I have the following data frame (consisting of both negative and positive numbers):
df.head()
Out[39]:
Prices
0 -445.0
1 -2058.0
2 -954.0
3 -520.0
4 -730.0
I am trying to change the 'Prices' column to display as currency when I export it to an Excel spreadsheet. The following command I use works well:
df['Prices'] = df['Prices'].map("${:,.0f}".format)
df.head()
Out[42]:
Prices
0 $-445
1 $-2,058
2 $-954
3 $-520
4 $-730
Now my question here is what would I do if I wanted the output to have the negative signs BEFORE the dollar sign. In the output above, the dollar signs are before the negative signs. I am looking for something like this:
-$445
-$2,058
-$954
-$520
-$730
Please note there are also positive numbers as well.
You can use np.where and test whether the values are negative and if so prepend a negative sign in front of the dollar and cast the series to a string using astype:
In [153]:
df['Prices'] = np.where( df['Prices'] < 0, '-$' + df['Prices'].astype(str).str[1:], '$' + df['Prices'].astype(str))
df['Prices']
Out[153]:
0 -$445.0
1 -$2058.0
2 -$954.0
3 -$520.0
4 -$730.0
Name: Prices, dtype: object
You can use the locale module and the _override_localeconv dict. It's not well documented, but it's a trick I found in another answer that has helped me before.
import pandas as pd
import locale
locale.setlocale( locale.LC_ALL, 'English_United States.1252')
# Made an assumption with that locale. Adjust as appropriate.
locale._override_localeconv = {'n_sign_posn':1}
# Load dataframe into df
df['Prices'] = df['Prices'].map(locale.currency)
This creates a dataframe that looks like this:
Prices
0 -$445.00
1 -$2058.00
2 -$954.00
3 -$520.00
4 -$730.00
Related
I have a column with data that needs some massaging. the column may contain strings or floats. some strings are in exponential form. Id like to best try to format all data in this column as a whole number where possible, expanding any exponential notation to integer. So here is an example
df = pd.DataFrame({'code': ['1170E1', '1.17E+04', 11700.0, '24477G', '124601', 247602.0]})
df['code'] = df['code'].astype(int, errors = 'ignore')
The above code does not seem to do a thing. i know i can convert the exponential notation and decimals with simply using the int function, and i would think the above astype would do the same, but it does not. for example, the following code work in python:
int(1170E1), int(1.17E+04), int(11700.0)
> (11700, 11700, 11700)
Any help in solving this would be appreciated. What i'm expecting the output to look like is:
0 '11700'
1 '11700'
2 '11700
3 '24477G'
4 '124601'
5 '247602'
You may check with pd.to_numeric
df.code = pd.to_numeric(df.code,errors='coerce').fillna(df.code)
Out[800]:
0 11700.0
1 11700.0
2 11700.0
3 24477G
4 124601.0
5 247602.0
Name: code, dtype: object
Update
df['code'] = df['code'].astype(object)
s = pd.to_numeric(df['code'],errors='coerce')
df.loc[s.notna(),'code'] = s.dropna().astype(int)
df
Out[829]:
code
0 11700
1 11700
2 11700
3 24477G
4 124601
5 247602
BENY's answer should work, although you potentially leave yourself open to catching exceptions and filling that you don't want to. This will also do the integer conversion you are looking for.
def convert(x):
try:
return str(int(float(x)))
except ValueError:
return x
df = pd.DataFrame({'code': ['1170E1', '1.17E+04', 11700.0, '24477G', '124601', 247602.0]})
df['code'] = df['code'].apply(convert)
outputs
0 11700
1 11700
2 11700
3 24477G
4 124601
5 247602
where each element is a string.
I will be the first to say, I'm not proud of that triple cast.
Loading in the data
in: import pandas as pd
in: df = pd.read_csv('name', sep = ';', encoding='unicode_escape')
in : df.dtypes
out: amount object
I have an object column with amounts like 150,01 and 43,69. Thee are about 5,000 rows.
df['amount']
0 31
1 150,01
2 50
3 54,4
4 32,79
...
