach(part1)
msg.attach(part2)
# Send the message via local SMTP server.
server = smtplib.SMTP('smtp.gmail.com:587')
server.starttls()
server.login(config.EMAIL_ADDRESS, config.PASSWORD)
server.sendmail(me,you,alert_msg.as_string())
server.quit()
You're really close. Three changes:
Don't open the html file in binary mode. Read the file directly into the html string
report_file = open('export.html')
html = report_file.read()
remove the subsequent assignment to html var
html = """\
"""
send the msg object as constructed
server.sendmail(me, you, msg.as_string())
That worked for me. Also keep in mind that by default gmail settings may not allow your script to send mail. If so you'll need to update your settings to allow "insecure" (meaning non-Google) apps to send mail.
As I'm still not an expert in python, I want to cat each changed xml file within a transaction within a commit to an svn repository and do something. In this case I check if an xml-file exists an then send out an email. For this I use pysvn and lxml to parse for the corresponding tag. This works but just for only one file. If I have 2 files with the tag I dows not work. Furthermore it makes sense, if there are more than 1 xml file which has the tag "Needs Review" to send out just 1 email with a list of the corresponding files. Does anybody have an idea how to change the "for changedFile..." to realize this?
#!/bin/env python
import os
import sys
import subprocess
# Import pysvn libs to act with svn
import pysvn
# Import smtplib for the actual sending function
import smtplib
# Import the email modules we'll need
from email.mime.text import MIMEText
from email.mime.multipart import MIMEMultipart
from email.mime.text import MIMEText
# Use lxml lib to parse tree for status
from lxml import html
#tmpFile = open('D:\my.log', 'w')
repository = sys.argv[1]
transactionId = sys.argv[2]
transaction = pysvn.Transaction(repository, transactionId, is_revision=True)
for changedFile in transaction.changed():
tree = html.fromstring(transaction.cat(changedFile))
if tree.xpath('//topic/#status')[0] == "Needs Review":
#tmpFile.writelines("This topic needs review")
# me == my email address
# you == recipient's email address
me = "test#example.com"
you = "test2#example.com"
# Create message container - the correct MIME type is multipart/alternative.
msg = MIMEMultipart('alternative')
msg['Subject'] = "TODO Review JiveX Doku"
msg['From'] = me
msg['To'] = you
# Create the body of the message (a plain-text and an HTML version).
text = "Some Text and please check this File."
html = """\
<html>
<head></head>
<body>
<p>The following commited Files need a Review.
Please Check.<br>
Here is the List of Files with links: file 1<br>file 2.
</p>
</body>
</html>
"""
# Record the MIME types of both parts - text/plain and text/html.
part1 = MIMEText(text, 'plain')
part2 = MIMEText(html, 'html')
# Attach parts into message container.
# According to RFC 2046, the last part of a multipart message, in this case
# the HTML message, is best and preferred.
msg.attach(part1)
msg.attach(part2)
# Send the message via local SMTP server.
s = smtplib.SMTP('192.168.1.20')
# sendmail function takes 3 arguments: sender's address, recipient's address
# and message to send - here it is sent as one string.
s.sendmail(me, you, msg.as_string())
s.quit()
How to send HTML content in email using Python? I can send simple texts.
From Python v2.7.14 documentation - 18.1.11. email: Examples:
Here’s an example of how to create an HTML message with an alternative plain text version:
#! /usr/bin/python
import smtplib
from email.mime.multipart import MIMEMultipart
from email.mime.text import MIMEText
# me == my email address
# you == recipient's email address
me = "my#email.com"
you = "your#email.com"
# Create message container - the correct MIME type is multipart/alternative.
msg = MIMEMultipart('alternative')
msg['Subject'] = "Link"
msg['From'] = me
msg['To'] = you
# Create the body of the message (a plain-text and an HTML version).
text = "Hi!\nHow are you?\nHere is the link you wanted:\nhttp://www.python.org"
html = """\
<html>
<head></head>
<body>
<p>Hi!<br>
How are you?<br>
Here is the link you wanted.
