Develop Reference

How can I create a separate function just to handle exceptions generated by the requests library?

I am a newbie in python software development. I have created a script which includes many functions returning output of a request and handling the exceptions generated by them. One of the func. is as below:
def ApiResponse(emailHash):
r=None
errorMessage = ""
url = "https://dummy.com"
try:
r = requests.get(url, timeout = TIMEOUT_LIMIT)
except requests.exceptions.Timeout as e:
errorMessage = "Timeout Error"
except requests.ConnectionError as e:
errorMessage = "ConnectionError"
except requests.RequestException as e:
errorMessage = "Some other Request Exception"
return r
I have many such functions returning response for different requests. But, they all repeat the exception handling code. I want to handle exceptions separately in another function so that I don't have to repeat myself. I have tried stuff like passing on the variable "e" to other function and comparing it to the exception types and return different error messages accordingly but I cant seem to compare, lets say, e == requests.exceptions.Timeout.
What else can i do just to separate out that exception handling part? I aim to write a modular code!

You can use exception-decouple package for good readbility:
from exception_decouple import redirect_exceptions
def timeout_handler(emailHash, e):
return "Timeout Error"
def default_handler(emailHash, e):
return "Other Error"
#redirect_exceptions(timeout_handler, requests.exceptions.Timeout)
#redirect_exceptions(default_handler, requests.ConnectionError,
requests.RequestException)
def ApiResponse(emailHash):
r=None
url = "https://dummy.com"
r = requests.get(url, timeout = TIMEOUT_LIMIT)
return r

one of the ways I found was to compare the type of the error with the error. for example in the above case.
def exception_handler(e):
if type(e) is requests.exceptions.ConnectTimeout:
return "Timeout Error"
elif type(e) is requests.ConnectionError:
return "ConnectionError"
else:
return "Some other Request Exception"
this should work

What can't I parse the API in my Telegram bot code?

I am trying to create a Telegram bot that allows users to search up recipes that require only ingredients that they have on-hand. It is built with Python and I have a rough code, but before I fine-tune the details, I want to get the basic form of it up and running. Unfortunately, I am facing difficulty in parsing the API for the recipes corresponding to ingredients that the user has listed in his/her message. Specifically, the logged error message is "Error parsing the API". Could someone take a look at my code and help me see what went wrong please?
This is the relevant portion of my code:
def handle_messages(messages):
for message in messages:
mappedIngreds = []
for i in range(len(message.text)):
ingred = message.text[i].lower()
if i == 0:
mappedIngreds.append(ingred)
else:
mappedIngreds.append(f"+ {ingred}")
# get responses from API
try:
response = requests.get(f"{apiURL}{mappedIngreds}{apiId}{apiKey}")
response.raise_for_status() # for debugging
except requests.RequestException:
logging.error("Error connecting to the API")
return None
# format responses into list of recipes
try:
recipes = []
for i in response.json():
recipeInfo = {}
recipeInfo["name"] = i["label"]
recipeInfo["url"] = i["url"]
recipes.append(recipeInfo)
except (KeyError, TypeError, ValueError):
logging.error("Error parsing the API")
return None
# send list of recipes to user
try:
bot.reply_to(message.chat.id, "Try these recipes:", *recipeInfo["name"], *recipeInfo["url"], sep="\n")
except:
logging.error("Error printing recipes")
My full code is here: https://pastebin.com/W0CceAt9

How to handle twilio exceptions by error code and process them

I am using the following approach for handling Twilio exceptions in Python:
try:
#code for sending the sms
print(message.sid)
except TwilioRestException as e:
print(e)
This allows me to send sms and Exceptions are handled by Python.
Now I need to "return" the exceptions codes in order to process them, let's say, give user a message depending on the exception.
How can I achieve that?

If raising exception is not an option you could simply add return under except block.
def func():
# your logic
try:
#code for sending the sms
print(message.sid)
except TwilioRestException as e:
print(e)
return e.code # or whetever attribute e has for it...
By default function will return None if everything goes right. In client code it will be like
err = func()
if err:
# sms wasn't sent, action required

How do I catch exceptions that have specific error messages in Python?

