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Force python to not output a float in standard form / scientific notation / exponential form [duplicate]
(6 answers)
Closed 4 years ago.
Are there any means by which one could tell Python 2.x/3.x to always use 3 digits for the exponent when printing a float (==IEEE754 double precision) in scientific format using the "E" format specifier (or another one)?
Unfortunately no, the width and precision of the format specifier only affect presentation of the mantissa. You will need to post-process the string if you want to affect the exponent.
Related
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Convert base-2 binary number string to int
(10 answers)
Converting integer to binary in python
(17 answers)
Closed 4 months ago.
I haven't been able to find a conclusive answer to my query. Is there any way we can represent a number in its binary representation but as a string? Then convert that string to the 32-bit unsigned integer.
As an example suppose we have the following binary number:
00000000000000000000000000001011
We want to represent it as a string:
"00000000000000000000000000001011"
However, I want to convert this thing back to the binary number and, eventually, it's integer form which would be 11. Does anyone have any idea how to do this in python?
This question already has answers here:
How to convert large float values to int?
(2 answers)
Closed 1 year ago.
Why does variable 'a = 123465789123456789' have a different value than variable 'b = int(123456789123456789.0)'?
Because python’s float (like in any other language) have a limit in precision, and you’ve reached it. On contrary, python’s integer type is of arbitrary precision, meaning that you’ll never reach its limit.
This question already has answers here:
Splitting a number into the integer and decimal parts
(9 answers)
How to get numbers after decimal point?
(37 answers)
Closed 2 years ago.
If I have a float like 32.879, and I want to end up with just 0.879, I can think of a few ways to do it, like:
Convert to string, strip off everything before the ., convert back to float; OR
32.879 - int(32.879)
Both of those feel like hacks. Is there no pure math operation that can do this?
Sort of like using abs() instead of if x < 0: x = x*-1
I'm dealing with Python, but if anyone can tell me the math name for this operation, I can probably google the Python way to do it.
This question already has answers here:
Use fixed exponent in scientific notation
(3 answers)
Display a decimal in scientific notation
(13 answers)
Closed 3 years ago.
Basically, given a float point number, say
f=0.25
I want
'25e-02'
I would only consider numbers with two decimals. How can I do this without multiplying 100??
If I simply do '%.1e'%0.25, I get '2.5e-01', which is not what I want. I wonder if there is any way that I can choose the number in the exponent part, namely the xx in e-xx.
This question already has answers here:
Formatting floats without trailing zeros
(21 answers)
Closed 4 years ago.
I am looking for an expression that will truncate a float to at most a certain number of digits. I want to preserve a certain number of decimals, without having unnecessary trailing 0s.
So, this almost works as desired:
"{0:3.f"}.format(number)
For input 3.123000001:
"{0:.3f}".format(3.1230000001)
'3.123'
Great. But for input 3:
"{0:.3f}".format(3)
'3.000'
I figured out the answer while I was writing the question. Just add .rstrip('0') to the expression. So:
"{0:3.f}".format(number).rstrip('0')