</p>
</body>
</html>
"""
# Record the MIME types of both parts - text/plain and text/html.
part1 = MIMEText(text, 'plain')
part2 = MIMEText(html, 'html')
# Attach parts into message container.
# According to RFC 2046, the last part of a multipart message, in this case
# the HTML message, is best and preferred.
msg.attach(part1)
msg.attach(part2)
# Send the message via local SMTP server.
s = smtplib.SMTP('localhost')
# sendmail function takes 3 arguments: sender's address, recipient's address
# and message to send - here it is sent as one string.
s.sendmail(me, you, msg.as_string())
s.quit()
Here is a Gmail implementation of the accepted answer:
import smtplib
from email.mime.multipart import MIMEMultipart
from email.mime.text import MIMEText
# me == my email address
# you == recipient's email address
me = "my#email.com"
you = "your#email.com"
# Create message container - the correct MIME type is multipart/alternative.
msg = MIMEMultipart('alternative')
msg['Subject'] = "Link"
msg['From'] = me
msg['To'] = you
# Create the body of the message (a plain-text and an HTML version).
text = "Hi!\nHow are you?\nHere is the link you wanted:\nhttp://www.python.org"
html = """\
<html>
<head></head>
<body>
<p>Hi!<br>
How are you?<br>
Here is the link you wanted.
</p>
</body>
</html>
"""
# Record the MIME types of both parts - text/plain and text/html.
part1 = MIMEText(text, 'plain')
part2 = MIMEText(html, 'html')
# Attach parts into message container.
# According to RFC 2046, the last part of a multipart message, in this case
# the HTML message, is best and preferred.
msg.attach(part1)
msg.attach(part2)
# Send the message via local SMTP server.
mail = smtplib.SMTP('smtp.gmail.com', 587)
mail.ehlo()
mail.starttls()
mail.login('userName', 'password')
mail.sendmail(me, you, msg.as_string())
mail.quit()
You might try using my mailer module.
from mailer import Mailer
from mailer import Message
message = Message(From="me#example.com",
To="you#example.com")
message.Subject = "An HTML Email"
message.Html = """<p>Hi!<br>
How are you?<br>
Here is the link you wanted.</p>"""
sender = Mailer('smtp.example.com')
sender.send(message)
Here is a simple way to send an HTML email, just by specifying the Content-Type header as 'text/html':
import email.message
import smtplib
msg = email.message.Message()
msg['Subject'] = 'foo'
msg['From'] = 'sender#test.com'
msg['To'] = 'recipient#test.com'
msg.add_header('Content-Type','text/html')
msg.set_payload('Body of <b>message</b>')
# Send the message via local SMTP server.
s = smtplib.SMTP('localhost')
s.starttls()
s.login(email_login,
email_passwd)
s.sendmail(msg['From'], [msg['To']], msg.as_string())
s.quit()
for python3, improve #taltman 's answer:
use email.message.EmailMessage instead of email.message.Message to construct email.
use email.set_content func, assign subtype='html' argument. instead of low level func set_payload and add header manually.
use SMTP.send_message func instead of SMTP.sendmail func to send email.
use with block to auto close connection.
from email.message import EmailMessage
from smtplib import SMTP
# construct email
email = EmailMessage()
email['Subject'] = 'foo'
email['From'] = 'sender#test.com'
email['To'] = 'recipient#test.com'
email.set_content('<font color="red">red color text</font>', subtype='html')
