Write and recode from one csv file to another - python

I am trying to select specific columns from a large tab-delimited CSV file and output only certain columns to a new CSV file. Furthermore, I want to recode the data as this happens. If the cell has a value of 0 then just output 0. However, if the cell has a value of greater than 0, then just output 1 (i.e., all values greater than 0 are coded as 1).
Here's what I have so far:
import csv
outputFile = open('output.csv', 'wb')
outputWriter = csv.writer(outputFile)
included_cols = range(9,2844)
with open('source.txt', 'rb') as f:
reader = csv.reader(f, delimiter='\t')
for row in reader:
content = list(row[i] for i in included_cols)
outputWriter.writerow(content)
The first issue I am having is that I want to also take from column 6. I wasn't sure how to write column 6 and then columns 9-2844.
Second, I wasn't sure how to do the recoding on the fly as I write the new CSV.

I wasn't sure how to write column 6 and then columns 9-2844.
included_cols = [6] + list(range(9,2844))
This works because you can add two lists together. Note that in Python3, range doesn't return a list, so we have to coerce it.
I wasn't sure how to do the recoding on the fly
content = list((1 if row[i] > 0 else 0) for i in included_cols)
This works because of the conditional expression: 1 if row[i] > 0 else 0. The general form A if cond else B evaluates to either A or B, depending upon the condition.
Another form, which I think is "too clever by half" is content = list((row[i] and 1) for i in included_cols). This works because the and operator always returns one or the other of its inputs.

This should work:
import csv
outputFile = open('output.csv', 'wb')
outputWriter = csv.writer(outputFile)
included_cols = [5] + range(8,2844) # you can just merge two lists
with open('source.txt', 'rb') as f:
reader = csv.reader(f, delimiter='\t')
outputWriter.writerow(reader[0]) # write header row unchanged
for row in reader[1:]: # skip header row
content = [int(row[i]) if i == 5 else (0 if int(row[i]) == 0 else 1) for i in included_cols]
outputWriter.writerow(content)

Related

How to delete a row in a CSV file if a cell is empty using Python

I want to go through large CSV files and if there is missing data I want to remove that row completely, This is only row specific so if there is a cell that = 0 or has no value then I want to remove the entire row. I want this to happen for all the columns so if any column has a black cell it should delete the row, and return the corrected data in a corrected csv.
import csv
with open('data.csv', 'r') as csvfile:
csvreader = csv.reader(csvfile)
for row in csvreader:
print(row)
if not row[0]:
print("12")
This is what I found and tried but it doesnt not seem to be working and I dont have any ideas about how to aproach this problem, help please?
Thanks!
Due to the way in which CSV reader presents rows of data, you need to know how many columns there are in the original CSV file. For example, if the CSV file content looks like this:
1,2
3,
4
Then the lists return by iterating over the reader would look like this:
['1','2']
['3','']
['4']
As you can see, the third row only has one column whereas the first and second rows have 2 columns albeit that one is (effectively) empty.
This function allows you to either specify the number of columns (if you know them before hand) or allow the function to figure it out. If not specified then it is assumed that the number of columns is the greatest number of columns found in any row.
So...
import csv
DELIMITER = ','
def valid_column(col):
try:
return float(col) != 0
except ValueError:
pass
return len(col.strip()) > 0
def fix_csv(input_file, output_file, cols=0):
if cols == 0:
with open(input_file, newline='') as indata:
cols = max(len(row) for row in csv.reader(indata, delimiter=DELIMITER))
with open(input_file, newline='') as indata, open(output_file, 'w', newline='') as outdata:
writer = csv.writer(outdata, delimiter=DELIMITER)
for row in csv.reader(indata, delimiter=DELIMITER):
if len(row) == cols:
if all(valid_column(col) for col in row):
writer.writerow(row)
fix_csv('original.csv', 'fixed.csv')
maybe like this
import csv
with open('data.csv', 'r') as csvfile:
csvreader = csv.reader(csvfile)
data=list(csvreader)
data=[x for x in data if '' not in x and '0' not in x]
you can then rewrite the the csv file if you like
Instead of using csv, you should use Pandas module, something like this.
import pandas as pd
df = pd.read_csv('file.csv')
print(df)
index = 1 #index of the row that you want to remove
df = df.drop(index)
print(df)
df.to_csv('file.csv')