4950 25,5
4951 39,5
4952 75,56
4953 5,9
4954 43,69
Name: amount, Length: 4955, dtype: object
Naturally, I tried to convert the series into the locale format, which suppose to turn it into a float format. I came back with the following error:
In: import locale
setlocale(LC_NUMERIC, 'en_US.UTF-8')
Out: 'en_US.UTF-8'
In: df['amount'].apply(locale.atof)
Out: ValueError: could not convert string to float: ' - '
Now that I'm aware that there are non-numeric values in the list, I tried to use isnumeric methods to turn the non-numeric values to become NaN.
Unfortunately, due to the comma separated structure, all the values would turn into -1.
0 -1
1 -1
2 -1
3 -1
4 -1
..
4950 -1
4951 -1
4952 -1
4953 -1
4954 -1
Name: amount, Length: 4955, dtype: int64
How do I turn the "," values to "." by first removing the "-" values? I tried .drop() or .truncate it does not help. If I replace the str",", " ", it would also cause trouble since there is a non-integer value.
Please help!
Documentation that I came across
-https://stackoverflow.com/questions/21771133/finding-non-numeric-rows-in-dataframe-in-pandas
-https://stackoverflow.com/questions/56315468/replace-comma-and-dot-in-pandas
p.s. This is my first post, please be kind
Sounds like you have a European-style CSV similar to the following. Provide actual sample data as many comments asked for if your format is different:
data.csv
thing;amount
thing1;31
thing2;150,01
thing3;50
thing4;54,4
thing5;1.500,22
To read it, specify the column, decimal and thousands separator as needed:
import pandas as pd
df = pd.read_csv('data.csv',sep=';',decimal=',',thousands='.')
print(df)
Output:
thing amount
0 thing1 31.00
1 thing2 150.01
2 thing3 50.00
3 thing4 54.40
4 thing5 1500.22
Posting as an answer since it contains multi-line code, despite not truly answering your question (yet):
Try using chardet. pip install chardet to get the package, then in your import block, add import chardet.
When importing the file, do something like:
with open("C:/path/to/file.csv", 'r') as f:
data = f.read()
result = chardet.detect(data.encode())
charencode = result['encoding']
# now re-set the handler to the beginning and re-read the file:
f.seek(0, 0)
data = pd.read_csv(f, delimiter=';', encoding=charencode)
Alternatively, for reasons I cannot fathom, passing engine='python' as a parameter works often. You'd just do
data = pd.read_csv('C:/path/to/file.csv', engine='python')
#Mark Tolonen has a more elegant approach to standardizing the actual data, but my (hacky) way of doing it was to just write a function:
def stripThousands(self, df_column):
df_column.replace(',', '', regex=True, inplace=True)
df_column = df_column.apply(pd.to_numeric, errors='coerce')
return df_column
If you don't care about the entries that are just hyphens, you could use a function like
def screw_hyphens(self, column):
column.replace(['-'], np.nan, inplace=True)
or if np.nan values will be a problem, you can just replace it with column.replace('-', '', inplace=True)
**EDIT: there was a typo in the block outlining the usage of chardet. it should be correct now (previously the end of the last line was encoding=charenc)
Time Floating P/L
2 2019.09.30 -16.60
3 2019.10.01 -4.40
4 2019.10.02 -1 162.04
5 2019.10.03 -82.88
I have a database the column Floating P/L is object that I need to convert it to float. I tried google, this default way is used:
df['Floating P/L'] = df['Floating P/L'].replace('[^\d.]', '', regex=True).astype(float)
However, after doing this, the minus symbol is deleted
2 16.60
3 4.40
4 1162.04
5 82.88
I am wondering how can I keep the minus symbol, I assume others may have the same problem, so I post it here
You might use
df['Floating P/L'] = df['Floating P/L'].replace('[^-\d.]', '', regex=True).astype(float)
# ^^^
I would remove all whitespaces (\s) and then convert to float that is:
import pandas as pd
df = pd.DataFrame({'Floating':['-16.60','-4.40','-1 162.04','-82.88']})
df['Floating'] = df['Floating'].replace('\s', '', regex=True).astype(float)
print(df)
print(df['Floating'].dtype)
Output:
Floating
0 -16.60
1 -4.40
2 -1162.04
3 -82.88
float64
I'm quite new to Python and I'm encountering a problem.
I have a dataframe where one of the columns is the departure time of flights. These hours are given in the following format : 1100.0, 525.0, 1640.0, etc.
This is a pandas series which I want to transform into a datetime series such as : S = [11.00, 5.25, 16.40,...]