When I have two Python exceptions that are the same exception class but a different error message, how do I catch them separately?
For specific use-case:
I'm using the Facepy library to hit the Facebook Graph API. When the API returns an error that isn't Oauth related, Facepy raises a facepy.exceptions.FacebookError and passes the error message given by the Facebook API.
I'm consistently hitting two different errors that I'd like to treat differently and the only way to parse them is the error message, but I can't figure out how to write my except clause--here it is in pseudo-code:
try:
#api query
except facepy.exceptions.OAuthError and error_message = 'object does not exist':
# do something
except facepy.exceptions.OAuthError and error_message = 'Hit API rate limit':
# do something else
How do I write these except clauses to trigger off both the exception and the error message?

Assuming the Exception's error message is in the error_message attribute (it may be something else — look at the Exception's __dict__ or source to find out):
try:
#api query
except facepy.exceptions.OAuthError as e:
if e.error_message == "object does not exist":
print "Do X"
elif e.error_message == "Hit API rate limit":
print "Do Y"
else:
raise

facepy's OAuthError derives from FacebookError and that has message attribute. https://github.com/jgorset/facepy/blob/master/facepy/exceptions.py#L8. So, you can use if condition with the message like this
try:
#api query
except facepy.exceptions.OAuthError as error:
if 'object does not exist' == error.message:
# do something
elif 'Hit API rate limit' == error.message:
# do something else
else:
raise

Catching a jira-python exception

I am trying to handle jira-python exception but my try, except does not seem to catch it. I also need to add more lines in order to be able to post this. So there they are, the lines.
try:
new_issue = jira.create_issue(fields=issue_dict)
stdout.write(str(new_issue.id))
except jira.exceptions.JIRAError:
stdout.write("JIRAError")
exit(1)
Here is the code that raises the exception:
import json
class JIRAError(Exception):
"""General error raised for all problems in operation of the client."""
def __init__(self, status_code=None, text=None, url=None):
self.status_code = status_code
self.text = text
self.url = url
def __str__(self):
if self.text:
return 'HTTP {0}: "{1}"\n{2}'.format(self.status_code, self.text, self.url)
else:
return 'HTTP {0}: {1}'.format(self.status_code, self.url)
def raise_on_error(r):
if r.status_code >= 400:
error = ''
if r.text:
try:
response = json.loads(r.text)
if 'message' in response:
# JIRA 5.1 errors
error = response['message']
elif 'errorMessages' in response and len(response['errorMessages']) > 0:
# JIRA 5.0.x error messages sometimes come wrapped in this array
# Sometimes this is present but empty
errorMessages = response['errorMessages']
if isinstance(errorMessages, (list, tuple)):
error = errorMessages[0]
else:
error = errorMessages
elif 'errors' in response and len(response['errors']) > 0:
# JIRA 6.x error messages are found in this array.
error = response['errors']
else:
error = r.text
except ValueError:
error = r.text
raise JIRAError(r.status_code, error, r.url)

I know I'm not answering the question, but I feel I need to warn people that could get confused by that code (as I did)...
Maybe you are trying to write your own version of jira-python or it's an old version?
In any case, here the link to the jira-python code for the JIRAError class
and here the list of codes
to catch the exception from that package I use the below code
from jira import JIRA, JIRAError
try:
...
except JIRAError as e:
print e.status_code, e.text

Maybe it is obvious and that's why you don't have it in your code paste, just in case, you do have
from jira.exceptions import JIRAError
somewhere in your code right?
Don't have enough reputation for comments so I'll add it answer for #arynhard:
I found the docs very light in particular in terms of example, you might find the scripts in this repo useful since they're all leveraging jira-python in someway or another.
https://github.com/eucalyptus/jira-scripts/

I might be wrong, but looks like you're catching jira.exceptions.JIRAError, while raising JIRAError - those are different types. You need to either remove "jira.exceptions." part from your except statement, or raise jira.exceptions.JIRAError instead.

Ok it's a very old one but I faced the same problem and this page is still showing up.
Here is how I trap the Exception, I used the Exception object.
try:
issue = jira.issue('jira-1')
except Exception as e:
if 'EXIST' in e.text:
print 'The issue does not exist'
exit(1)
regards