Read csv file with empty lines

Analysis software I'm using outputs many groups of results in 1 csv file and separates the groups with 2 empty lines.
I would like to break the results in groups so that I can then analyse them separately.
I'm sure there is a built-in function in python (or one of it's libraries) that does this, I tried this piece of code that I found somewhere but it doesn't seem to work.
import csv
results = open('03_12_velocity_y.csv').read().split("\n\n")
# Feed first csv.reader
first_csv = csv.reader(results[0], delimiter=',')
# Feed second csv.reader
second_csv = csv.reader(results[1], delimiter=',')
Update:
The original code actually works, but my python skills are pretty limited and I did not implement it properly.
.split(\n\n\n) method does work but the csv.reader is an object and to get the data in a list (or something similar), it needs to iterate through all the rows and write them to the list.
I then used Pandas to remove the header and convert the scientific notated values to float. Code is bellow. Thanks everyone for help.
import csv
import pandas as pd
# Open the csv file, read it and split it when it encounters 2 empty lines (\n\n\n)
results = open('03_12_velocity_y.csv').read().split('\n\n\n')
# Create csv.reader objects that are used to iterate over rows in a csv file
# Define the output - create an empty multi-dimensional list
output1 = [[],[]]
# Iterate through the rows in the csv file and append the data to the empty list
# Feed first csv.reader
csv_reader1 = csv.reader(results[0].splitlines(), delimiter=',')
for row in csv_reader1:
output1.append(row)
df = pd.DataFrame(output1)
# remove first 7 rows of data (the start position of the slice is always included)
df = df.iloc[7:]
# Convert all data from string to float
df = df.astype(float)
If your row counts are inconsistent across groups, you'll need a little state machine to check when you're between groups and do something with the last group.
#!/usr/bin/env python3
import csv
def write_group(group, i):
with open(f"group_{i}.csv", "w", newline="") as out_f:
csv.writer(out_f).writerows(group)
with open("input.csv", newline="") as f:
reader = csv.reader(f)
group_i = 1
group = []
last_row = []
for row in reader:
if row == [] and last_row == [] and group != []:
write_group(group, group_i)
group = []
group_i += 1
continue
if row == []:
last_row = row
continue
group.append(row)
last_row = row
# flush remaining group
if group != []:
write_group(group, group_i)
I mocked up this sample CSV:
g1r1c1,g1r1c2,g1r1c3
g1r2c1,g1r2c2,g1r2c3
g1r3c1,g1r3c2,g1r3c3
g2r1c1,g2r1c2,g2r1c3
g2r2c1,g2r2c2,g2r2c3
g3r1c1,g3r1c2,g3r1c3
g3r2c1,g3r2c2,g3r2c3
g3r3c1,g3r3c2,g3r3c3
g3r4c1,g3r4c2,g3r4c3
g3r5c1,g3r5c2,g3r5c3
And when I run the program above I get three CSV files:
group_1.csv
g1r1c1,g1r1c2,g1r1c3
g1r2c1,g1r2c2,g1r2c3
g1r3c1,g1r3c2,g1r3c3