# Send the message via local SMTP server.
with smtplib.SMTP('localhost') as s:
s.login('foo_user', 'bar_password')
s.send_message(email)
Here's sample code. This is inspired from code found on the Python Cookbook site (can't find the exact link)
def createhtmlmail (html, text, subject, fromEmail):
"""Create a mime-message that will render HTML in popular
MUAs, text in better ones"""
import MimeWriter
import mimetools
import cStringIO
out = cStringIO.StringIO() # output buffer for our message
htmlin = cStringIO.StringIO(html)
txtin = cStringIO.StringIO(text)
writer = MimeWriter.MimeWriter(out)
#
# set up some basic headers... we put subject here
# because smtplib.sendmail expects it to be in the
# message body
#
writer.addheader("From", fromEmail)
writer.addheader("Subject", subject)
writer.addheader("MIME-Version", "1.0")
#
# start the multipart section of the message
# multipart/alternative seems to work better
# on some MUAs than multipart/mixed
#
writer.startmultipartbody("alternative")
writer.flushheaders()
#
# the plain text section
#
subpart = writer.nextpart()
subpart.addheader("Content-Transfer-Encoding", "quoted-printable")
pout = subpart.startbody("text/plain", [("charset", 'us-ascii')])
mimetools.encode(txtin, pout, 'quoted-printable')
txtin.close()
#
# start the html subpart of the message
#
subpart = writer.nextpart()
subpart.addheader("Content-Transfer-Encoding", "quoted-printable")
#
# returns us a file-ish object we can write to
#
pout = subpart.startbody("text/html", [("charset", 'us-ascii')])
mimetools.encode(htmlin, pout, 'quoted-printable')
htmlin.close()
#
# Now that we're done, close our writer and
# return the message body
#
writer.lastpart()
msg = out.getvalue()
out.close()
print msg
return msg
if __name__=="__main__":
import smtplib
html = 'html version'
text = 'TEST VERSION'
subject = "BACKUP REPORT"
message = createhtmlmail(html, text, subject, 'From Host <sender#host.com>')
server = smtplib.SMTP("smtp_server_address","smtp_port")
server.login('username', 'password')
server.sendmail('sender#host.com', 'target#otherhost.com', message)
server.quit()
Actually, yagmail took a bit different approach.
It will by default send HTML, with automatic fallback for incapable email-readers. It is not the 17th century anymore.
Of course, it can be overridden, but here goes:
import yagmail
yag = yagmail.SMTP("me#example.com", "mypassword")
html_msg = """<p>Hi!<br>
How are you?<br>
Here is the link you wanted.</p>"""
yag.send("to#example.com", "the subject", html_msg)
For installation instructions and many more great features, have a look at the github.
Here's a working example to send plain text and HTML emails from Python using smtplib along with the CC and BCC options.
https://varunver.wordpress.com/2017/01/26/python-smtplib-send-plaintext-and-html-emails/
#!/usr/bin/env python
import smtplib
from email.mime.multipart import MIMEMultipart
from email.mime.text import MIMEText
def send_mail(params, type_):
email_subject = params['email_subject']
email_from = "from_email#domain.com"
email_to = params['email_to']
email_cc = params.get('email_cc')
email_bcc = params.get('email_bcc')
email_body = params['email_body']
msg = MIMEMultipart('alternative')
msg['To'] = email_to
msg['CC'] = email_cc
msg['Subject'] = email_subject
mt_html = MIMEText(email_body, type_)
msg.attach(mt_html)
server = smtplib.SMTP('YOUR_MAIL_SERVER.DOMAIN.COM')
server.set_debuglevel(1)
toaddrs = [email_to] + [email_cc] + [email_bcc]
server.sendmail(email_from, toaddrs, msg.as_string())
server.quit()
# Calling the mailer functions
params = {
'email_to': 'to_email#domain.com',
'email_cc': 'cc_email#domain.com',
'email_bcc': 'bcc_email#domain.com',
'email_subject': 'Test message from python library',
'email_body': '<h1>Hello World</h1>'
}
for t in ['plain', 'html']:
send_mail(params, t)
Here is my answer for AWS using boto3
subject = "Hello"
html = "<b>Hello Consumer</b>"
client = boto3.client('ses', region_name='us-east-1', aws_access_key_id="your_key",
aws_secret_access_key="your_secret")
client.send_email(
Source='ACME <do-not-reply#acme.com>',
Destination={'ToAddresses': [email]},
Message={
'Subject': {'Data': subject},
'Body': {
'Html': {'Data': html}
}
}
Simplest solution for sending email from Organizational account in Office 365:
from O365 import Message
html_template = """
<html>
<head>
<title></title>
</head>
<body>
{}
</body>
</html>
"""
final_html_data = html_template.format(df.to_html(index=False))
o365_auth = ('sender_username#company_email.com','Password')
m = Message(auth=o365_auth)
m.setRecipients('receiver_username#company_email.com')
m.setSubject('Weekly report')
m.setBodyHTML(final_html_data)
m.sendMessage()
here df is a dataframe converted to html Table, which is being injected to html_template
I may be late in providing an answer here, but the Question asked a way to send HTML emails. Using a dedicated module like "email" is okay, but we can achieve the same results without using any new module. It all boils down to the Gmail Protocol.