What I have tried already :
Transforming my objects into string :
S = [str(x) for x in S]
Using datetime.strptime :
S = [datetime.strptime(x,'%H%M.%S') for x in S]
But since they are not all the same format it doesn't work
Using parser from dateutil :
S = [parser.parse(x) for x in S]
I got the error :
'Unknown string format'
Using the panda datetime :
S= pd.to_datetime(S)
Doesn't give me the expected result
Thanks for your answers !
Since it's a columns within a dataframe (A series), keep it that way while transforming should work just fine.
S = [1100.0, 525.0, 1640.0]
se = pd.Series(S) # Your column
# se:
0 1100.0
1 525.0
2 1640.0
dtype: float64
setime = se.astype(int).astype(str).apply(lambda x: x[:-2] + ":" + x[-2:])
This transform the floats to correctly formatted strings:
0 11:00
1 5:25
2 16:40
dtype: object
And then you can simply do:
df["your_new_col"] = pd.to_datetime(setime)
How about this?
(Added an if statement since some entries have 4 digits before decimal and some have 3. Added the use case of 125.0 to account for this)
from datetime import datetime
S = [1100.0, 525.0, 1640.0, 125.0]
for x in S:
if str(x).find(".")==3:
x="0"+str(x)
print(datetime.strftime(datetime.strptime(str(x),"%H%M.%S"),"%H:%M:%S"))
You might give it a go as follows:
# Just initialising a state in line with your requirements
st = ["1100.0", "525.0", "1640.0"]
dfObj = pd.DataFrame(st)
# Casting the string column to float
dfObj_num = dfObj[0].astype(float)
# Getting the hour representation out of the number
df1 = dfObj_num.floordiv(100)
# Getting the minutes
df2 = dfObj_num.mod(100)
# Moving the minutes on the right-hand side of the decimal point
df3 = df2.mul(0.01)
# Combining the two dataframes
df4 = df1.add(df3)
# At this point can cast to other types
Result:
0 11.00
1 5.25
2 16.40
You can run this example to verify the steps for yourself, also you can make it into a function. Make slight variations if needed in order to tweak it according to your precise requirements.
Might be useful to go through this article about Pandas Series.
https://www.geeksforgeeks.org/python-pandas-series/
There must be a better way to do this, but this works for me.
df=pd.DataFrame([1100.0, 525.0, 1640.0], columns=['hour'])
df['hour_dt']=((df['hour']/100).apply(str).str.split('.').str[0]+'.'+
df['hour'].apply((lambda x: '{:.2f}'.format(x/100).split('.')[1])).apply(str))
print(df)
hour hour_dt
0 1100.0 11.00
1 525.0 5.25
2 1640.0 16.40
How do I get the Units column to numeric?
I have a Google spreadsheet that I am reading in the date column gets converted fine.. but I'm not having much luck getting the Unit Sales column to convert to numeric I'm including all the code which uses requests to get the data:
from StringIO import StringIO
import requests
#act = requests.get('https://docs.google.com/spreadsheet/ccc?key=0Ak_wF7ZGeMmHdFZtQjI1a1hhUWR2UExCa2E4MFhiWWc&output=csv&gid=1')
dataact = act.content
actdf = pd.read_csv(StringIO(dataact),index_col=0,parse_dates=['date'])
actdf.rename(columns={'Unit Sales': 'Units'}, inplace=True) #incase the space in the name is messing me up
The different methods I have tried to get Units to get to numeric
actdf=actdf['Units'].convert_objects(convert_numeric=True)
#actdf=actdf['Units'].astype('float32')
Then I want to resample and I'm getting strange string concatenations since the numbers are still string
#actdfq=actdf.resample('Q',sum)
#actdfq.head()
actdf.head()
#actdf
so the df looks like this with just units and the date index
date
2013-09-01 3,533
2013-08-01 4,226
2013-07-01 4,281
Name: Units, Length: 161, dtype: object
You have to specify the thousands separator:
actdf = pd.read_csv(StringIO(dataact), index_col=0, parse_dates=['date'], thousands=',')
This will work
In [13]: s
Out[13]:
0 4,223
1 3,123
dtype: object
In [14]: s.str.replace(',','').convert_objects(convert_numeric=True)
Out[14]:
0 4223
1 3123
dtype: int64