group_2.csv
g2r1c1,g2r1c2,g2r1c3
g2r2c1,g2r2c2,g2r2c3
group_3.csv
g3r1c1,g3r1c2,g3r1c3
g3r2c1,g3r2c2,g3r2c3
g3r3c1,g3r3c2,g3r3c3
g3r4c1,g3r4c2,g3r4c3
g3r5c1,g3r5c2,g3r5c3
If your row counts are consistent, you can do this with fairly vanilla Python or using the Pandas library.
Vanilla Python
Define your group size and the size of the break (in "rows") between groups.
Loop over all the rows adding each row to a group accumulator.
When the group accumulator reaches the pre-defined group size, do something with it, reset the accumulator, and then skip break-size rows.
Here, I'm writing each group to its own numbered file:
import csv
group_sz = 5
break_sz = 2
def write_group(group, i):
with open(f"group_{i}.csv", "w", newline="") as f_out:
csv.writer(f_out).writerows(group)
with open("input.csv", newline="") as f_in:
reader = csv.reader(f_in)
group_i = 1
group = []
for row in reader:
group.append(row)
if len(group) == group_sz:
write_group(group, group_i)
group_i += 1
group = []
for _ in range(break_sz):
try:
next(reader)
except StopIteration: # gracefully ignore an expected StopIteration (at the end of the file)
break
group_1.csv
g1r1c1,g1r1c2,g1r1c3
g1r2c1,g1r2c2,g1r2c3
g1r3c1,g1r3c2,g1r3c3
g1r4c1,g1r4c2,g1r4c3
g1r5c1,g1r5c2,g1r5c3
With Pandas
I'm new to Pandas, and learning this as I go, but it looks like Pandas will automatically trim blank rows/records from a chunk of data^1.
With that in mind, all you need to do is specify the size of your group, and tell Pandas to read your CSV file in "iterator mode", where you can ask for a chunk (your group size) of records at a time:
import pandas as pd
group_sz = 5
with pd.read_csv("input.csv", header=None, iterator=True) as reader:
i = 1
while True:
try:
df = reader.get_chunk(group_sz)
except StopIteration:
break
df.to_csv(f"group_{i}.csv")
i += 1
Pandas add an "ID" column and default header when it writes out the CSV:
group_1.csv
,0,1,2
0,g1r1c1,g1r1c2,g1r1c3
1,g1r2c1,g1r2c2,g1r2c3
2,g1r3c1,g1r3c2,g1r3c3
3,g1r4c1,g1r4c2,g1r4c3
4,g1r5c1,g1r5c2,g1r5c3
TRY this out with your output:
import pandas as pd
# csv file name to be read in
in_csv = 'input.csv'
# get the number of lines of the csv file to be read
number_lines = sum(1 for row in (open(in_csv)))
# size of rows of data to write to the csv,
# you can change the row size according to your need
rowsize = 500
# start looping through data writing it to a new file for each set
for i in range(1,number_lines,rowsize):
df = pd.read_csv(in_csv,
header=None,
nrows = rowsize,#number of rows to read at each loop
skiprows = i)#skip rows that have been read
#csv to write data to a new file with indexed name. input_1.csv etc.
out_csv = 'input' + str(i) + '.csv'
df.to_csv(out_csv,
index=False,
header=False,
mode='a', #append data to csv file
)
I updated the question with the last details that answer my question.