Below is my simple sample code for sending HTML mail only by using "smtplib" and nothing else.
```
import smtplib
FROM = "....#gmail.com"
TO = "another....#gmail.com"
SUBJECT= "Subject"
PWD = "thesecretkey"
TEXT="""
<h1>Hello</h1>
""" #Your Message (Even Supports HTML Directly)
message = f"Subject: {SUBJECT}\nFrom: {FROM}\nTo: {TO}\nContent-Type: text/html\n\n{TEXT}" #This is where the stuff happens
try:
server=smtplib.SMTP("smtp.gmail.com",587)
server.ehlo()
server.starttls()
server.login(FROM,PWD)
server.sendmail(FROM,TO,message)
server.close()
print("Successfully sent the mail.")
except Exception as e:
print("Failed to send the mail..", e)
```
In case you want something simpler:
from redmail import EmailSender
email = EmailSender(host="smtp.myhost.com", port=1)
email.send(
subject="Example email",
sender="me#example.com",
receivers=["you#example.com"],
html="<h1>Hi, this is HTML body</h1>"
)
Pip install Red Mail from PyPI:
pip install redmail
Red Mail has most likely all you need from sending emails and it has a lot of features including:
Attachments
Templating (with Jinja)
Embedded images
Prettified tables
Send as cc or bcc
Gmail preconfigured
Documentation: https://red-mail.readthedocs.io/en/latest/index.html
Source code: https://github.com/Miksus/red-mail
I'm trying to learn python from a book ("Hello! Python"). This code should, according to the book, send an email. no luck so far.
import os
from email.mime.multipart import MIMEMultipart
from email.mime.text import MIMEText
import smtplib
def send_message(message):
s = smtplib.SMTP('smtp.me.com')
s.sendmail(message['From'], message['To'], message.as_string())
s.quit()
def mail_report(to, ticker_name):
outer = MIMEMultipart()
outer['Subject'] = "Stock report for " + ticker_name
outer['From'] = "myemail#mac.com"
outer['To'] = to
# Internal text container
inner = MIMEMultipart('alternative')
text = "Here is the stock report for " + ticker_name
html = """\
<html>
<head></head>
<body>
<p>Here is teh stock report for
<b> """ + ticker_name + """ </b>
</p>
</body>
</html>
"""
part1 = MIMEText(text, 'plain')
part2 = MIMEText(html, 'html')
inner.attach(part1)
inner.attach(part2)
outer.attach(inner)
filename = 'stocktracker-%s.csv' % ticker_name
csv_text = ''.join(file(filename).readlines())
csv_part = MIMEText(csv_text, 'csv')
csv_part.add_header('Content-Disposition', 'attachment', filename=filename), outer.attach(csv_part)
return outer
if __name__ == '__main__':
email = mail_report('myemail#mac.com', 'GOOG')
send_message(email)
I don't get an error, but I also don't get an email. (needless to say, i'm using my actual email, not 'myemail#mac.com') All suggestions and suggested reading appreciated.
You can run a local smtp debugging server. Find where smtpd.py is located, then run the command:
$ python /usr/lib/python2.7/smtpd.py -n -c DebuggingServer localhost:8025
Then on a second terminal screen run the Python interpreter:
>>> import smtplib
>>> s = smtplib.SMTP('localhost', 8025)
>>> s.sendmail('me', 'you', 'Hi!')
You should see 'Hi!' in the first screen.
smtplib.sendmail should eventually raise an exception if it can't send the mail - it may just take a while for the timeout due to the connection being dropped by a firewall. Give it a few minutes. Meanwhile, read below about what could be going wrong.
The code tries to directly connect to smtp.me.com and send mail via SMTP (port 25). This will only work if:
Your internet setup lets you make outgoing connections on port 25
smtp.me.com listens on port 25 (it does)
the recipient email is a valid address ending in #mac.com (myemail#mac.com is not valid: 550 5.1.1 unknown or illegal alias: myemail#mac.com
)
smtp.me.com still processes emails for #mac.com (Mobile Me was shut down in favor of iCloud some time ago, so I'm not sure the #mac.com addresses are still valid)
You can substitute any other mail server for smtp.me.com, preferably that of your ISP, which should be willing to relay email to any address (unlike smtp.me.com, which will only care about the mac.com domain).