Python: How to iterate every third row starting with the second row of a csv file

I'm trying to write a program that iterates through the length of a csv file row by row. It will create 3 new csv files and write data from the source csv file to each of them. The program does this for the entire row length of the csv file.
For the first if statement, I want it to copy every third row starting at the first row and save it to a new csv file(the next row it copies would be row 4, row 7, row 10, etc)
For the second if statement, I want it to copy every third row starting at the second row and save it to a new csv file(the next row it copies would be row 5, row 8, row 11, etc).
For the third if statement, I want it to copy every third row starting at the third row and save it to a new csv file(the next row it copies would be row 6, row 9, row 12, etc).
The second "if" statement I wrote that creates the first "agentList1.csv" works exactly the way I want it to but I can't figure out how to get the first "elif" statement to start from the second row and the second "elif" statement to start from the third row. Any help would be much appreciated!
Here's my code:
for index, row in Sourcedataframe.iterrows(): #going through each row line by line
#this for loop counts the amount of times it has gone through the csv file. If it has gone through it more than three times, it resets the counter back to 1.
for column in Sourcedataframe:
if count > 3:
count = 1
#if program is on it's first count, it opens the 'Sourcedataframe', reads/writes every third row to a new csv file named 'agentList1.csv'.
if count == 1:
with open('blankAgentList.csv') as infile:
with open('agentList1.csv', 'w') as outfile:
reader = csv.DictReader(infile)
writer = csv.DictWriter(outfile, fieldnames=reader.fieldnames)
writer.writeheader()
for row in reader:
count2 += 1
if not count2 % 3:
writer.writerow(row)
elif count == 2:
with open('blankAgentList.csv') as infile:
with open('agentList2.csv', 'w') as outfile:
reader = csv.DictReader(infile)
writer = csv.DictWriter(outfile, fieldnames=reader.fieldnames)
writer.writeheader()
for row in reader:
count2 += 1
if not count2 % 3:
writer.writerow(row)
elif count == 3:
with open('blankAgentList.csv') as infile:
with open('agentList3.csv', 'w') as outfile:
reader = csv.DictReader(infile)
writer = csv.DictWriter(outfile, fieldnames=reader.fieldnames)
writer.writeheader()
for row in reader:
count2 += 1
if not count2 % 3:
writer.writerow(row)
count = count + 1 #counts how many times it has ran through the main for loop.
convert csv to dataframe as (df.to_csv(header=True)) to start indexing from second row
then,pass row/record no in iloc function to fetch particular record using
( df.iloc[ 3 , : ])
you are open your csv file in each if claus from the beginning. I believe you already opened your file into Sourcedataframe. so just get rid of reader = csv.DictReader(infile) and read data like this:
Sourcedataframe.iloc[column]
Using plain python we can create a solution that works for any number of interleaved data rows, let's call it NUM_ROWS, not just three.
Nota Bene: the solution does not require to read and keep the whole input all the data in memory. It processes one line at a time, grouping the last needed few and works fine for a very large input file.
Assuming your input file contains a number of data rows which is a multiple of NUM_ROWS, i.e. the rows can be split evenly to the output files:
NUM_ROWS = 3
outfiles = [open(f'blankAgentList{i}.csv', 'w') for i in range(1,NUM_ROWS+1)]
with open('blankAgentList.csv') as infile:
header = infile.readline() # read/skip the header
for f in outfiles: # repeat header in all output files if needed
f.write(header)
row_groups = zip(*[iter(infile)]*NUM_ROWS)
for rg in row_groups:
for f, r in zip(outfiles, rg):
f.write(r)
for f in outfiles:
f.close()
Otherwise, for any number of data rows we can use
import itertools as it
NUM_ROWS = 3
outfiles = [open(f'blankAgentList{i}.csv', 'w') for i in range(1,NUM_ROWS+1)]
with open('blankAgentList.csv') as infile:
header = infile.readline() # read/skip the header
for f in outfiles: # repeat header in all output files if needed
f.write(header)
row_groups = it.zip_longest(*[iter(infile)]*NUM_ROWS)
for rg in row_groups:
for f, r in it.zip_longest(outfiles, rg):
if r is None:
break
f.write(r)
for f in outfiles:
f.close()
which, for example, with an input file of
A,B,C
r1a,r1b,r1c
r2a,r2a,r2c
r3a,r3b,r3c
r4a,r4b,r4c
r5a,r5b,r5c
r6a,r6b,r6c
r7a,r7b,r7c
produces (output copied straight from the terminal)
(base) SO $ cat blankAgentList.csv
A,B,C
r1a,r1b,r1c
r2a,r2a,r2c
r3a,r3b,r3c
r4a,r4b,r4c
r5a,r5b,r5c
r6a,r6b,r6c
r7a,r7b,r7c
(base) SO $ cat blankAgentList1.csv
A,B,C
r1a,r1b,r1c
r4a,r4b,r4c
r7a,r7b,r7c
(base) SO $ cat blankAgentList2.csv
A,B,C
r2a,r2a,r2c
r5a,r5b,r5c
(base) SO $ cat blankAgentList3.csv
A,B,C
r3a,r3b,r3c
r6a,r6b,r6c
Note: I understand the line
row_groups = zip(*[iter(infile)]*NUM_ROWS)
may be intimidating at first (it was for me when I started).
All it does is simply to group consecutive lines from the input file.
If your objective includes learning Python, I recommend studying it thoroughly via a book or a course or both and practising a lot.
One key subject is the iteration protocol, along with all the other protocols. And namespaces.

Replace column in csv with modified column

I got a csv file with a couple of columns and a header containing 4 rows. The first column contains the timestamp. Unfortunately it also gives milliseconds, but whenever those are at 00, they are not given in the file. It looks like that:
"TOA5","CR1000","CR1000","E9048"
"TIMESTAMP","RECORD","BattV_Avg","PTemp_C_Avg"
"TS","RN","Volts","Deg C"
"","","Avg","Avg"
"2015-08-28 12:40:23.51",1,12.91,32.13
"2015-08-28 12:50:43.23",2,12.9,32.34
"2015-08-28 13:12:22",3,12.91,32.54
As I don't need the milliseconds, I want to get rid of those, as this makes further calculations containing time a bit complicated. My approach so far:
Extract first 20 digits in each row to get a format such as 2015-08-28 12:40:23
timestamp = []
with open(filepath) as f:
for _ in xrange(4): #skip 4 header rows
next(f)
for line in f:
time = line[1:20] #Get values for the current line
timestamp.append(time) #Add values to list
From here on I'm struggling on how to procede further. I want to exchange the first column in the csv file with the newly created timestamp list.
I tried creating a dictionary, but I don't know how to use the header caption in row 2 as the key:
d = {}
with open(filepath, 'rb') as csv_file:
csv_reader = csv.reader(csv_file, delimiter=',')
for col in csv_reader:
#use header info from row 2 as key here
This would import the whole csv file into a dict and I'd then change the TIMESTAMP entry in the dict with the timestamp list above. Is this even possible?
Or is there an easier approach on how to just change the first column in the csv with my new list so that my csv file in the end contains the timestamp just without the millisecond information?
So the first column in my csv should look like this:
"TOA5"
"TIMESTAMP"
"TS"
""
2015-08-28 12:40:23
2015-08-28 12:50:43
2015-08-28 13:12:22
This should do it and preserve the quoting:
with open(filepath1, 'rb') as fin, open(filepath2, 'wb') as fout:
reader = csv.reader(fin)
writer = csv.writer(fout, quoting=csv.QUOTE_NONNUMERIC)
for _ in xrange(4): # copy first 4 header rows
writer.writerow(next(reader))
for row in reader: # process data lines
row[0] = row[0][:19] # strip fractional seconds from first column
writer.writerow([row[0], int(row[1])] + map(float, row[2:]))
Since a csv.reader returns the columns of each row as a list of strings, it's necessary to convert any which contain numeric values into their actual int or float numeric value before they're written out to prevent them from being quoted.
I believe you can easily create a new csv from iterating over the original csv and replacing the timestamp as you want.
Example -
with open(filepath, 'rb') as csv_file, open('<new file>','wb') as outfile:
csv_reader = csv.reader(csv_file, delimiter=',')
csv_writer = csv.writer(outfile, delimiter=',')
for i, row in enumerate(csv_reader): #Enumerating as we only need to change rows after 3rd index.
if i <= 3:
csv_writer.writerow(row)
else:
csv_writer.writerow([row[0][1:20]] + row[1:])
I'm not entirely sure about how to parse your csv but I would do something of the sort:
time = time.split(".")[0]
so if it does have a millisecond it would get removed and if it doesn't nothing will happen.

How do create new column in csv file using python by shifting one row

I have CSV file like below. It is huge file with thousands of records.
input.csv
No;Val;Rec;CSR
0;10;1;1200
0;100;2;1300
0;100;3;1300
0;100;4;1400
0;10;5;1200
0;11;6;1200
I want to create output.csv file by adding new column "PSR" after 1st column "No". This column value depends on column "PSR" Value. For 1st row, "PSR" shall be zero. From next record on-wards, it depends on "CSR" value in previous row. If present and previous record CSR value is same, then "PSR" shall be zero. If not, PSR value shall have the previous CSR value. For exmple, Value of CSR in 2nd row is 1300 which is different to the value in 1st record ( it is 1200). So PSR value for 2nd row shall be 1200. Where in 2nd and 3rd row, CSR value is same. So PSR value for 3rd row shall be zero. So new value PSR depends on CSR value in present and previous field.
Output.csv
No;PCR;Val;Rec;CSR
0;0;10;1;1200
0;1200;100;2;1300
0;0;100;3;1300
0;1300;100;4;1400
0;1400;10;5;1200
0;0;11;6;1200
My Approach:
Use csv.reader and iterate over the objects in a list. Copy 5th column to 2nd column in list. Shift it one row down.
Then check the values in 2nd and 5th column (PCR and CSR), if both values are same. Replace the PCR value with zero.
I have problem in getting 1st step coded. I am able to duplicate the column but not able to shift it. Also 2nd step is quite straightforward.
Also, I am not sure whether this approach is correct Any pointers/recommendation would be really helpful.
Note: I am not able to install Pandas on CentOS. So help without this module would be better.
My Code:
with open('input.csv', 'r') as input, open('output.csv', 'w') as output:
reader = csv.reader(input, delimiter = ';')
writer = csv.writer(output, delimiter = ';')
mylist = []
header = next(reader)
mylist.append(header)
for rec in reader:
mylist.append(rec)
rec.insert(1, rec[3])
mylist.append(rec)
writer.writerows(mylist)
If your open to non-python solutions then awk could be a good option:
awk 'NR==1{$2="PSR;"$2}NR>1{$2=($4==a?0";"$2:+a";"$2);a=$4}1' FS=';' OFS=';' file
No;PSR;Val;Rec;CSR
0;0;10;1;1200
0;1200;100;2;1300
0;0;100;3;1300
0;1300;100;4;1400
0;1400;10;5;1200
0;0;11;6;1200
Awk is distributed with pretty much all Linux distributions and was designed exactly for this kind of task. It will blaze through your file. Add a redirection to the end > output.csv to save the output in a file.
A simple python approach using the same logic:
#!/usr/bin/env python
last = "0"
with open('input.csv') as csv:
print next(csv).strip().replace(';', ';PSR;', 1)
for line in csv:
field = line.strip().split(';')
if field[3] == last: field.insert(1, "0")
else: field.insert(1, last)
last = field[4]
print ';'.join(field)
Produces the same output:
$ python parse.py
No;PSR;Val;Rec;CSR
0;0;10;1;1200
0;1200;100;2;1300
0;0;100;3;1300
0;1300;100;4;1400
0;1400;10;5;1200
0;0;11;6;1200
Again just redirect the output to save it:
$ python parse.py > output.csv
Just code it as you explained it. Store the previous CSR and refer to it on the next loop through; just be sure to update it.
import csv
with open('input.csv', 'r') as input, open('output.csv', 'w') as output:
reader = csv.reader(input, delimiter = ';')
writer = csv.writer(output, delimiter = ';')
mylist = []
header = next(reader)
mylist.append(header)
mylist.insert(1,'PCR')
prev_csr = 0
for rec in reader:
rec.insert(1,prev_csr)
mylist.append(rec)
prev_csr = rec[4]
writer.writerows(mylist)
with open('input.csv', 'r') as input, open('output.csv', 'w') as output:
reader = csv.reader(input, delimiter = ';')
writer = csv.writer(output, delimiter = ';')
header = next(reader)
header.insert(1, 'PCR')
writer.writerow(header)
prevRow = next(reader)
prevRow.insert(1, '0')
writer.writerow(prevRow)
for row in reader:
if prevRow[-1] == row[-1]:
val = '0'
else:
val = prevRow[-1]
row.insert(1,val)
prevRow = row
writer.writerow(row)
Or, even easier using the DictReader and DictWriter capabilities of csv:
input_header = ['No','Val','Rec','CSR']
output_header = ['No','PCR','Val','Rec','CSR']
with open('input.csv', 'rb') as in_file, open('output.csv', 'wb') as out_file:
in_reader, out_writer = DictReader(in_file, input_header, delemeter =';'), DictWriter(out_file, output_header, delemeter =';')
in_reader.next() # skip the header
out_writer.writeheader() # place the output header
last_csr = None
for row in in_reader():
current_csr = row['CSR']
row['PCR'] = last_csr if current_csr != last_csr else 0
last_csr = current_csr
out_writer.writerow(row)

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